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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
; g8 F9 t* e: Z* l/ b: Z# v8 J' x* P% z; x" l* _5 ^: }  }
public Object buildActions () {) C) L7 U- m4 s! m7 ]. T4 W1 [0 V
    super.buildActions();
# _2 r+ M: R" }5 @% U# j+ n    . ^" v# U: K) g2 G/ w+ Q9 |% e
    // Create the list of simulation actions. We put these in% a2 l7 P6 Z, r" u( W
    // an action group, because we want these actions to be) i% p3 `2 _1 b4 q( d2 ]+ J  t) a
    // executed in a specific order, but these steps should7 [6 k+ F5 _- A" I6 N, l- M
    // take no (simulated) time. The M(foo) means "The message* }5 ?; G& N" C) e$ ~( @0 O
    // called <foo>". You can send a message To a particular
9 r& c: L4 Z. f, q! Z    // object, or ForEach object in a collection.
1 B% n% i1 _: x. l: X. n* B+ w        / S: Y; Z0 x2 D; E
    // Note we update the heatspace in two phases: first run
7 q0 ~: d" J, q, s; S; P) Q! `    // diffusion, then run "updateWorld" to actually enact the
" v$ j- z5 W; C2 u8 b$ w    // changes the heatbugs have made. The ordering here is
  Q! D, m" m/ o. G, {9 R    // significant!
; X8 C9 M" I) Y" C3 V# T        6 k3 Q; g+ L1 q+ M  C
    // Note also, that with the additional+ B3 H; o, Z, b/ Q8 M( P, c4 E) ?
    // `randomizeHeatbugUpdateOrder' Boolean flag we can) W, T" ?* d( @8 [
    // randomize the order in which the bugs actually run  n# X- v1 P# z( b% S; ~- M( H
    // their step rule.  This has the effect of removing any
5 K( v5 M" a5 U6 w5 ^$ @2 k/ J    // systematic bias in the iteration throught the heatbug3 e# v; ^+ Q9 t1 h! e& s
    // list from timestep to timestep9 T$ S, k+ f9 G0 Q! @! e9 b, l
        
9 Z+ ?- J: n5 T8 E    // By default, all `createActionForEach' modelActions have* \# s1 H0 q" M
    // a default order of `Sequential', which means that the
' {& ^4 ]1 f- y- e  k, ^    // order of iteration through the `heatbugList' will be
4 H0 u; [$ o* S: x$ F9 z    // identical (assuming the list order is not changed
5 m5 X; ^9 ]9 Q- s  X    // indirectly by some other process).
$ l$ s+ r& R, R( D$ H! k   
9 h5 J% }* ~- N2 H8 d    modelActions = new ActionGroupImpl (getZone ());
/ b0 a- @+ {2 D9 u
% S+ m0 C" W; O    try {
4 n: {8 u! ]0 A  Z. B* o9 f4 e3 h      modelActions.createActionTo$message
1 p. }; }: v$ Z% J# o2 Y) S        (heat, new Selector (heat.getClass (), "stepRule", false));9 S3 t- R' z# W9 n
    } catch (Exception e) {
7 k8 ]- z4 Y( ], J- s- C1 L      System.err.println ("Exception stepRule: " + e.getMessage ());% Q6 V* I9 C% D( S9 D) p. V
    }
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$ B& L/ u. L7 J, ^    try {) N. r6 r! ]! g! @2 u
      Heatbug proto = (Heatbug) heatbugList.get (0);$ `1 D# e" \& \4 }
      Selector sel = 5 a2 f2 }+ A1 ]; A
        new Selector (proto.getClass (), "heatbugStep", false);1 ~3 [4 F8 i& K+ V
      actionForEach =# V0 T! T6 W+ A2 z4 ]5 {) E
        modelActions.createFActionForEachHomogeneous$call* S+ \9 f* E! j
        (heatbugList,
: E) p( _* t3 H4 h         new FCallImpl (this, proto, sel,
0 O! J! S3 B  f% [' O" L, a                        new FArgumentsImpl (this, sel)));
$ E. |$ S& E6 p" z! n" W- i9 a# k, X7 `    } catch (Exception e) {! u) z8 R8 {: Z5 A2 f; E
      e.printStackTrace (System.err);
* s+ M  a% N2 Y; P$ l7 m% m) H8 ^# A    }
, _0 q, j6 O) N6 S. X   
7 }5 d5 I" I9 A! l+ f    syncUpdateOrder ();1 F& r  x+ i' v& @
: D0 H: O% n6 X( `9 o2 ~: V; q  |
    try {7 o! p# o1 z9 G) _- z
      modelActions.createActionTo$message
7 Q" G' \7 E# c2 M' y3 R        (heat, new Selector (heat.getClass (), "updateLattice", false));
% h! U6 ?5 E3 [8 F  P* i1 e: B- K9 a    } catch (Exception e) {
6 }# p- W" Q% F% Q1 {) w. A' W$ [      System.err.println("Exception updateLattice: " + e.getMessage ());
: t, _! m4 W* v, e; ?9 \    }8 H5 g' M- d2 h- A
        
& S( p% z& r3 B; }1 b    // Then we create a schedule that executes the0 b6 O( C% N' `7 ?2 n1 g
    // modelActions. modelActions is an ActionGroup, by itself it. X" f& Y( I5 g0 e+ N! f+ v
    // has no notion of time. In order to have it executed in
& q6 @5 y- P8 Y" ]7 Y2 t' J    // time, we create a Schedule that says to use the
0 d, f" Z9 N3 q' j5 B' }    // modelActions ActionGroup at particular times.  This
+ N$ K# |' d8 ^5 F    // schedule has a repeat interval of 1, it will loop every3 E2 L) a" V+ Z
    // time step.  The action is executed at time 0 relative to* j. V. Z! w& n$ f
    // the beginning of the loop.1 g) s4 O% O8 i7 F5 M
7 p9 d8 b" o! D; R) p! }
    // This is a simple schedule, with only one action that is6 E& l7 o& N) i* e( h  v
    // just repeated every time. See jmousetrap for more
& n6 v9 O1 Y4 u: w/ P' z    // complicated schedules.& n$ i) a2 m/ b2 e
  
; i$ o5 @% F" Q    modelSchedule = new ScheduleImpl (getZone (), 1);
9 [' x" w7 X' J" W    modelSchedule.at$createAction (0, modelActions);
- T" F+ w) O8 b& A        
. y9 g6 O; g- E* H1 Z8 ?- ~3 b    return this;
1 b( y& @: N, h' {( }" u6 I& K" }  }
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