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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:3 ]/ [, j. A$ u0 r/ R7 S3 `; O, m1 Q

8 \7 L/ Z! N4 P2 ~. B9 o8 V1 u4 O public Object buildActions () {
6 v0 C- A/ K6 F  r* Z/ e* P    super.buildActions();
0 }+ V0 H7 h# ]8 ^, C5 r   
/ B4 z8 A+ o5 E& b& a% Z7 ~4 n2 Q    // Create the list of simulation actions. We put these in
* R5 Z/ p/ H5 g8 Q" f/ V% J    // an action group, because we want these actions to be* T4 l: C; @0 K& F
    // executed in a specific order, but these steps should: I0 C% i; h1 X5 U
    // take no (simulated) time. The M(foo) means "The message  m' T8 t2 W5 G; X6 J! n, {
    // called <foo>". You can send a message To a particular6 Y* ]) U# ]) N! ^
    // object, or ForEach object in a collection.* W8 ~8 _3 |2 Y8 _7 ?3 G- q0 Z
          s2 m* Z# S! m& P5 |" c" s
    // Note we update the heatspace in two phases: first run
9 X# t" i5 g* I. N$ A3 F8 M# p    // diffusion, then run "updateWorld" to actually enact the/ j' R2 _; M9 F, c
    // changes the heatbugs have made. The ordering here is
- U2 ]: G% R1 D# s" v    // significant!. o  m# S- M, r, q8 L: [
        
1 B* U! _: y  d% \1 T    // Note also, that with the additional' ]* K( h: L9 V+ h* b/ w7 k
    // `randomizeHeatbugUpdateOrder' Boolean flag we can! C- w5 o% z" `$ I+ q4 B% K: [
    // randomize the order in which the bugs actually run
7 W- F! U9 u: V8 Y/ ?4 `1 u! \    // their step rule.  This has the effect of removing any
& c) ?; c; m% M" Y  Q* T    // systematic bias in the iteration throught the heatbug$ |1 q; K7 Q* X+ J- ^
    // list from timestep to timestep
. `+ Y! z( W! c8 E# f+ F2 _6 ~+ g" K        
- c- {* H5 J1 F2 M/ Y( A: o: M    // By default, all `createActionForEach' modelActions have: b6 a! o0 n/ I& o
    // a default order of `Sequential', which means that the1 Q6 D; s4 A/ J" g3 d  K8 o: b
    // order of iteration through the `heatbugList' will be+ D" r9 G. ~$ c8 B6 h. o' t& D( v
    // identical (assuming the list order is not changed
1 z! Q# ^1 a8 b    // indirectly by some other process).
/ v7 z/ f* c( t' b, ?   
, g+ k; G; I$ j    modelActions = new ActionGroupImpl (getZone ());
0 l% V2 _2 b( m; s2 C6 P' Q4 ^
5 s1 C. |6 G4 {. \+ X    try {* I6 o3 S5 D3 a
      modelActions.createActionTo$message7 A3 j4 p- z. ]+ l  I* b
        (heat, new Selector (heat.getClass (), "stepRule", false));
8 X" P1 r; V9 G& h- C1 |$ p    } catch (Exception e) {
' t! ^( h1 t+ Q1 m0 T: c7 l' y      System.err.println ("Exception stepRule: " + e.getMessage ());
1 v% f! W& Q% O& v( @$ P9 Y    }/ ~! e2 Z. A' R" Q; g" ?- m( i
- A9 w1 f, y$ W3 u; ]& b* O
    try {( V) Y3 [5 a* s% o* W6 `# P6 h! u
      Heatbug proto = (Heatbug) heatbugList.get (0);. N+ J. ^  O+ P% H, ~2 t/ Q5 N
      Selector sel =
) p1 E+ D8 k5 S# s* p        new Selector (proto.getClass (), "heatbugStep", false);
& c: \. Y9 }2 V) l      actionForEach =
1 ~0 \  t: w2 ^  v6 H        modelActions.createFActionForEachHomogeneous$call
2 w- G: L- b- [8 Q- w        (heatbugList,
. R5 D: W: Y1 `         new FCallImpl (this, proto, sel,
7 m' x6 l& G. f# f$ l' o                        new FArgumentsImpl (this, sel)));6 T0 U$ |& X" z7 i4 z1 k0 p
    } catch (Exception e) {7 V, B" ~, d" C; S
      e.printStackTrace (System.err);; C0 m3 n- E  V$ u6 ]! z5 E7 {
    }7 V' o9 `% D7 B  c" ~
   
/ \' }+ f. J$ `: b    syncUpdateOrder ();
% C! D! u" V9 c& P. L( Z% M  A9 K- E
    try {
1 j0 u- v" |+ M/ M1 ~$ _- j      modelActions.createActionTo$message & R9 R& L% o  m, Z1 e
        (heat, new Selector (heat.getClass (), "updateLattice", false));
, J4 S$ f6 n7 j. |$ ~' ]3 R. N    } catch (Exception e) {
, p' i0 U, G/ A5 e1 _      System.err.println("Exception updateLattice: " + e.getMessage ());
6 g2 O6 K& A7 d    }
  V5 R4 Z* l" y! e        . c/ s$ R, K% U' j; s
    // Then we create a schedule that executes the
8 S6 y4 B2 _: R1 V) m6 p    // modelActions. modelActions is an ActionGroup, by itself it/ X* v- @# ]+ Y7 ]2 v1 k7 ~4 M( N
    // has no notion of time. In order to have it executed in
$ K% H/ k1 p- S. D) `    // time, we create a Schedule that says to use the" X! Y$ p8 E( S8 i8 B) |
    // modelActions ActionGroup at particular times.  This
, V8 l* S4 Y( s$ o2 `5 l. ^    // schedule has a repeat interval of 1, it will loop every4 M" l" P( m, ?% f! D
    // time step.  The action is executed at time 0 relative to2 G. M/ T' ~- E0 @1 @  [1 G" Z
    // the beginning of the loop.( F/ T6 f2 Z+ ?  c2 M( m+ L

- M1 a) }! D3 V: C    // This is a simple schedule, with only one action that is0 V9 G) d2 M. S2 X. C7 t( f2 q
    // just repeated every time. See jmousetrap for more# s' c+ K! S5 E% ~: J4 Z$ F+ X
    // complicated schedules.) I: e5 ~; w3 I4 i
  
* ~( g0 h) L  n/ a5 V. `/ R( Y; W    modelSchedule = new ScheduleImpl (getZone (), 1);
- v2 s4 `2 ^  h8 n4 y    modelSchedule.at$createAction (0, modelActions);
% R+ f' P( C  z/ l        & j+ |; q0 z4 Z  T" \) k. @
    return this;9 ?/ B. z: Y7 ]5 `' u+ H$ V6 p+ [# S
  }
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