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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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/ a7 T0 G! W6 ]不好意思,打错了个字母,呵呵呵!# M6 M. t0 d9 g9 X" W+ W
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示# F0 d$ N+ L9 Q+ T8 I# G( L
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!. a, T+ `9 p/ l# m6 X; u: C+ Q
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j,k,nstep,c, scheduleteps,mincomptime:integer;: B5 ?# n4 G# w% r. U" ^
M:string;
x0 u! y: W5 m3 k/ ^( w! J selecTab:table[integer,integer,integer,string];1 H4 C6 I ^1 L! D3 _
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initorders;
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scheduledorders.delete;" p, M7 _$ T% M% l9 N
seletTab.create;
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4 b5 x( g( J* O9 B orders.initialize({2,1}..{2,*},0);
0 k" C4 `! E5 k5 M orders.initialize({4,1}..{4,*},0);
- e7 ]2 A$ U3 n7 e7 E0 p, p for j:=1 to numorders loop
) J. ?9 N: A4 j5 Z: f: d& ]7 b orders[5,j]:=orders[1,j][2,1]; _7 r) I9 l! y! p( n: e
next;) E6 u7 f }( w5 t, D
occres.initialize({1,1}..{1,*},0);" g% X2 }, m( D0 `& `4 c5 d
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--XUNHUAN% V) s) {/ |9 ~* S E) Q
for scheduledsteps:=1 to numsteps loop --0 V& _$ q2 n# J9 a1 i% j
selectab.delete;
& [( r8 Q( _' y3 o* R8 ?8 q& M3 E k:=1;
7 c# v2 ^2 }. B& U for j:=1 to numorders loop H0 C* s& ^% \/ @3 T! Z
4 L+ u7 T& q" N& ?( f* _ nstep:=orders[2,j]+1;: {9 ]- D4 _3 }0 B
if nstep<=orders[3,j] then' i8 ^' [% C8 H6 `. y S# g
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];, `' N: A9 ]& S2 g7 ^
k:=k+1;
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end;3 G, b7 D, ~3 i" A4 j2 l! W \
next;
8 [8 I5 E- T: b( l: K mincomptime:=selecttab.min({3,1}..{3,*});
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0 ?! h' k. k9 D8 @ from j:=1 until j>selectab.ydim loop) Y- |& Z% o. Z9 y/ f/ ^
. `) ^: O- h0 Q if selectab[2,j]<mincomptime then
& O4 a7 K# r' M& Z- w( q, s8 [- L j:=j+1;3 U& H. w2 A) x% p6 j0 }: `
else9 T$ P4 M5 K- R
selecttab.cutrow(j);" H. f. D1 x/ s, d4 W
end;
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( y- i# O& S$ S j:=selectionrule(selecttab);
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3 d4 ^7 l, J# j' t9 ~5 h7 ?" E& Q nstep;+orders[2.j]+1;& G$ B0 ?2 @6 @0 l" W
orders[2,j]:=nstep;. S; c0 f) e4 F
m:=orders[1,j][1,nstep];0 [: p! k( }" `" A0 c* F
c:=orders[5,j]6 Q- M% B3 ]6 p" B+ S% g" e
occres[1,m]:=c;
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* a9 I' @2 b' B I --jieguo:start,end,res,job,step( s. r8 U6 }3 F, B* ^3 a
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
" y' n2 p" r$ y/ f" f for k:=1 to numorders loop }. Y- V P! Q( b7 Y' w3 o
nstep:=orders[2,k]+1;# t7 ~: [3 n3 ~2 c# n0 H3 z/ q
( g, A- L: S/ u/ r if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
+ r* X j# r+ i- i' Z orders[4,k]:=max(c,orders[4,k]);
, D* D* ?6 O4 c2 h --
) T. b$ C; ~; P) m9 o# ~ orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
6 s- C4 k+ s% f" p P) C w --
9 F6 F* o E+ p6 r7 X0 p }: ^6 z end;+ }. Y* F2 Z4 ^/ Q4 |' [& P
next;2 m1 U q F# u6 b% C! q' F2 f V7 V
nstep:=orders[2,j]+1:
( }" E. G1 n! E6 I# |- A if nstep<=orders[3,j]& M/ ^0 z. }$ W; I% W
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
, A& ?' D/ k1 r1 c orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
$ G/ I3 ~( x" P9 y D) W end;
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. B6 K' x: d0 i& T5 V6 ?" S0 h print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});! u4 | Z3 m8 y7 p5 O
mygantt;0 e' }9 g1 g( n4 j+ A1 ]) |/ b
ens;
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