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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
2 ~! s# T- P4 M1 a1 J$ ~% d5 T# ?$ E3 {& ^/ ]
public Object buildActions () {
' x& c1 I6 E( b, x* N( B* U    super.buildActions();4 x' F/ I' ]; j0 E3 ]2 Z0 q
    7 ]( {5 H% I3 s& I
    // Create the list of simulation actions. We put these in  b( d8 a1 _# k+ O' O( ?: T9 g
    // an action group, because we want these actions to be4 t, M) w' \9 q/ R  e  Y" r5 y, M( V
    // executed in a specific order, but these steps should
3 G- ?+ T8 f- A5 o; \    // take no (simulated) time. The M(foo) means "The message; a& J, w7 d$ b! a
    // called <foo>". You can send a message To a particular- m; z2 H& A. ]1 Q; j9 f! G( m) e
    // object, or ForEach object in a collection.
2 ^+ |0 O, e3 F! G0 i/ r        
- \! x3 P& Z/ z# h2 [& ]    // Note we update the heatspace in two phases: first run& h) `( c/ u5 B& ?
    // diffusion, then run "updateWorld" to actually enact the& O8 Y" F* O+ h# ~4 o8 b
    // changes the heatbugs have made. The ordering here is( f; ?( T2 c$ J$ T5 W& k
    // significant!
" K: {0 `) w1 U4 u% l, G        
9 x% b# D: e5 s3 G* O0 L6 q    // Note also, that with the additional
4 N- X6 y" v/ r  t& {    // `randomizeHeatbugUpdateOrder' Boolean flag we can8 f( F9 i6 j3 ~8 s
    // randomize the order in which the bugs actually run- W( |0 e" s( r( p/ K
    // their step rule.  This has the effect of removing any
! V+ V& L: x1 S7 Q$ E2 t: G    // systematic bias in the iteration throught the heatbug6 _% o( r$ x: ^+ l( i. v) o8 J3 M
    // list from timestep to timestep
( _' o  ^! s+ `1 _2 k5 W1 n: l& S& [        
  [, g) g4 r0 P5 C! p9 d4 w    // By default, all `createActionForEach' modelActions have9 h1 i1 r/ U6 G& N
    // a default order of `Sequential', which means that the- L0 I% ~0 D& O  f: h
    // order of iteration through the `heatbugList' will be. f$ |; {: v7 _  k' b1 X2 z
    // identical (assuming the list order is not changed) \! s6 Z; X/ z/ H! v6 v* h
    // indirectly by some other process).
( e. v6 h1 U& t; C. Q    1 H) p% F7 I) O9 [& ]$ \! ~$ Z
    modelActions = new ActionGroupImpl (getZone ());( I& A: X3 g% v/ d, {5 T* H
1 z: z  D. c  ?2 Z7 n0 \
    try {8 E* ^; o+ ^+ @3 w" q
      modelActions.createActionTo$message. l# g* v1 O$ O
        (heat, new Selector (heat.getClass (), "stepRule", false));
& K7 J; M  s* c( R, h1 I    } catch (Exception e) {
) X& e/ w1 T1 b! b5 Z      System.err.println ("Exception stepRule: " + e.getMessage ());, v3 i5 V3 s( H7 Z0 g
    }& l9 j" |* v+ F" _- g

- E, {1 D  I" \$ t    try {
* E- U/ u) B- w7 G% p      Heatbug proto = (Heatbug) heatbugList.get (0);! Y# I! F' A' g
      Selector sel =
& ]& s0 ]/ @# D+ C5 l  F) J        new Selector (proto.getClass (), "heatbugStep", false);
$ e" V; T% D, k! k& C* ^      actionForEach =
, e% v. [& l, S5 x4 W        modelActions.createFActionForEachHomogeneous$call
2 r! o; b2 D( N        (heatbugList,! E, P0 n# g: ?6 m4 g, V# ]
         new FCallImpl (this, proto, sel,/ I, r+ U4 P( q) X( k: M
                        new FArgumentsImpl (this, sel)));
( g/ W7 k) Z% ]: J    } catch (Exception e) {
2 D- R/ x: j7 b7 E+ m2 z+ {      e.printStackTrace (System.err);7 q1 P' D9 p0 r& Y: Y9 [' L
    }/ S, s# A% u0 o
    ! k3 p. ~( @+ X, `1 E
    syncUpdateOrder ();% v+ }( T( O" y6 k7 `, x

; ~! _6 u* W3 [1 g9 ~' Q# Y! o    try {* W/ _& u, ^4 g% R% K/ R# ~2 C
      modelActions.createActionTo$message 3 F- I" i3 E! G4 G7 r; A9 Q. Z
        (heat, new Selector (heat.getClass (), "updateLattice", false));
) ~1 W0 P8 o0 w    } catch (Exception e) {
! M# Y* i, f3 k) P      System.err.println("Exception updateLattice: " + e.getMessage ());* F2 O$ g" p& Q
    }
6 q/ O4 ]# P5 P: e9 }8 u/ L" f) Q        / _* m" p( ^- o* r1 k! U* j% R
    // Then we create a schedule that executes the
3 p2 k4 F7 E/ z9 [8 l/ Z; R    // modelActions. modelActions is an ActionGroup, by itself it
  b  M7 k; I6 z( ?6 p& H" d) z    // has no notion of time. In order to have it executed in. E2 b6 ]5 @+ c5 h
    // time, we create a Schedule that says to use the2 Y7 C) R. z4 y% W, ]
    // modelActions ActionGroup at particular times.  This
) y$ Z8 p7 }4 t7 b    // schedule has a repeat interval of 1, it will loop every
- E9 h8 E; c% _! ^% k: s9 w% ?    // time step.  The action is executed at time 0 relative to
. B2 u8 L: v5 ]5 q    // the beginning of the loop.; [* R1 _' a8 r/ U* @
$ r/ E9 X4 E% g$ O3 n6 y
    // This is a simple schedule, with only one action that is
4 ]3 X$ l; @, W/ z    // just repeated every time. See jmousetrap for more5 D& H6 C4 T6 ^
    // complicated schedules." p/ c7 H3 q  u: e2 [& h
  5 _! v' L) `( f$ B+ X
    modelSchedule = new ScheduleImpl (getZone (), 1);
+ @+ f& }1 H" |6 k% `% p8 G) E    modelSchedule.at$createAction (0, modelActions);
" z! ]+ A/ K8 T1 ?        
; R1 ?, I; W+ s# t: `    return this;. @+ O/ U& z+ H4 k. w
  }
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