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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:8 x6 n- K3 i8 K' d& e
! ^8 r1 @5 I8 S# ?  G0 o  S% }
public Object buildActions () {
8 e! j$ s7 _& b( v  o! Z* Y    super.buildActions();
, L: R4 \$ ?- E3 ]3 H: K. u+ Z4 h   
- A4 c2 n1 H, B    // Create the list of simulation actions. We put these in) N2 v+ R( g/ Y9 l1 ~7 n
    // an action group, because we want these actions to be4 F6 [1 f( J/ `9 h% m" X
    // executed in a specific order, but these steps should8 o% s7 q9 ~  Q
    // take no (simulated) time. The M(foo) means "The message& k) d0 |4 w0 Y& I5 K, }/ c7 B! y
    // called <foo>". You can send a message To a particular
" i9 Z; Y' q  r! `2 W! H    // object, or ForEach object in a collection.) c0 X( C' F) }* a
        $ D3 `5 w+ K& ~6 @3 T
    // Note we update the heatspace in two phases: first run
3 o- {* B8 j0 o' P    // diffusion, then run "updateWorld" to actually enact the# j7 H. h, ^1 g% N7 L  @) W
    // changes the heatbugs have made. The ordering here is
* T) M9 Z' x3 R+ j2 m% {2 a3 e    // significant!9 b$ A0 O0 E! l: K* n% _+ \; X' A
        1 n& Z, Z! U2 }
    // Note also, that with the additional4 h1 Z0 l% r. R4 {% f$ I
    // `randomizeHeatbugUpdateOrder' Boolean flag we can+ T& A8 m, R, B3 A; Z: ~
    // randomize the order in which the bugs actually run- R: C5 q; M9 k, t& B8 e8 H
    // their step rule.  This has the effect of removing any- d$ I  c% H3 r  V7 P3 j
    // systematic bias in the iteration throught the heatbug. \5 |) S1 u# x& e; `
    // list from timestep to timestep- q2 H2 b) P2 ^$ P
        : B, s# n  U. _2 Q* L* l& `( _) k3 [
    // By default, all `createActionForEach' modelActions have
$ h0 D( X9 S* O    // a default order of `Sequential', which means that the
) m2 B3 s% [) M    // order of iteration through the `heatbugList' will be& ?9 m; _& F% C+ t
    // identical (assuming the list order is not changed) {' _+ {" q9 q# Y
    // indirectly by some other process).
! X5 E1 U- L* u5 m+ V    2 S1 t9 ^. U' t2 E8 ]. {) E
    modelActions = new ActionGroupImpl (getZone ());$ o- t1 g% g% `  R' r# F$ }+ {" X

/ [, g6 y8 o0 ]; a* }+ S    try {5 e7 S- o1 y; e$ u
      modelActions.createActionTo$message  K1 q9 x0 Y: d1 U3 E
        (heat, new Selector (heat.getClass (), "stepRule", false));+ G6 p1 a) H- A4 y8 [% {
    } catch (Exception e) {
3 j% x$ A& p' `: p' ]$ O( ^. e      System.err.println ("Exception stepRule: " + e.getMessage ());* e) Q. [" f4 y
    }
4 K8 N8 \' ?8 f) \0 {. w# A* m
# I, s4 h5 [$ h/ p/ Y" I    try {& ^* h3 C0 p, A- i2 ?# y
      Heatbug proto = (Heatbug) heatbugList.get (0);
  R2 ?! \* j  w+ O$ N      Selector sel = % G  ?* |1 o0 O
        new Selector (proto.getClass (), "heatbugStep", false);
% V& U1 u" `( y* q3 B# c      actionForEach =
6 U2 i3 E& v3 W% D        modelActions.createFActionForEachHomogeneous$call
/ g. O7 N9 j5 M2 N$ P: C9 ]8 n) @        (heatbugList,
9 p6 k  z7 ]8 R+ R1 j. e         new FCallImpl (this, proto, sel,2 J! Q8 O0 ~: s* l" T
                        new FArgumentsImpl (this, sel)));
5 c5 D: `$ H' g7 F) L1 K, l; X* Q    } catch (Exception e) {% Z9 p( F5 S% v! H2 H
      e.printStackTrace (System.err);  X$ ~! }# p/ p
    }/ t% ]8 g( O0 |$ S5 M
   
7 L2 @' d; z5 r4 G    syncUpdateOrder ();
, P4 s( b! P4 D( L, X. X
1 x0 u, G; v+ F+ T4 c" [7 k, L    try {, R7 s8 A: ^; i. P% c
      modelActions.createActionTo$message 6 C4 b9 \( @# {+ t8 N
        (heat, new Selector (heat.getClass (), "updateLattice", false));
( `; a( W6 j4 T8 z5 S% _4 c' M    } catch (Exception e) {7 ~4 ?; U4 f4 @* y
      System.err.println("Exception updateLattice: " + e.getMessage ());
7 X; ]4 U# x6 S9 \5 U    }
3 T1 W+ K, W2 W* s- P) O* H$ I        % |, n3 a: ]5 d6 |% S
    // Then we create a schedule that executes the
7 g3 @) F( U8 F3 h! N    // modelActions. modelActions is an ActionGroup, by itself it  Z" j7 t2 L+ |' G3 c" ^" F. z
    // has no notion of time. In order to have it executed in8 d7 U% b1 `- R
    // time, we create a Schedule that says to use the
9 ?. ^4 i" v8 q& r1 ]    // modelActions ActionGroup at particular times.  This8 L/ l# t3 \9 x8 T
    // schedule has a repeat interval of 1, it will loop every
( l1 W) }, N  y6 w    // time step.  The action is executed at time 0 relative to1 M# c# m) n6 l& F- O( s7 m
    // the beginning of the loop., L+ c7 b/ X% F) w

/ s, e! L/ H5 `    // This is a simple schedule, with only one action that is7 T, j4 w8 K3 Y$ y! J
    // just repeated every time. See jmousetrap for more
, {0 q% d9 z9 ?$ x6 J" q: l    // complicated schedules.
/ _7 u% l( d, {  [. o2 ]1 L  
( x5 h+ P+ X1 ^) U* n: ^    modelSchedule = new ScheduleImpl (getZone (), 1);
, }1 B0 X; c% n  P1 g    modelSchedule.at$createAction (0, modelActions);9 d/ f! C6 F/ N2 `/ _/ D8 W
        
* s: |  [" D6 F% a2 C! G" s+ y. n    return this;
. V& d/ O/ T7 A, ~2 }8 I  }
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