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发表于 2010-5-11 13:19:52
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用list吧
; d3 W# `; m5 }patches-own [wealth rank] x: Q6 ~0 t$ u1 f. a A+ o
to setup
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ask patches [set wealth random 100 set pcolor green ]- s5 d8 G/ a* O
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to go j% k, c" R& h$ t% E. ~3 N
let mylist1 []
7 v1 t7 V9 t9 a set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
% {, R, D9 d6 \: K( R e let mylist2 []
3 G, x/ f3 Q/ u1 o+ `' N set mylist2 n-values count patches [? + 1]3 O8 m8 D. X4 j. e
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( foreach mylist1 mylist27 G3 p& q: K/ l% D6 s! t
[
+ j$ C' r) q% N1 m0 L% k( _6 e0 C9 ]+ Y ask ?1[ set rank ?2]
2 y% J$ z7 L# e, f: i show [rank] of ?1
& _1 }) n% Q- ~. L& ` ) o$ ?3 r( R* [# z; j N* {
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)
% j. \) _$ D6 T. [, W let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
* U) ~( _6 D* Q: K show count patches' D, V: V! F; k/ Q0 ^1 n
show mylist1 ( }- V+ f4 \% A3 z. b V
show mylist32 P: M9 e: J) b- d" g
end
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这时的mylist1 和mylist3 应该是一样的 |
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