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发表于 2010-5-11 13:19:52
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用list吧
# k2 [ [: h/ B9 mpatches-own [wealth rank]
7 H0 X6 H- H% H8 T$ q- rto setup
8 P% C, U% b3 v' J ca
9 _7 d; o/ ]6 M6 j) g) e0 U ask patches [set wealth random 100 set pcolor green ]
- Q! a$ t% A5 X' l9 [$ Lend
1 M0 _ Z3 `7 m) b) C/ G( t/ c5 R" A4 \" K$ r" n y+ T% T
to go
* t# F, r* d) I" } let mylist1 [] k( x, W, D% l, O- a2 Y, l
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches( X" |1 I9 f: c' S L
let mylist2 []% G8 y8 L8 W( ?) X; d; n
set mylist2 n-values count patches [? + 1]* r* t3 m2 {+ u' i3 f" Z
+ ` `! P! i& R4 Y ( foreach mylist1 mylist20 B7 [! w: \3 t0 L2 V8 T
[
5 I2 q& y6 B% | d( ]$ Y ask ?1[ set rank ?2]
* R9 n# n5 T3 \3 ^; D* j9 D7 C show [rank] of ?1& V, S* N. n; \; o% ~. U1 }
2 U/ I, ]7 K$ x8 s ]
: I& Z B) e3 }: N" L) F( E/ v, [ )! R& u1 ~, }! J3 c
let mylist3 []) J4 i. j2 v2 S( x* I
4 R* b0 H+ D) a { L
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches% M2 f! v. i3 U. T d
show count patches
# J: [ A w9 c* Y* l" k show mylist1 ; U; {' r( h" B% [- Y
show mylist3
. g9 E! T) q4 M% vend5 [" j9 d: |( b" |1 m3 R" ]4 S
% T/ J, n) ~5 n( L# V. Y |
这时的mylist1 和mylist3 应该是一样的 |
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