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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 r* I0 Z0 X" y2 _2 {* I" ]
7 B2 A1 j1 J/ H% ^我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
3 W4 p. W# t7 P5 Ebegin P_in arriving
( c1 O2 z' \, `" u1 Z' ] move into Q_in
3 L1 k4 w1 c3 `& p2 y use oper for 2 min$ g$ Y/ w" X( Y
send to oneof(0.95:P_in1,0.05:die)
3 ^7 K9 [. u/ s1 M4 [end
: ^, h( b8 `$ Q, {; Gbegin P_in1 arriving
/ d0 m9 Y6 `: ?- H1 z2 ^- n if load type = load1 then0 g4 O. y# S2 F2 ?
begin( X4 X7 {) O- b' ?7 E, r
move into Q_m18 A% d$ ? x% ]4 ]& Z4 b0 D3 W
use M1 for u 5,1 min! `8 n3 g5 F+ C# O7 d( X3 C
move into Q_out1
$ }( D6 d9 _* I4 X5 o6 N4 r wait to be ordered on orderlist OL_1
2 o }5 Y* E6 e9 x5 f4 u1 k end
2 @* {6 [; ?' ]2 U( N if load type = load2 then
( }$ Z* K$ M1 i begin6 L& x1 B& V6 W4 Y5 L& e) \
move into Q_m2/ C+ D. d# M. q1 T. i
use M2 for n 8,1 min
1 f* y# k% z" s& U$ o- K move into Q_out2
( z$ Q. b" B1 B3 Z. I# `3 q" a wait to be ordered on orderlist OL_2
9 h1 k7 H4 Q$ T ^+ A end
' t9 Z+ D& a; a& L; Mend, x' ^% Z1 H" l/ N. H5 k% ~
begin P_dunmy arriving
; y3 q' q% | x5 R set i = 1+ S6 s3 f( l9 h; Y3 ~/ b2 u: N; B* i2 C
while i > 0 do( o. ~" h7 M; x8 @8 }9 O( |
begin 3 ~/ K$ y4 {/ s7 B% L
order 1 loads from OL_1 to die
' m. { D$ i! ]. }4 {3 k in case order not filled backorder on OL_1
% ^1 S- b- R+ v7 f) _ order 1 loads from OL_2 to continue) B: `( ]& `1 V- k% N1 y
in case order not filled backorder on OL_22 O* W: d8 C- ^- E% E1 U+ E8 X0 x0 ^7 K) v
move into Q_1) o- B6 I' g$ P5 F
use Massm for n 5,1 min
9 S4 U2 s L; g/ ~" ? send to die
. N F5 r- I5 b( ] end
% Q0 m0 t I' r, D& M7 Uend
4 {9 @ w6 s4 s! a0 D) c$ k& C6 L: w这是我的报告0 Y$ V% f5 \% v
*** AutoMod 11.1 ***2 }% e2 {$ G* W0 T2 y9 f
Model q3 G* }8 f1 C& m
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
# c' k6 ^5 s5 t! D4 C3 ?/ tCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
v6 g7 x1 ?/ e& G8 FStatistics for Process System "q"
% y/ N9 n; I$ e) @, D3 O P! H2 g& tProcess Statistics
: _7 A, b# u; c% w" Z SName Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 |7 f; @. K G
========================================================================================& {8 S1 }8 x! V1 p A; m2 h
P_in 222 1 0.32 -- 2 0 -- 126.04 --+ C- ]9 @* }9 d& v# o1 j# j
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
* I$ n& a1 \$ @4 f4 z1 [9 GP_in3 0 0 0.00 -- 0 0 -- 0.00 --" u. D6 S; O: [0 O" {' E$ q
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
+ z& l) _. |, C0 ^$ f) ?P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
2 I& x6 I. K1 _" }Process Traffic Limit Statistics
7 ?2 r/ P% K/ \6 C g& OName Total Cur Average Capacity Max Min Util Av_Time Av_Wait' I9 ]6 h# Z2 `( F/ d2 h+ e% k
========================================================================================
: Y. X- h, d0 x! g8 r: V) N) jP_in 222 1 0.32 Infinite 2 0 -- 126.04 --4 V8 f% c* I4 ]1 q: z! r
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --+ r0 U+ _5 j/ p, q5 K( G
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
8 d+ @" E0 C+ w! c9 p0 E2 K6 h$ sP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --1 A1 r! p0 U# J8 c: s5 e j
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --/ a# U) p9 w4 U
Queue Statistics7 z+ }, {! ~& K
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait, P7 M" F) ?2 k6 y+ a X( \
========================================================================================- y9 V1 m8 { V7 {2 H" z) V
Space 223 0 0.00 Infinite 1 0 -- 0.00 -- ?1 P% v& |# _3 N, s4 `1 C
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --, M8 m z- a% r! G& W
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --; _0 C5 _* `& Y- x
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
# j+ V" k4 F5 a$ LQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --5 k* F& @ y" J- s5 {! e
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --) t% U6 @' c' \
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.001 B+ R# T1 Y+ d/ q
Order List Statistics
9 A+ r2 i& I0 ^% J8 e. XName Total Cur Average Max Min Av_Time Tot_Back_Ordered* m: L, \8 Y/ Q; E" j4 U5 U' Q
================================================================================
m; Z/ K# I7 p0 }1 [9 A5 iOL_1 139 139 67.23 139 0 41789.43 1
9 N: b3 m; L* mOL_2 71 71 34.26 71 0 41693.20 1
- |4 |. v$ h9 k: B" ~9 ?% mResource Statistics) q. }8 v$ W( l; c# r2 ^
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State , E6 j$ w. j( L7 a% W
====================================================================================================
% f4 i5 c6 U6 a# BM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 3 V& p4 d: u4 x) W2 ~
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- * o- S- `/ R' G2 g! P( ?1 F
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
4 [* o9 R' s" k' x1 f) t+ Xoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- ( b9 ^( Y4 o/ X8 @0 \
Random Number Streams5 [' T5 t% E6 ~2 [; I
Name Total
8 R9 f. z9 i' T============================
' z p* _' P9 U- ostream0 455
- G3 H9 @* X3 A7 G: _3 Istream_M1_1 04 K; w i. W/ v
stream_M2_1 0
/ a+ X: C3 v( N Jstream_Massm_1 0! g/ K7 R0 N* u5 H- b( Q
stream_oper_1 00 I. M' \5 A. @+ U
stream_load1_1 1842 B& E F. P) |! O2 J t- n: u
stream_load2_1 76, J5 A5 m9 _& H& K: }
stream_dummy_1 07 G$ _7 |' ?7 B J5 U2 u/ Y, O! Y
; ?. K9 ^- x! m' l2 j8 L2 o3 ^
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
