HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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6 L0 b5 b- y& w; _! s) L public Object buildActions () {$ R* r# ^( G& f
super.buildActions();& B! c; G! x+ T6 M
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// Create the list of simulation actions. We put these in
1 n2 k' q7 Q5 `. p6 f // an action group, because we want these actions to be
& I9 V y% S( V: A5 y0 h // executed in a specific order, but these steps should2 B4 ^: H! X3 u* w, i2 q$ d
// take no (simulated) time. The M(foo) means "The message% C7 y4 x( h5 P7 H* I: ~
// called <foo>". You can send a message To a particular
; D6 V. e8 L* G# S. [ // object, or ForEach object in a collection.
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. F! ^. p2 E1 S# i) [+ Y // Note we update the heatspace in two phases: first run
^) b. R5 K# K4 ]" f: o // diffusion, then run "updateWorld" to actually enact the( ^- }7 X/ @) Y+ \; C
// changes the heatbugs have made. The ordering here is n# q& n$ d% d' G$ d
// significant!9 \9 H/ n& C# D: _- b) m
/ Z8 R8 I* d& m6 [/ B // Note also, that with the additional
- E% U- g* N! s0 t& X // `randomizeHeatbugUpdateOrder' Boolean flag we can( q9 d9 R& q' _ v: u" q
// randomize the order in which the bugs actually run- M. J' @2 V0 m8 p" f8 ^
// their step rule. This has the effect of removing any; @9 n- \3 u3 C. y4 |2 z5 N& @( V
// systematic bias in the iteration throught the heatbug y$ U5 B5 v; x& G
// list from timestep to timestep: t7 f# }6 @0 V& ]2 {
6 j2 u1 ~7 Z6 G; O4 k+ a( @ // By default, all `createActionForEach' modelActions have
0 k) r. {+ @+ H // a default order of `Sequential', which means that the1 e3 I( R9 S8 W; V0 ^2 C9 A& o
// order of iteration through the `heatbugList' will be: j$ M: e: t: [7 O& s
// identical (assuming the list order is not changed
& Z5 {, Z9 x. L: D, i // indirectly by some other process).
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3 `: n/ o; R/ [: }: i modelActions = new ActionGroupImpl (getZone ());
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try {
) v/ i) p* I0 @8 \( s& b; ` modelActions.createActionTo$message
: q6 X& R9 n0 ~; s4 U (heat, new Selector (heat.getClass (), "stepRule", false));
4 n! {1 H* _5 O/ @1 Y- {3 j } catch (Exception e) {: e5 Z- x! p/ ?* a3 S1 e6 Q4 c$ ]- k
System.err.println ("Exception stepRule: " + e.getMessage ());9 N5 j3 Y1 i" U
}
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0 |0 U, a6 f- |4 d; U* s try {
2 v& [0 Y$ S, f x) o8 n$ J Heatbug proto = (Heatbug) heatbugList.get (0);
( u/ D7 R# C2 ~1 F- M Selector sel = ! f3 q0 i9 Q9 f& V
new Selector (proto.getClass (), "heatbugStep", false);
8 D3 S: w! C/ M1 c2 S actionForEach =
. r7 N% `) `$ a2 v' b/ M, |/ l modelActions.createFActionForEachHomogeneous$call4 h9 ]; B3 v3 s' u6 t& L; W
(heatbugList,+ G! M) C: Y. n0 m1 c
new FCallImpl (this, proto, sel,
9 F% K. e6 `9 N* S1 J new FArgumentsImpl (this, sel)));
5 j6 K# q3 x( ~% D } catch (Exception e) {
+ d" o3 P' v0 e- O. b$ } e.printStackTrace (System.err);
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syncUpdateOrder ();
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try {9 h7 V0 w, t, D R, U" w | {9 G
modelActions.createActionTo$message
8 P4 _; p: I0 v* f3 n# I# x5 R (heat, new Selector (heat.getClass (), "updateLattice", false));
8 e9 W) ~1 _% m" O9 M0 b } catch (Exception e) {& y* ]% g' g: h4 U$ w; S
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the
$ I$ V, B' N- O3 q; S: v // modelActions. modelActions is an ActionGroup, by itself it: Z* C7 }3 n8 z7 p* F' M" }* a
// has no notion of time. In order to have it executed in
% w, p! ?: E* W2 }; a4 } // time, we create a Schedule that says to use the7 u) e- x j+ {, B& P& i
// modelActions ActionGroup at particular times. This
5 a; B& e2 A8 s // schedule has a repeat interval of 1, it will loop every
. F# s. I: N9 Y# { // time step. The action is executed at time 0 relative to2 V' T. e5 q$ T1 }2 [
// the beginning of the loop.
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// This is a simple schedule, with only one action that is
6 h! l/ c8 c' S9 Y+ F" M% G // just repeated every time. See jmousetrap for more) g7 a; L* [2 e" Z& w. c3 e0 T
// complicated schedules.3 y: ^9 D* Q5 U( S5 ?
6 _6 Z7 c. s+ ?) {
modelSchedule = new ScheduleImpl (getZone (), 1);: d0 ^7 R* {% U6 s$ @ w
modelSchedule.at$createAction (0, modelActions);3 B) ~8 ^. `9 q" P3 F
, f. i/ b0 E; H& D" e return this;
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