HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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1 e7 W! _% V& g" s# R& O public Object buildActions () {
; K b1 N4 [# c N super.buildActions();
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; L) ?5 B e9 O // Create the list of simulation actions. We put these in
z! V- | @6 A& t // an action group, because we want these actions to be
?7 V% w0 J3 |% } // executed in a specific order, but these steps should2 z# g/ i2 L2 h, D
// take no (simulated) time. The M(foo) means "The message* K2 a; S/ y7 n0 [: f' b
// called <foo>". You can send a message To a particular- K# R% |- [# L7 _8 K2 X) ~
// object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run& r; r! S+ f2 {
// diffusion, then run "updateWorld" to actually enact the4 b4 h4 q# H! K+ {' ?6 L- Z
// changes the heatbugs have made. The ordering here is
3 c" d0 F* ~ `* S // significant!
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3 `) |) L( h) g( M2 i // Note also, that with the additional" A# v# W# A) T* Y9 J
// `randomizeHeatbugUpdateOrder' Boolean flag we can& G4 i& C( o, {* i" |4 ?# k& w
// randomize the order in which the bugs actually run
! c) d1 X8 T5 `7 f& i4 Y% ` // their step rule. This has the effect of removing any
$ J \! q: _2 A& H% N5 d // systematic bias in the iteration throught the heatbug: `1 D" A' J5 i& \' ~: K
// list from timestep to timestep
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// By default, all `createActionForEach' modelActions have6 {: z3 `1 @ d1 |- |. y8 i
// a default order of `Sequential', which means that the6 e+ B3 J1 j( {6 \5 F: ^" i, L
// order of iteration through the `heatbugList' will be
8 r. k* z' Q7 b0 k5 o. E // identical (assuming the list order is not changed6 ]) H [1 D( T6 c' f. w
// indirectly by some other process).: c! B2 I, ]1 G
1 \8 Y8 `1 O5 Q: I+ T7 x! a- A" K modelActions = new ActionGroupImpl (getZone ());9 H' u" m& L/ i9 M- ] }
9 E) R3 k# D$ p try {! @" H4 ~' c. g* E: p% p! z6 c; T
modelActions.createActionTo$message
3 w* V5 A- \: W* F& E" ^$ w7 ^5 K: d (heat, new Selector (heat.getClass (), "stepRule", false));
1 R* Z4 d( |% @$ y4 W( E } catch (Exception e) {. L w$ p A; L7 F4 M/ j/ i! m$ o6 W l8 ?
System.err.println ("Exception stepRule: " + e.getMessage ());7 q$ i o c0 ^& x( c/ G/ y) h5 o
}
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try {( I6 p" j' Z" H/ D" M/ D9 O$ \
Heatbug proto = (Heatbug) heatbugList.get (0);2 d6 W" @" ?* m c8 s2 }9 Z# V
Selector sel =
1 X) @; B" k) A0 | new Selector (proto.getClass (), "heatbugStep", false);& b* f) r* r M5 c
actionForEach =
; X' d7 f8 g1 U- g$ a+ D modelActions.createFActionForEachHomogeneous$call6 C$ `1 Z6 Z- r6 |* [7 I
(heatbugList,
$ N4 X. l5 y0 K' w! Z1 Z new FCallImpl (this, proto, sel,- G. [, ]3 p8 {! f& C
new FArgumentsImpl (this, sel)));% _/ {1 F8 s$ x% w5 ~& F/ e' D
} catch (Exception e) {9 t( T% ^! v/ D* n# ^
e.printStackTrace (System.err);% ^, |! L5 {* w( C8 t+ B& y* }
}
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syncUpdateOrder ();1 m) M _+ \% Z: A1 X
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modelActions.createActionTo$message
/ K Z+ W3 a2 n' j, z (heat, new Selector (heat.getClass (), "updateLattice", false));$ M, W; F$ o- j: N+ q
} catch (Exception e) {
/ l1 y9 F3 I9 a: a$ S. P% ^ System.err.println("Exception updateLattice: " + e.getMessage ());
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: n+ I/ B/ ^ T- K( [5 A // Then we create a schedule that executes the- m% O) X& ~- |, L6 y
// modelActions. modelActions is an ActionGroup, by itself it+ @' O* x5 s; f( m1 v* `
// has no notion of time. In order to have it executed in* g7 d$ @+ ?( H" I5 g
// time, we create a Schedule that says to use the
3 G) y) ~6 u; B1 E# s) \ // modelActions ActionGroup at particular times. This& {# v# }; p0 y
// schedule has a repeat interval of 1, it will loop every, R6 {9 K3 c& p) D9 v( T% f3 }
// time step. The action is executed at time 0 relative to
. \4 V2 `, h" `7 C3 ~ // the beginning of the loop.
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// This is a simple schedule, with only one action that is: N( M. |, _' L4 S7 x, \0 r8 N
// just repeated every time. See jmousetrap for more
, l$ _# o; C8 t+ q: M% d3 Z; d // complicated schedules.) w E2 E! G; m. y5 W0 w3 m
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modelSchedule = new ScheduleImpl (getZone (), 1);
6 I) ~; ~. ]( H p modelSchedule.at$createAction (0, modelActions);
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return this;7 D% z0 k% U- D0 _
} |