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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:' E9 d% \; I3 }9 u6 g  W

. L9 E) V: G1 z5 b# I. V( q public Object buildActions () {
! B( k- j, V1 F; v0 I) i    super.buildActions();4 c! z# p: a3 m5 ~5 ~) n2 K6 ], w3 |' j
   
& l8 l, ^7 a. V7 K$ M- X    // Create the list of simulation actions. We put these in
! p6 l' I% w2 B+ f  y& m% D    // an action group, because we want these actions to be7 n' E/ p- c/ K- D
    // executed in a specific order, but these steps should; Z- F' g/ m; \$ D+ @
    // take no (simulated) time. The M(foo) means "The message
/ _: i% r/ v! V5 J2 e% V5 d    // called <foo>". You can send a message To a particular
, A  n. _, H& @6 R! t    // object, or ForEach object in a collection.' @! m- }7 D8 u0 b9 x1 b
        
9 S8 Q# D1 O7 A) Y7 e+ I( q    // Note we update the heatspace in two phases: first run
# @+ Y; Z* |1 H/ O    // diffusion, then run "updateWorld" to actually enact the
2 R: v" E. g* M; f6 C    // changes the heatbugs have made. The ordering here is& i% [8 L8 ?0 z/ w' B
    // significant!
: J9 @2 Z# u0 L) M' F        : O( v7 a: r  d! m0 [7 X' c8 \
    // Note also, that with the additional
9 s8 X; n% `0 O    // `randomizeHeatbugUpdateOrder' Boolean flag we can
+ g$ a2 _; A; {  N    // randomize the order in which the bugs actually run9 x5 H9 R& Y4 D  ?( W
    // their step rule.  This has the effect of removing any
2 j8 y& d1 V4 C1 [+ M2 h7 ~# v    // systematic bias in the iteration throught the heatbug
7 T+ w# r% @& L$ D; a7 R1 Q    // list from timestep to timestep
% {1 ~1 M9 o; d. H; {  }; N+ q        
2 U: q5 ~$ v" ^4 K5 b8 w6 x. P# ?    // By default, all `createActionForEach' modelActions have% ~1 ^- |/ H/ I  S- l
    // a default order of `Sequential', which means that the; c: i# G# N( f5 U+ w! w
    // order of iteration through the `heatbugList' will be
: C* F: I8 o1 [4 @8 [    // identical (assuming the list order is not changed
# C, M( Q+ S. s+ b$ {9 f    // indirectly by some other process).
( \! _6 w' R+ c) {   
- ~6 p. Z3 Y1 {2 a. z. ~/ h- G    modelActions = new ActionGroupImpl (getZone ());
7 t: e- r6 N9 s& v# V
! S$ d" K9 U  w) `    try {. K/ ]% j# n6 L0 J3 v: L
      modelActions.createActionTo$message# w! I! h! t, r4 u4 v) B9 k
        (heat, new Selector (heat.getClass (), "stepRule", false));
, i7 }+ t& ]+ c; t8 m$ K    } catch (Exception e) {
- ^8 U; q* G/ a      System.err.println ("Exception stepRule: " + e.getMessage ());' B5 d" S2 Q6 V: `- I
    }4 ]% _. Q, b; b' K. U
/ `  v! a0 V4 _! \5 y* [
    try {: o6 Y: g; z! a! X
      Heatbug proto = (Heatbug) heatbugList.get (0);
& W$ V: I8 G, e) B. o5 Y      Selector sel =
3 s& A7 h3 @! V, X% Z* q        new Selector (proto.getClass (), "heatbugStep", false);
1 W& N1 A, [" K' [8 z' L( ^$ E      actionForEach =
# Y: J- x. j* {7 J4 B2 g        modelActions.createFActionForEachHomogeneous$call" M8 P* A& @/ _' _
        (heatbugList,
1 A' Y0 S: A9 g5 X         new FCallImpl (this, proto, sel,9 @. z" z6 A" q( g. c- P
                        new FArgumentsImpl (this, sel)));$ j3 ?+ r# b2 I2 u3 J9 R. J
    } catch (Exception e) {
0 Y; i( i4 q$ D# b: Y1 X      e.printStackTrace (System.err);7 D( x! o; O; h" K  P2 a/ k
    }5 Y  G$ Z# Y0 f9 J# J% v: D
    # p3 I) d: f. v' \, h2 F" I0 Y! |5 O
    syncUpdateOrder ();
) h: l% Z1 {2 I) @. m+ }8 |6 S1 N) G$ d2 n2 j- U
    try {
, e3 `, p6 m' C5 m      modelActions.createActionTo$message
9 v" T  i2 Z, r3 c        (heat, new Selector (heat.getClass (), "updateLattice", false));8 z% ?5 r; q" f/ y$ c
    } catch (Exception e) {8 \/ ]  x/ h4 [; H. l1 V% e
      System.err.println("Exception updateLattice: " + e.getMessage ());: k) ^( ^  o- v5 P+ u
    }
6 |3 s7 ]6 h% R+ J# \        8 L3 {' H$ {6 W5 W. Y
    // Then we create a schedule that executes the
$ a* A+ L" R  k- v' X8 c0 U. s    // modelActions. modelActions is an ActionGroup, by itself it. T+ A% R! c& b! D! f9 P
    // has no notion of time. In order to have it executed in6 c  n% P( V0 r& Y8 @3 O6 ?- o1 ]1 j
    // time, we create a Schedule that says to use the$ R6 X$ I; ?' F, \! Y8 ~
    // modelActions ActionGroup at particular times.  This5 J$ p' `; r* ^' E* U' u" B0 {
    // schedule has a repeat interval of 1, it will loop every5 r( B8 a+ B+ I! o+ B% p8 c
    // time step.  The action is executed at time 0 relative to
4 Y/ D6 X& J' @9 ]8 G, x" t2 C    // the beginning of the loop.
' G- B' g% {2 O) r9 {* I. F/ H) E. J9 Z, k
    // This is a simple schedule, with only one action that is- |5 C* X0 \! e/ c: q
    // just repeated every time. See jmousetrap for more
2 [! ]: b# P3 j) v+ f; U    // complicated schedules.
; ^3 J: a: f, K  
9 O. F) b# p- m9 j5 J    modelSchedule = new ScheduleImpl (getZone (), 1);
- e; X( N- L9 q1 x  }4 C- g+ Y$ k    modelSchedule.at$createAction (0, modelActions);  f- v2 L0 f/ C4 @, {; A- r0 D7 ~
        
! P0 n, K9 Z. N: D  T$ B3 C    return this;
" ~0 a2 J* x/ {, _0 _. E  e" T6 s  }
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