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发表于 2010-5-11 13:19:52
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用list吧8 B2 Y' J: D2 L( \# S6 K% F$ q
patches-own [wealth rank]( x8 j% H* @* G& S" H
to setup
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5 |1 [$ A2 o' w) U. G; k/ x ask patches [set wealth random 100 set pcolor green ]2 @* X# w+ S: C4 n! z$ C
end( d- ~9 e D$ ]* e5 D) A4 U
( x" m; J3 N/ uto go
( A3 b. T o! k+ h; F T let mylist1 []- _* ^. \6 p5 d
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches& c- U" z, {, O% q3 M" R
let mylist2 []" q2 Z" z8 R% X$ A" n* K
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]+ ?* K& j9 K. P# O& |5 ?( [+ a8 T/ u
show [rank] of ?1. O+ y" R8 z- e ~! Y) }" t# I8 N
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]
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$ u/ h. S9 M" g0 N) t let mylist3 []0 A% S+ j% F$ R& X
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches6 U# j4 o: v! d% D* }2 M
show count patches; [( I; d: Z. w" Q a
show mylist1
5 T9 ~5 Y( Z6 A; h( N/ v+ T show mylist39 U) z) R* \. T; r: M$ p- P
end
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2 v5 b2 A/ e( v8 C W! ?) {这时的mylist1 和mylist3 应该是一样的 |
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