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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
8 Z: y; m; q- c) F. I9 F. D3 n5 L; V& i1 {
public Object buildActions () {
' d( D2 |) b) u8 P8 I    super.buildActions();
8 y2 D, V! z" z. j    ' K, @/ E4 a4 E* r0 E' G5 m
    // Create the list of simulation actions. We put these in- G4 M. i6 K% t+ O* V' J% ~! c
    // an action group, because we want these actions to be
1 O8 I3 V+ g& r& x    // executed in a specific order, but these steps should
: [* B6 W1 D/ X8 m+ t( S$ _) l    // take no (simulated) time. The M(foo) means "The message
' L1 }9 \6 l5 `" \0 e3 w1 ^    // called <foo>". You can send a message To a particular
2 t* U, \3 [* h3 g3 N# S* n    // object, or ForEach object in a collection.
  W# }$ h5 Q0 x( ?/ i5 p! s; E- k        % y7 N5 e% @" I
    // Note we update the heatspace in two phases: first run
0 T0 H" l1 C- R- I9 w5 y7 L2 A    // diffusion, then run "updateWorld" to actually enact the
- Z- @6 Y) N1 |0 ^, I    // changes the heatbugs have made. The ordering here is
3 e& P. e% s, I& e1 }6 P    // significant!4 C! W: j9 S/ E5 E" f6 _6 c
        7 j) ?6 u$ `3 r; `! ~" j
    // Note also, that with the additional2 J+ z( ^' |! h# k9 S
    // `randomizeHeatbugUpdateOrder' Boolean flag we can9 i; f( l  t. _) t7 I' ^
    // randomize the order in which the bugs actually run
; C- I4 I% ^! N* y    // their step rule.  This has the effect of removing any- k/ E  y2 I2 y& s# B
    // systematic bias in the iteration throught the heatbug
0 y# A7 O9 ]( A5 }8 n0 z5 ?    // list from timestep to timestep
' j9 c+ K+ U; R/ f2 P2 e        ) n9 m6 }! o& m( n9 @
    // By default, all `createActionForEach' modelActions have
/ r4 u5 G$ S1 Q; L    // a default order of `Sequential', which means that the
9 c0 l% e6 M! z$ O. e5 \    // order of iteration through the `heatbugList' will be
; p; s3 k8 R8 n) c3 Z. R0 |4 T2 c) i    // identical (assuming the list order is not changed' g# q' j  u5 _
    // indirectly by some other process).
: u7 {2 q/ L% Z2 a5 \# S$ G   
* ~8 @, u, a& B0 l( j) c( b6 n    modelActions = new ActionGroupImpl (getZone ());; x' x# I; M1 o9 A
8 T6 j. ^3 a- i5 F) _0 D0 R7 C$ S% H
    try {
5 O6 c! [4 h  o      modelActions.createActionTo$message
' u. e" F5 [3 T8 P. q/ y. o        (heat, new Selector (heat.getClass (), "stepRule", false));9 G+ e0 l' A4 @+ d/ C
    } catch (Exception e) {4 N, j1 A% }# a7 O7 C
      System.err.println ("Exception stepRule: " + e.getMessage ());
* P6 t; x2 ?# z' V" G    }* l% V8 X; @+ z( p" S& M
% s! M4 s! H% c: t) s0 F
    try {
9 M! D/ J0 p* C2 c! K      Heatbug proto = (Heatbug) heatbugList.get (0);% b" m+ @6 {; H+ X
      Selector sel = # r. ~# n& c; M- I
        new Selector (proto.getClass (), "heatbugStep", false);
* g! z" y9 I3 o6 w& d      actionForEach =
$ k! P1 Q& k) p( C% H        modelActions.createFActionForEachHomogeneous$call
5 l. e9 N" _7 T3 s. ?0 n        (heatbugList,
/ y' `  _5 P% s# d         new FCallImpl (this, proto, sel,
5 e! M4 S& L, I7 j# b                        new FArgumentsImpl (this, sel)));
2 [* |8 p8 y) Z, |  \6 X% H+ U* `    } catch (Exception e) {
# }8 Y: M& `' b  G5 k      e.printStackTrace (System.err);
- e" M- s& K" S: f- y# \    }
+ I8 Q( E. h) e  ~  i2 m" l    0 A& t. ~/ g. a; P. |8 J
    syncUpdateOrder ();
8 B, c/ A0 B' {) ]# a2 o- t0 R
+ p+ {0 n+ E$ ~    try {& r# ]. o* N- w# P& n+ z- g$ D
      modelActions.createActionTo$message / H8 b. d( W! K6 g0 ^
        (heat, new Selector (heat.getClass (), "updateLattice", false));0 ~9 [1 M& O$ c7 r7 g4 J
    } catch (Exception e) {
) ~- G& F1 l' @. }7 _1 \2 l      System.err.println("Exception updateLattice: " + e.getMessage ());
3 X0 Q. A* M6 E0 I( n- V    }
" n2 \- C" F9 `6 A' O, q$ S/ O$ N        ' D0 w2 j8 L  T6 S
    // Then we create a schedule that executes the+ V/ `) h' Z8 z. z% H( R% O
    // modelActions. modelActions is an ActionGroup, by itself it. _3 P6 ]' e3 F- L) b$ R' V
    // has no notion of time. In order to have it executed in
( `3 r  O5 r0 }: S* z# E. l( D    // time, we create a Schedule that says to use the3 s4 P9 ~  v) v$ Z: h$ p; Q
    // modelActions ActionGroup at particular times.  This
3 e+ X' g8 ~# ]) T4 i" s# m: w6 K    // schedule has a repeat interval of 1, it will loop every
( b) s( V7 [8 T    // time step.  The action is executed at time 0 relative to
) E3 E" L' ]- l3 k& T    // the beginning of the loop.
, L1 I! g, e4 c( F& \) V2 B+ @4 a, u, C- B! u& X0 ^. b* {
    // This is a simple schedule, with only one action that is5 v, t$ e  m( h$ l
    // just repeated every time. See jmousetrap for more4 F; ?1 i7 p* \
    // complicated schedules.- h9 Y  Y% m9 ]/ F* K% }" ^' g
  & n5 I. Y. d( J* s; j4 H/ j
    modelSchedule = new ScheduleImpl (getZone (), 1);! Q# [# p/ ]/ o% ~6 a
    modelSchedule.at$createAction (0, modelActions);
* p. E9 @" b: L        7 s: g/ J4 y# a* g6 o4 M
    return this;+ T" k' v5 A1 C3 D4 X
  }
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