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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
& v3 f  m, I# g1 T- [& W4 ^5 V, N: m, c, E$ Q+ U; A* {" I4 ?
public Object buildActions () {7 L& v( J" w2 z' Y
    super.buildActions();$ W1 p; v' ?/ `
    ( `% s/ R7 t, t
    // Create the list of simulation actions. We put these in8 U: p1 V* }- m) B* r- a, i
    // an action group, because we want these actions to be: R, X5 G1 x% G1 W$ v
    // executed in a specific order, but these steps should
' Y2 ?; |- O$ o! m: F/ l    // take no (simulated) time. The M(foo) means "The message
* B7 T( l" G, a6 E# l    // called <foo>". You can send a message To a particular# @- _6 p8 x1 ?1 B5 Y
    // object, or ForEach object in a collection.
, B; u2 p5 c0 B( P! F& p0 G3 h( E        3 b2 b3 A. s  _
    // Note we update the heatspace in two phases: first run
: S: h) H/ z5 A6 R* N# R    // diffusion, then run "updateWorld" to actually enact the
3 s) M& O/ z" J5 |' g7 _    // changes the heatbugs have made. The ordering here is
: m& P$ |/ s2 _# ~; `9 J+ k    // significant!( ^0 f4 b3 X7 H5 K7 n) J! r
        1 \. k$ C% m. z/ |- M+ c
    // Note also, that with the additional2 J8 C" ^. a5 `2 ]
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
) O' Y4 e# `# ^    // randomize the order in which the bugs actually run# r$ Q+ {8 O* Q9 A1 [3 a8 M
    // their step rule.  This has the effect of removing any/ X" u# l9 H+ M) D# _2 g; x1 w
    // systematic bias in the iteration throught the heatbug  D$ o0 K' ?  F, e8 ~( q* ?
    // list from timestep to timestep
/ {( h/ e* f! `5 ~6 S* l3 i6 @        # c/ c1 R( D8 C" Z! v, A- B
    // By default, all `createActionForEach' modelActions have2 J( D( h4 t1 a' ~; m
    // a default order of `Sequential', which means that the
: y' ?$ Y8 S, _2 N    // order of iteration through the `heatbugList' will be0 c1 h  h/ C! x# G" c5 V
    // identical (assuming the list order is not changed* ~. p6 D  k5 z* U0 V  [
    // indirectly by some other process).
2 w7 w% e. ~: w% s& Q8 `) p  B$ ]    4 V* H6 }* H0 c
    modelActions = new ActionGroupImpl (getZone ());
7 B2 d7 ^0 o% p& w& [' g1 D
& f! z* _: m4 W    try {8 w6 Z4 c5 l, `5 J
      modelActions.createActionTo$message
! j3 \# w; c0 X. Z6 A. L" P        (heat, new Selector (heat.getClass (), "stepRule", false));
: ?# J! }% n  x    } catch (Exception e) {
" S, I7 B3 y. b/ p# Z, c      System.err.println ("Exception stepRule: " + e.getMessage ());
! _% v2 j5 K& G7 F2 x" G    }$ Q9 Q$ |# L% ]! X  d5 J

9 G  Z) t, v0 E3 k( [$ a    try {
4 T: h# s& D8 }; ]8 g7 b      Heatbug proto = (Heatbug) heatbugList.get (0);" v9 d7 d. u% [+ B# V' H; N4 H
      Selector sel =
) H+ v7 W' S! f# e- e        new Selector (proto.getClass (), "heatbugStep", false);& X, F& \9 X( U
      actionForEach =
9 l. F+ I" M8 g5 M7 Q$ ?        modelActions.createFActionForEachHomogeneous$call8 q$ x8 ]7 D1 g* y+ c) A
        (heatbugList,
, j( ?0 A2 e! G, b, ]         new FCallImpl (this, proto, sel,
7 K+ z1 H0 r- H- b" n8 S                        new FArgumentsImpl (this, sel)));
& v8 _- e% r+ o: a6 t( ~4 r    } catch (Exception e) {9 B/ f& l9 V9 E0 K9 z
      e.printStackTrace (System.err);
% ?5 X7 F4 D# X& v2 J( N4 \9 v    }; T: F7 v, @: }0 L
   
' D' ~% D$ D7 j) E( D  b- e    syncUpdateOrder ();7 B- n) @, k  G9 h: l' {% k

- S/ _+ O( O9 |9 R6 \, V8 |( f    try {
! B( q  u0 O: X0 R3 M2 }      modelActions.createActionTo$message
3 v$ ~/ v4 L- ^9 D  `3 }        (heat, new Selector (heat.getClass (), "updateLattice", false));
5 d( q* b) a2 I9 D    } catch (Exception e) {2 \, G3 Q" S2 M* @- m' G' l
      System.err.println("Exception updateLattice: " + e.getMessage ());7 k$ T3 e7 _( J8 B% d2 ^4 ?
    }
/ s& @: U1 m5 g( K4 V        + f4 Z; b9 W5 V6 H& I
    // Then we create a schedule that executes the( j7 Y9 v. [. u. C7 Z1 ~
    // modelActions. modelActions is an ActionGroup, by itself it
) m, h8 g6 m4 {: j4 p1 N4 K    // has no notion of time. In order to have it executed in
/ w6 Q/ _2 T* p    // time, we create a Schedule that says to use the0 b: ~8 M+ u6 z
    // modelActions ActionGroup at particular times.  This
+ ]1 L* i$ }* B* T9 k    // schedule has a repeat interval of 1, it will loop every8 ~" v, g! ^7 m& m8 X0 y
    // time step.  The action is executed at time 0 relative to
% \9 f7 q* n6 Z2 P) S* _    // the beginning of the loop.3 u4 X6 o: R- R$ H& m  Q
+ ^, q& ~+ P- w2 @
    // This is a simple schedule, with only one action that is" D) ~/ c# I8 f. s2 O$ Y( i/ a/ J8 w
    // just repeated every time. See jmousetrap for more$ h0 Q$ p: Z  [: h" B
    // complicated schedules.# c9 N  y5 {/ F6 g8 x
  
: j! [1 v- Q) p    modelSchedule = new ScheduleImpl (getZone (), 1);, C# k. N5 m/ y
    modelSchedule.at$createAction (0, modelActions);% }3 X+ M( K( d& z1 s0 B
        # J* a8 L8 A9 k" P3 B, Y
    return this;- t2 n0 R* `3 D7 \) B
  }
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