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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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& j* K1 @4 J. G# @: v我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
. z+ m5 k; n8 Q" sbegin P_in arriving% B5 c7 J- @' ?. F, T8 Q
move into Q_in% y6 r/ l, v- F( C5 X
use oper for 2 min H( F8 a% R6 X' J' G7 q& Y
send to oneof(0.95:P_in1,0.05:die)0 r7 l- W' H& M4 t. R$ i( T& r
end
7 ^0 a9 S+ u6 z# U0 Z& H4 h( Ibegin P_in1 arriving
3 t a/ r. Z$ |; w) T' ] if load type = load1 then
/ Q3 \& H2 A. X. y begin
- J8 P- W$ P" E$ H move into Q_m16 ]& e n3 l; O0 D
use M1 for u 5,1 min3 o9 k- N# v- i# V" ]- z9 O$ P
move into Q_out12 u- X6 K9 Z) r. e% o/ g% T0 b
wait to be ordered on orderlist OL_1
7 M; N3 z1 y, g3 ^9 Y& y end2 F- e1 \2 y. K3 s# d
if load type = load2 then
! D" m# ?( L2 W: d- t begin
& k& I5 d/ k+ w; c, z5 Q move into Q_m2: m: l0 S6 O* H8 }5 c6 z3 {& \+ n; E
use M2 for n 8,1 min
: |' |/ r8 D, E$ X. Q" ~1 z; k move into Q_out2 O1 F8 o7 R: z) ]
wait to be ordered on orderlist OL_2
* D0 [: w ~2 h end
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begin P_dunmy arriving/ R# j8 T$ G. Y& g$ P- {
set i = 1) I# a( o) C- K2 u, y; C
while i > 0 do
; Q/ @( a6 Q) ?6 X begin 6 b6 W' L% ^- V! L
order 1 loads from OL_1 to die( S* r5 g1 d: D2 Z* m7 U% d
in case order not filled backorder on OL_1
# x- e" z2 p+ { order 1 loads from OL_2 to continue
" [+ e4 P6 I; Z in case order not filled backorder on OL_2
: y" q9 b Z q' N move into Q_1
+ A, J7 ]7 T5 Y use Massm for n 5,1 min8 t- Z& y. F& P, d
send to die
8 C) r& @. A. ~# m( a' M) T9 Y! @ end1 V& h" J/ Z w x0 n7 I
end
6 k; k9 |" G9 \1 w$ T7 }这是我的报告9 b6 N* Z; b% a7 r
*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
/ w" [( [3 d$ K' _2 J5 R, [CPU time: Absolute: 42.859 sec, Relative: 42.859 sec% I' |8 u3 [2 d. U: v
Statistics for Process System "q"
, f, l+ q$ S, L1 jProcess Statistics
( u! @/ Z8 w7 n7 aName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# E- e1 Z; Q. k9 l/ z========================================================================================
9 D5 P6 D2 \7 |) |P_in 222 1 0.32 -- 2 0 -- 126.04 --2 V" f! d# O% @: c6 l c0 q$ X
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --8 g* G3 l2 X; B6 B5 l4 `
P_in3 0 0 0.00 -- 0 0 -- 0.00 --6 i7 o* J, e. v4 e3 p
P_in4 0 0 0.00 -- 0 0 -- 0.00 -- N$ E5 A0 N! M5 K$ g, f
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
; ~7 ^8 l/ ?5 CProcess Traffic Limit Statistics3 f4 n2 U* } _" j- t' z
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& \1 c* E2 D2 X. V$ ]========================================================================================
& C4 A. h' H& v- k+ f( OP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
3 c. K! S2 Q. Q$ |P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --! Y) [8 Q' i0 Q! |
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
2 C( }6 Z% j) o; I: X, j8 B) G3 RP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
3 g! }1 n) J! n# S# PP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
9 Z' k& r' C9 M! qQueue Statistics! H1 a/ K2 m1 K6 R
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait* p7 b J% E1 R& P4 w
========================================================================================# ?, h, R$ O& b5 f9 Q$ `
Space 223 0 0.00 Infinite 1 0 -- 0.00 --. f4 ^( d, y |; @; H2 Z2 J
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --' h( C9 `+ ?* h) i( V9 ]
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
: H/ T0 T: _, `' {4 [4 uQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
. T/ X; K5 d2 K7 z/ i6 ]. }Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
F* x9 F# q0 X( `) xQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --; D! `* W1 W4 Z% T+ ^
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
: L/ P) b) V$ kOrder List Statistics
?% V" B6 S9 e- `8 X, dName Total Cur Average Max Min Av_Time Tot_Back_Ordered8 f. l8 @: l$ G e" g( w: R
================================================================================
0 C7 Y0 M- _* G" |. ~OL_1 139 139 67.23 139 0 41789.43 1
$ d/ H9 h: y' z4 Y: V' A+ sOL_2 71 71 34.26 71 0 41693.20 1( j1 Z! a; M% H4 b/ s7 n9 G, m* n
Resource Statistics; }1 F. g) B, ?& d6 F1 E
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
# w' ?7 z9 d6 r0 C0 r3 |, q/ u( s4 J====================================================================================================
3 Z6 K; @4 U9 b! U" k" ZM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 7 E: }2 a$ m) |& ]5 A) j
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
# ]5 ~# e3 d7 q) nMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
: m! [1 L) R @0 V7 {' |6 boper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 5 G: A/ K9 |. n4 A1 A# E
Random Number Streams8 n& H: x8 _/ g% ^- z4 ^4 S/ I2 F7 A
Name Total
0 k' [* {* B( j- T1 R============================4 o( G" d4 ^# R- L
stream0 455
* _3 p o( Q% s7 h& p3 |/ U7 `stream_M1_1 0
! T( N. @6 v$ V: X; G/ sstream_M2_1 02 s1 s. W+ @. W$ r. ~
stream_Massm_1 0, f4 L: Z* D( y
stream_oper_1 00 u) L* |# q* t. _
stream_load1_1 184- B$ b! u) z! h0 Y8 @0 U
stream_load2_1 76
$ \. }7 j$ b; T3 Pstream_dummy_1 0
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
