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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:( L) X3 ~, w2 m2 g& }

9 `: b$ ~0 Q6 X4 W public Object buildActions () {6 }, s7 ^1 x- `5 T' h4 t  I; f# x
    super.buildActions();$ n' D: N2 R! R6 A' I( T% k
    7 \" J, y1 S$ p3 ]  ~$ D
    // Create the list of simulation actions. We put these in3 g# Z6 z* b# V) D
    // an action group, because we want these actions to be
/ m9 n& {% N3 f- b" }$ [    // executed in a specific order, but these steps should
6 H& |" b# Y9 o9 X, U    // take no (simulated) time. The M(foo) means "The message
2 Z! A! e5 ]. V! ~& @1 q- f    // called <foo>". You can send a message To a particular/ R+ w4 C' m( M, S
    // object, or ForEach object in a collection.
. B4 ?1 ^9 J* l' [- h        
- Q: c8 O5 W+ T/ d7 o    // Note we update the heatspace in two phases: first run
/ |; j  |8 m+ y9 l+ r    // diffusion, then run "updateWorld" to actually enact the
+ [% j5 Y" K! a" s    // changes the heatbugs have made. The ordering here is
; W# W+ P. e  r' X" N0 {    // significant!
3 k9 f: O/ J, k. X! R4 ?        
1 q9 X- L5 G! v    // Note also, that with the additional: x  H/ ]9 ?$ f9 g
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
# V1 u# a& T% t    // randomize the order in which the bugs actually run/ }  i+ _! w) Z) C! T
    // their step rule.  This has the effect of removing any
% ~1 W. O  M9 t* S/ g    // systematic bias in the iteration throught the heatbug: U6 |0 N3 h# |6 r
    // list from timestep to timestep
0 s) W+ U2 \" U        1 K& @( j( L  _; M- Z
    // By default, all `createActionForEach' modelActions have
% v! x9 \$ R' _5 F) N    // a default order of `Sequential', which means that the
: ?/ h* [0 }$ f  t/ A- g9 \/ d    // order of iteration through the `heatbugList' will be
% b0 K6 Y; H6 v, J/ V* M    // identical (assuming the list order is not changed! a8 }* O9 r: ?4 g$ {8 Z2 W
    // indirectly by some other process).
" _7 t" t2 e, e" V! e   
& I2 ^4 L) ^& `; t5 Y! v    modelActions = new ActionGroupImpl (getZone ());
9 v: K9 D) o: o% q4 I4 K0 D6 U, F$ G
    try {) A6 ~1 [, r# k& u  p
      modelActions.createActionTo$message
, _  i4 p. y/ C$ e        (heat, new Selector (heat.getClass (), "stepRule", false));8 q1 R' D" e* ^4 z" W  O
    } catch (Exception e) {
. Z* [* v* |" t      System.err.println ("Exception stepRule: " + e.getMessage ());
7 u! X0 ?) q$ u2 y    }
+ s3 p7 Q) |, w) u6 s! h9 L+ }! {( D
    try {
) Q0 i8 P2 f3 z      Heatbug proto = (Heatbug) heatbugList.get (0);
  e* J& J  g8 ]" Z& U" p, \) N      Selector sel = 8 U6 \1 N' V) D1 a
        new Selector (proto.getClass (), "heatbugStep", false);
) x# b+ H+ R6 x) R  o$ g2 H/ [      actionForEach =& \1 o7 |% q5 h* A" G% l; @- ]/ p. E/ V
        modelActions.createFActionForEachHomogeneous$call
, _$ h9 z+ \. W7 V: L        (heatbugList,% d7 K# H! m$ f$ x
         new FCallImpl (this, proto, sel,
7 h0 Q2 [7 ~9 T                        new FArgumentsImpl (this, sel)));
4 |5 \8 @5 i5 A2 L    } catch (Exception e) {8 _6 A5 T3 [) N$ c# \
      e.printStackTrace (System.err);
" A$ Q% U0 I2 W" m    }- Q5 T# l* y2 y8 C4 v2 T. P( r6 h
    ; K6 l% Z3 }$ m+ V  Y
    syncUpdateOrder ();
5 r% s! X& o( `5 l6 A5 L2 N0 X1 i0 }! M# i+ y/ _, O4 t
    try {# h( e: t) r5 i' P/ T
      modelActions.createActionTo$message
' U3 Q' U7 P3 m" B        (heat, new Selector (heat.getClass (), "updateLattice", false));
7 Z+ Q0 P2 c" n, L3 B$ z4 ]3 G    } catch (Exception e) {- A" \( n8 F* _, N
      System.err.println("Exception updateLattice: " + e.getMessage ());: y* N& f. [7 L1 N& g) U$ S4 b
    }
0 U% {2 l! K8 w        / u( N& c* y1 _
    // Then we create a schedule that executes the
% ^5 Y, w0 Q+ Y; @0 I. Q- U    // modelActions. modelActions is an ActionGroup, by itself it
, Y- c! T# Z* ]. b; x6 M( G    // has no notion of time. In order to have it executed in
/ e; @8 G; P+ Y/ F9 y    // time, we create a Schedule that says to use the. H' p( q( h" i4 h1 i
    // modelActions ActionGroup at particular times.  This, P2 j8 s. @+ @( y/ X
    // schedule has a repeat interval of 1, it will loop every# C) I: ^' I( G
    // time step.  The action is executed at time 0 relative to; V  N$ }$ o$ z7 Y, L1 e+ `, l, s
    // the beginning of the loop.  I& r5 |  J* L, d4 \& l. q0 J

7 e! w" X, ^# p+ t/ _" N: a+ _8 i    // This is a simple schedule, with only one action that is
4 U- M7 L/ j) H/ V& j    // just repeated every time. See jmousetrap for more- T, a3 J2 @. N- F6 @2 b
    // complicated schedules.
( q9 b& c+ o3 `  @" K) Q  
* k0 N( ^1 M) q, E! D2 x    modelSchedule = new ScheduleImpl (getZone (), 1);
6 x+ Y; Y% O' b- c7 e    modelSchedule.at$createAction (0, modelActions);
; B, A; X; J/ h0 f        + k: @  J  m) `4 B! f) O
    return this;* d. ~% X3 p% ^4 k4 U3 x
  }
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