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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:5 q/ t% V6 ]/ I* b! O- q

5 G7 f, i: C) x+ l% L/ R% h public Object buildActions () {  _: G5 q* `0 g) E4 H/ o
    super.buildActions();" d0 W; m4 F& S
    + k, I1 X% `4 g2 ]6 P- g
    // Create the list of simulation actions. We put these in3 I. A3 W! c$ Q. X0 o. U* T: c% d9 Y
    // an action group, because we want these actions to be( H: q+ u6 O4 q2 a* Y' _: y2 a8 T: H% ^$ P
    // executed in a specific order, but these steps should
. f" }% M9 |. s    // take no (simulated) time. The M(foo) means "The message2 b; N: ]# N( H! T2 @
    // called <foo>". You can send a message To a particular
, c- E# C# k6 _0 l. \. J    // object, or ForEach object in a collection.7 {5 H/ B! S" y, O/ r7 y6 y
        1 Y' P& f8 o) q# F
    // Note we update the heatspace in two phases: first run
9 ?. J! Z" A& |( B5 L, s    // diffusion, then run "updateWorld" to actually enact the  w! \, T: r! n! h
    // changes the heatbugs have made. The ordering here is; a/ n3 H0 r1 L
    // significant!5 c$ u4 x. m* @3 m
        * L- S; e0 p' I9 J8 q! r
    // Note also, that with the additional5 M6 k* z, Y$ R$ _2 c6 g' e
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
+ E' C0 M  W7 w+ Y    // randomize the order in which the bugs actually run
0 n5 a8 v" S4 g    // their step rule.  This has the effect of removing any% `. ?7 F) j! s4 `- _( ?6 C  A
    // systematic bias in the iteration throught the heatbug
5 q" ~9 a- r" h9 y8 ^& O3 N1 E    // list from timestep to timestep
( B$ q: X& h6 E$ ?5 a8 n, \        2 n: m" j4 p# v! Q9 F  N# K
    // By default, all `createActionForEach' modelActions have
6 K3 ?/ R# E# o& `  ^    // a default order of `Sequential', which means that the
) K# ^1 V" G) o- Y0 `3 }5 d    // order of iteration through the `heatbugList' will be
2 c2 o5 [* v  k. L    // identical (assuming the list order is not changed
& H: B* D6 O! b, e5 O    // indirectly by some other process).
1 G7 j5 y) t) w( R- a    ) U( B( u0 `8 q, @
    modelActions = new ActionGroupImpl (getZone ());
( ?& ^' R9 }3 T# _; B" }
3 b5 ?* K* y+ T+ k: N7 M+ ]( {    try {
  X/ w) }# Y: k: J( i      modelActions.createActionTo$message
* S! v6 G) B3 F, C        (heat, new Selector (heat.getClass (), "stepRule", false));' l+ V, T! j" t3 X
    } catch (Exception e) {
' l2 M, p( r1 e+ {/ I$ I      System.err.println ("Exception stepRule: " + e.getMessage ());
/ G5 \& L( y1 z5 J) O, G, |    }
" G0 W5 q& L; P  t$ U0 t& l& g" p' ?) p4 O
    try {! N' p' s- _5 r5 H2 `+ K
      Heatbug proto = (Heatbug) heatbugList.get (0);
; p/ m$ H! W) F2 k) C      Selector sel =
) }% h( J/ y' ]1 ~        new Selector (proto.getClass (), "heatbugStep", false);3 }# }$ Z* O7 f" U8 z
      actionForEach =; f3 O$ O* g# @* K8 w0 s+ s1 g
        modelActions.createFActionForEachHomogeneous$call
4 e+ h' Y, e) d8 _" _; V3 e        (heatbugList,
/ Z: s/ Z+ C" a) S7 J( L" W         new FCallImpl (this, proto, sel,
- L; ~# X4 O3 W* @4 X                        new FArgumentsImpl (this, sel)));
6 }* U/ a. R2 ^, n8 e8 w: T    } catch (Exception e) {8 O3 i( O3 v  ]4 _
      e.printStackTrace (System.err);) N- o. M0 j' d0 M) m( G
    }$ U( k% P5 F1 g% c
   
, F( B! P8 B9 y! A: e7 F& N( B    syncUpdateOrder ();
* E- z, c7 o. i5 [
2 B. f/ l5 [5 Y( d2 j    try {
: }0 S( v2 i; i      modelActions.createActionTo$message
8 s+ E. b  e7 C1 w9 }4 \        (heat, new Selector (heat.getClass (), "updateLattice", false));
2 s8 Q0 [& X' t+ m. K0 P: a, C8 G    } catch (Exception e) {# v! {5 d  y! S8 r
      System.err.println("Exception updateLattice: " + e.getMessage ());
2 \" ?$ n  I6 F1 X" s    }- u1 Y1 p+ `0 C5 a7 W
        ; ?8 B) O: D$ y' a' Z
    // Then we create a schedule that executes the& h* X' V( `% B
    // modelActions. modelActions is an ActionGroup, by itself it0 w; ~8 K  ^  E$ C) l
    // has no notion of time. In order to have it executed in
- R  [/ {' E* k$ n1 p, c, I; j    // time, we create a Schedule that says to use the5 `# r3 m# @; h( x1 c) m( e" ~, w, ~
    // modelActions ActionGroup at particular times.  This  a; _5 F. `- T5 }) T$ @
    // schedule has a repeat interval of 1, it will loop every3 w" z5 f; W! V1 ?% @7 o- S4 d
    // time step.  The action is executed at time 0 relative to
" Z! g4 A. y" w$ }2 W; J8 Q# O    // the beginning of the loop.
+ }: T) }* h$ y0 I- ?3 [
+ k7 I! p+ Z: G* M    // This is a simple schedule, with only one action that is7 i+ A  K8 w6 @! w9 L4 p5 K- Q
    // just repeated every time. See jmousetrap for more
: F% ]; B8 ~: M( g    // complicated schedules.
! }$ Z# [# [/ E2 o3 R. J! L" [& t# M  2 B7 R% K' r% I) L
    modelSchedule = new ScheduleImpl (getZone (), 1);
5 V) H% o4 R- _$ N    modelSchedule.at$createAction (0, modelActions);1 i$ h" y9 O1 o$ }" S6 i
        : A: q0 R9 a( l) H9 O
    return this;
  X- ?+ ^! z3 _+ X6 @  }
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