HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:1 M$ x% Z3 r: v0 N+ [
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public Object buildActions () {
8 z T% H8 ] B& _+ ^ super.buildActions();& f5 M6 ^2 v; R$ a3 k
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// Create the list of simulation actions. We put these in
& M* I6 }+ [& b4 b3 w2 D // an action group, because we want these actions to be
$ k& ~' y. W( H$ P: p% ` // executed in a specific order, but these steps should6 w1 H1 e" \% e0 f: j7 s4 M
// take no (simulated) time. The M(foo) means "The message$ f( w& q% j- }
// called <foo>". You can send a message To a particular7 x# b( R$ ?5 P$ R( Y( K0 e
// object, or ForEach object in a collection.& G2 @- G: H# C- a% N: Q7 o. Y
* u: D; K" \& @- y) G // Note we update the heatspace in two phases: first run
. Z* I# c6 |, {" M- S( g // diffusion, then run "updateWorld" to actually enact the
& u. z: m4 |1 l d, ~! m // changes the heatbugs have made. The ordering here is# f+ J/ ]1 }2 b( ?
// significant!
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// Note also, that with the additional# l& U6 j. z& E- z6 ~
// `randomizeHeatbugUpdateOrder' Boolean flag we can
7 w* a" k6 A9 _( N: } // randomize the order in which the bugs actually run
! X% p! |8 a9 g // their step rule. This has the effect of removing any
( @9 R3 ]. v) }, d6 B1 x // systematic bias in the iteration throught the heatbug. Y- Q% k4 o! e
// list from timestep to timestep! Z6 O; S1 D& Z, Z. g! O* X6 [ j
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// By default, all `createActionForEach' modelActions have
/ {2 l) E. h, Z b0 A7 b9 u // a default order of `Sequential', which means that the
' D3 a" e4 s( ?4 {& H' M7 |! n // order of iteration through the `heatbugList' will be
( Q6 k( }+ ~- o2 a // identical (assuming the list order is not changed
5 _, f5 _+ l! {( }7 \1 b; C+ r // indirectly by some other process).; i) W# z+ z/ d' _1 N* \9 \/ `8 R
" W) S& G7 r/ p# }7 z# y( o modelActions = new ActionGroupImpl (getZone ());
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modelActions.createActionTo$message
" T" u- E+ i$ e (heat, new Selector (heat.getClass (), "stepRule", false));
0 a3 \ [8 i2 B: G' T/ W } catch (Exception e) {
i" e; {3 h* i) Q* R; X/ ~9 ` _ System.err.println ("Exception stepRule: " + e.getMessage ());4 H* j2 ^) r) Q7 B( a( X; o7 N
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Heatbug proto = (Heatbug) heatbugList.get (0);
" F7 Z5 W, }* q) o Selector sel =
) t$ ~" e Q( u j( y" f1 ~/ ~& R! S new Selector (proto.getClass (), "heatbugStep", false);0 D; [0 k9 E6 o$ W6 b8 F4 u
actionForEach =8 Y+ L; F8 M5 [" N* z9 \' }! N1 k
modelActions.createFActionForEachHomogeneous$call0 W6 z( o; _8 _- w5 r
(heatbugList,/ U9 h$ I: c4 o1 S" V
new FCallImpl (this, proto, sel,5 M- Y' ]6 Q3 ]
new FArgumentsImpl (this, sel)));
' v' r# ]9 j& W% Z" q, X } catch (Exception e) {6 {8 p% @5 h* ~* `9 s
e.printStackTrace (System.err);& R" m: V. `3 d( X ]+ I1 Q
}
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syncUpdateOrder ();7 W, R# ]: [% G. r: Q) ~ J$ C
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try {- x* x, q$ B# o
modelActions.createActionTo$message 9 f ]( G& g, x5 ? U# t9 U# J
(heat, new Selector (heat.getClass (), "updateLattice", false));5 k, J4 N1 I4 u1 U) w
} catch (Exception e) {* D, u/ A: Y6 g* }7 s
System.err.println("Exception updateLattice: " + e.getMessage ());
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6 I4 _9 i E0 ^# L // Then we create a schedule that executes the
. h6 l- ?/ }, _2 i0 T8 d. c // modelActions. modelActions is an ActionGroup, by itself it5 D# k% W/ Y& R9 H* k1 N
// has no notion of time. In order to have it executed in& {- a! T5 M4 g" v5 C! u
// time, we create a Schedule that says to use the
" l0 o" z; Q- I- X4 y; V // modelActions ActionGroup at particular times. This3 [5 \8 d$ h# l U7 c1 a
// schedule has a repeat interval of 1, it will loop every) V9 `7 ? `8 y- C9 d& i
// time step. The action is executed at time 0 relative to
q" s* x( c; \1 x! i. s // the beginning of the loop.4 o$ L2 U! L7 ~( x
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// This is a simple schedule, with only one action that is Q+ b( M0 n8 j, p/ J* f4 B# Z
// just repeated every time. See jmousetrap for more8 ]0 d" B6 W/ E# l
// complicated schedules.- B" x7 h) ~" K P3 U" a3 O7 {
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modelSchedule = new ScheduleImpl (getZone (), 1);
; A7 @; A' N. |: I" A& I X modelSchedule.at$createAction (0, modelActions);
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return this;; w! G# w. Q$ l' G
} |