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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 ) ]2 l# j+ H/ d( _& [
! j4 h$ I' j) P5 n( B" b我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
- B, i6 j# ?1 X" n3 bbegin P_in arriving
1 H; g M; I1 x. Q1 q move into Q_in( k9 I/ [7 W4 x* @; H
use oper for 2 min- U+ y4 |( j) m7 [% o& v1 j( P
send to oneof(0.95:P_in1,0.05:die)
. E5 n5 T. x+ b- T; ^1 Q9 aend! C; d2 ]) T/ X7 `7 L
begin P_in1 arriving
8 ~5 h$ U# a8 u, k if load type = load1 then
% b: F) Y" _ x- n begin
9 L* Z( x4 v# ?' X move into Q_m19 U* b+ c1 B4 R) a* ~
use M1 for u 5,1 min
! V" |' T7 r. E4 C4 ^ move into Q_out1" t4 }: E+ J# ~6 ?6 T
wait to be ordered on orderlist OL_13 Q( q! i' T- s
end$ c' x4 }- Y5 u6 H! u
if load type = load2 then# L y5 n. [/ \8 ]
begin8 m+ L: A; y6 ?4 V/ x- b
move into Q_m2
7 l" y( E2 K! D2 \" ~$ Y3 A x use M2 for n 8,1 min
( D' P1 ~8 m$ t7 J: S move into Q_out2, Y4 {( i. u0 \$ }
wait to be ordered on orderlist OL_2
/ E! j w& p8 J. ?0 F% w1 R8 k end
1 {% V) a% G4 {+ R S: ^% l3 J& h# tend4 u/ F3 z: M, ^3 O
begin P_dunmy arriving
/ p+ C. U R. [) Z" R set i = 1& O% [, d$ d" e G" |( n" p3 f
while i > 0 do
" R A/ `! |- I2 k* v& e begin
% [3 l9 E5 B. q1 p& @2 N( K order 1 loads from OL_1 to die
% s/ {8 T$ \# s3 k \, |+ t in case order not filled backorder on OL_1* t A/ \, x2 m8 M/ Y0 v& Q
order 1 loads from OL_2 to continue8 |' a$ }( n) B; {8 d4 F
in case order not filled backorder on OL_2
0 z* I- ]. W8 R/ q0 I move into Q_1
* V+ p# E! ]- c ? use Massm for n 5,1 min$ `! ^# h" n+ i* e, A9 C/ R- I
send to die
0 `0 p. P* t( D0 [1 n$ N; k end" m& o* i1 I6 P
end7 ?# X* z; K3 {( e$ \$ m4 |
这是我的报告+ ]" }) i0 i& \9 u' X8 G
*** AutoMod 11.1 ***
% i4 w+ G4 e: u ~- T9 C! NModel q1 ]6 r% K9 }2 @$ i7 ^$ Q
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00* r5 z& J" z" }( ~
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
4 Z8 K% r& M7 C& D6 {Statistics for Process System "q"
& E! O' S+ M4 G' rProcess Statistics
- g) W; q8 N; l4 _4 ?4 ~: r- UName Total Cur Average Capacity Max Min Util Av_Time Av_Wait, O" G2 |& W; D) y
========================================================================================' |7 }: R; K0 i7 ]+ ]) w }: a
P_in 222 1 0.32 -- 2 0 -- 126.04 --/ p. Z! Q' E( D% l' s4 S: U
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --" @" g; q* O' l' i7 F1 ?$ U
P_in3 0 0 0.00 -- 0 0 -- 0.00 --+ w; V5 k9 |; J* d
P_in4 0 0 0.00 -- 0 0 -- 0.00 --" n% g2 i4 w- Y& X6 I
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
; L1 m' b, H0 }& a4 `& qProcess Traffic Limit Statistics
: ~$ }0 u' Z0 yName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
3 J% j" t5 K- k, J- n! G+ H/ k========================================================================================/ v& ~, ?( Q/ P* h
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
3 C- O( W4 {& ?- T4 d JP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
' v) ~1 I7 `/ f# b- f/ \* o' IP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
P) E( a; Q+ C( q5 iP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --: F/ n) u$ o2 `$ Y7 W
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --1 T0 l9 z0 p& Z% j
Queue Statistics3 p9 l7 r2 N X% u
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait* d2 K" i) O4 B) d; P4 b
========================================================================================
" d' v7 _+ T3 k, z' z; [5 nSpace 223 0 0.00 Infinite 1 0 -- 0.00 --+ D* Z) K3 f! t0 d0 Z n$ V1 s
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --: w2 e8 Q# T, Q [) c3 p1 ~1 x5 K3 O6 w2 V( |
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --, w% s P. I. g' ]5 O D
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --* m* u+ A1 u9 g6 ]+ p' n; ?
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --) K( G, z. f. _5 O5 L
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --* y1 `' n1 `6 |4 F9 F' d X. A, _
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00) _; z0 y* m+ t7 f
Order List Statistics
. E1 c+ ?3 @4 a3 ?: OName Total Cur Average Max Min Av_Time Tot_Back_Ordered: T. O- ~' x; E+ j0 g& Z" _
================================================================================1 U, W; K+ i- Z$ G1 s
OL_1 139 139 67.23 139 0 41789.43 1
: R3 a: P5 N& i. QOL_2 71 71 34.26 71 0 41693.20 11 L, K( b9 \% H* o1 Q
Resource Statistics- A m0 t0 z1 ]6 _
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
+ Y: Y0 e% E1 a! W/ U====================================================================================================: ?+ { m$ O$ h. o" _
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 0 F6 m# H! R0 {7 j
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- * {# a* J+ p' T
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
" I$ O+ P" T8 V( T5 Woper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
% d) n. L; l: ?5 I5 d [Random Number Streams
* z9 L* m3 r$ FName Total ; e U# m( j, {8 ]8 @! f- C
============================
, Z* y$ |$ h6 R* x/ C; a# J- y6 ostream0 455
" b' z9 n7 I+ Q3 K6 Q0 ^5 estream_M1_1 0; h2 k: h! z: J) U) P: e- r5 ]
stream_M2_1 0& P- c7 v a4 E# |* H7 O8 O% K/ n1 E9 I
stream_Massm_1 0( m! m6 U1 l/ P2 l$ U# o
stream_oper_1 0) W1 g* e2 F t6 w
stream_load1_1 1845 Y! E! E7 C d% ~; T% b8 |
stream_load2_1 76; `- ~% o3 K4 X6 b. w+ N. K! Z
stream_dummy_1 04 s0 H2 y; A& H5 w) o* w
' P5 H% a1 e9 H3 z- K( y
请问我的错误在那里?我用的版本是11.1的学生版 |
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