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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:$ [+ ^7 {* n* H0 W! {& D( {. A

- ]' p0 w8 i7 _' O( G5 e public Object buildActions () {
& k+ B$ x) C$ K) Q9 r' b, I& Z    super.buildActions();
5 y! G6 |  v7 x: N) m% s4 j   
8 \% U) L$ z/ h3 ?3 ]    // Create the list of simulation actions. We put these in
! ]% t  n7 y' t$ v    // an action group, because we want these actions to be9 M& E: W, j1 p8 N0 I
    // executed in a specific order, but these steps should
0 u3 `; Q: g% M! Z7 _& S# L    // take no (simulated) time. The M(foo) means "The message7 N$ Q- I0 \+ `4 C
    // called <foo>". You can send a message To a particular
4 P$ p8 L; y* e6 e2 a& X& Q% Y    // object, or ForEach object in a collection.
) C1 J# w9 D. J! {        ( q4 y2 b7 M6 D+ d9 f
    // Note we update the heatspace in two phases: first run
* ^, m" C. i' Y- x/ ]/ G    // diffusion, then run "updateWorld" to actually enact the
% {! H( {7 m. r    // changes the heatbugs have made. The ordering here is/ w0 O1 E/ Z) h, C
    // significant!" C1 d- j& G& Z! k
        
2 Y: S" C9 D, F0 s    // Note also, that with the additional  |) X- F9 X5 w; E; m
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
. i/ r: [0 l- E. c    // randomize the order in which the bugs actually run3 {( q5 w: P* t  ], Y) @7 k: _
    // their step rule.  This has the effect of removing any
% I- Z3 K5 T+ C4 Z, b! t    // systematic bias in the iteration throught the heatbug  X6 k/ i0 M, U9 @, v: C
    // list from timestep to timestep
- x! e1 C6 w6 T! B3 u5 ?" b        3 k3 c  B" i8 {" T
    // By default, all `createActionForEach' modelActions have
! K3 E/ j* V, k! i8 m    // a default order of `Sequential', which means that the
: E6 m2 `0 [% j! ^6 W    // order of iteration through the `heatbugList' will be0 \( q0 Z; J" m" V0 |8 w8 O# t: H
    // identical (assuming the list order is not changed" l" |3 A. m4 G% r# D# D0 s
    // indirectly by some other process).$ @6 k! X' I. P2 A
    * T- j; ?2 {4 I5 w
    modelActions = new ActionGroupImpl (getZone ());  A. q7 U; D  N6 z3 N

9 C* |8 A+ V  h    try {8 {6 X& s) G8 J$ Q
      modelActions.createActionTo$message
! [7 D( M" D( b2 K* O; [( K* e        (heat, new Selector (heat.getClass (), "stepRule", false));
7 r; q5 B9 c) w1 y& I, B    } catch (Exception e) {
1 `9 I; @4 @( _, `# `* ?. d      System.err.println ("Exception stepRule: " + e.getMessage ());0 I" }; ~- H' V
    }& t7 @/ ^2 n% I# H" [6 C1 x

  x- Y- X: Z- Q" g8 N& t* `, ?+ V/ H    try {$ B8 V; c1 ?: T
      Heatbug proto = (Heatbug) heatbugList.get (0);
/ m. T: {" h, U2 P2 ?! ^& m5 }0 T      Selector sel = 0 u5 G! i, S) Z/ m6 k! H" g
        new Selector (proto.getClass (), "heatbugStep", false);  n2 ]' @) z0 ]" g
      actionForEach =- M: N5 a4 g* E: \/ _$ [
        modelActions.createFActionForEachHomogeneous$call" x7 T7 f0 P7 g8 L
        (heatbugList,! l) F- N3 e: \- s3 o1 K  E# [8 U
         new FCallImpl (this, proto, sel,
9 ^+ X: Z  A* U                        new FArgumentsImpl (this, sel)));
& ?1 A, L0 T' k( h' I9 u$ R    } catch (Exception e) {
( c: Q( `' D% N$ ^      e.printStackTrace (System.err);  @# a; Z# _1 {5 y. Z% K
    }# d2 }3 O; _1 o1 A# P" x
   
  i+ _9 B9 r7 p    syncUpdateOrder ();7 u" Z5 i; W6 r0 p* ~5 f3 |! M
; D2 H" f7 _5 z) M; ~  D8 c
    try {$ F! u; C# m! T  m5 i4 i$ M& E% B6 }
      modelActions.createActionTo$message
  t, F5 l  F2 {3 t( Q6 O( s        (heat, new Selector (heat.getClass (), "updateLattice", false));. P% S1 @+ T* _7 A* `1 u  ?& U3 x3 |
    } catch (Exception e) {3 m4 \) c$ X! r! B, N0 T$ v" U1 R
      System.err.println("Exception updateLattice: " + e.getMessage ());
- O" W" x# W9 O. b' L    }: R( J3 \2 R6 e
        
  ^# S- u! T8 i2 g, B- D    // Then we create a schedule that executes the
. Z; O) d/ s8 ^/ B    // modelActions. modelActions is an ActionGroup, by itself it: c/ k. i1 u. v8 l& ?) c, r# A' F
    // has no notion of time. In order to have it executed in
5 g4 V. B9 y5 \6 c; ~& C    // time, we create a Schedule that says to use the
, Z$ c, ]8 Z. o2 ]    // modelActions ActionGroup at particular times.  This
$ L1 x- T$ F! ~% ]& s5 h" V9 C5 r    // schedule has a repeat interval of 1, it will loop every
5 z* m7 M# T5 o" z0 U3 p6 q    // time step.  The action is executed at time 0 relative to4 V+ z3 a5 @/ b5 Q  k
    // the beginning of the loop.
0 t% x/ w/ _( C- l' {
5 _: S4 L, t! a7 O    // This is a simple schedule, with only one action that is
7 V" y4 W& g' m+ v6 S# c' [/ r    // just repeated every time. See jmousetrap for more
8 o  A0 N! F5 u: }# X9 I    // complicated schedules./ z" ^3 e- G9 j' u  r. F
  
9 B, W& {0 l4 |6 y. x$ [* T    modelSchedule = new ScheduleImpl (getZone (), 1);9 Z+ c# g. X) T
    modelSchedule.at$createAction (0, modelActions);
4 |, n& t+ \' H/ b3 {        
# w- B" s" n" I5 w2 N6 C/ [3 N3 s    return this;
$ b: ?( `+ G, ]  _  }
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