设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 10751|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:$ d- Z; X4 z- `$ B3 U. S- _; t+ ]; T

7 c5 j* W6 W- g' k' ] public Object buildActions () {
' T- t3 c; c! s& U! K    super.buildActions();
3 o+ Q6 B" C, e1 Y9 g, ~/ a) Q    1 t. m7 J4 m& j% \
    // Create the list of simulation actions. We put these in
& i( R* |# Y3 m6 f* Q5 m    // an action group, because we want these actions to be
% [. {0 U% M- O    // executed in a specific order, but these steps should' O# g, ^# V" e7 m" V7 ~
    // take no (simulated) time. The M(foo) means "The message0 q5 b, T% z3 a! o8 z. f
    // called <foo>". You can send a message To a particular
7 N& Q7 j# @2 ~6 E# y$ r    // object, or ForEach object in a collection.
1 V( ?" d% ^$ k        0 k1 |1 H/ ]) E  C) C  c: z
    // Note we update the heatspace in two phases: first run3 w) m  S8 K! R- f8 A* P  n! ?8 r% D
    // diffusion, then run "updateWorld" to actually enact the, T+ D% L0 _0 c$ E6 T- p
    // changes the heatbugs have made. The ordering here is& a8 s/ K& |+ P! Y0 q0 f3 i! q7 ?  [
    // significant!
- I, \6 @, l% M2 k; k4 e- t        1 x' D5 i5 t9 A' O3 l4 D, S
    // Note also, that with the additional2 k- l2 q) Z, K# c
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
: c( u$ H# M( J/ |  i    // randomize the order in which the bugs actually run
! _9 S) g+ {3 l2 M/ i; L' H8 Q    // their step rule.  This has the effect of removing any
3 ^  y9 E5 X  o3 Y/ F. i    // systematic bias in the iteration throught the heatbug
+ ^6 H0 m4 O2 }, {% l% U% z    // list from timestep to timestep* h& Z6 k- i8 ~) J. W" ~
        : ?8 W0 K! m1 w5 G: m! d
    // By default, all `createActionForEach' modelActions have
0 O, o1 i8 d% [    // a default order of `Sequential', which means that the( U& ?" U( `" U6 t7 M$ q4 ]
    // order of iteration through the `heatbugList' will be1 Z! H9 ~+ X: u/ T. p
    // identical (assuming the list order is not changed. R/ n$ D+ k# R/ u: {  ~3 M1 n7 ?
    // indirectly by some other process).
: a$ \0 E* m' [; k   
% p0 I% a! w" E0 r( _    modelActions = new ActionGroupImpl (getZone ());
# S) ]. c0 m" U( V- p
" U8 }" M; j3 n1 f9 ], Z    try {2 L, g: s- Q' ^) R) e
      modelActions.createActionTo$message: ~* Q# G2 h! p4 k2 v
        (heat, new Selector (heat.getClass (), "stepRule", false));9 ?& S) C3 X3 h
    } catch (Exception e) {
5 ^9 c, I6 x  B, u/ b      System.err.println ("Exception stepRule: " + e.getMessage ());" Z$ R: J' N7 _/ T9 ?
    }2 e  P" _- }7 h  G6 Y0 |
7 \7 e3 C# ?! W' G" o0 l
    try {
- v$ ^& \+ h( [" B4 [' y      Heatbug proto = (Heatbug) heatbugList.get (0);7 R/ [) P' C2 o2 a, L8 z
      Selector sel =
2 Q' w& ?9 X3 ]6 _        new Selector (proto.getClass (), "heatbugStep", false);0 b5 y; G/ N% ~+ v' z  |% X
      actionForEach =
' W) e+ G/ p- K. I4 g        modelActions.createFActionForEachHomogeneous$call
1 Y) M" M3 H0 P* k- P        (heatbugList,' W' I6 d3 y; }/ E: b; Q: S
         new FCallImpl (this, proto, sel,
* ]1 l# Y* }6 z1 ^8 r                        new FArgumentsImpl (this, sel)));
: U1 h( ?! \& d+ o    } catch (Exception e) {% C; d# F% X" M2 f9 b
      e.printStackTrace (System.err);% s6 J$ ]- s  T5 j+ L$ n$ m
    }
$ s; _: o& z& a* f+ U& u( K    $ X, B7 _4 o7 z- W
    syncUpdateOrder ();' g: x% _% ^/ F; O
# [: V/ `( ^  v. [9 Y1 j
    try {
& o, F$ k9 e( S- l  P; g, p      modelActions.createActionTo$message
$ K+ E9 J1 }7 s, x1 a        (heat, new Selector (heat.getClass (), "updateLattice", false));
" E: v4 _( a# Z2 @% O    } catch (Exception e) {
. O9 R* e* A0 v. r' g      System.err.println("Exception updateLattice: " + e.getMessage ());5 g, ^2 z2 K! {
    }, m5 ~( s' ^0 T3 |
        
% u! F8 N; F8 ~& Y) H7 y    // Then we create a schedule that executes the  r7 B" E. {' N
    // modelActions. modelActions is an ActionGroup, by itself it
9 J$ t# m& p4 C* V$ c+ x% o9 c% F    // has no notion of time. In order to have it executed in
) B6 D5 D9 @$ x1 r  s) Q5 g    // time, we create a Schedule that says to use the
# B3 q, p3 R7 S" s    // modelActions ActionGroup at particular times.  This
# B1 m4 Y1 @5 n+ Z7 a) I9 X  C    // schedule has a repeat interval of 1, it will loop every
/ Q. B* l0 u% G4 Z( h0 r8 i    // time step.  The action is executed at time 0 relative to
. n3 ^: H/ G: ], B# a/ ]" A    // the beginning of the loop.
. F2 @, S# d! l" d8 ~" b
2 W5 W4 M2 x. d' k( a    // This is a simple schedule, with only one action that is
4 Q' G" G  j. ~) F& @: V$ G    // just repeated every time. See jmousetrap for more
# `. D+ I9 x$ P1 T* z! n    // complicated schedules.
7 C+ b* I5 C9 I: L2 ?/ n  
  J+ h- X2 `* j# R* g    modelSchedule = new ScheduleImpl (getZone (), 1);. z; g2 O5 l$ `: R' p
    modelSchedule.at$createAction (0, modelActions);* J& c8 \9 D+ V( c! L+ {  q2 {
        - J% _2 `) _: w) ^. S" a
    return this;
. a+ ?3 h8 P+ j  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-5-16 12:17 , Processed in 0.019889 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表