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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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public Object buildActions () {4 C' i. q# h) d: f6 u
    super.buildActions();
$ |9 @! t1 U7 e+ _5 w3 D    0 F0 o$ O) d$ ~. i( E- m
    // Create the list of simulation actions. We put these in
* l8 |# T+ {5 Y; d( t    // an action group, because we want these actions to be( w& _( f( A7 H4 {
    // executed in a specific order, but these steps should8 v2 ?2 ]! T: Y& K
    // take no (simulated) time. The M(foo) means "The message
+ G) L1 ^6 Q% V# ^4 I* I    // called <foo>". You can send a message To a particular
& ], u4 f/ }/ o, ?    // object, or ForEach object in a collection.% A( e3 }/ r0 g/ X3 e1 B4 W
        9 [  [5 o" ?$ j. P
    // Note we update the heatspace in two phases: first run! O5 y$ B+ t7 @- Q0 i
    // diffusion, then run "updateWorld" to actually enact the
3 C* R! \( r6 x/ A5 @4 v    // changes the heatbugs have made. The ordering here is
, `- d2 j+ g2 k" W+ [- {    // significant!3 f6 I1 |2 h+ N3 L+ }
        
* P6 ]" u; Z' \% k+ a+ i    // Note also, that with the additional
1 y1 b* I: U2 s% O9 v  i8 e    // `randomizeHeatbugUpdateOrder' Boolean flag we can
* j9 c( S6 w. c1 i" n2 V( J    // randomize the order in which the bugs actually run0 v! E/ Z8 H: L4 t# K! x& C9 I
    // their step rule.  This has the effect of removing any
$ A7 z& e# N- L" e, R- k& g    // systematic bias in the iteration throught the heatbug
% Y$ @3 S7 _' k, Y    // list from timestep to timestep7 \0 j# H# Y" d; J2 P2 \8 @8 r
        6 o8 C- N3 H2 b) x7 r" ^. ^# Q3 U
    // By default, all `createActionForEach' modelActions have
4 O1 y% e5 v3 f# p    // a default order of `Sequential', which means that the' S7 |# t  v2 U9 u2 g1 V6 s9 X6 ?2 v
    // order of iteration through the `heatbugList' will be
4 p7 |1 w) p$ B& s    // identical (assuming the list order is not changed! v; _2 k# T0 C) R% J
    // indirectly by some other process).; C: {, S5 d$ G5 a: P
   
1 a' b2 N( m* q: j3 W& s$ c    modelActions = new ActionGroupImpl (getZone ());
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2 l$ Y' d) `6 A6 \, N    try {* M/ m7 h5 r: u- l2 g
      modelActions.createActionTo$message
' {) [! n. p% i1 }/ V9 W        (heat, new Selector (heat.getClass (), "stepRule", false));9 n! M5 ]' @# @4 q/ P( F$ A
    } catch (Exception e) {) U, X/ H4 f, w. W! \! \) R. O) x2 N
      System.err.println ("Exception stepRule: " + e.getMessage ());" c' q3 u: x% {' l
    }: u, c6 a/ Z/ I) ]

3 d1 {, e" R  J    try {
; y, q3 U  A" @$ e1 \      Heatbug proto = (Heatbug) heatbugList.get (0);9 H( k5 b+ X6 o7 D
      Selector sel =
+ ~* F/ |% a5 J' h* N2 [        new Selector (proto.getClass (), "heatbugStep", false);
$ j" _. O/ p! g. [9 d! H- ~% Q      actionForEach =
: @% z( u7 K3 X5 j0 U        modelActions.createFActionForEachHomogeneous$call
9 ~5 r$ n" N  i9 e  o7 ^& Q        (heatbugList,
! C$ G% Q; w; y1 O4 L  F$ f         new FCallImpl (this, proto, sel,% a4 l- F/ U  z$ R! q9 ?& d
                        new FArgumentsImpl (this, sel)));
; S& R) O1 a' F% `# d* Y( R  ~    } catch (Exception e) {6 H/ n8 \7 D- K' d- O
      e.printStackTrace (System.err);
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    ( _6 @4 O2 }* ^4 {; N6 g
    syncUpdateOrder ();$ a: e7 c0 {' Q8 _, D& m! |
9 r* _" \, M4 T, `; b% ~  x; Q
    try {7 x# `' u2 n3 n' M
      modelActions.createActionTo$message , Y5 W8 c+ `2 j$ j  F2 T* O* h
        (heat, new Selector (heat.getClass (), "updateLattice", false));( a" Z; |. o; ~4 M; y' ~* d
    } catch (Exception e) {7 O. E' a" ~4 d; h: y
      System.err.println("Exception updateLattice: " + e.getMessage ());- s& E8 {+ P0 H6 k! R8 l# F
    }2 K( m) ]' s  F) M$ `0 y9 A" @
        
, Y0 r6 Y% Q3 F; H3 O% c& c4 B    // Then we create a schedule that executes the
9 E# O$ N3 }9 }4 u    // modelActions. modelActions is an ActionGroup, by itself it
- \1 X# M# a) @7 @' c    // has no notion of time. In order to have it executed in
- U, x  t7 B* B$ s    // time, we create a Schedule that says to use the% d+ `& a! R9 q& b+ E% a
    // modelActions ActionGroup at particular times.  This
1 u8 ?% F6 H6 N& A" \# L: k    // schedule has a repeat interval of 1, it will loop every
) E  @# v7 X3 \' J+ N    // time step.  The action is executed at time 0 relative to
: s: V5 y5 x- Q3 G. Q$ o0 S, k4 ~    // the beginning of the loop./ C9 p3 a' V  r: W, B* [+ G9 p; L$ N
1 t9 ~# O, k) c6 i5 e  O
    // This is a simple schedule, with only one action that is
! A5 U- n3 q  B4 R* i; I5 T% w    // just repeated every time. See jmousetrap for more
9 c. x  Q0 ]5 A  Y8 d0 M    // complicated schedules.9 W* z& F0 h+ Z" j( Q
  
% Q: `( F# E# M4 r8 J4 ?4 W$ a- _    modelSchedule = new ScheduleImpl (getZone (), 1);
6 c/ O' U# C# S$ Q8 ~7 P% i    modelSchedule.at$createAction (0, modelActions);
# l& p( F; |+ m# W; \7 O) f        
- O- O5 B* t9 e% B2 k" d4 |    return this;
6 H  X6 R% j& d2 M* n% _  }
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