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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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: A }& u; C% Q* g5 b4 ?& x R不好意思,打错了个字母,呵呵呵!% p3 I* _* a D: M
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示, F$ M4 J7 D8 U9 p: x8 h
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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% R" s0 T# N9 }9 R9 f j,k,nstep,c, scheduleteps,mincomptime:integer;6 g m/ J w7 W! r5 G* C3 f
M:string;% V# t& ^% Z' R8 J) n" i+ }
selecTab:table[integer,integer,integer,string];. L/ W4 `! S& h/ h; k
do
" N; g0 r: S7 w7 i+ v8 s M/ E initorders;4 A9 ]3 b$ F' g. D
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scheduledorders.delete;
/ m& K4 p! c8 I( N) K seletTab.create;
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orders.initialize({2,1}..{2,*},0);
P# w p7 l+ i! W9 B orders.initialize({4,1}..{4,*},0);! `7 N N" Q h, ^1 c d
for j:=1 to numorders loop4 L: Q2 w2 f4 R3 X' P4 `) a5 x
orders[5,j]:=orders[1,j][2,1];- ]! j) h/ E; _* a# f$ C
next;2 {4 V/ v' d& f2 f
occres.initialize({1,1}..{1,*},0);
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! H/ [0 e* ]. _( S3 E --XUNHUAN% [2 F. b( z* ~ p! [7 q
for scheduledsteps:=1 to numsteps loop --; y0 {+ y* N+ D
selectab.delete;& E" ^1 X- y# M& C' U( |: N6 D) o
k:=1;
: Q* l: @# s% o' y: N% [/ T for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
& s3 ?; E6 H4 m0 X5 Y# c if nstep<=orders[3,j] then
: h9 E' e5 w+ J selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
u$ _6 e/ w" F7 q3 t0 _3 P9 X& } k:=k+1;
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end;
' S3 ^* C7 q$ e9 B/ a" k next;
Y- k4 w- ^4 H4 ~* {) k9 M+ F mincomptime:=selecttab.min({3,1}..{3,*});4 D( d) `2 e- t1 |# N
9 @* p! g) ]. P. d; u1 R1 \; Y3 q from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then' I* Z' p$ Q! X4 n" D2 g
j:=j+1;+ S# Y2 _/ e* N2 i
else
0 e% I t0 w$ V, Y: Y selecttab.cutrow(j);8 I& K# W4 U$ R) T. ^
end;
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$ E+ ?. S5 A. \" n b, D% j& p/ ~ j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
( N7 ]' d' m9 z0 O orders[2,j]:=nstep;
" o/ p3 \9 F* t( C m:=orders[1,j][1,nstep];6 x, P5 U. ~# \. t
c:=orders[5,j]+ ~1 c% d$ i7 z2 Y- l
occres[1,m]:=c;' [/ r" j- a+ b% ]5 L9 d) o
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--jieguo:start,end,res,job,step: E7 \. }: z$ B F5 F! l& o
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
7 } Z. }3 c" H! H9 l- D7 Q$ {3 R for k:=1 to numorders loop7 z$ R3 r* } W: e# K
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m; J8 z V6 N' \: w0 `3 b n
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then! Y2 ]8 j! j# d$ h" _
orders[4,k]:=max(c,orders[4,k]);" H- T& ~ L0 _# M6 c3 }
--
' m* H+ Z9 ^7 a orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;1 F1 z) k& e3 Q# M3 K) ]
next;/ Y/ ^7 r% Z' s: Y1 Q
nstep:=orders[2,j]+1:3 X7 g/ r; h; e5 V& u
if nstep<=orders[3,j]
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then' `+ V+ Z7 @/ d. K" j% i, a; R
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);1 b$ Q) ^$ y/ k: H6 L
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
$ Y2 T' W: I* d% g; a- R end;
. K1 B3 x4 Q4 I! ?* i; g next;5 }8 T. O! U! H( i7 F7 ^
L8 W* K* L2 ]# ~1 ^" ^ print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;: @& }- w2 {# ]# P
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