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发表于 2010-5-11 13:19:52
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用list吧8 N# `, D$ h$ t! Z. y5 {( A. Q- `
patches-own [wealth rank]
' F" h9 s1 S" ~+ B! V9 Dto setup
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ask patches [set wealth random 100 set pcolor green ]
" d8 u+ F- S, c; F4 o* s2 ?- bend
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1 M1 ~. v6 o3 \. U# w, q( fto go1 ~( ?! m( B4 i! ]
let mylist1 []% V4 |$ x3 {( o. G. C4 Y
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
7 {4 U: r& M8 P( v, l0 N3 T* t let mylist2 []8 L; Z7 P" n% Z4 e; V$ D) ^
set mylist2 n-values count patches [? + 1]
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$ @5 B" F4 E- K2 ?6 H ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]# @7 b3 {* p' P# }3 n( a1 m f/ }
show [rank] of ?16 x- ~3 j3 |5 l% v. ^7 x* J
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]
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, z7 A8 N2 W# e( r2 G+ W let mylist3 []
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8 O* g' v9 v m& l' y! n/ ^1 } set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
& N! z* ]6 H3 l+ |+ w% t, Q8 s show count patches
# M; G( Q" j1 ]) K# U% u+ J3 O show mylist1 7 Q; j! G: b+ a# H* m
show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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