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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
@0 t+ |' y% U! i1 ^大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
. x$ h& m0 h( A' @“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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1 g, n. X# i2 I0 \# ~6 w; Z* \ M:string;: ^! L. @) }0 I3 Q
selecTab:table[integer,integer,integer,string];
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7 g$ Y, p8 a+ w( P0 P initorders;3 R7 @& X+ y5 l# J7 v
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scheduledorders.delete;6 \9 h& y9 x4 g" z0 d3 C4 h$ J3 c
seletTab.create;' ^1 f! D) q8 P2 \/ ~
! @' @& J: b; _7 K orders.initialize({2,1}..{2,*},0);
: L% V# Y8 }* G1 y7 @3 L orders.initialize({4,1}..{4,*},0);& c) r# J' ?; c/ ? L: L& [3 z
for j:=1 to numorders loop( E7 @& d, w5 S8 i1 f. D/ l: v* I
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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for scheduledsteps:=1 to numsteps loop --: J% x% S$ {, U
selectab.delete;
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% K6 V" a& c6 F( ? for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
: W+ J: r' C9 n9 ^' @7 s: j( C if nstep<=orders[3,j] then$ G! `. Y9 d5 R5 o) G3 j
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];, L* e7 n, q W; O
k:=k+1;2 s# |" {4 q+ x, I4 O4 f# g+ s
3 E& ?. K# d6 U7 V: ^2 e/ |6 ?& Z% W end;
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mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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- g' P9 R: P& X$ M* A if selectab[2,j]<mincomptime then
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else
$ n0 G4 I' o/ W6 O ?5 e selecttab.cutrow(j);
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end;- R/ W, f) R/ `" [3 J
8 G# a2 U5 l: m2 N/ R& B j:=selectionrule(selecttab);0 d7 N. P, i* E$ O
1 T3 N. a) [+ ^. L3 L8 i5 E3 ~ nstep;+orders[2.j]+1;1 {' ~& n+ X* Q( N" r# ]
orders[2,j]:=nstep;
# T7 h5 H# i8 ?; q) J m:=orders[1,j][1,nstep];/ B2 V+ y% ]/ l/ `3 G0 g
c:=orders[5,j]
* }: i$ S+ ~. n6 _ occres[1,m]:=c;0 E; o# J3 c0 D" ]+ i% [
' u: Z& H7 _- g/ x --jieguo:start,end,res,job,step5 x+ s9 @6 l E+ X4 G1 ?
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);5 E3 J& C. d7 e* \2 K5 g5 A
for k:=1 to numorders loop- r$ b" z. m. D4 X
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m5 t" _( s0 K" J h9 k- P6 ~) i* Q
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then$ g' V; {$ i n- \
orders[4,k]:=max(c,orders[4,k]);
" X t. G! N K* w --
3 Y8 x) v3 \" T6 b' b& v orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
, I# U/ C4 Y* {$ x5 D, {2 u next;
0 `6 [& u* g0 ] nstep:=orders[2,j]+1:5 d, Y; N- j& y
if nstep<=orders[3,j], ]; X* I9 n8 Y
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
+ ~; Y2 U( X! E, k5 J orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
4 b# A2 A; y2 m1 G end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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