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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 # g: E3 {! V( U
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
( _8 F4 \5 s% M. wbegin P_in arriving0 e8 R. j) n2 F5 G* O
move into Q_in1 i9 Z+ Y/ q! s! i/ {! v7 e2 X8 g
use oper for 2 min
8 G7 c& {# Y0 K2 U send to oneof(0.95:P_in1,0.05:die)
( p. V$ }4 b4 a' X% ^4 hend
9 r7 H8 ]( F- F8 o: u$ c: tbegin P_in1 arriving
r+ _" k% W- y! ]" y if load type = load1 then8 M, u: O* X8 J! W$ R; ?4 D- o
begin4 |: A% y4 m( o; t
move into Q_m1
) M# X0 Z7 K7 g9 R: ?8 u: P use M1 for u 5,1 min6 M. a6 E; e I U
move into Q_out1, w5 f" r8 @0 y$ ^- u+ i7 m
wait to be ordered on orderlist OL_1, E' ~* q& c* h2 U+ a
end0 S3 N( N! q% p5 B& _! f% ?7 p
if load type = load2 then8 k- L) m6 a/ p
begin x! ?5 f+ z7 @+ V
move into Q_m2
# _/ N& u# y5 n# }1 d! G, l use M2 for n 8,1 min- S$ b, v7 q& Y" R* Z
move into Q_out2
( P; Q; q1 ^7 j4 N, U wait to be ordered on orderlist OL_22 p0 t% C5 @8 U8 B- i |7 ]
end* R/ X: m6 k" [/ U9 j; _
end: m) O1 [$ x h* o9 g* ?0 u8 l
begin P_dunmy arriving/ ?! C4 w/ r) {' g
set i = 1: V/ ]2 b: P/ z" m; c8 M
while i > 0 do
3 `% v7 t$ j+ b" d) p* \( L, o begin 4 _" N8 d7 `) t* i! u9 m! G8 Y4 D
order 1 loads from OL_1 to die
" ^# J' c4 ?9 e9 W# d) A. W in case order not filled backorder on OL_1
! L+ a( C8 l# o3 P* \ order 1 loads from OL_2 to continue
3 x! \1 F. A4 F& B* J+ v, B/ h in case order not filled backorder on OL_2
' C( r5 K5 Z% M! r! Q# K9 O$ ~0 P move into Q_1
5 W, ]& E- W- e( f# |8 F use Massm for n 5,1 min0 a# }7 J% {% r; Q* M
send to die
% o7 q: Y( Y* v# ] end
! C4 e. c! Y: ], Uend
3 m: F' l [2 N/ N! z) E$ A7 e; X这是我的报告
4 H% _. f& A7 a( k. ]+ a*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.009 M. W$ O; l! J6 w6 r. ?
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec8 f7 L6 {( h) P% n' F" t
Statistics for Process System "q"* x7 }4 A! b! b4 _' d' \" |
Process Statistics
3 v. B/ a Q, f G% |$ {Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait3 Z3 x. \0 b0 ~% _( [; n
========================================================================================. f8 s: \! a2 l& W5 o8 |2 g2 M
P_in 222 1 0.32 -- 2 0 -- 126.04 --8 t+ B, _. R4 L8 h
P_in1 212 210 102.38 -- 210 0 -- 41725.92 -- [1 v, S# q7 U1 q
P_in3 0 0 0.00 -- 0 0 -- 0.00 --6 {$ T! y9 ^; ~1 j3 W; u/ _
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
% S+ I4 A" r* O8 ~; CP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
: t8 C% h6 t) c2 i5 r7 o% SProcess Traffic Limit Statistics
( b+ C" W9 B! iName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
7 y% Y$ }) w7 Z+ x& W* n========================================================================================
4 _+ Q9 V8 K5 O2 W1 eP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
6 U. w8 G$ P5 W1 M: u7 SP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --# D4 p7 E% E' f8 J, M
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --2 g* w# E' }# r; F. ]( {
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --2 b7 Y, Z+ e3 E8 E8 k8 ]
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --8 N- \1 J3 ?) v
Queue Statistics. F! b% {7 p; {& ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait$ l* ] j/ |/ A9 o
========================================================================================; C7 c6 o0 V# b4 f1 [9 t* B- N
Space 223 0 0.00 Infinite 1 0 -- 0.00 --5 U1 E' b8 s {6 m9 B
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --9 c8 I2 Z* {7 A2 t
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --3 N3 n7 A5 f! X4 w4 B/ b
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
3 g; u, _# R) oQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --! K, n( N% l% v* \
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
# g c5 A& g3 Q1 N1 l4 `! WQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
# D6 C% N# i- D! N- vOrder List Statistics
$ H; u- N+ H _& z# ]. w ZName Total Cur Average Max Min Av_Time Tot_Back_Ordered; P7 M& M5 c. R( n) Z- l; n& E+ m! z
================================================================================
& l$ k/ A' C, o: r" qOL_1 139 139 67.23 139 0 41789.43 1
6 e t" U0 ^+ \* E/ f1 } rOL_2 71 71 34.26 71 0 41693.20 1
& z9 ^! S1 y4 y& f) c1 w2 cResource Statistics5 x/ E- s6 f7 Q- u
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State % Q* j, \ i" f3 I ?: {! g
====================================================================================================
/ _7 X! U7 n8 wM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
7 P$ W$ Q& P5 X: s/ t) ?. ZM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
" \# h3 H# k: S% @4 x/ y7 ?Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
- S0 L5 n5 V2 B7 ~7 |. O* @oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
1 F2 a; {2 `$ W9 T& o& [3 O7 D( rRandom Number Streams5 d; {7 g' _8 |$ b
Name Total ( i! j$ m" [; @
============================
! e2 F/ t4 ~7 |9 H6 qstream0 455
; o- @% ~' i+ h( T% Fstream_M1_1 0
5 h7 [0 t' Q$ j/ S( X: \stream_M2_1 0# M2 [3 ~ `" O7 I# w9 k
stream_Massm_1 0$ V: ~) Z- S+ ^" K }! \" Q: c7 D
stream_oper_1 0
+ Z. L! Q+ k8 s" ?- Ystream_load1_1 184( y6 U9 F* \' E5 p/ @; W
stream_load2_1 766 i% W( x1 f: p/ x
stream_dummy_1 0* n" Q- ?2 h4 E6 R( ]7 D
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
