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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
E. I1 A2 I4 d; O. f% E7 C" H- t0 v9 [- k; G; b. W
我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
) \- \+ l7 B6 S$ f$ V: X% B1 }begin P_in arriving- x P" l0 e. [/ c
move into Q_in
% y+ F# O0 x8 l( z! j Q use oper for 2 min
2 g9 q/ K( n. K0 n6 ]9 F/ E0 C send to oneof(0.95:P_in1,0.05:die)3 ~1 x) n' z* P
end1 C6 p: r0 o4 m4 Q3 F
begin P_in1 arriving o. I. ~1 e$ J* z' e4 v* F2 r
if load type = load1 then: M4 i# {* C- U; M1 F/ S
begin+ s; v) j0 h1 g6 m5 g+ }
move into Q_m1
6 J/ q* {8 G; N use M1 for u 5,1 min" `, k6 r: o8 r. Y7 g9 d
move into Q_out1; T, T, E% `& n
wait to be ordered on orderlist OL_1
/ n, t! g9 v+ i2 M$ J1 S end& {% L4 r; `4 T6 X
if load type = load2 then
0 c/ Y* l/ f% N$ a1 K- D- B begin; w$ `9 \1 i1 O) i) v7 `7 Q
move into Q_m2
4 y9 h/ j, @$ H: G$ W$ f2 d use M2 for n 8,1 min4 i- T' _& t! Y$ \
move into Q_out24 ]5 j7 C1 h/ A! [
wait to be ordered on orderlist OL_2
+ G7 ?5 r9 U# r9 E! @. t5 e end
0 M7 G- ]! B x1 |% r, Pend7 p! T4 C! b+ w2 g9 V# E6 @
begin P_dunmy arriving
( h1 N8 R9 j3 M8 c7 f set i = 19 |5 ~% @* d1 \1 @6 E I) e$ Q8 q# ]
while i > 0 do5 s7 x$ H! @/ r: l" B# h
begin
2 ]5 i( s- m9 d1 k order 1 loads from OL_1 to die) J n2 g3 e8 N+ d2 a& f
in case order not filled backorder on OL_1: c) ]. ^/ m0 k$ r/ b- T" F, `
order 1 loads from OL_2 to continue( ?$ `, b3 P0 Y4 P2 d/ n. M
in case order not filled backorder on OL_2
6 S+ m }9 _! X& N, x6 n move into Q_1
( C/ x' k& C% L/ P+ M% X use Massm for n 5,1 min/ h- f! ]" q& h6 s# S
send to die
4 ]( @+ o' v1 n9 C6 ]. ^ end$ q5 H1 b; F( \
end
/ q" @# f7 _! K) W+ o$ G这是我的报告
' F2 a$ M' D& z. [; H$ K*** AutoMod 11.1 ***, v4 O2 J- k$ U" { u3 J
Model q' q8 I) c, I" O$ E1 y; R7 T
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
- T+ x7 c, S& u$ R; ^+ xCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
- d, \) A% n) ^: V: ]Statistics for Process System "q"
4 L1 I& H3 {. c+ p: t( hProcess Statistics
3 }+ [% [% X3 @, X7 \$ uName Total Cur Average Capacity Max Min Util Av_Time Av_Wait3 V% P2 `% Q+ ]$ D% J
========================================================================================
' Z% s) O) U' s M6 G! o0 {P_in 222 1 0.32 -- 2 0 -- 126.04 --
7 S k# R- j! E% c% s, @- |/ mP_in1 212 210 102.38 -- 210 0 -- 41725.92 --0 h& a; O# _4 }& ?) c
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
% z: n& D/ A$ v2 j7 uP_in4 0 0 0.00 -- 0 0 -- 0.00 --9 o$ i; Z! b. W
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --& o. F' t6 V* `/ g4 ~
Process Traffic Limit Statistics
* q; p* r* x4 D. e% B4 A# R4 DName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
; k |! ^5 r6 H0 r/ \: d( J% `========================================================================================
3 d D9 D! ^, j; w$ T% {" \* T; jP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
% y9 g+ X1 g! W% `+ b/ }$ b) N" KP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --2 R' r. Q' @0 \; Y' Q) s0 n8 R
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
3 ~. f& P% b$ z. MP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
2 W8 ]1 P( L0 O' G5 e* x% xP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
$ [$ a( b6 ]% b/ \" o8 P& FQueue Statistics
: b, p6 Q5 C% ?' n- ]: @6 p0 rName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 z/ a# |! e& O/ K9 P/ c* |========================================================================================. O# P% q) [/ U' z( I# P7 ~
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
$ u0 S7 s; k! O* _6 wQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --* P; Q/ @; d/ O6 l% n: I- m0 R
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --; j5 U6 s) [6 ~& n
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --) E. f' x. L% S% z; V; J8 Y
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --; N& L: `% ` i# T# L
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --- c# m/ A( s7 N" r8 {% E
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
; h9 j" ^8 P6 c: I3 nOrder List Statistics
: G+ y4 [3 v: Z7 v3 Z) lName Total Cur Average Max Min Av_Time Tot_Back_Ordered
1 c0 T, s* H4 b/ A' P================================================================================! h2 }+ H7 w3 K. V. Z |4 {
OL_1 139 139 67.23 139 0 41789.43 17 p4 n& m U3 z9 i& d2 \
OL_2 71 71 34.26 71 0 41693.20 1
# u4 s8 |) w3 ^8 @Resource Statistics
! }( G% ?( D0 IName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
4 q" f1 d y* ]+ p) E5 q. ?1 |====================================================================================================8 T# A3 j/ n+ ]' n. ^/ i! C* j
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
3 |0 d: W: X' V$ ]9 c2 {, P4 o9 [- tM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- : W0 y! E, N+ }( P, v9 f2 Z9 v
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
7 h' U# o5 ?" ]6 T( R) A- toper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
8 V1 d) K% q' @ i. f2 _$ _$ R5 C) WRandom Number Streams8 M8 o! z# f( P2 g
Name Total
, M) `1 }% p2 q1 `1 f8 g, u3 S: @# a/ P============================
) H9 C" F& Q- ~; a( rstream0 455$ S4 x/ g- r, C8 A5 P. P T
stream_M1_1 0" T* k3 g, K( `
stream_M2_1 0
+ L6 k( m& _7 o; \stream_Massm_1 0
* D9 I3 _% a! Y7 nstream_oper_1 0* r' f) E+ W2 A" x# M# Q
stream_load1_1 184
) [* U4 \/ y8 j$ r y, ]1 Jstream_load2_1 766 n! Y3 j3 Y3 m( l
stream_dummy_1 0 y# y/ X( Q( m M& B/ d7 [3 \
' E" ~- b& z2 f7 `请问我的错误在那里?我用的版本是11.1的学生版 |
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