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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:; c/ a7 B3 K+ ~+ B& B* I
begin P_in arriving8 H$ c6 ^" a$ `1 h
move into Q_in
7 k8 |: o- S9 Q4 X/ s; M$ d use oper for 2 min. w* f: L7 T* l
send to oneof(0.95:P_in1,0.05:die)
4 @ ], W' n/ L1 r- J( bend
! \% \- `, P _5 f tbegin P_in1 arriving. G& J! u, k4 R$ W* k# a6 ` @
if load type = load1 then
; v) U2 o \0 I( @ begin$ k) m" h" e/ t' Y) V
move into Q_m1& W9 ^% E/ v O- I
use M1 for u 5,1 min$ u9 o- k) {. L/ l T) x8 t7 d$ D+ }
move into Q_out1
\, _, H" A/ ~. F wait to be ordered on orderlist OL_1
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if load type = load2 then. Z- u. ^. s0 f3 S: s' _7 j$ G
begin
2 }- p7 N& s9 p4 Y move into Q_m22 s( B6 l3 T4 e4 R3 l$ F
use M2 for n 8,1 min
7 I* }% A0 c# z; n, J move into Q_out2
$ G1 q: J4 I) y- j wait to be ordered on orderlist OL_26 D$ S7 X' D9 B8 R: s
end& _" ]) b* M$ D
end
* X8 W2 O6 S/ x1 ]7 J* ~& j4 R! dbegin P_dunmy arriving9 `" s: L6 q5 E( h; { v
set i = 1
' `: A7 ~ y/ y/ o* }. \ while i > 0 do) d/ ^# K7 I7 K* i4 w: {. _' j
begin
, O0 Z9 H$ D0 x8 w order 1 loads from OL_1 to die
7 z' h" d" H9 @9 o, f in case order not filled backorder on OL_11 {' `8 p9 g8 c) Q% T" F4 d5 m* H
order 1 loads from OL_2 to continue, z# X0 G0 S- S6 W) N* N
in case order not filled backorder on OL_2
" Q- w+ O l$ r move into Q_1- K1 l9 c5 o, F7 i0 `8 k A
use Massm for n 5,1 min
6 i" Q5 C7 v0 S; @ send to die
6 H6 G+ _- h o" S end4 } l* R' F9 A4 b" {9 ^5 D0 f
end. D' r; {2 f: A# y5 F8 n
这是我的报告5 g1 k. T/ q2 C* \9 B: y( o9 j$ @* l; d. s
*** AutoMod 11.1 ***
& }& P$ w, c$ y% Y% ~2 x( v% b5 IModel q
- \' u% o" J& Z q7 hStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00/ K) N- B7 I& K1 l" c7 e
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
5 R( k! g/ J$ f" A0 UStatistics for Process System "q"
* ?) w- q4 R0 H" B J0 s8 t. HProcess Statistics+ J& S0 R3 i$ n( K' p7 H( X+ H
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
$ r' l) ~3 m6 K# t========================================================================================% W: k6 p( t) \5 d( W
P_in 222 1 0.32 -- 2 0 -- 126.04 --
; G* z& L) i' {8 oP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
# A3 X, i& j' j) \; t' O6 X1 wP_in3 0 0 0.00 -- 0 0 -- 0.00 --: G" C3 i: B4 E6 _: O; `
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
1 p) q6 }/ ^" j. V, s4 k0 aP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --. l1 B' A3 a6 \! Y7 U8 j, O
Process Traffic Limit Statistics
2 Q9 B2 ?3 u1 WName Total Cur Average Capacity Max Min Util Av_Time Av_Wait( y3 {. C! w( K
========================================================================================+ l& X1 |1 i( }. R
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
K3 Z! m; d% [2 gP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --$ k/ |6 v% j# b* T
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
( G" b9 y- O% d, T1 g8 mP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --( P. n3 v& [! E
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --( S* g, {1 I7 Z6 D
Queue Statistics
# ?$ h |- H1 d: B1 JName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* ?0 b4 W. B8 W+ P========================================================================================- z5 w7 X" E0 Q4 ^% J
Space 223 0 0.00 Infinite 1 0 -- 0.00 --4 @' r8 m" @/ I7 L0 X4 l6 H+ c
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
; k& J9 E* `! T) W KQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --4 J$ K, Q2 n6 K
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
2 H7 R( `2 n. e* o: N* T! T$ rQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
- l9 v) c, g# o' E1 l- j" S. CQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --! j0 D3 q/ R) J/ I
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.001 Z$ Q* T- T6 p* q$ d" A' |9 ?
Order List Statistics
' R6 x8 r- j) }. XName Total Cur Average Max Min Av_Time Tot_Back_Ordered
) p$ g) b9 G8 _; o' m6 b& B; M: U================================================================================
4 B% n# [5 L- v0 jOL_1 139 139 67.23 139 0 41789.43 15 w' _8 W9 e0 _6 s
OL_2 71 71 34.26 71 0 41693.20 1
- H6 U1 B3 C0 @* C3 QResource Statistics
3 ?' C% [6 L& E) [3 `7 TName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State : L4 p( W# [- p0 {
====================================================================================================
. H/ B1 y9 E3 V7 y# S [& gM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- % q0 z) s. {1 R! S5 a, ?0 j5 b' g
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ( ?. ^7 e" ?- r* G0 W' [4 C
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
/ Q8 n, p3 [" w# t* h8 R0 I$ ooper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
, V1 m$ U( @: Z' @3 Y x4 iRandom Number Streams* z, S+ F6 D/ h" [
Name Total 6 u2 V: h1 L0 A& h& `8 P8 v' l5 n
============================
, {% w' h( n/ W; Zstream0 455
2 C6 s6 C, y9 ~stream_M1_1 0
C# }3 w5 |$ W; `" w, a* sstream_M2_1 0
0 b/ _* L( T0 Z/ X! Pstream_Massm_1 0
) G% H. X) O" W; V/ r4 Bstream_oper_1 00 m$ o7 ?6 q# u7 N. Y
stream_load1_1 184
! P" Q; K! ?# }' pstream_load2_1 76. q1 u: r( C" Z9 j% K8 ]
stream_dummy_1 0" R) ?+ n5 \8 u5 b
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请问我的错误在那里?我用的版本是11.1的学生版 |
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