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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
: X$ J; p. T6 T' j4 [, C3 J4 J
public Object buildActions () {
6 l& z8 `' C+ s! W: j    super.buildActions();  P, ]( ?2 G3 ~5 g% ]1 u
    ( W9 b/ G0 x1 ?5 K$ H% e% T
    // Create the list of simulation actions. We put these in
; N# i" V' g4 L    // an action group, because we want these actions to be
. g8 R  b) t! J# J    // executed in a specific order, but these steps should' k' i) F% L* J* J2 I. B, J' k* F" {
    // take no (simulated) time. The M(foo) means "The message
. ~- `# i2 [  T. ]2 @    // called <foo>". You can send a message To a particular' o- G# j7 O# |9 b0 F0 q3 r% E
    // object, or ForEach object in a collection., p) t4 Q* F1 i# W6 g
        
' x( t/ K5 U9 B$ A8 ]4 e% Y8 g    // Note we update the heatspace in two phases: first run
5 O/ U# c+ B; w% i* u7 s! Y- z    // diffusion, then run "updateWorld" to actually enact the/ V1 H* P$ v- o% |1 E6 C# {7 y
    // changes the heatbugs have made. The ordering here is
, e, Q1 q2 i( H' k+ I! v0 G    // significant!- O& M, m' o1 N; M/ I( K' g( k/ A1 |
        
* |3 d* m: E+ l! a    // Note also, that with the additional
& [4 D0 L3 x- y5 B7 X0 D    // `randomizeHeatbugUpdateOrder' Boolean flag we can" }( ^7 z! i' S+ ^$ U: J. [& O
    // randomize the order in which the bugs actually run
5 ?1 e8 g/ ^' `( N    // their step rule.  This has the effect of removing any2 q' E/ r3 m0 _5 p
    // systematic bias in the iteration throught the heatbug3 }6 L3 m4 q4 I. I9 V
    // list from timestep to timestep
- Q2 U' @3 _7 K# U4 P5 i* V7 w        - d5 A/ y2 a! A, S* x8 K3 `( \
    // By default, all `createActionForEach' modelActions have# n8 ^% E! S& n  [+ u
    // a default order of `Sequential', which means that the7 z+ k, A; L2 a6 g+ y- Y
    // order of iteration through the `heatbugList' will be
3 D' N, \) ^. A1 T3 t: Z    // identical (assuming the list order is not changed) r* D2 P( W" n7 c! k% W
    // indirectly by some other process).
% @$ u3 r7 L! J# Q* h    : }+ E9 j3 t# ?+ L6 O% |
    modelActions = new ActionGroupImpl (getZone ());3 N& t; }* G+ d2 e( i; t7 A0 |

7 B1 k8 k4 `2 D6 G. {5 J    try {
, K$ `: u9 M' L8 ?% r- X      modelActions.createActionTo$message
" b" U. B2 ?7 g1 T        (heat, new Selector (heat.getClass (), "stepRule", false));5 h, ~) c* F1 F. h; x$ t
    } catch (Exception e) {
1 }; S9 j. i% q7 W/ [7 z3 G* ^: r      System.err.println ("Exception stepRule: " + e.getMessage ());
8 j' M2 W3 b' M' L0 U5 R    }& x9 o: \) U# a2 V: ^2 |
/ I+ l' E, A6 H; F6 |8 e
    try {/ C: W7 b7 R/ U# m
      Heatbug proto = (Heatbug) heatbugList.get (0);
9 A) D7 A% J, V1 J$ {' F      Selector sel = + k% T! i7 f: D8 [! ]
        new Selector (proto.getClass (), "heatbugStep", false);
; B9 Q& M5 W0 f* F1 X- Y1 Q3 N      actionForEach =+ g. J7 ]$ l7 h1 P3 N0 D' h7 g
        modelActions.createFActionForEachHomogeneous$call! T0 o% P+ @, H: S
        (heatbugList,
( Z+ P: b. ^6 I" \9 P. M/ y         new FCallImpl (this, proto, sel," X. [* u; u* p; e
                        new FArgumentsImpl (this, sel)));1 x; {5 w( ]: [1 Z- U$ {
    } catch (Exception e) {
; |4 m6 v. a9 W3 M      e.printStackTrace (System.err);1 \. R# ?* q6 x$ M% ?/ C
    }1 b' N3 q& k+ J
    1 [1 L, B( Q% z/ u4 ]9 f4 j
    syncUpdateOrder ();
* B( J# ?/ }+ H) X9 i7 ^& m& ^/ h' q( C# q
    try {
" U+ R) y. T9 ~8 i8 W" q% {      modelActions.createActionTo$message - {- I/ s& G9 @, f
        (heat, new Selector (heat.getClass (), "updateLattice", false));" _) n: M* n' P
    } catch (Exception e) {
* r+ t: x7 L% d. |% Q1 [      System.err.println("Exception updateLattice: " + e.getMessage ());) ~2 C- U2 ?3 P0 C
    }6 A4 O( D. _& V6 m* i- h
        & |; |& ^+ |4 F  W9 l  l: u
    // Then we create a schedule that executes the
' c+ s) p6 O; m# ?$ g    // modelActions. modelActions is an ActionGroup, by itself it  x% }# f, i0 u7 T
    // has no notion of time. In order to have it executed in
+ j: ?: M9 U4 Q( `( i    // time, we create a Schedule that says to use the
4 r3 r2 g. T; _( Y+ E$ {2 c. l    // modelActions ActionGroup at particular times.  This, _! B$ V1 ?! X& h4 t) Q) [
    // schedule has a repeat interval of 1, it will loop every& X" a  m) _; G4 U# E# {6 {
    // time step.  The action is executed at time 0 relative to
- Y3 @. O% q8 c/ d. @5 ?) S    // the beginning of the loop.
( C1 `( r+ |- C7 S
7 m, Z1 Z; [9 g2 V; E  ^' t    // This is a simple schedule, with only one action that is
- L% }; ]2 N* J' m: M2 }    // just repeated every time. See jmousetrap for more
& k' M8 {8 B& q# J    // complicated schedules./ p, F7 m7 O" _, ?1 C( P* \
  
0 h! r- Z& {2 z* X/ ]6 h7 N    modelSchedule = new ScheduleImpl (getZone (), 1);
! B! F. J  Z+ J( G+ z/ A    modelSchedule.at$createAction (0, modelActions);
! `/ E: I$ g4 z) h        9 q6 I0 [5 W* X" d) E' ~8 s
    return this;/ Q$ t' u; }1 n2 Q7 \# M
  }
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