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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:9 D( l- y7 x: M; q- N! C
# F5 m' r$ A" i5 v% U4 r3 c
public Object buildActions () {
( @- [* w" b6 P  t    super.buildActions();) _; B! v: c# Z* n4 p: ^+ Z* S
   
4 R. `6 U) o/ F. L  h/ U    // Create the list of simulation actions. We put these in: }1 n+ J1 n2 g! k$ h+ V: t% k# C
    // an action group, because we want these actions to be" X/ U2 }' N! K- V1 M
    // executed in a specific order, but these steps should
, B+ ]" k6 H2 L    // take no (simulated) time. The M(foo) means "The message
1 T  b/ M7 ]5 ]+ x' u3 [    // called <foo>". You can send a message To a particular+ i3 l5 G  Q" ^% ~' u9 J
    // object, or ForEach object in a collection.
' D# e5 Y6 ?. p# r  ^' p- D        
7 x$ q" q$ u, W1 B0 \3 S! W: G    // Note we update the heatspace in two phases: first run0 f% N' a' S1 }1 \8 W
    // diffusion, then run "updateWorld" to actually enact the0 ?8 \8 D# G6 R; ~7 Q
    // changes the heatbugs have made. The ordering here is
7 ~* }5 @& \% n" u1 n) |    // significant!
) p9 q1 i4 `7 N& h. _. k' i        * q0 b% P4 X' k& N# G
    // Note also, that with the additional0 ^# d- _# Z8 u: ~
    // `randomizeHeatbugUpdateOrder' Boolean flag we can3 t* Y5 E% `; X! L1 c1 }( ]+ F
    // randomize the order in which the bugs actually run0 G8 D# y' q2 U: u6 t6 c( U
    // their step rule.  This has the effect of removing any. L* B+ J0 G4 h. f- v+ K) w
    // systematic bias in the iteration throught the heatbug
4 P% A2 t. s9 g7 Q    // list from timestep to timestep
4 o4 t$ G( I) g4 n1 I# [) a        9 S6 l3 Y  L6 ~2 {1 e
    // By default, all `createActionForEach' modelActions have
. r9 _3 ~8 U* d' F1 p    // a default order of `Sequential', which means that the$ `  |7 c; O; ]& G% M
    // order of iteration through the `heatbugList' will be+ M9 t* O# z# _, v
    // identical (assuming the list order is not changed
. ~2 j4 J8 F8 n# k1 p8 c* c    // indirectly by some other process).
3 t  f) p  B8 q4 r0 _# \  P7 J   
1 K3 ^/ x) }- H* k0 l$ V% G$ ]    modelActions = new ActionGroupImpl (getZone ());
6 Q. V7 a" i$ s/ u
6 H' e2 r$ ~9 p    try {
( j# _8 G1 Q5 ?8 R1 m      modelActions.createActionTo$message/ z# f4 ?$ ]& l. W9 @0 k7 }
        (heat, new Selector (heat.getClass (), "stepRule", false));: \" E$ n' j2 T; g2 y* O; Z4 {$ a
    } catch (Exception e) {6 E6 t& _) k: k; n( q) F
      System.err.println ("Exception stepRule: " + e.getMessage ());. @+ O/ I( d  w
    }
' I$ R3 m7 X- k& f/ v2 K/ H
9 z+ _+ u1 W! G2 l4 w  k/ n1 _    try {2 V" g; f  d& }0 t7 ?3 r: t
      Heatbug proto = (Heatbug) heatbugList.get (0);
& }3 I* Z1 i, q      Selector sel = # V7 W; D' ~/ I$ w2 g) `
        new Selector (proto.getClass (), "heatbugStep", false);
- w4 n  f- c7 ?* P$ }      actionForEach =
& D) \& T! O% `9 f8 _: v% B: ~        modelActions.createFActionForEachHomogeneous$call% f) K+ y: b  A* Z( D& u: v' p
        (heatbugList,
! k. |4 |  G7 \5 l         new FCallImpl (this, proto, sel,4 a% F4 z! k: }/ E
                        new FArgumentsImpl (this, sel)));' z0 U8 ]/ R* @$ T) }5 R7 B
    } catch (Exception e) {: p* s/ ?# ^% O( r3 O
      e.printStackTrace (System.err);# I6 ?! v) B9 f" Q* G
    }
3 h1 A( d7 X7 Q2 T    - a0 u4 x2 ~5 _" n9 K% `2 l
    syncUpdateOrder ();5 |. k$ j" C3 c  d9 U5 O
, I, H( D0 ^' {; o1 k
    try {
# t2 U% y* s( K: @# v      modelActions.createActionTo$message + P( t. g2 W+ U. g+ s
        (heat, new Selector (heat.getClass (), "updateLattice", false));$ X! D& w1 {5 k# |4 e% H3 s
    } catch (Exception e) {' T+ Y& T. u' G/ ?
      System.err.println("Exception updateLattice: " + e.getMessage ());
- K$ V/ P% T$ t# ?    }
) n2 h$ E: d* k. w7 t        
- f9 s( Z0 Y6 @: v    // Then we create a schedule that executes the6 {' ?+ z$ _+ s& T) ?9 G) A6 ~
    // modelActions. modelActions is an ActionGroup, by itself it) l' _2 v7 d# B' ~" Z+ i4 y5 `4 X! c7 @
    // has no notion of time. In order to have it executed in
( [) i' d* W6 _    // time, we create a Schedule that says to use the* ]7 t* A5 \/ b# V/ Q: n! R1 C
    // modelActions ActionGroup at particular times.  This
# u8 n- W5 o, Y3 _" |1 W7 O7 H8 l    // schedule has a repeat interval of 1, it will loop every
# X5 ^( |* T2 b* X- s& G* v    // time step.  The action is executed at time 0 relative to, Q1 \/ _' x" U+ k% ~$ _
    // the beginning of the loop.
5 o$ h( l: W$ B* c- @- Z3 |
2 G$ u, K* K* I+ |$ v9 ?0 l: W$ W    // This is a simple schedule, with only one action that is
) X, H6 Y( z3 t$ s$ ^3 ]    // just repeated every time. See jmousetrap for more  R5 }. s0 ?, S" A
    // complicated schedules.
0 v9 j( z% o- F: P7 r9 {. f: s  
7 y  J- A" q) e, R8 ?8 d    modelSchedule = new ScheduleImpl (getZone (), 1);- Z: I6 o- g8 h, H( o3 y
    modelSchedule.at$createAction (0, modelActions);
' h; F* [- c- Y4 I$ y5 H& x7 l        ) s6 [$ e- A6 [+ s) s) }
    return this;# k0 Q! ?* w8 r) t- ]
  }
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