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本帖最后由 soso001 于 2014-12-17 14:53 编辑 ! O( F& ]6 X* L2 T* s5 Q" J
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不好意思,打错了个字母,呵呵呵!9 Z! M' h: L0 g
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
$ P; V8 p% d U6 f7 }3 }“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
0 h, H2 M1 q% u' } M:string;
! [9 u6 o/ Z5 ]; W# w selecTab:table[integer,integer,integer,string];
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initorders;2 x% n3 n0 S7 P! w) h' S
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scheduledorders.delete;1 s" U* F4 |: R6 u8 `. I* C
seletTab.create;% u( Q& {) P. A* M
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orders.initialize({2,1}..{2,*},0);: A$ U( @( w! Q& X2 r, u* q7 W% I
orders.initialize({4,1}..{4,*},0);
* x: S: T9 [! `( G6 S5 k7 o/ F for j:=1 to numorders loop3 [% t+ j9 {* P* f" U
orders[5,j]:=orders[1,j][2,1];) W' x8 r& v! l
next;
7 p6 ?+ K; H# f# h occres.initialize({1,1}..{1,*},0);! U% }5 @2 Y2 f( O4 G- k( V" W
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--XUNHUAN
8 L3 f) f+ E1 L M for scheduledsteps:=1 to numsteps loop --
( P! q; O8 h5 { selectab.delete;$ P X* s) V8 x7 @+ L
k:=1;
+ c# G) ?( H& K) e. z for j:=1 to numorders loop
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nstep:=orders[2,j]+1;/ y+ M! M8 [3 `8 z
if nstep<=orders[3,j] then$ r7 z, H, L7 L
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
' q. b% R% B) v5 A, g6 E k:=k+1;1 P! {0 k w7 q+ @2 x
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next;
# x: v' `6 A6 q u mincomptime:=selecttab.min({3,1}..{3,*});8 w/ t& }3 Z3 y* @ I( k
$ u' j7 i) G, n from j:=1 until j>selectab.ydim loop/ M% @, }& t( R6 h+ @
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if selectab[2,j]<mincomptime then
0 E# j; w' Y" n7 g8 R) P$ z# @' g j:=j+1;
7 H/ M# D& [' v1 a( c else
* D* h! c% k) |# ^ selecttab.cutrow(j); E+ h, e* e9 x' k0 s* m+ ?
end;
' L0 I' s( G( |& y1 { end;
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- e* ^' Q+ d5 c# i C8 Z5 _. { j:=selectionrule(selecttab);1 [1 ]8 K- C1 V, B+ \
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nstep;+orders[2.j]+1;
b( o6 |0 {! e( \1 s& c7 c0 N; c orders[2,j]:=nstep;
5 L0 |' n$ d9 K' ? m:=orders[1,j][1,nstep];
% }; c& D% s& i( u8 h c:=orders[5,j]( s( p! l1 d: f) V
occres[1,m]:=c;# m: ~/ M( C5 a# @% V! Q
9 }) P. T/ S8 D --jieguo:start,end,res,job,step
6 s! B# c4 R7 @, P% Z' k scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);/ C- P! ], G( i( {
for k:=1 to numorders loop+ n1 W, ~. Y( @' l
nstep:=orders[2,k]+1;* H& E3 S x0 R* v7 u, K
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m5 ]+ T6 ]; D% V
--& g, J$ Q" {; V0 E
then! l' V b9 O% u/ D; }
orders[4,k]:=max(c,orders[4,k]);; { B6 Q2 F. ?) `+ Y
--
8 B$ C* K8 E& F orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];* C/ |+ P: ^) A3 J
--
k+ b4 ?) z; R. ?" w% t' L end;
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nstep:=orders[2,j]+1:
% V2 t( M" q3 E! S# t if nstep<=orders[3,j]
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* X2 z" ~$ @% t/ a then
4 R* E: P: W* O3 \, x orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);% n# u4 ~4 C% j% d. U# ^
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];/ Z4 {9 k y8 S; p6 H
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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