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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:: z7 z4 C, F$ {5 e8 [: m% ?

5 `: m' s5 w  v: _8 _8 B6 n public Object buildActions () {
* i9 e. V7 v; {# y- U    super.buildActions();
3 a( X9 T+ h( d8 g    2 a) a- {5 K9 l" ~) f0 Y. P# X
    // Create the list of simulation actions. We put these in$ \1 Y* k  _! T0 j% Z+ B
    // an action group, because we want these actions to be
$ }; t- E% t  l2 {7 T# G+ x+ f    // executed in a specific order, but these steps should( U$ E9 C9 V2 c5 V0 ~0 j
    // take no (simulated) time. The M(foo) means "The message
6 L& h0 H0 w. {$ s; K    // called <foo>". You can send a message To a particular
2 j$ t- q, L( K( ]4 \  O# }- c    // object, or ForEach object in a collection.  i6 }( Q$ }3 M+ n  L: [! p( |
        
4 f) B0 ~5 U! ?; Q+ W# \    // Note we update the heatspace in two phases: first run/ X9 j& Y5 [, q# j( f  q
    // diffusion, then run "updateWorld" to actually enact the/ O3 j, D* I# |/ x$ ~5 E9 M
    // changes the heatbugs have made. The ordering here is, G; |% R* u# S- W
    // significant!! S- t7 N  I' q9 `- L; [
        / o+ s+ R5 D* \; D
    // Note also, that with the additional
( O6 q0 ?8 p7 y# O( v) {    // `randomizeHeatbugUpdateOrder' Boolean flag we can. d$ x( E/ m% _: Y" f
    // randomize the order in which the bugs actually run0 x% v- n* ?6 T- Y& ^) M/ u
    // their step rule.  This has the effect of removing any
+ m0 M0 S+ _7 `, h    // systematic bias in the iteration throught the heatbug
* h1 B  j  C1 ~) v: J    // list from timestep to timestep: ~; q' E4 J4 \" \5 R* c& E
        ! \5 R* ]7 r8 U
    // By default, all `createActionForEach' modelActions have  G- @% Z* A& T0 {$ A* S
    // a default order of `Sequential', which means that the
% Z6 c' E( d, Q9 @    // order of iteration through the `heatbugList' will be) j$ I5 q5 I! K. U" P  D; G: Q/ I  d
    // identical (assuming the list order is not changed
! f9 I& `4 h7 u8 E& ]7 ?    // indirectly by some other process).
' G2 q. c1 H$ Y2 K   
$ v1 k% C  O3 U# ^    modelActions = new ActionGroupImpl (getZone ());
. Z! _5 D6 }. F% c# ]2 c
$ s$ u% Z/ a2 u* j# R    try {
, x3 m4 o  C8 q) E0 [      modelActions.createActionTo$message
* g- J  O( W" f  R- c        (heat, new Selector (heat.getClass (), "stepRule", false));- J( n( p4 c4 o0 J2 [9 Q: ]
    } catch (Exception e) {
# Z7 ]& I; B) F/ k; ]      System.err.println ("Exception stepRule: " + e.getMessage ());% {3 U; j4 e2 q5 ~: N6 o
    }
2 w2 f" p* d  m( p8 \) y) v; m5 ~+ j1 M3 r
    try {$ z: `3 S/ E7 F8 X! {  o
      Heatbug proto = (Heatbug) heatbugList.get (0);
" \/ V: w" b1 Y5 B+ h0 ^- B) p      Selector sel = 8 g: C' N, k/ \- o# V; C) W
        new Selector (proto.getClass (), "heatbugStep", false);
& d) c# ^5 l" d, l& [      actionForEach =1 S; V( C7 ]; g- M1 e# f
        modelActions.createFActionForEachHomogeneous$call
# L% A3 J# [" r1 E$ L        (heatbugList,* e7 O+ g& \0 g) g0 g3 M
         new FCallImpl (this, proto, sel,0 M& m3 K* u7 f+ F
                        new FArgumentsImpl (this, sel)));
' T$ Z  L' H1 l9 k- [4 C& u    } catch (Exception e) {0 r8 E+ Y8 @4 W; a& [
      e.printStackTrace (System.err);4 ?. E8 [8 f" F; W
    }
3 S1 T# G, T! I4 \2 Z1 G5 f   
; ?* ]* e3 a/ t: ?+ J1 \    syncUpdateOrder ();
# _+ z3 r: ]5 U# A3 z' n
% w/ w, M. Q' m    try {
  U9 C0 }. c5 u      modelActions.createActionTo$message $ w! o7 x; A5 U1 E' U$ f2 t1 c# A
        (heat, new Selector (heat.getClass (), "updateLattice", false));9 U' G: ~& o, @$ ~6 v/ S
    } catch (Exception e) {
  y/ }  @5 I6 j# _5 e      System.err.println("Exception updateLattice: " + e.getMessage ());
# H4 \9 o3 D! F1 O: ~0 b    }- J3 y5 g! ]+ R* m' L" m' Z/ s, F1 v& g
        
1 O& a3 l- k$ t0 R    // Then we create a schedule that executes the' t& \3 i" b" y& {. I3 z+ q
    // modelActions. modelActions is an ActionGroup, by itself it
+ x" f9 Y- ]+ o- v    // has no notion of time. In order to have it executed in( ^$ f; t; F  g3 P5 C
    // time, we create a Schedule that says to use the- O2 @7 v5 G) _
    // modelActions ActionGroup at particular times.  This
7 l2 l7 \9 X* G% Y1 `. v) N! |    // schedule has a repeat interval of 1, it will loop every) _. b0 m6 C+ f; X6 y9 B8 _% E1 X
    // time step.  The action is executed at time 0 relative to% c# e; j- C! x; N  ]- P2 p
    // the beginning of the loop./ ~* b" z* U9 m- s$ r, J0 _

4 ~4 w. }: p* u    // This is a simple schedule, with only one action that is2 K$ S6 y: y" S8 K/ b! X
    // just repeated every time. See jmousetrap for more' {8 V  @: D: N* A2 |2 K/ n) j$ i
    // complicated schedules.+ |; G; y8 ]* I
  
4 |* o  w* z; e; j4 T+ E& M    modelSchedule = new ScheduleImpl (getZone (), 1);, V5 R" }! \. P. S
    modelSchedule.at$createAction (0, modelActions);
8 h6 x+ ], i) u( U# l- z1 \: L# Q          b0 s1 z$ \. S- E
    return this;
5 m, P: Y/ X/ w+ I  }
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