设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 8961|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
! Y6 \# v% T& x: m- |, D( U1 h. Q* _$ c6 P! M
public Object buildActions () {
# Y$ Q8 [" M1 e+ S    super.buildActions();2 M# a7 G6 z+ g! x
    5 P* S8 O# J; I; N: ?
    // Create the list of simulation actions. We put these in4 t; k& U$ o' [/ Y
    // an action group, because we want these actions to be
* B7 ]: h4 j$ G2 n3 h4 y. n    // executed in a specific order, but these steps should& P; d' F  j1 T/ B) h2 E/ U
    // take no (simulated) time. The M(foo) means "The message
$ \$ ^+ F3 B3 x( z8 ^5 B    // called <foo>". You can send a message To a particular
' s9 o7 \' e0 i6 L# M' n6 s5 z$ a    // object, or ForEach object in a collection.
. ?% ~1 d3 \% j1 B        4 G& H- X" e! C: @0 h) B/ C
    // Note we update the heatspace in two phases: first run7 X$ N! K/ U% i
    // diffusion, then run "updateWorld" to actually enact the, ^2 p  H1 Z  ]1 G: K
    // changes the heatbugs have made. The ordering here is
' `2 h2 W+ M" U, Q, M    // significant!; v6 C/ A4 b' h1 K, Y7 {
        
* l' d- l' y; `    // Note also, that with the additional
1 E( y: Y* |- S1 n0 G3 ?    // `randomizeHeatbugUpdateOrder' Boolean flag we can: R' l$ A( F7 T+ F& k) V& T/ e6 R
    // randomize the order in which the bugs actually run
; }% i& q, c1 O; C( q; M9 X    // their step rule.  This has the effect of removing any* v* t5 L( \! P: A- ]& n0 z
    // systematic bias in the iteration throught the heatbug1 y+ i0 W7 @7 u7 D* i2 v
    // list from timestep to timestep
- ?3 s) T4 \( W4 _- [0 _        0 m2 E; @! a5 q) t2 _, k: G
    // By default, all `createActionForEach' modelActions have$ B. @) Q8 N, x  K1 S
    // a default order of `Sequential', which means that the
. l' X/ P1 V, U- p    // order of iteration through the `heatbugList' will be
/ N: |3 ^* @2 u    // identical (assuming the list order is not changed
! t1 I% S; o$ G. ~    // indirectly by some other process)." F; Z, ~- w" G1 b* R1 @$ n( S& p, U* j
   
- t3 H- C( }; |! W0 Y    modelActions = new ActionGroupImpl (getZone ());
3 N5 U, s& l5 ^0 V
) x; `  e: s+ s0 ~4 p, k1 _    try {
2 L. ]0 `, N2 {0 ]: N( h( E      modelActions.createActionTo$message: t2 L& T" [1 d  b- y6 L- a
        (heat, new Selector (heat.getClass (), "stepRule", false));* }) t* g3 [/ m( B0 y+ M- b2 ?
    } catch (Exception e) {, r9 _% x& y% y6 W' ]" N
      System.err.println ("Exception stepRule: " + e.getMessage ());0 P( t) s# u6 Z9 G/ n
    }% @7 e8 S8 E7 z/ b3 }: f, X
1 t6 B4 j' @* Y; M! q% e& E
    try {% U5 r5 G, f1 M3 V. b+ R5 _
      Heatbug proto = (Heatbug) heatbugList.get (0);
" q8 A0 k2 \2 v, \; X$ x( ?      Selector sel =
+ N9 @/ D: ~6 v, Q3 C7 |1 A8 V        new Selector (proto.getClass (), "heatbugStep", false);
! F8 j! _. Q  h      actionForEach =
' O' A, C) e7 ?8 c& b' j% _+ |        modelActions.createFActionForEachHomogeneous$call
, t9 _' _: X7 {0 B2 _% l& O0 ?" a: j        (heatbugList,
: S! }5 V4 s7 J8 D2 g% p% p4 R         new FCallImpl (this, proto, sel,
, F0 ^/ H8 ^5 R/ G& u$ {& p                        new FArgumentsImpl (this, sel)));
& g4 D; h4 p4 t    } catch (Exception e) {) Q$ y7 y* e5 l0 i& Z8 M
      e.printStackTrace (System.err);) n+ r: d& v' L( q2 J9 a
    }1 |' }0 E$ i" Z; H, R5 K
    - D; R5 {" `2 F/ h0 `3 z: |
    syncUpdateOrder ();% ^( Y0 U& H; ~! Y5 _

' `0 p/ \( f3 o& Y) r    try {
( f+ i! S4 @2 N, O2 C      modelActions.createActionTo$message & Y+ i; L% m0 c& P2 V& q
        (heat, new Selector (heat.getClass (), "updateLattice", false));
5 c4 A, [2 m3 e  {: n    } catch (Exception e) {5 d* `6 Z3 W; P0 w( p6 f# W
      System.err.println("Exception updateLattice: " + e.getMessage ());
& C: @# z' a; Z  t+ {$ t    }  Y" M& D( {) `" b
        
+ S& w* Y0 y% Q    // Then we create a schedule that executes the
- @  |( O$ a8 x$ G    // modelActions. modelActions is an ActionGroup, by itself it, W" F2 y. _6 u0 ]* H
    // has no notion of time. In order to have it executed in
; ]! C$ A! m% R& }# `) k    // time, we create a Schedule that says to use the$ M# Y$ `8 ?, h& `( [' h3 C, P
    // modelActions ActionGroup at particular times.  This
' S4 h5 S! H% x    // schedule has a repeat interval of 1, it will loop every1 ^: |5 Q1 k+ y& a. j
    // time step.  The action is executed at time 0 relative to
# b+ s+ a4 {( F# b+ P    // the beginning of the loop.
9 F$ S0 T9 N5 {, q  C+ k
. d0 R6 o' v' \3 b3 M! {- \$ T    // This is a simple schedule, with only one action that is
, O  m! n1 S6 [6 e; _& ]    // just repeated every time. See jmousetrap for more
+ M1 X: C8 A3 W5 M; _    // complicated schedules.+ ]0 b3 \) J- M9 }2 e9 l
  
4 ^: [" P7 B: j; w" i4 h5 @    modelSchedule = new ScheduleImpl (getZone (), 1);
1 V+ `) c* \  e; J& {5 n9 u    modelSchedule.at$createAction (0, modelActions);
2 j6 x! D% z" q! |" i        
- c& K# v! q1 @7 m    return this;
! X+ b  I2 h, k" C- r  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-2-5 06:43 , Processed in 0.024014 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表