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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
  Z1 ~# S1 N6 u+ v' W
6 V& A: K" c1 D& p9 O/ q5 B public Object buildActions () {
  Z$ W  w6 `- N- Q8 o8 N    super.buildActions();1 ]7 O2 X& v1 p& Y/ q; ~# P
   
9 U# N8 Q- x3 l/ j; K    // Create the list of simulation actions. We put these in& {# o* {/ g$ f  {# h
    // an action group, because we want these actions to be: R! J( A: N9 M1 v9 ]( s) s7 ?
    // executed in a specific order, but these steps should3 {- x) X+ T4 y2 E
    // take no (simulated) time. The M(foo) means "The message# X+ H) j) ^8 Y' V- k! L
    // called <foo>". You can send a message To a particular
! f, \& m. U( }# R, Y7 {    // object, or ForEach object in a collection.* S1 G' K( u5 `3 w- v( ^/ B
        , Y$ o2 j' J' m  q! Q
    // Note we update the heatspace in two phases: first run
) e. i5 K2 H6 ^. @' d! Y    // diffusion, then run "updateWorld" to actually enact the
7 g3 @+ p/ @6 H# t  U  X    // changes the heatbugs have made. The ordering here is8 e4 M/ W. G* |1 D* p: Q" t) n8 N
    // significant!
. c, I, [1 ?/ Z& G! {        ) c" o* i4 o( B+ w. k
    // Note also, that with the additional
7 T" a  h4 c# z7 N7 N" z* {    // `randomizeHeatbugUpdateOrder' Boolean flag we can& H1 c6 z( q1 m, v
    // randomize the order in which the bugs actually run
: P/ W. c; [; S/ N9 W5 o& P    // their step rule.  This has the effect of removing any) m5 D2 p$ l, h* ^
    // systematic bias in the iteration throught the heatbug
( F3 C8 |, E' H    // list from timestep to timestep& b+ `* y$ B, X
        
% \1 k% z7 s/ E3 z    // By default, all `createActionForEach' modelActions have2 m2 S$ X; x/ p) N" N" f
    // a default order of `Sequential', which means that the& [0 f' z, m5 W: X* y0 ~
    // order of iteration through the `heatbugList' will be
# U! u. q/ H. |( h$ S: [    // identical (assuming the list order is not changed
0 V) ^; f2 b1 W% s+ ]/ d; ?2 o3 ^    // indirectly by some other process).
3 w6 Q: S' k- n3 n! g' {   
0 k/ `; }, c% L    modelActions = new ActionGroupImpl (getZone ());$ {* b3 q# y6 N: U! b$ [, _
7 W# A6 z. n+ L) e: ~
    try {
( a* [( E. a+ ^% t" ?  U$ g      modelActions.createActionTo$message4 y8 E: h" l8 d+ @7 u
        (heat, new Selector (heat.getClass (), "stepRule", false));
+ {% t1 S8 i, _- r$ ?) w: y, u6 s    } catch (Exception e) {
& s2 K# x, W9 h5 \$ r& V      System.err.println ("Exception stepRule: " + e.getMessage ());& c4 Q* {" y: a/ x$ m5 b
    }
, `1 ]1 A+ v7 c0 R, M! ~* m( A, l7 a% G% U8 o
    try {5 J" k% F, }4 ?7 O% [3 h4 }3 j" i
      Heatbug proto = (Heatbug) heatbugList.get (0);
$ H) `# B+ |2 u( V      Selector sel =
8 v- g8 ?$ K8 w; ~        new Selector (proto.getClass (), "heatbugStep", false);
6 v6 M0 D% q. L$ C      actionForEach =
6 K+ H4 @/ A; b( e8 U        modelActions.createFActionForEachHomogeneous$call6 K5 q) p8 I6 N8 c6 h
        (heatbugList,
6 P, \, [1 g9 v* b4 c. n  n         new FCallImpl (this, proto, sel,/ c1 v/ X" V5 A
                        new FArgumentsImpl (this, sel)));2 |9 l' l- T" `( N- f& I2 q
    } catch (Exception e) {
( `# O7 l# j' S5 H& y4 y      e.printStackTrace (System.err);
1 U4 c6 S+ |2 A, L    }) k( ]( u8 m; }( `
    * I- d: S3 ^% _6 H8 j; X6 k1 I
    syncUpdateOrder ();' [/ i8 V  s- C# b: o: |

  F1 |8 i% o7 P& q    try {7 X3 I& L4 I  {- y5 H& Q
      modelActions.createActionTo$message * E0 k! _# p. A0 B- Q6 q
        (heat, new Selector (heat.getClass (), "updateLattice", false));
* a4 I4 ^) ]& ]% t    } catch (Exception e) {
; m6 A8 w/ k, e+ `1 [# N7 V' M, s      System.err.println("Exception updateLattice: " + e.getMessage ());, z6 h/ P# G7 O0 @
    }  v) J& }! h$ s8 ~* ?5 s
        
- J) e$ ]/ X( G    // Then we create a schedule that executes the
; \* w. Z/ {/ y9 \8 L. R$ Q    // modelActions. modelActions is an ActionGroup, by itself it
. t4 X; _8 |$ u4 X6 Y3 b    // has no notion of time. In order to have it executed in0 f$ c$ g- T6 v& m, [9 a  ?0 F0 L
    // time, we create a Schedule that says to use the
4 F1 T: T5 w  l% \; \    // modelActions ActionGroup at particular times.  This1 H4 O6 x; m' b5 x: V* Q
    // schedule has a repeat interval of 1, it will loop every
6 L$ Y) ]6 Z9 A: p& e# U    // time step.  The action is executed at time 0 relative to
; Y: ]- c  J9 T# N    // the beginning of the loop.* }  G9 G$ D$ ^/ ]# [
, s" S2 J- Y8 A7 D
    // This is a simple schedule, with only one action that is: a" N) Z+ ]; }& F, h# v* Q
    // just repeated every time. See jmousetrap for more
' K( j5 B) P* }+ M& }3 K' E. h1 E; j    // complicated schedules." {6 U- e7 Z' u3 e  X. N5 w' x; w
  7 H* I( e2 e: c- ^
    modelSchedule = new ScheduleImpl (getZone (), 1);
, o& k( A7 x  O. L$ a    modelSchedule.at$createAction (0, modelActions);
) H5 ~1 [4 y0 Q2 }; L        $ X1 U: t9 B( Z3 H0 u
    return this;
3 Q1 y$ g! R" a' G  }
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