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发表于 2010-5-11 13:19:52
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用list吧4 {! a6 m0 f' g6 [
patches-own [wealth rank]8 f0 R g# `! l: o* V) N, j# `
to setup
; J1 F' G a5 ] ca
8 a9 J/ E: q* h ask patches [set wealth random 100 set pcolor green ]
v9 G' j% W6 rend9 U3 b0 ]5 v6 r- R" |2 a
; }" A/ o0 b! j# _2 eto go( j$ O1 D9 P; Z; N4 X
let mylist1 []# T4 T' ]8 g1 [! ~5 e5 f
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
@5 l+ D5 ?3 P, t: y let mylist2 []
! U( e4 ]* X' o0 Y( A) t% B, s; g set mylist2 n-values count patches [? + 1]7 J3 r3 w" e* H) E* x
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( foreach mylist1 mylist23 ?6 H' i4 G2 Z! Z( o
[
3 E0 ^7 Z# T% @) g ask ?1[ set rank ?2]
% o+ T5 t& y4 a' a4 B% i! o9 M5 b: y show [rank] of ?1
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)
/ D2 G6 e$ n! y; v7 h& B let mylist3 []
8 m3 _) j3 r9 ]; v$ Z" l
% P. T& s+ V* I- D set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
* d9 ~# X4 A- n! F, B show count patches; D2 K6 [3 u. U) Q5 ]0 }+ | i
show mylist1
$ \+ \* q1 ~- H4 A( Z- A" o* I/ ? show mylist3
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9 u, [) d# N$ Z
这时的mylist1 和mylist3 应该是一样的 |
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