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本帖最后由 soso001 于 2014-12-17 14:53 编辑 0 }4 u) d+ U/ p6 T. ~# }* H; w
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不好意思,打错了个字母,呵呵呵!. ~ S; h8 f% F
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示. o- \, T& M G- K( }0 k
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;6 e# h/ E" D8 J( G
M:string;* ], s" E% v- x! F* A2 U
selecTab:table[integer,integer,integer,string];
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initorders;5 B4 D& c5 g; \2 z$ z5 T
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scheduledorders.delete;
- a5 f% r; S d' d+ p seletTab.create;
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orders.initialize({2,1}..{2,*},0);
0 n: ]5 ]0 L- [5 j2 R u# B orders.initialize({4,1}..{4,*},0);
& I. t4 ~8 P: L7 @; g$ p# p0 M7 C for j:=1 to numorders loop7 k7 N v+ R! b+ L
orders[5,j]:=orders[1,j][2,1];
: _9 g2 _4 {4 D: O, ? i/ n8 l" r& E, | next;
h9 u* O- s# [! F) H- s6 R occres.initialize({1,1}..{1,*},0);
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for scheduledsteps:=1 to numsteps loop --4 L1 W* ?7 `1 B
selectab.delete;' a5 N, e! S% {
k:=1;. K; f3 x# z4 c- Y
for j:=1 to numorders loop2 X- k$ Y, r$ E# n: p- l$ i% }
T, f- d& I. c! K) \* C nstep:=orders[2,j]+1;
; I8 x! A0 A. m- D if nstep<=orders[3,j] then
' O: H3 ^- k/ U) P- w$ r/ B" C0 K7 i selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
7 F$ A- y# t. j* x8 C k:=k+1;% b) n/ x# B# N) P% d, A
4 J3 R" s% a" J1 ^3 z) h end;0 v c. ]6 o4 u: c$ b& G$ y, |
next;) l3 q' z8 c1 z5 _
mincomptime:=selecttab.min({3,1}..{3,*});, s2 R/ @$ k4 W, u7 E0 u5 j! H" A
8 v2 y+ P7 j F1 g# t' m7 z3 u from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
" e+ A+ n# ?) l U0 ]; ] j:=j+1;
2 s" z7 A3 H0 }! H- B9 Q& n else
* J( S$ U0 P0 P8 @. _ selecttab.cutrow(j);, \; `2 x7 U* W, e
end;
3 O! E, ?6 M5 ?! X* i6 R, z end;
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; B( w! h/ c" Q/ I2 }. U6 W4 x j:=selectionrule(selecttab);& q$ a9 Z* G' y2 J/ J" P& I
9 H: {4 t( k; n4 s4 X nstep;+orders[2.j]+1;
3 w& V6 ~1 c# S* B orders[2,j]:=nstep;. h# R& s+ ?; s
m:=orders[1,j][1,nstep];: m4 E- N/ r! M" O! o6 S
c:=orders[5,j]
" J. J$ | [3 ~+ [/ J- x0 { occres[1,m]:=c;) ~, f' |8 G1 o
3 v1 a/ ?$ t3 F1 p' Z& g --jieguo:start,end,res,job,step& j8 L- w( B- h& h/ [
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
# v0 I4 R! `( f7 v* g+ N* G for k:=1 to numorders loop
4 `/ @$ }7 ], j. K nstep:=orders[2,k]+1;: q' [- X. |) {0 g( ]# a- r
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then% K& G0 m: A2 S1 [- V5 e3 _$ T3 E; W& g' A
orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;3 G- l3 G8 m/ v+ ~: U8 ?9 m0 `
next;% `5 R- U) h% N; U \
nstep:=orders[2,j]+1:
9 k+ A5 l$ U- y% X, a if nstep<=orders[3,j]- Q3 E- `3 E5 P P" H* D3 {4 |
- |" D% s+ c- F" Q, ` then
, X" f7 t! Y: E% A( a4 _ orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]); C3 d$ P' D D6 L" w' J3 E% N" ?
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
4 q" b( c( |( O end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});% }( Y) G6 A& D% s& c" K# h
mygantt;
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