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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 ! a; i' F( n* \6 y {
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：8 D. A4 y, N7 _& F5 v# }. T4 D
begin P_in arriving
: l2 K& H. Q3 a3 I5 v move into Q_in
, ] ?# w! z" K# A+ S use oper for 2 min2 n7 _- Z! e0 K' D
send to oneof(0.95:P_in1,0.05:die)3 Y! A$ X: x# X( H# j
end
4 H* Z! z. G- L/ y5 obegin P_in1 arriving) [1 t, W1 Q1 A! \( Z# C) ]
if load type = load1 then. z1 L0 Y A) _2 X
begin T1 p: s. N+ X! R( Z4 n$ P
move into Q_m1
$ z( ?6 K! r5 h3 G4 G' s, f- G% C K use M1 for u 5,1 min2 }1 k/ i! W3 d5 p
move into Q_out1
! ^ O5 y4 D K: E& b/ K. h) n6 H wait to be ordered on orderlist OL_1# _4 x' I& \# m. \, M6 Q! a) e+ y
end+ G6 J8 l! b+ y8 d9 L4 q2 U
if load type = load2 then
; S T2 c9 D. u" ~4 Z begin& j$ b) X& u1 @/ ?
move into Q_m21 @ e" Z/ l: N
use M2 for n 8,1 min
+ C1 L+ A) ~& u5 z: k. f move into Q_out2
1 p$ d. v7 X) I wait to be ordered on orderlist OL_2
' c; ~; O. U* ^ end1 p c/ X2 v1 Y: ?
end/ [, T5 X7 U5 Q; Z8 a7 K. P; n
begin P_dunmy arriving/ x" U5 o# w* E! U
set i = 1
$ Q! J% z2 g t) x- ~ while i > 0 do
) y6 k$ y8 c6 A; J' r2 q. E- D begin
2 Y& O3 p3 r/ C order 1 loads from OL_1 to die
# q/ _2 g2 m% e4 D in case order not filled backorder on OL_1
( R. c8 w0 N8 u2 Z" F order 1 loads from OL_2 to continue, t( U9 Q# q5 W4 b
in case order not filled backorder on OL_22 M1 H3 R2 b# H8 J d
move into Q_1
7 ^& [/ b t8 ` a use Massm for n 5,1 min
1 `& _4 i! s; a( p4 d send to die4 N T6 d2 Q2 I3 f% D& e; C" b
end
4 w% S7 A( J5 V8 p. d3 k+ Aend
: L" {/ v0 ^9 k, I3 O这是我的报告3 F& T! R0 q6 x) X
*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00/ Q- k' [& A. ]) l6 f+ ]: ?: U
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec$ L% Q% \! S, } |6 r! @4 M& s3 p
Statistics for Process System "q"
V+ k- m+ `# ^* C; q) fProcess Statistics# J0 Q) m4 F- }: [" ^2 m/ d9 H
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
; `8 w3 @2 Y5 v5 t========================================================================================& W7 Y' ^+ T$ \# c) p
P_in 222 1 0.32 -- 2 0 -- 126.04 --
" U+ f" B0 f8 v/ r' aP_in1 212 210 102.38 -- 210 0 -- 41725.92 --$ [9 Y% T; O, D; H& p5 V$ z0 @
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
! N, c# p7 Y# z9 q! R" r" n3 b+ Q2 yP_in4 0 0 0.00 -- 0 0 -- 0.00 --! I1 u. X! h( x" f" b$ F
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
( f, t7 ?7 J* _$ p- l. \8 R# ~% t. _Process Traffic Limit Statistics
' `) v9 y% r1 s/ I0 ~% ~Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
0 i" b1 e m) D- }7 |========================================================================================
/ Q* G% ]7 {6 `P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
. ]6 Z( }, k( Z1 UP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
8 m; |- T2 J8 f7 GP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
8 q3 S: ?. l& X0 fP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --; F6 U) m- |% z; @
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --: J4 @5 o, `* o3 h8 }
Queue Statistics
: J8 G1 s. U, ^% g( U/ EName Total Cur Average Capacity Max Min Util Av_Time Av_Wait7 w8 {7 ^, g; t( m8 C r$ w" L
========================================================================================( ~: h# ]+ o4 A
Space 223 0 0.00 Infinite 1 0 -- 0.00 --+ a9 @1 ~" F/ g/ a4 G+ U( Z8 l' {7 T
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
9 I" k6 p7 y9 OQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --% a# @" J4 B8 y* S6 i6 w
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
) I' b! U8 C+ c/ a# |0 ]Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --# X5 l& z6 l& I2 u6 x
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --% T: O' S# C7 `; z$ v* o; a
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
1 O2 d- G* ~7 z9 g! E' o- ~Order List Statistics
7 I* R. e8 Z0 ^. B2 v* tName Total Cur Average Max Min Av_Time Tot_Back_Ordered
9 q B* V6 S: a" s: ^================================================================================
3 Y! o. R. l' Q% {" p! pOL_1 139 139 67.23 139 0 41789.43 1$ S0 Z9 l o6 L+ O9 A
OL_2 71 71 34.26 71 0 41693.20 1
' J; z+ v1 m- v; G# R sResource Statistics8 Y2 t8 {1 l2 x6 `
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
4 C) P4 H$ [& d; `====================================================================================================3 r g% o, r9 h7 m
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
6 n, u$ l" k) k. }) fM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
3 _& v6 m8 k% z# v7 ]Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
& E: m$ l% t% X/ m+ a H" ~oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 9 e5 r) \5 ?' r0 J+ M; N+ j; V
Random Number Streams
- W& f5 T, y) l6 _3 ~5 E! T+ NName Total 9 Y6 L- \# u/ a2 u" s4 M
============================
9 Z$ ~, e0 a/ O0 Nstream0 455 r+ J7 i) f8 c' g/ A
stream_M1_1 0: E2 m- i+ H9 x4 \4 u) Z
stream_M2_1 0
: u. M) K3 X) ?( v- e+ lstream_Massm_1 0
+ q, P. i. d7 F: l' Zstream_oper_1 0! Q) N+ P1 g& v$ G
stream_load1_1 184# P2 j* K" s& K$ O+ \( Q
stream_load2_1 76
7 Y, @/ R% M7 }stream_dummy_1 02 i" L3 a6 o8 ^% _/ Q
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
