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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:/ ~: z, g! w- b9 f/ P

6 c* u0 i4 d1 ^0 R$ T5 k6 q public Object buildActions () {# H% G1 t1 Z5 n8 @/ ?
    super.buildActions();
5 h3 F( X/ `, e1 e    * A# Q2 [$ g) D3 ~2 y
    // Create the list of simulation actions. We put these in: t0 s: @9 f+ a3 U& l# e4 J) d
    // an action group, because we want these actions to be; A5 a( J  ]3 {5 w! h
    // executed in a specific order, but these steps should$ }7 e9 Z  C/ {# S: i6 ~: c
    // take no (simulated) time. The M(foo) means "The message- Y! x. m+ ?; h; x3 ^; o- r, y( `0 V
    // called <foo>". You can send a message To a particular
- G7 r0 V8 }$ [5 B& k    // object, or ForEach object in a collection.# k5 `- J2 k) t0 k( X6 v
        " z& x9 O* g* N8 K% f+ B
    // Note we update the heatspace in two phases: first run
$ ]5 N5 r. e+ F    // diffusion, then run "updateWorld" to actually enact the
1 e* z2 p( J# X4 d  p    // changes the heatbugs have made. The ordering here is; U2 E0 }( J7 s; w1 O
    // significant!
1 B0 L% Z3 A5 n" `        
/ T) N- L0 b; l, s. H% V2 I    // Note also, that with the additional
1 |0 x9 {# v3 L* u    // `randomizeHeatbugUpdateOrder' Boolean flag we can' w( @- Q" N% I4 D
    // randomize the order in which the bugs actually run4 b- x8 M9 |, v$ F' _3 c1 _
    // their step rule.  This has the effect of removing any
6 \- @. S1 S, K: @2 L6 U. z    // systematic bias in the iteration throught the heatbug
' Q1 m2 l" J8 V3 E! E% F3 o    // list from timestep to timestep
: n& V5 {2 v) I        
: I9 _2 D0 r9 r& D  }* c( T3 d    // By default, all `createActionForEach' modelActions have
2 J* ^8 i+ ]$ Z+ d' ^    // a default order of `Sequential', which means that the8 d# h6 d* Z$ F; M! I9 |- [( Z
    // order of iteration through the `heatbugList' will be  s* x: @; t+ j6 ?  A1 C8 L! I* L
    // identical (assuming the list order is not changed
( B+ J2 M& f. c6 X' T0 N    // indirectly by some other process).7 X9 d$ D4 d7 K3 d. U+ V- x
   
% b1 D  J  |/ s( `    modelActions = new ActionGroupImpl (getZone ());
+ [# ?, h: p7 G. P$ Z6 _  V* D1 ]8 f. Z
    try {3 S! G7 \) d/ X7 V
      modelActions.createActionTo$message
$ W+ e6 c; N: N        (heat, new Selector (heat.getClass (), "stepRule", false));
; [7 p; c5 [) f    } catch (Exception e) {# g6 Y  q7 v4 J- j& C, n: P4 }
      System.err.println ("Exception stepRule: " + e.getMessage ());% Z/ `5 K1 Q6 ~; N! _; H' F
    }
5 y4 c0 ?* M$ |* w" f0 W1 j( M2 H1 R( l8 a) `# ^! S
    try {6 F1 G: W3 C2 |1 F1 t: P  m/ v
      Heatbug proto = (Heatbug) heatbugList.get (0);
, q+ s5 Q' u( O& h      Selector sel =
; u  y4 w, l1 {        new Selector (proto.getClass (), "heatbugStep", false);
& }5 _" t, z' Q9 A/ A      actionForEach =5 R3 t" X5 L0 z9 Q
        modelActions.createFActionForEachHomogeneous$call
( u: k7 |: J" w( R9 n, a        (heatbugList,
) N7 ], R( ~3 N7 c3 |4 R) D" ^         new FCallImpl (this, proto, sel,9 F* A2 u& _# c6 r; @' p9 D( |
                        new FArgumentsImpl (this, sel)));
& x4 p' T: f: o% |6 r+ ~    } catch (Exception e) {
0 t0 @' F3 u) L# P7 G- F0 Q      e.printStackTrace (System.err);
' b/ m* k9 R0 G2 ~    }) e. |! B' B9 b
    ' q. X: [. F5 o( c  s
    syncUpdateOrder ();2 {4 z$ R4 z% O
! A( k3 R0 V$ b" g
    try {+ D  l8 H) ]% W9 T5 L  l8 {
      modelActions.createActionTo$message
; L$ P8 u6 k& d6 |+ k5 s3 |* v        (heat, new Selector (heat.getClass (), "updateLattice", false));8 g: ?8 ^0 j0 l1 N5 [
    } catch (Exception e) {
9 t2 r9 M: r+ m# w0 P5 N; {! H      System.err.println("Exception updateLattice: " + e.getMessage ());8 N/ [# ?1 n3 n3 U5 c
    }
+ p7 w: n* U# [; B* T* k7 a        5 I; ]1 c0 m9 z. @+ ~- G
    // Then we create a schedule that executes the
' h( b7 y9 n* N2 ~" H! O    // modelActions. modelActions is an ActionGroup, by itself it: f9 W' l- ?# t5 \
    // has no notion of time. In order to have it executed in
% m% x: E& M) t: B    // time, we create a Schedule that says to use the
+ T1 [6 X: q0 E. p    // modelActions ActionGroup at particular times.  This5 e' W3 f8 F4 G6 V, Y0 c- i- r
    // schedule has a repeat interval of 1, it will loop every
9 U& D/ h1 s( g3 U: i& u1 z    // time step.  The action is executed at time 0 relative to, p7 q3 l: t( C. I
    // the beginning of the loop.
, y. `2 [' B9 j& y
, {1 C: Z8 b* S7 q) T: c) Q2 }+ W    // This is a simple schedule, with only one action that is
+ S: E. P; v% a# g6 ^( b) \1 S    // just repeated every time. See jmousetrap for more
$ T2 N: o+ l1 @: D+ y; H    // complicated schedules.4 l; T; p# B, o' ?, V, e# [6 G
  % t: ~, i, d& f( z7 L6 J0 i2 Z
    modelSchedule = new ScheduleImpl (getZone (), 1);4 ^+ m% S- U% d; m% b
    modelSchedule.at$createAction (0, modelActions);
+ d+ `- m% f4 z5 T- z" {6 x8 _6 E        
! r& x( |* N$ x* r! ?* S5 B6 P    return this;
4 w: W4 r% N, N" d2 L( L  }
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