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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
, v6 N/ R& t* |: T5 e9 S6 b
9 a/ W/ P' \& T public Object buildActions () {8 z  F* |0 b1 W; m- b
    super.buildActions();: q- c9 Q9 y4 U
    4 K* @4 n; t- T: _- @9 }( J
    // Create the list of simulation actions. We put these in# I, ~* E$ o6 f* r5 \) @. g
    // an action group, because we want these actions to be
5 g! n% h2 @% i. c3 F4 |2 w6 i$ L    // executed in a specific order, but these steps should
% p5 H: y- z+ C  q    // take no (simulated) time. The M(foo) means "The message0 k. v, o. k$ v/ r7 ^- Y
    // called <foo>". You can send a message To a particular7 b/ |3 {2 e2 E
    // object, or ForEach object in a collection.. O* o" `, m! v  Z
        
7 k, X+ D1 v/ S    // Note we update the heatspace in two phases: first run
6 P8 r# U, @% o    // diffusion, then run "updateWorld" to actually enact the
5 u  W$ a/ X& G. j    // changes the heatbugs have made. The ordering here is
7 d' k  c7 G  v9 o7 P) [+ ^    // significant!
# f8 e% T) Q+ Z1 E, Z        : x4 F$ \* G, ]# q( k/ [9 a  N
    // Note also, that with the additional
) q3 j6 i  a( @+ f  Z" O1 ?3 F$ [7 I    // `randomizeHeatbugUpdateOrder' Boolean flag we can
2 R- Q- w& Q0 b" b  K# f    // randomize the order in which the bugs actually run
( ?5 n: T# {- k8 U$ [! O" I* e( r    // their step rule.  This has the effect of removing any
# D7 ]9 z4 P- u' E    // systematic bias in the iteration throught the heatbug
. E* I) }/ s$ J+ w& _' D. Z+ w# i7 }    // list from timestep to timestep1 x0 W. p( z" X) U# c% N: k& W4 b
        & J# ^! W4 V% f( K
    // By default, all `createActionForEach' modelActions have! e2 ~' i$ u  r8 u4 f
    // a default order of `Sequential', which means that the  J! {9 u. r% p" R" ^) @
    // order of iteration through the `heatbugList' will be
3 c6 P& p2 Y* {- D0 j) B& L$ K    // identical (assuming the list order is not changed
8 {' w3 e$ {1 [" l/ x- x0 B. p    // indirectly by some other process).
4 K6 A. a1 ]2 R! h0 J( p9 f    . x8 m% o9 Q5 o$ h! x
    modelActions = new ActionGroupImpl (getZone ());
: n% d: i  M- W! a1 x" h# q7 h0 }7 ]9 {
    try {+ k4 ?6 X8 }# b$ `
      modelActions.createActionTo$message
$ @* ?$ c# E, R- l9 U; i* R! h        (heat, new Selector (heat.getClass (), "stepRule", false));* j6 r  \. m8 Q; I4 W& K. Y
    } catch (Exception e) {
8 i: `8 b  F% A      System.err.println ("Exception stepRule: " + e.getMessage ());6 j" X1 d  p/ ^: ~
    }
* ^0 L1 [$ K* b% C' V+ c$ P
$ J" J; H0 i4 f, ]$ Y# S& f    try {
6 J' t% o% @" w5 N- j1 y, ~3 i% J      Heatbug proto = (Heatbug) heatbugList.get (0);. {- @6 `' _, \8 W8 b* s
      Selector sel = . X  N- G- K: ~9 a4 G
        new Selector (proto.getClass (), "heatbugStep", false);: Q9 R: Q$ ]# ~5 S. U- s
      actionForEach =
9 w, L9 p: b" n; z8 ?; W) y        modelActions.createFActionForEachHomogeneous$call% ^: c: Q5 y$ P+ u8 M
        (heatbugList,
3 r* ]% n5 \% f$ C8 W- G         new FCallImpl (this, proto, sel,' p! B, o. T. S( c" O
                        new FArgumentsImpl (this, sel)));
2 n! Q5 H/ T; E    } catch (Exception e) {
+ n2 X, Q7 p6 l8 V+ _, z& e      e.printStackTrace (System.err);+ D9 m% R! K4 l4 V6 _& X4 i! ~
    }! C9 r7 h7 J7 L
   
# h5 `  }$ a2 {; L$ R    syncUpdateOrder ();$ g9 _' R7 j* e) P( W- c
: V7 G( [/ m+ ^
    try {
7 ?" x3 |( n4 B( K      modelActions.createActionTo$message
' S7 D: q( l8 @+ D        (heat, new Selector (heat.getClass (), "updateLattice", false));
( B, m9 E0 ^0 c6 X' R( y    } catch (Exception e) {. U/ j& [9 \% k3 E* G! ^2 x
      System.err.println("Exception updateLattice: " + e.getMessage ());
( d% N4 S( L3 Y9 b2 |3 `    }
1 W7 E" [  |: U& n* C        
0 a. [, n/ a$ e/ i0 a: W' ~    // Then we create a schedule that executes the
* }% U: p# ]# P0 Q( \9 L    // modelActions. modelActions is an ActionGroup, by itself it
, [3 s. R" O- W. M; N$ k    // has no notion of time. In order to have it executed in
5 x& e, @) [/ C5 K% y( e# O    // time, we create a Schedule that says to use the/ N  V7 c# r: t3 K0 G
    // modelActions ActionGroup at particular times.  This
  y6 R8 w+ n- a  j8 a( ]    // schedule has a repeat interval of 1, it will loop every. j5 o7 B  v( A. G
    // time step.  The action is executed at time 0 relative to
. L6 u9 G, [: R: I$ r    // the beginning of the loop.
. X( B: S" b0 q) l
  R3 R8 ~; b) F$ o5 g5 L5 B! f& {; }    // This is a simple schedule, with only one action that is7 g- t2 m$ i1 ^0 p# S
    // just repeated every time. See jmousetrap for more1 @' \5 r$ i# H3 d8 D3 W9 v- M* w
    // complicated schedules." E3 Q" d: N; i- q$ a
  ; E# k1 Q7 L) ]/ K2 z
    modelSchedule = new ScheduleImpl (getZone (), 1);
2 s0 E# i+ j% t0 u4 W$ z( X    modelSchedule.at$createAction (0, modelActions);- v; ~) k8 Q! C, q
        7 x. d* j$ f. _  y. a1 b. U5 l  X% K" f
    return this;% @1 [8 j; Y/ o- E5 p$ \$ ]5 X- J
  }
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