本帖最后由 GJM 于 2009-12-5 21:43 编辑
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- x( p4 E$ J7 G7 j! ]2 e: @底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去' d3 y3 C* f$ A' H
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不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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$ F2 l6 I# p, g# @: v* l& r& H/ r--------------------------------------------
0 `' O6 |, k- M- T2 O% K% Mbegin P_something arriving3 J& T; q. W- ~4 f3 x# B
move into Q_wait
* O4 \) L4 @, U9 @7 n, V6 h move into nextof(Q_mA,Q_mB,Q_mC)
, X7 u2 a1 S9 D0 Q, y use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
8 m) K7 G' J- H9 H& s+ U3 b5 | send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
" [9 V( P0 e2 X& F) J% a( S send to die
' D1 n' `& s3 pend
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$ t( I1 r& x% Lbegin P_mA_down arriving
! D+ }4 L0 a. _ z( \# Z# I while 1=1 do
! F, f* \1 H: v4 t, G! R4 s0 f begin
2 }/ L: }6 c0 p( {6 g# k- [$ V wait for e 110 min
6 N0 |1 q9 L% p5 w1 u( G( W* s% o6 _ take down R_mA) @8 B( {9 Q! {' S! h
wait for e 5 min1 M* j4 I4 b8 k: M( D
bring up R_mA
9 {% o$ H2 a! Q: R! i end, m1 A S5 }& d
end+ l7 ^4 F) r2 \. [2 S5 p
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begin P_mB_down arriving# v' O$ A' u: Y8 J. }0 @
while 1=1 do
5 {. W; V0 s- T, @/ @! n begin- i1 E8 A% H+ O4 \3 K
wait for e 170 min4 T4 k* k& p) g2 t7 _- Z
take down R_mB
8 {& l8 C2 {+ W: B7 D1 W4 t% Z! _ wait for e 10 min2 y! K: g7 V6 ?
bring up R_mB
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end& I% N, x* k+ C. w
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begin P_mC_down arriving5 W+ Y. G- H3 [* p R: C
while 1=1 do 6 l7 b1 }8 D5 @+ T. f2 D
begin
/ [5 ~; x* Y! X. Z1 G wait for e 230 min; \8 @3 _9 z4 W+ ~! C
take down R_mC- V( G. Y0 |- n. _
wait for e 10 min6 ~" d5 t8 E, J6 x6 P: B7 r; L' M
bring up R_mC
, i( [1 C' J! B, T* { end
4 m) e1 ^: T2 I) b% ^end6 i5 f. m' }, q2 I
2 G) E3 N! b7 p# [& j0 ybegin P_mA_clean arriving
& T9 l, V& d* s! b& R! a while 1=1 do2 a2 v# w& C- Z( t. F% [+ A; F9 ~
begin
& @' q8 v; A8 [7 X4 S wait for 90 min3 b8 ]8 N1 c- ?1 C8 o. V U
take down R_mA9 T! |0 I1 s, G( l
wait for 5 min4 f$ J: C Q! X9 l! Y
bring up R_mA
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end
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begin P_mB_clean arriving' B6 t) j/ g5 {9 ~0 n
while 1=1 do
5 }% w( a6 H' m3 \% F6 c4 c begin
$ z$ i4 d! D" T7 y+ g% |. N1 i wait for 90 min
( s$ X/ f/ v$ F* c3 y8 Z take down R_mB
, X& e% |- Q2 N$ @3 f wait for 5 min
4 V" V6 D4 c/ m bring up R_mB: J4 n/ _2 s w' p) r5 j6 K
end
5 z. I# k3 j2 e. d7 X9 V- M" Rend
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) c+ j& f- I, zbegin P_mC_clean arriving. N Q& y5 f) _6 |, v. r
while 1=1 do0 q3 y& e: U% P
begin1 G! ^4 J5 E( g5 H1 u" k
wait for 90 min
: A* u. @* t( U+ M$ z4 ^/ n take down R_mC) R; @0 A8 z+ B0 E
wait for 10 min
7 E+ M0 N) V& N9 n bring up R_mC
4 {9 q* j) k- z end
' T, X. @" t, J# v' M/ R2 pend
- J( I) s8 \% w* N7 [- o----------------------------------------# W; }/ \( r/ T* d( w( }
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Exercise 5.9
7 t" x# g* H' Q: E/ K5 z4 X. b( S! c2 R/ C1 |* Y5 n
# S- l5 n; L, S9 a$ }Create a new model to simulate the following system:
+ W; I! w' v8 Y* YLoads are created with an interarrival time that is exponentially
) g5 g2 e/ a4 Y( m* \distributed with a mean of 20 minutes. Loads wait in an infinite-2 x, X; a- e {. b
capacity queue to be processed by one of three single-capacity,
% r! y/ L8 w& varrayed machines. Each machine has its own single-capacity queue
; u4 j5 r5 Q! {where loads are processed. Waiting loads move into one of the three
/ f; Y! Z& r. F% ]0 zqueues in round-robin order. Each machine has a normally 5 E; L) Z: D* v
distributed processing time with a mean of 48 minutes and a standard
4 x" W% ~% Y3 T8 Qdeviation of 5 minutes.' J0 W, {2 J3 Q3 X
The three machines were purchased at different times and have - x0 @! K7 P* |3 Q: x' H
different failure rates. The failure and repair times are exponentially
7 L: F- o @/ C4 Gdistributed with means as shown in the following table:
) _3 K3 C2 {* ~) zNote The solution for this assignment is required to complete 7 w8 R, M; ?. ~8 M& O0 s9 \
exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of 9 }8 K( q1 S+ n
your model.
9 A G7 l, C$ s. u; W: D
! {- A D+ J" wMachineMean time to failMean time to repair$ i+ H% a6 w4 W
A110 minutes 5 minutes( D0 R7 t/ u. s c+ m6 d0 {/ h
B 170 minutes 10 minutes5 |7 |) d+ a7 ~& P9 t: r; T
C230 minutes 10 minutes* ~5 r: d1 w8 v: ~0 K
3 J$ _- U! M, \7 _8 v3 f, q% KThe machines also must be cleaned according to the following
8 i# [" w7 O2 i4 _4 Uschedule. All times are constant: 5 o0 B4 Y& A3 ^6 v( ^' z
$ ?. s1 t R8 D+ v+ ]; J5 }; HMachineTime between cleanings Time to clean& L8 g& d1 W! A) t
A90 minutes 5 minutes0 B+ p, g% ~$ v" _) w0 {
B 90 minutes 5 minutes/ ^4 I8 \* P5 p7 H
C90 minutes 10 minutes
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. D+ e d- m, l% D& ^& o% u& FPlace the graphics for the queues and the resources.
1 a$ ]0 Q% M s6 Z* `1 uRun the simulation for 100 days.* |" Q" k( T, a m1 y. e: P
Define all failure and cleaning times using logic (rather than resource
2 S+ _4 k* q; Q$ jcycles). Answer the following questions:
, \2 y) a0 R+ f% Za.What was the average number of loads in the waiting queue?$ b3 f. ^6 T* n- D
b.What were the current and average number of loads in Space? % _8 |, K; w' k" y c' d3 l
How do you explain these values? : w% w8 I+ K5 V6 b" \
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