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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
( `8 H. B& p5 ]5 v
# c& ]5 E0 S& e public Object buildActions () {: x2 h! F0 e5 G
    super.buildActions();5 k7 P1 i/ A8 X9 o6 Y' c) i7 b# B( b
    * s; e' a8 m5 X/ y7 Z' P: h
    // Create the list of simulation actions. We put these in
0 D, E/ z" ~! l$ m, @! Z    // an action group, because we want these actions to be
4 V/ |0 s: p, D) g    // executed in a specific order, but these steps should
* w( N7 _4 v! }& i    // take no (simulated) time. The M(foo) means "The message! T, t4 r" O: g
    // called <foo>". You can send a message To a particular3 P: Y- h* c* h% t1 Q
    // object, or ForEach object in a collection.
4 [' \5 v8 M0 \2 h& b        
# o$ J# [& F& [% u    // Note we update the heatspace in two phases: first run
  J" I# ^6 r& G9 \, R    // diffusion, then run "updateWorld" to actually enact the
2 _2 ~. w1 H8 V0 I* a7 n; \    // changes the heatbugs have made. The ordering here is; p& v0 _5 t5 b
    // significant!
0 f9 E+ _; b& A0 g/ z        
8 ?# o5 U( N$ C    // Note also, that with the additional
2 n. [6 |- F. Q$ v3 j) P! s    // `randomizeHeatbugUpdateOrder' Boolean flag we can! [1 N1 M- g+ G
    // randomize the order in which the bugs actually run
) b( X7 c% W, q7 w/ Q" }4 J2 }  b    // their step rule.  This has the effect of removing any
: F9 c4 s/ X& g8 r* z    // systematic bias in the iteration throught the heatbug1 T! J! J% k4 [; ?
    // list from timestep to timestep; x( b$ E& Q+ d0 u) D
        
& q  O  t) [. Y% X! ?! k    // By default, all `createActionForEach' modelActions have
4 u* |* _3 X  n: b  W8 O    // a default order of `Sequential', which means that the8 A; b, _$ P! J% [. c, k0 r
    // order of iteration through the `heatbugList' will be
* l, T7 z: Q1 e4 j' M& q, F    // identical (assuming the list order is not changed. s9 r% E0 d8 b+ n: O. w' M0 k: C
    // indirectly by some other process).& }7 b7 T$ L' y1 {
   
) \9 S( V6 ?3 k$ I: D, {    modelActions = new ActionGroupImpl (getZone ());
2 j/ u/ F& n( w
! h' n2 M5 I: G    try {
8 d" m2 E0 f7 T; n8 A      modelActions.createActionTo$message; D+ X% F; c3 e* n0 P$ i: A, n
        (heat, new Selector (heat.getClass (), "stepRule", false));
) A7 U5 S0 o& U, m- S( x    } catch (Exception e) {
, V# r' f+ n; N$ u1 [- q2 F, {3 d" P      System.err.println ("Exception stepRule: " + e.getMessage ());
6 u$ `4 u0 s/ H* J" T    }
5 d* d1 c  _  a1 T* U
* m0 H+ \% j" u" ^5 J/ `6 T3 L. ?    try {7 l. R8 p6 a. ~3 m# l
      Heatbug proto = (Heatbug) heatbugList.get (0);. V6 U1 A6 h( P: @" }
      Selector sel =
' h  H) T9 Y, z8 d        new Selector (proto.getClass (), "heatbugStep", false);; H0 n8 o. q. a4 Q: t
      actionForEach =
5 p- L3 y, M7 ?        modelActions.createFActionForEachHomogeneous$call
1 F' f  S2 k. ]        (heatbugList,
, i3 v3 {, d# W* N. K- r         new FCallImpl (this, proto, sel,
7 v1 \9 J4 M8 A                        new FArgumentsImpl (this, sel)));& h' L" B" f0 w1 ^6 q
    } catch (Exception e) {) b# f( ?$ ?4 T5 E) a
      e.printStackTrace (System.err);2 s: y$ v9 ?: N9 ^. Y
    }
4 ^4 R: G( h6 N( ~& S   
& y" T- j9 U* K    syncUpdateOrder ();6 f0 S' B1 z. ?% A, a3 l5 m
' `- j, P7 ~: z$ a; }
    try {
1 @+ E3 a9 P. }  A      modelActions.createActionTo$message
& Z% _6 d6 h/ ~4 Z6 g        (heat, new Selector (heat.getClass (), "updateLattice", false));/ G6 I+ U, g2 l+ a$ {" T
    } catch (Exception e) {
2 {  p5 s" P  l9 v7 W      System.err.println("Exception updateLattice: " + e.getMessage ());
, O+ T, k1 d" D  s; K: E4 }' Y  a" Z, i    }
1 Y% F2 `6 D. v6 ~        
7 l/ M, ^/ A6 U    // Then we create a schedule that executes the$ O- X- T! |- J2 X, f
    // modelActions. modelActions is an ActionGroup, by itself it- I7 Q1 O  ?1 i
    // has no notion of time. In order to have it executed in
! l8 y3 r/ n" L. G) t    // time, we create a Schedule that says to use the
) y+ O9 Q: r3 v! P  d  d    // modelActions ActionGroup at particular times.  This
4 i7 N5 Z: V/ P    // schedule has a repeat interval of 1, it will loop every
* R% L! K4 f2 W1 F    // time step.  The action is executed at time 0 relative to: M! |1 a( d+ {3 H; ^" z" g
    // the beginning of the loop.
) s' I: M2 ]) c# S9 w) L: ~8 G. G0 K, B! \
    // This is a simple schedule, with only one action that is
) y* g' Y! _% v    // just repeated every time. See jmousetrap for more4 f& p$ r+ t0 N+ Y& p
    // complicated schedules.4 [6 S- g5 @/ n
  1 X2 D/ z2 t' B( _* p
    modelSchedule = new ScheduleImpl (getZone (), 1);
/ j8 R& y- [7 G8 I# O& r    modelSchedule.at$createAction (0, modelActions);2 ~1 B! C% g9 U# E  Y5 C
        
3 `. p7 \0 x8 F  Z) L+ f1 X( C  W    return this;- p+ |, {% Q. l! _8 f* G7 z, O
  }
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