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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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" \; ]/ @/ N3 P+ c不好意思,打错了个字母,呵呵呵!
' u, y- Q) o9 N& g7 W" V: ^大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
: w7 n5 U( v! f“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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" x+ _, |0 _: D j,k,nstep,c, scheduleteps,mincomptime:integer;
4 j# E6 D) C5 [0 ^! q M:string;
# D: X, g1 M0 y( z, W6 ?: o selecTab:table[integer,integer,integer,string];
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initorders;0 G; M' V3 D8 c) X
0 q' w; {9 J2 @; ^) M$ l: }/ M- l scheduledorders.delete;
! H( q* x2 y* D" b0 J5 S seletTab.create;
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orders.initialize({2,1}..{2,*},0);; t& C4 o Z$ X& J
orders.initialize({4,1}..{4,*},0);
% @" x( [& ?2 d3 I0 T2 Z4 ~& _ for j:=1 to numorders loop5 o+ d( N! { K: K
orders[5,j]:=orders[1,j][2,1];3 X/ \. f0 r$ [
next;
2 t- G( z/ E# L8 x occres.initialize({1,1}..{1,*},0);
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for scheduledsteps:=1 to numsteps loop --
4 {3 O: x' F- j1 k) @+ t0 u selectab.delete;, a1 f6 v( }& L" A0 [! d4 N" m( R- C
k:=1;0 Y( q9 M% b- }* a
for j:=1 to numorders loop
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6 Y. {7 v% o M9 E5 q; h4 \2 n nstep:=orders[2,j]+1;& K; {0 l1 e T/ a2 L
if nstep<=orders[3,j] then# p! s! q6 }6 i& i% E
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
# m' b0 Y. T6 |1 r7 { k:=k+1;$ N& k+ T6 g T ~, ^% O
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end;9 B. \- ^5 q: S8 @' B7 w
next;
9 e$ H2 b! D- j& y4 e, S/ G2 I. H. y mincomptime:=selecttab.min({3,1}..{3,*});3 C: h3 f" b; s. k% _' a
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from j:=1 until j>selectab.ydim loop" |$ m8 a) A2 s' ]1 B
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if selectab[2,j]<mincomptime then& b( D( B- q9 v2 N
j:=j+1;
3 \$ s) A( K, B. f else
6 J: ?' V* L' ^* D; S( E selecttab.cutrow(j);% ]. B( ^6 c2 R$ h: L1 z. i; z
end;' S1 A: W* p9 y3 W: O: K; g
end;
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" {. o" `+ a8 i1 s j:=selectionrule(selecttab);; m" V2 x# m) S9 ^* g( B6 D& [
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nstep;+orders[2.j]+1;
5 j5 I: x2 A: d0 u orders[2,j]:=nstep;
) R- M3 }8 k ? m:=orders[1,j][1,nstep];
" t# ]6 N% @ @4 \5 c c:=orders[5,j]
) f! b- g, A( w, b occres[1,m]:=c;6 I9 @' t$ I \# K! a# k
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--jieguo:start,end,res,job,step
8 }6 N9 u% F r- E( N, | scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);2 ?9 i$ m0 W9 W$ q9 W; I$ r
for k:=1 to numorders loop
/ E# k6 b0 _9 {6 a5 Q0 F, v6 p$ L7 {# d5 r nstep:=orders[2,k]+1;" a* N) g+ \8 @+ e: L
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then, l( @6 B& P7 D4 H1 A1 j
orders[4,k]:=max(c,orders[4,k]);
7 L* w \* h' Z( Q K& | m --
/ D3 L! f1 }! [8 G- x3 u orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];6 t# o& s( y' G8 k
--
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next;' r( r* z; Q# C5 O
nstep:=orders[2,j]+1:
* ?5 P. @5 A, ? if nstep<=orders[3,j]" o( N0 C& Z" d: y
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then3 e# _9 a' L7 g- ~7 C3 v0 n4 H
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
# O9 T" c2 F7 v- U7 F orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];8 N% ?7 G7 V8 E' c
end;
+ X0 i y- V' J+ _* z! f next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});9 H- |& h8 m8 M- n) i& H
mygantt;& Z' w" r; A! A% @& ]9 q
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