HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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2 {# @4 f b8 A; R( V2 T7 O a public Object buildActions () {' S/ P7 e# i _. l, {$ S" S
super.buildActions();
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. }+ M0 V- u" \( _1 P+ P // Create the list of simulation actions. We put these in
* M7 v/ _/ Q: g! E // an action group, because we want these actions to be
1 O' x9 K$ Q7 l/ J u- m // executed in a specific order, but these steps should Z0 U7 D4 j/ C1 P" `0 |
// take no (simulated) time. The M(foo) means "The message
% Z$ a- l/ l4 q7 I' T7 `! ^" A // called <foo>". You can send a message To a particular- b! H* N: T5 [. T, s( M
// object, or ForEach object in a collection.. O% _4 L" H' M/ k8 N- }
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// Note we update the heatspace in two phases: first run
$ y# v1 E, I) Y* W3 r // diffusion, then run "updateWorld" to actually enact the9 P0 A" { L6 d3 k+ ~
// changes the heatbugs have made. The ordering here is
+ X" N5 ~4 E# c1 j // significant!& a4 P& n, N9 ~4 D
2 k) {' O/ @# ?4 \0 ~ // Note also, that with the additional ~3 g8 \: m( j0 g. s
// `randomizeHeatbugUpdateOrder' Boolean flag we can7 L% B0 h# p) m4 ]. H- P
// randomize the order in which the bugs actually run" S3 M7 ~; g, b
// their step rule. This has the effect of removing any$ |' ^* k% a) B3 J/ ]
// systematic bias in the iteration throught the heatbug
0 R6 T2 x# c/ X4 w) V2 j; { // list from timestep to timestep. |% X& K# [) h0 a- {
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// By default, all `createActionForEach' modelActions have" _; B9 X/ y2 b9 H( X
// a default order of `Sequential', which means that the
1 ]" j1 x7 ?. k$ a* n' d // order of iteration through the `heatbugList' will be
( H3 M: b s, R- ^( e3 Q // identical (assuming the list order is not changed0 I$ ^& D) F* [/ n/ k3 h6 q
// indirectly by some other process).: }1 c9 K! A @6 |6 d' ]" R
0 |0 v: r3 i; b" Y# A modelActions = new ActionGroupImpl (getZone ());
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modelActions.createActionTo$message
' Y% ?* s7 X. ~/ S9 Z (heat, new Selector (heat.getClass (), "stepRule", false));/ w% {6 a! V$ x$ v5 V! }3 {
} catch (Exception e) {" a2 x* {2 q( | n* i q% e
System.err.println ("Exception stepRule: " + e.getMessage ());: t$ ]# v4 u/ |/ X% T
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0 H2 t6 g! _8 v1 l7 d1 i# j try {
1 z3 ]8 s9 b) m1 a5 @$ o* {1 Y5 G: m Heatbug proto = (Heatbug) heatbugList.get (0);' b: ], g: J2 K
Selector sel = " y/ C1 ?% |* }
new Selector (proto.getClass (), "heatbugStep", false);5 D$ a. {# P8 t2 O4 ^5 i- \
actionForEach =
! i: A% D; Z7 h2 u1 B modelActions.createFActionForEachHomogeneous$call; K! @- c2 d5 _9 g$ s
(heatbugList,
. n. Z# b1 I5 r new FCallImpl (this, proto, sel,; z/ G: G& b" i. B2 n, y& V# o
new FArgumentsImpl (this, sel)));
- F7 i3 c/ l8 c; G } catch (Exception e) {8 O3 c+ C3 }6 Q0 x& H
e.printStackTrace (System.err);
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) B/ T" K3 u) T, i$ t1 y3 p) J syncUpdateOrder ();" ]2 m1 Q+ c. P- z
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try {/ r/ `$ }" i f
modelActions.createActionTo$message 5 D( x" E- f% S
(heat, new Selector (heat.getClass (), "updateLattice", false));
: F, f- ?& N3 f3 t1 K } catch (Exception e) {4 a; ~; J( N6 J5 ]
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the7 d9 Q& M3 P F$ M V
// modelActions. modelActions is an ActionGroup, by itself it
" w3 d- F% R; E! ~; F' R& o // has no notion of time. In order to have it executed in3 g* A5 K8 Y; {6 e
// time, we create a Schedule that says to use the
& K# n, u% b% s // modelActions ActionGroup at particular times. This
9 z3 Z5 |$ y& ^# B // schedule has a repeat interval of 1, it will loop every
% u5 c) E$ q& `! J // time step. The action is executed at time 0 relative to
: @8 r$ N- p% q8 Q // the beginning of the loop.
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// This is a simple schedule, with only one action that is
. O- v% p1 ^1 J/ ] // just repeated every time. See jmousetrap for more$ L0 D5 C7 K& o& K, D/ R
// complicated schedules.
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modelSchedule = new ScheduleImpl (getZone (), 1); ^6 G: j* u3 A5 r
modelSchedule.at$createAction (0, modelActions);
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} |