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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：8 I, C/ i3 `5 M# l' T% z
begin P_in arriving
/ E* p( d& b, O! T8 u E7 { move into Q_in
1 b/ ?! e' r3 a; W use oper for 2 min
$ K- v5 Z& D) R9 b send to oneof(0.95:P_in1,0.05:die)
2 x( r- o- L6 g! n) M/ n$ @end0 y( a( R' O S
begin P_in1 arriving# _5 q/ N& }2 q
if load type = load1 then2 m( G* y: K) p q6 r
begin4 y* p$ U" m' Z+ P% p7 a, ^
move into Q_m15 {% K/ P$ p$ Y3 r _; X
use M1 for u 5,1 min- t% m) I, E/ |
move into Q_out1. ^6 p$ }. ]' i, \! F T4 H
wait to be ordered on orderlist OL_1; r" K9 k* T& @7 p2 _
end
" I" C |3 }9 k3 s if load type = load2 then
5 _$ f# X% \2 L# u1 P/ ]5 h1 {$ Q( N begin
' [, p3 A' |8 t9 G2 C/ L- L) r move into Q_m22 Q' y7 [6 P6 g0 D6 r
use M2 for n 8,1 min* c/ b, I$ {2 W( @2 f: o
move into Q_out2
6 B' i6 [* Q* |! v wait to be ordered on orderlist OL_2
) v2 @5 U% |- z; K0 W0 Z N2 O ? end1 u/ i( ^+ L5 i& C) \
end6 I5 e) ?9 W4 B. Q8 Y
begin P_dunmy arriving
: e4 P* D( k# m5 ] set i = 1
, `" K4 O9 F) q! F) L( s; q while i > 0 do( z8 k' q, |& _* b0 t, Z" o" U/ S
begin 6 O0 D1 g3 G) q7 O
order 1 loads from OL_1 to die
( z! o2 L# x- T( a2 d in case order not filled backorder on OL_1& e) @/ Y6 u4 l G, u; \* E
order 1 loads from OL_2 to continue7 o& ]6 \+ f3 T' [& o6 ]
in case order not filled backorder on OL_26 i0 P/ a/ }% P% T' k& c Q
move into Q_1
$ @( N. ]) T y& ` use Massm for n 5,1 min5 k& c: I* R& K
send to die
: G& v @; H( z* v# }5 R |: u% @. y end
, e: \5 b9 l# P0 ]- R( Xend
2 D7 a0 F) P9 h/ b" r' z这是我的报告* u2 \. M# K" x# ~% X
*** AutoMod 11.1 ***. H5 }; f% F: A. Y, \& y$ I+ q
Model q
6 F. U) H4 F$ {! x8 ~ qStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.002 o4 X5 V7 D4 ?% G
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec5 e0 o: R- Q2 Z5 U' s# O
Statistics for Process System "q". C+ u4 H6 T) o! {* k
Process Statistics j; A7 H E0 T
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
" T( e; f$ S0 w0 ^% v========================================================================================
0 O4 |$ u2 F+ h$ Z9 x4 uP_in 222 1 0.32 -- 2 0 -- 126.04 --8 ]6 j# k+ E# ]( y, a
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
/ Y/ |/ L3 ~. z+ |- SP_in3 0 0 0.00 -- 0 0 -- 0.00 --7 P- H: h8 L2 b# V0 X
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
, A! a" A# k8 jP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --" @" b7 u; j! `( n; Q, B; R
Process Traffic Limit Statistics
& `8 }& X0 e8 K. E3 {3 ?9 U6 eName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# ~* P2 B) O- @( e========================================================================================4 g1 a8 l+ K7 I
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --4 W5 N6 D- l) K' G, s
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --! G/ n1 w1 k% I" a7 V+ Z8 m
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --7 h. ]) h: r/ v% a! f, j& V: w
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --$ V% H0 ^6 q- C
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
# [0 U# D: @% V6 P; yQueue Statistics) r7 m1 q# T! n! z; Q
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
% G0 Q. p/ H$ b+ G, O" p3 O========================================================================================
# |+ t1 ? {6 X8 ^Space 223 0 0.00 Infinite 1 0 -- 0.00 --2 y1 k/ ?' P; p, ] Y, e; M
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --- @' k4 [# p0 j+ E! X
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
& V y3 p7 H9 L5 [Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --) N8 U2 m/ y ~4 O" ^( p2 G
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
' l& A4 x2 A; n& w# e( G9 _$ hQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --. i+ O& o) U3 i9 p# _3 ?* T. ]
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
& B. n2 P1 C" tOrder List Statistics
8 s+ A- M0 s$ xName Total Cur Average Max Min Av_Time Tot_Back_Ordered
; ]. C: I' C6 s4 k- w================================================================================3 i4 b' X" F$ M0 R6 k
OL_1 139 139 67.23 139 0 41789.43 1' Q; ^" D% c& R' i% c3 l
OL_2 71 71 34.26 71 0 41693.20 1
6 s" @# N" d4 X4 BResource Statistics
. ^0 F9 w1 g0 s" x4 MName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
% n$ q/ S, a" x+ q====================================================================================================
# P* c- W Q" ~% bM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
* _8 G8 U; R3 r( U8 g$ U" e! kM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 1 S3 U A% ]! W1 L5 B( H
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
. G+ i% t+ s7 ^% [( t$ boper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 3 s! s% t; m6 F# w( ]
Random Number Streams3 _+ j& g0 o9 s% w7 Y, i
Name Total
/ ~: W& R x, I1 \( A& u3 ?============================
2 x+ j; b0 |+ D# e# Kstream0 455! L6 p2 E& \7 b$ X
stream_M1_1 06 t4 _4 k( a2 [
stream_M2_1 0/ I& l/ @" x9 y9 |: v0 y
stream_Massm_1 01 Z, |2 y8 ^( w" M0 J8 e* e0 ?4 W
stream_oper_1 0
8 ? a m' G9 y% o0 M8 Sstream_load1_1 184
- B! U( G Y& E' E* ]( vstream_load2_1 76
7 _6 R- ]) m% [. Astream_dummy_1 0
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& }* w/ o3 M$ P) n4 O3 i. ~) g# q请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
