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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
5 }! w! L5 n! A! K
; @# h& P8 ~3 U5 W( R public Object buildActions () {9 X1 {2 ]5 E# i; `2 {
    super.buildActions();( f0 A5 o- V4 i. |/ D3 ]
   
; e! ~1 E. O, h) p    // Create the list of simulation actions. We put these in, K6 ?/ t; W6 t5 A
    // an action group, because we want these actions to be
& F- R  [- G- g+ ]7 O' _    // executed in a specific order, but these steps should7 S; x+ z& T) O9 W
    // take no (simulated) time. The M(foo) means "The message
7 n! y6 g( k: E- m; a& w( ]    // called <foo>". You can send a message To a particular
. o: p) q- j7 J' Y* L4 f    // object, or ForEach object in a collection.! I- i9 n  U5 h, Y+ Z/ ?& Y
        
8 u" p5 v" j9 L$ @' n    // Note we update the heatspace in two phases: first run8 }+ k, p. A5 n) C2 Q* c6 m; p
    // diffusion, then run "updateWorld" to actually enact the
0 }+ K4 R/ i- ]6 r4 j3 Y    // changes the heatbugs have made. The ordering here is( C& l  m4 u- D' X2 q4 D/ w
    // significant!
% c0 r. X7 y' [0 h& f( P( ~4 A9 n- e        
4 p. e1 F  ]. V, _    // Note also, that with the additional; `7 g( O  o* r
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
# q+ @& N( U0 k% C    // randomize the order in which the bugs actually run: S1 e" n4 G& R6 x1 A- r, ?0 a( Z
    // their step rule.  This has the effect of removing any
- `+ X7 @6 f% F- N6 Q( M    // systematic bias in the iteration throught the heatbug: H3 h% o$ p! {- ^& z8 E
    // list from timestep to timestep
8 g9 i8 e& s( t4 u9 _4 c6 S( |        
- L0 }6 t; b! D  S1 Y! ?    // By default, all `createActionForEach' modelActions have
  h; a9 s9 C$ M5 \  I; h6 V8 D    // a default order of `Sequential', which means that the
# e' |+ z7 V5 V6 v    // order of iteration through the `heatbugList' will be
1 s  l7 p- H2 A9 o    // identical (assuming the list order is not changed
0 f7 `) c7 o$ o. N& y    // indirectly by some other process).
4 {5 u) k1 Z5 T! A, o    1 T+ j1 V' I/ `! K
    modelActions = new ActionGroupImpl (getZone ());
4 |9 r: r. H  h* R0 r' y
  M- p+ K: h4 D4 P/ T2 h    try {1 O2 }0 u1 n' v8 W" ^8 e/ o
      modelActions.createActionTo$message, W9 E4 i/ L3 r5 F* r5 d
        (heat, new Selector (heat.getClass (), "stepRule", false));2 b- g/ t' W' ~6 v+ A0 i
    } catch (Exception e) {
1 y8 l! ~% h/ k, v0 y      System.err.println ("Exception stepRule: " + e.getMessage ());
4 h" {5 A7 q0 ]; z0 P+ e( `/ n    }: H+ G: H, ^: ]. z2 W  i  H

; {& X/ s9 l+ T7 j* {    try {
) |7 p% S. k6 A; V4 Z      Heatbug proto = (Heatbug) heatbugList.get (0);8 {1 ?$ W) x/ R
      Selector sel =
& F! F; _; F* ?$ v2 k' a/ f$ f        new Selector (proto.getClass (), "heatbugStep", false);1 C& U- `% \7 a* I$ F: O
      actionForEach =8 X6 q. y4 r/ U# R. [8 H
        modelActions.createFActionForEachHomogeneous$call& [0 V+ t: u( x7 t  b
        (heatbugList,
. M9 k! f# K( m4 a6 y' j         new FCallImpl (this, proto, sel," }9 m% _0 Z- O% }' _" J
                        new FArgumentsImpl (this, sel)));
: K, A, J! }) q1 H    } catch (Exception e) {
7 ~* M6 P( B4 z$ v0 d( j! b9 C      e.printStackTrace (System.err);/ Z3 j; c) |; q
    }5 P) \6 q1 Y0 X7 i6 v5 S8 J; f
   
7 Y/ O) \" K. a# @/ z2 v    syncUpdateOrder ();
" K9 I$ `5 h( c
5 x- Z6 u3 ]' ]1 e: t& \" L3 G; \    try {
, A7 t+ k& i) V8 K      modelActions.createActionTo$message ! t$ z; V8 Z/ _/ {1 x, ~
        (heat, new Selector (heat.getClass (), "updateLattice", false));& n0 }; M+ B$ n# {+ ?& A
    } catch (Exception e) {6 m0 S* \9 H' [/ s" Z9 E" n
      System.err.println("Exception updateLattice: " + e.getMessage ());
. {% [, V- A" U2 Z  F    }
; z$ i; n* m- Q' d$ f( a1 ^# h        - H) A# P9 u4 W9 k
    // Then we create a schedule that executes the) w, T: _9 B0 Y( a$ _' O# v2 d
    // modelActions. modelActions is an ActionGroup, by itself it
+ h# G4 H8 q3 w& w    // has no notion of time. In order to have it executed in
1 D* N) U. d3 U6 g    // time, we create a Schedule that says to use the
6 j* ~& c2 Z$ J2 q    // modelActions ActionGroup at particular times.  This
/ _! N1 N9 D1 s; }7 b% @+ _    // schedule has a repeat interval of 1, it will loop every) G" M5 @* |, I( A6 L
    // time step.  The action is executed at time 0 relative to
4 Y& f, l6 J3 A: C+ y! n0 q    // the beginning of the loop.( N% V) z* i7 U( C1 c& L4 W

( N* L& @) u: U" F1 {4 v    // This is a simple schedule, with only one action that is& G# H# [4 u3 b1 l: J* |! ?
    // just repeated every time. See jmousetrap for more' a* J: N! p/ e5 Z5 a2 d
    // complicated schedules.- Z. B, W% O, J4 e1 S
  
/ c) V7 Z9 }) q+ p9 Y! n: ~    modelSchedule = new ScheduleImpl (getZone (), 1);
* y& ]3 m3 o* o5 a8 Z: @: t    modelSchedule.at$createAction (0, modelActions);
/ A. `. F9 `1 ?1 |! s' K        9 z3 Q8 C6 Y  @/ R- z
    return this;6 V5 V3 q' N5 v$ h, |5 W
  }
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