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本帖最后由 soso001 于 2014-12-17 14:53 编辑 9 `1 P9 j; Q; c
& l9 B: B/ A/ t, o4 V不好意思,打错了个字母,呵呵呵!* a- @/ R+ K/ d; [6 p
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
% o8 z8 I" H+ W5 s8 U y“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!0 g( W4 b k% L- ]: @; v
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j,k,nstep,c, scheduleteps,mincomptime:integer;
; ?( d) _" Y+ `4 W4 _2 y8 B7 o7 V1 A M:string;
$ M0 H+ z4 e4 N selecTab:table[integer,integer,integer,string]; e, O5 _. p i7 @9 ^1 V+ m0 s- R2 |; X
do( f8 B& R+ R7 l& f1 l& }2 ?1 O
initorders;) ?/ y$ Y8 w5 W0 S0 p# E
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scheduledorders.delete;% r) a4 g7 n5 z# \# Y4 T
seletTab.create; m; ~9 o) l& q1 R; s8 @* b
; s0 e# C" l& R$ X9 T orders.initialize({2,1}..{2,*},0);
- e" j* `3 p: o/ [: y E) D orders.initialize({4,1}..{4,*},0);
# g7 i# _$ R3 W# ~$ d for j:=1 to numorders loop- h4 W5 C) F0 P+ h, B
orders[5,j]:=orders[1,j][2,1];! S' p3 r9 y; z% q
next;
# F: S2 X8 f" Y. F occres.initialize({1,1}..{1,*},0);
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--XUNHUAN: `' Q' n) J+ t
for scheduledsteps:=1 to numsteps loop --! P2 ~, f$ u: w
selectab.delete;
, C2 |" l; }: I: f; i/ _% u k:=1;& f+ S" @! Z2 l0 T. f
for j:=1 to numorders loop" ^/ ?2 H. k; j# t" a
) u6 K+ \2 ? K+ G {2 H8 D: v1 Q nstep:=orders[2,j]+1;& }( E6 `% ?& J
if nstep<=orders[3,j] then
7 S* X) ~4 f9 ]( Z' P( t selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
6 E; q3 ]9 X& e5 G; J8 ^; r k:=k+1;
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5 e5 e7 A/ P0 b, ^ end;
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mincomptime:=selecttab.min({3,1}..{3,*});
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! X& a7 [+ v D. X7 d from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
$ k# c0 O* A9 B( K0 f$ y! y. C/ M j:=j+1;
) K9 H% L0 g. b+ ^ else
3 _3 S* p7 |2 F: p5 C5 g: U selecttab.cutrow(j);
3 W5 g" x, n$ V3 V1 a end;# o0 P( P9 I. }- j: V8 }: `
end;
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: l7 l0 d# z6 r7 D" S! _- F j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
! \: v- ]6 P; J- @) f orders[2,j]:=nstep;
u* P; N9 O& c" o. `7 j# n m:=orders[1,j][1,nstep];% H: K3 F$ u% r4 q3 w
c:=orders[5,j]
' s9 [9 h# Z0 P& t occres[1,m]:=c;
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--jieguo:start,end,res,job,step4 z$ J* [9 P2 ~" C$ m1 ^
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);+ u- e3 U3 {0 [2 w1 H' l
for k:=1 to numorders loop" ~+ `+ H6 j1 g
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m9 b" r* [6 Q" g2 ]) Z
-- H% i$ T# I, D2 k
then' ^0 |; y Y* P; D( [9 r8 |8 V7 y6 l
orders[4,k]:=max(c,orders[4,k]);- u* K, s8 V+ r" q; H: y6 Q9 ?
--
, B. A, @7 }6 T' u orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
, E3 `' _( C+ _. j3 l next; o5 n! P& j7 C7 r: g
nstep:=orders[2,j]+1:
+ ^. D9 u4 O- F, \5 \8 G" A if nstep<=orders[3,j]$ S Q& @, {$ F. y+ B7 e
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
0 v7 A, k" Q$ r3 F orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];8 ?; Z9 T5 g* _; c" x
end;: ^5 [( j$ n# Q
next;
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+ y! k% P3 N0 [+ d print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
5 N; q* Y4 T! p% w, C( j5 K mygantt;
% ~1 c% z6 [ P* O& @! n5 N ens; i. Y/ ~0 [" [$ c, v( i
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