HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:0 }& f# h* K! T! ~/ z
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public Object buildActions () {3 O0 }8 |( D3 d1 m. s* L9 G
super.buildActions();1 u7 ^. i O9 S! X
) @, P& R4 o6 {' j o8 P // Create the list of simulation actions. We put these in$ n0 k7 E6 m# f ^$ s6 h
// an action group, because we want these actions to be
, `7 O" D& M' c3 _! v // executed in a specific order, but these steps should
* ]) K& @3 d" b% S! R: z4 R. u // take no (simulated) time. The M(foo) means "The message1 e$ ^! g8 J R/ f2 D
// called <foo>". You can send a message To a particular- n* s' `' M$ }7 y
// object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run* m3 k2 q8 D, [/ }. i5 l) R
// diffusion, then run "updateWorld" to actually enact the
! r- i! b- g% J* h5 ^5 E1 ~ Z // changes the heatbugs have made. The ordering here is- q0 G" }5 s$ A' R+ \) H+ H
// significant!1 O6 i S6 r- H- U# F# b6 Z
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// Note also, that with the additional& r' J5 g: P( V( r
// `randomizeHeatbugUpdateOrder' Boolean flag we can
- f' p! U2 ]" H8 M+ `/ p# t4 v // randomize the order in which the bugs actually run
9 Q7 t6 ]2 |% x! N // their step rule. This has the effect of removing any7 x6 w2 v0 t" O, v
// systematic bias in the iteration throught the heatbug
+ j3 M g3 Z: `; D // list from timestep to timestep% Q* g6 M& o& v- g0 ]! Y
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// By default, all `createActionForEach' modelActions have, y' U6 d8 Q( }
// a default order of `Sequential', which means that the
, ^9 V; ]: m2 e* K // order of iteration through the `heatbugList' will be: i, l2 q/ d/ d* N; F% j
// identical (assuming the list order is not changed2 n4 C# B- T$ l" y
// indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ()); P5 T& l6 y) U# S8 v
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try {% P5 j* L' Y4 ^4 Y" |
modelActions.createActionTo$message1 Q9 c8 W+ E, e: C5 P% \8 z' n
(heat, new Selector (heat.getClass (), "stepRule", false));
% N8 T6 C& ~2 z/ _* n4 ]1 a } catch (Exception e) {
5 F& k r# z$ @" q9 W4 Y System.err.println ("Exception stepRule: " + e.getMessage ());
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Heatbug proto = (Heatbug) heatbugList.get (0);! _) j9 W; c9 k/ I5 G
Selector sel =
+ z- _+ Z3 B7 x% S3 G9 h new Selector (proto.getClass (), "heatbugStep", false);
+ e W8 i0 S5 [ actionForEach =/ w: f2 m- M6 u9 d
modelActions.createFActionForEachHomogeneous$call x# {+ o# b2 Q0 T# r
(heatbugList,
; O8 K8 ]; ~+ q4 P' n new FCallImpl (this, proto, sel," X6 a& f6 | _- [: A. t
new FArgumentsImpl (this, sel)));
% g: `4 h" w }: G. K } catch (Exception e) {
2 ]1 Z1 h" s. ^! `5 u! b e.printStackTrace (System.err);0 X( t8 l: j2 P% D0 C7 o u% U
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$ v; p% r- |3 y }, E F syncUpdateOrder ();
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try {
L! n7 c% v3 b. @; \" ^ modelActions.createActionTo$message + k! i; ^5 }% I' z1 @/ k: m
(heat, new Selector (heat.getClass (), "updateLattice", false));- R, n- e6 a9 e3 W0 ~
} catch (Exception e) {
7 ?8 h/ R1 P8 M System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the
3 h1 b# s/ _6 p+ C- E$ W1 x // modelActions. modelActions is an ActionGroup, by itself it8 A: R0 `* R# A+ M; D9 h
// has no notion of time. In order to have it executed in
/ }0 N. {" N2 @' f5 v, W7 B1 L // time, we create a Schedule that says to use the3 F% T# [8 n$ J' d X) f
// modelActions ActionGroup at particular times. This
5 u: C! u* l- |7 b$ ?) E% e // schedule has a repeat interval of 1, it will loop every S. W$ C' [( N" B: F% G$ j/ t
// time step. The action is executed at time 0 relative to1 L: e$ @5 a6 m0 G/ [" g i- n
// the beginning of the loop.
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// This is a simple schedule, with only one action that is6 i4 A5 B* U( i- U! ]8 k9 m
// just repeated every time. See jmousetrap for more0 C% [! L- }" F2 n v
// complicated schedules.
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" L) z) S& i b0 K- A7 V- e0 W& Z modelSchedule = new ScheduleImpl (getZone (), 1);; J) B/ `, _1 r- e
modelSchedule.at$createAction (0, modelActions); l# n a! C3 B
, U- h0 l+ U3 H0 @ return this;" p1 B% A2 f! X) P& x; E3 M
} |