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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:: |3 r" N8 ~% F, m7 `2 p5 b

4 L; b+ n/ E2 F# i public Object buildActions () {
, X( P% }! o) R/ P% s    super.buildActions();
9 Q; q# _0 ?. k   
& H# E; m( _/ i' e) g    // Create the list of simulation actions. We put these in
9 t0 p1 X, Z0 ]; z. i# ^; @    // an action group, because we want these actions to be
7 a# E$ J7 [& x; m% `    // executed in a specific order, but these steps should
' R8 n( q* B( z; J. N% b6 ^3 r+ O0 h    // take no (simulated) time. The M(foo) means "The message1 z4 i$ C( E' m: [, L; _( F# n9 R" X1 E
    // called <foo>". You can send a message To a particular
" I7 c7 b0 v+ f# S- ^- c; _. c" x, \    // object, or ForEach object in a collection.
+ w4 m' Z: J5 H0 v7 H& O  `% ?        ' {% o# H; I8 M4 J$ E( r. u/ @
    // Note we update the heatspace in two phases: first run
1 X8 Y. x& N( ^! F    // diffusion, then run "updateWorld" to actually enact the$ L/ S1 G3 g7 Y! l$ A
    // changes the heatbugs have made. The ordering here is
, `) G& H  _* F    // significant!1 ?& H) ~% L8 \; i
        
& H7 m8 S+ g( `# U: b3 P    // Note also, that with the additional6 d0 C5 M5 C2 W5 A. G) R5 C3 l5 l# @) }
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
$ q9 x$ o3 c3 j    // randomize the order in which the bugs actually run
" m4 D) ?+ n6 |& ~6 d# q    // their step rule.  This has the effect of removing any4 s. J. `& `+ J4 c( D/ [- M/ b
    // systematic bias in the iteration throught the heatbug- Z/ j: Z+ ~( k% t8 s
    // list from timestep to timestep
" s& n  K7 \9 n        
! G4 M4 ^+ n. D1 h2 `. M    // By default, all `createActionForEach' modelActions have/ j% _  |0 ?+ v7 j
    // a default order of `Sequential', which means that the8 v+ `8 w: P/ @( q* [- T' g) I
    // order of iteration through the `heatbugList' will be
4 E. N- \6 C& ?+ y* T" e    // identical (assuming the list order is not changed
  j/ r. {1 i# b8 q" l    // indirectly by some other process).# K% G9 h9 E/ ?- b4 f' @
   
7 C7 y" l0 `, b! @. h4 P    modelActions = new ActionGroupImpl (getZone ());
% _2 u7 |" x& g# i) Y# h7 N
2 i3 a" [. V' ~& Z# X    try {6 r7 ^' r/ O/ b- k( u) c
      modelActions.createActionTo$message. T  h; @6 Z2 o" g
        (heat, new Selector (heat.getClass (), "stepRule", false));
4 h; W0 z- V8 F6 c: O    } catch (Exception e) {" N+ B5 Z* B9 P& D, W+ t
      System.err.println ("Exception stepRule: " + e.getMessage ());
0 y( d. o- n, {- t7 L    }
6 U# e3 j4 p) i7 t& w! j4 C& g! j# r
    try {$ U5 W3 C. g& F% R' z
      Heatbug proto = (Heatbug) heatbugList.get (0);
' u3 ?7 S* {- A$ `6 u      Selector sel = 6 n7 @) H3 B4 B! p  [6 ]- ~9 _
        new Selector (proto.getClass (), "heatbugStep", false);( m* L. @& W1 k8 m8 V; ~
      actionForEach =
- R9 O3 e- ]5 L8 Q0 n7 W        modelActions.createFActionForEachHomogeneous$call
7 O, K9 I  d! f        (heatbugList,
, a8 G( G2 Z$ e# d  k; a/ u         new FCallImpl (this, proto, sel,3 C& o4 F) H6 J+ p3 V8 s
                        new FArgumentsImpl (this, sel)));
8 k/ U- N3 ^* u0 k* |$ z  w3 v    } catch (Exception e) {% S/ \7 E% ]1 o! y- b6 E! M2 s
      e.printStackTrace (System.err);
9 Y- ~/ `# Z; b) J2 m    }
) J* x; p/ R. h/ t! p3 Q   
8 g, R: [& Z4 b8 c% q/ f    syncUpdateOrder ();
: W7 X  K7 l9 v# Z7 U" n! g5 j2 X  G8 X! \
    try {7 W( _; F9 s8 y% N" F. t
      modelActions.createActionTo$message
6 J/ L1 T' u# \) ]1 n        (heat, new Selector (heat.getClass (), "updateLattice", false));: \' t. R1 [% }2 k! q3 R/ H
    } catch (Exception e) {
( Y) J8 U7 H* N% }+ ^5 @      System.err.println("Exception updateLattice: " + e.getMessage ());" [' p! l: |# Y
    }
# o8 V- z* p% {+ a        
0 b2 b4 A+ H2 E+ [5 T" ^& I8 G    // Then we create a schedule that executes the  j1 |8 L% Q2 h- J* e
    // modelActions. modelActions is an ActionGroup, by itself it
! |( o$ a+ z; P" B1 B) W    // has no notion of time. In order to have it executed in! ?2 A# D9 e; o. T
    // time, we create a Schedule that says to use the
6 D% `$ _# R! V: {, v    // modelActions ActionGroup at particular times.  This
) U, O9 ~5 ~* }; d( D# I    // schedule has a repeat interval of 1, it will loop every
9 v9 }/ s8 g" |, J. h5 d# J/ C5 q    // time step.  The action is executed at time 0 relative to! _5 Q2 h$ z+ I1 Q
    // the beginning of the loop.
$ z* T. f$ E  _3 ^$ F( j
$ Y! G+ V! X2 \0 w$ r3 y    // This is a simple schedule, with only one action that is- \) G2 j5 n8 [
    // just repeated every time. See jmousetrap for more" E+ J. ^! h* k8 ]8 k
    // complicated schedules.
' c! N2 y' V' b  G, }5 ^; C+ h/ j: d  
" J! L" f" q+ F" b    modelSchedule = new ScheduleImpl (getZone (), 1);
4 E" C: W+ O. c; Q+ \    modelSchedule.at$createAction (0, modelActions);9 Y  ^2 T' G2 m9 l  u# r# c
        - x/ E6 K& z! D* J: c  W$ j* N
    return this;
* T9 J; ?+ n4 ^5 \) ~/ ?3 K3 x  }
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