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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:; M( C5 V% ?5 t( ~3 `  E. E

! F, b* c4 E: o  [# f8 i6 I public Object buildActions () {) @. J$ B: c7 N2 a* N5 b. o% `
    super.buildActions();# R1 l( n2 B9 ^- G3 X* C) W+ \
   
3 S3 X" {! p9 x& e9 d    // Create the list of simulation actions. We put these in# }0 k) j: ]4 I
    // an action group, because we want these actions to be
0 H: t1 N; k) _5 D5 `    // executed in a specific order, but these steps should, J# T3 {. a9 D. V  o
    // take no (simulated) time. The M(foo) means "The message, J5 ?' O0 q5 N! _
    // called <foo>". You can send a message To a particular
; o1 O* [' {: S    // object, or ForEach object in a collection.
- L1 g) X( S, U- ]; l6 A- N, V        + q# r; }) R# |
    // Note we update the heatspace in two phases: first run6 x: j% h5 `& V
    // diffusion, then run "updateWorld" to actually enact the
2 ?" W6 v  |+ ]/ [$ F$ u! w    // changes the heatbugs have made. The ordering here is
& @- x: m& v+ O5 b    // significant!, y; Q6 L8 x& ~0 H6 ^
        
! [; q1 J6 e. L8 Q    // Note also, that with the additional- S" F' f) ^0 p; W# v3 {7 `
    // `randomizeHeatbugUpdateOrder' Boolean flag we can  p1 b/ F/ w! ?4 H
    // randomize the order in which the bugs actually run
4 W& Q8 y( y6 g" H3 L) _    // their step rule.  This has the effect of removing any5 M! f7 f" m4 G. o$ S8 Z. {
    // systematic bias in the iteration throught the heatbug
% c+ E/ ^' A! k    // list from timestep to timestep
1 m$ P- I* |0 _        ) ~3 R: ?$ M( i6 F' Q: J* W
    // By default, all `createActionForEach' modelActions have7 ^, _5 \: p/ I# r5 J) u, V
    // a default order of `Sequential', which means that the
, Y( C3 T+ y" r4 }    // order of iteration through the `heatbugList' will be' h5 I) w+ r- q0 x, j
    // identical (assuming the list order is not changed# C  N/ @! E: c8 f3 h
    // indirectly by some other process).  F* l9 C4 A% s3 H4 X+ |0 |
    8 i9 I# \9 c# j% Q: q# ]# C
    modelActions = new ActionGroupImpl (getZone ());
$ a! ?/ Q: d% v1 e* r& N- p, `; q- Y1 U6 a* X& M
    try {
1 H+ m( L9 j* o+ F      modelActions.createActionTo$message
9 A! _8 T: r, q- W, c        (heat, new Selector (heat.getClass (), "stepRule", false));
* v  ^3 u2 J2 r    } catch (Exception e) {& P% }( e4 n8 [+ _$ r6 Y1 C1 q
      System.err.println ("Exception stepRule: " + e.getMessage ());3 v" P- d5 ^0 c+ `$ G6 Y$ S3 r
    }
  S/ t; f! p* O% I
6 U( t  b  j4 i9 t$ c4 X    try {0 p- E: g; ^2 i9 J; {+ d1 h, I" f( r
      Heatbug proto = (Heatbug) heatbugList.get (0);
" G  S: C' W% l/ A# v4 ^8 ^      Selector sel = 7 Q2 ^( r" b2 s+ W: n
        new Selector (proto.getClass (), "heatbugStep", false);
5 n* H8 Z7 L4 F! ?+ v; q      actionForEach =& H+ R5 w  z7 N7 Q$ A; y1 V
        modelActions.createFActionForEachHomogeneous$call
) O4 g/ |' L0 u$ R) G        (heatbugList,4 o$ l1 t" t7 a( q7 [) O+ A, Q" u% ]
         new FCallImpl (this, proto, sel,9 s7 W- d# P. L/ x5 A) b8 U# a
                        new FArgumentsImpl (this, sel)));7 J' E# y) }, A: s
    } catch (Exception e) {& R9 l# L: g8 g+ Q3 c. k
      e.printStackTrace (System.err);
0 `8 Z( t- W- \+ \9 N9 v" K    }
9 {, ]" Q! D' n- y9 w   
! I$ o0 z! E8 q% |0 v* _4 N" R    syncUpdateOrder ();" e0 e: s7 N7 T! L, m

0 U3 h) e, J, d# }! F    try {
, v0 k( z- F3 A      modelActions.createActionTo$message / `3 D; p" {+ V" u# Q. I
        (heat, new Selector (heat.getClass (), "updateLattice", false));! Q& O- r1 G1 ]# p, v+ s
    } catch (Exception e) {9 S. X- Z+ I6 |6 a. v" H
      System.err.println("Exception updateLattice: " + e.getMessage ());
6 U2 ]& p! F1 B0 U  h% `4 t    }& `; \, T/ {; h
        
) {- g; D; N  U6 b# J    // Then we create a schedule that executes the
1 p: o( A7 ~9 ^$ U* N" c4 D    // modelActions. modelActions is an ActionGroup, by itself it
  p! Z9 ?! I3 x* t& N  r    // has no notion of time. In order to have it executed in$ s6 O7 v" Y' O+ P* s$ n8 x0 q9 ~5 P
    // time, we create a Schedule that says to use the
6 l: a5 s+ ~5 C2 Z5 z  p    // modelActions ActionGroup at particular times.  This3 N! g( d' `6 Y2 n, A4 T
    // schedule has a repeat interval of 1, it will loop every
/ c' K9 D6 [7 O4 P+ g$ b5 L! d2 z    // time step.  The action is executed at time 0 relative to  _# [+ N: y9 u6 y
    // the beginning of the loop.
3 T' l+ R+ Q: f% U# L; k
- q5 w4 @3 y  M) K1 G# x2 {    // This is a simple schedule, with only one action that is2 k" Q, \- E+ z8 o& g) ^, I
    // just repeated every time. See jmousetrap for more6 \4 f8 P! b3 v  x2 |
    // complicated schedules.
( I9 G8 z, n; W5 X( `$ d  
0 m- f9 U) e, z    modelSchedule = new ScheduleImpl (getZone (), 1);
1 u  X* [6 k: |+ y! w! B    modelSchedule.at$createAction (0, modelActions);
# V/ ]0 M6 O5 `$ p        " x& m! V) m# ~! {4 {' d  u
    return this;  C0 F8 F+ Y! k. b1 t! A+ [
  }
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