HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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public Object buildActions () {) z3 Z' B' g8 d1 t9 d _
super.buildActions();5 v2 U# _6 k6 B0 `6 z q
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// Create the list of simulation actions. We put these in
# f2 D# M% v" v/ }6 o // an action group, because we want these actions to be
: J- q- `- v' X. e. n- e- C6 d // executed in a specific order, but these steps should, P# q1 {! g, \, M6 y" w
// take no (simulated) time. The M(foo) means "The message* v. s+ R k9 N! n% A
// called <foo>". You can send a message To a particular+ C* O1 C I# M8 F) G
// object, or ForEach object in a collection.' b6 m$ r! G- g: v
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// Note we update the heatspace in two phases: first run/ y- ]& k) p. Q' V
// diffusion, then run "updateWorld" to actually enact the1 L3 @- y0 D3 E
// changes the heatbugs have made. The ordering here is
/ k& w0 D; ]5 w* b' G& K // significant!& R- B( M: y0 t
0 g2 K1 `. N" f/ u // Note also, that with the additional
+ Q+ z* P# Q& x& i6 }- n // `randomizeHeatbugUpdateOrder' Boolean flag we can" t- t2 m3 w Z& }! q5 S. p2 N
// randomize the order in which the bugs actually run
+ m9 x6 W4 V( i# I2 G // their step rule. This has the effect of removing any
% H4 _0 {/ U! @6 k3 `6 n // systematic bias in the iteration throught the heatbug; [) G4 ?! }* d: {
// list from timestep to timestep
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: o% T+ [) @4 D // By default, all `createActionForEach' modelActions have
8 p/ Y3 p2 t! _7 i7 E5 H6 Z0 j* W // a default order of `Sequential', which means that the
$ s6 O& l5 V9 C0 f( w // order of iteration through the `heatbugList' will be) a: z% l' W, i4 e7 O
// identical (assuming the list order is not changed
~5 f! D6 T( D: @7 l! K3 u( }# v, O // indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ());$ B! r1 ]- x L# P ^8 o
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try {
; [$ M: S5 H: A% g# H. s0 [$ |' |7 [ modelActions.createActionTo$message
) q& i3 K' o: ^( E (heat, new Selector (heat.getClass (), "stepRule", false));
% f7 Z5 F" V- ~+ b) h9 e) q } catch (Exception e) {
' r, S, S5 G3 I5 W, n$ ] System.err.println ("Exception stepRule: " + e.getMessage ());) e- P2 c# k. z |0 G8 F m
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try {
! O+ V2 [ ]: @9 Q Heatbug proto = (Heatbug) heatbugList.get (0);
; ?% k% K; ^* Z7 H Selector sel =
8 T \$ z* g- B a" y new Selector (proto.getClass (), "heatbugStep", false);
' ~4 U) M0 E2 m0 k" `) ~ _$ y actionForEach =
! M3 i0 v0 z- B6 S G u" I% j modelActions.createFActionForEachHomogeneous$call
" |# j6 W- s# m1 j% z" u (heatbugList,
, N6 j" a, i: J new FCallImpl (this, proto, sel,
9 u7 }3 ?0 K; M5 m+ S2 g, ~ new FArgumentsImpl (this, sel)));$ S! u, i0 m1 `% f- u
} catch (Exception e) {
. |/ O/ l: |& o x6 S0 e e.printStackTrace (System.err);+ b5 H W0 X4 z0 n, V
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syncUpdateOrder ();
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modelActions.createActionTo$message
+ N2 _- _% h2 |1 J5 D2 W (heat, new Selector (heat.getClass (), "updateLattice", false));
q' V$ M6 |3 z9 c6 T } catch (Exception e) {7 w7 l% \2 Q: F- z6 o7 b/ r! I- B
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the; h# e% T! S) p' v3 x1 W
// modelActions. modelActions is an ActionGroup, by itself it
/ j* \* P" T1 I$ D0 l // has no notion of time. In order to have it executed in3 ~4 g: M- i/ F. @% Q- i0 v
// time, we create a Schedule that says to use the* t" |" V4 j! ?6 K, C6 {3 s. x( K
// modelActions ActionGroup at particular times. This4 A% o5 n' k9 y: ]# Z
// schedule has a repeat interval of 1, it will loop every4 F6 p- f7 F- Y4 k6 P; G
// time step. The action is executed at time 0 relative to0 W ]6 ~+ m; z. k2 v4 ]
// the beginning of the loop.
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// This is a simple schedule, with only one action that is8 h3 N) `9 o5 `, t2 Z7 }
// just repeated every time. See jmousetrap for more: H! g6 K( S7 w: N! C
// complicated schedules.
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% I; V: y5 R( I( Z modelSchedule = new ScheduleImpl (getZone (), 1);1 s; j" H5 ]# Q
modelSchedule.at$createAction (0, modelActions);& d4 S, @+ D: H
2 E& R* z R: q3 n( C" V return this;
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