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发表于 2010-5-11 13:19:52
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用list吧
+ ~' W' G8 _$ M' J* n" B! ipatches-own [wealth rank]
* z3 t" ]8 J" ^, H( U. Nto setup3 A& D" E, v6 x# x( |+ K% C) R. |
ca
. k1 z! Z) k9 L, ]# F: B( _1 K ask patches [set wealth random 100 set pcolor green ]# y/ e) n5 x. c3 S6 b& S5 _: H
end" T0 m' D7 H# a2 P, x2 w1 F
t0 F$ {3 B, ] T) yto go* ^2 W( @) F, s8 ~6 P* F
let mylist1 []
2 |2 m0 G& k3 h! w1 [2 Q s0 ~& b set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches) C7 u) C3 p _* t! P
let mylist2 []
! Q) n( ^' h! W% J, a8 B set mylist2 n-values count patches [? + 1]$ h0 l9 R/ X6 N2 n* L3 G
! Q( y/ S2 R1 |( Q6 {8 k4 s3 c
( foreach mylist1 mylist21 {& }) i9 g* j8 p% C7 S# `3 S4 Y
[" u" J1 O6 K* ^
ask ?1[ set rank ?2]
& x. o) D+ g% o2 }: T# C1 u- i show [rank] of ?11 S0 H$ ?- ]" m1 a: t
# D& Y, w, P; H8 M }3 z
]
8 ~2 C) ^! _& S& e )
; V% a0 X6 d# t; A let mylist3 []
4 q7 p. Y% D) r% }" T5 Z0 x
) O& S- m: m+ C1 z: q9 R% S set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
7 ?4 w% |4 N; a! ` show count patches3 V/ A$ H- X7 H. K. O' x2 R. Z5 o
show mylist1 ( N' C' k( I3 d2 K& w
show mylist3. i7 _+ G, ^& R. t1 S
end6 w B. ~% Z) M" t) N* A3 w7 c1 P$ `
$ | N% M+ d6 i, |4 U
这时的mylist1 和mylist3 应该是一样的 |
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