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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:1 M5 h1 u) G3 n* y' L
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public Object buildActions () {, q7 F- b7 x& v8 S+ P
    super.buildActions();
% A+ i2 O; Z0 V: C, [, _   
' q/ B8 c  j9 Z& P# q9 K2 f    // Create the list of simulation actions. We put these in: K' T: [" J8 [6 b2 V
    // an action group, because we want these actions to be: \$ m3 i/ N, l3 v
    // executed in a specific order, but these steps should
! M; \5 q; v9 t3 A& ?0 U5 h7 \    // take no (simulated) time. The M(foo) means "The message
/ N3 ^9 Y! V+ q    // called <foo>". You can send a message To a particular
7 L5 l8 O9 U  k' t% C+ n% {4 ?    // object, or ForEach object in a collection.0 @6 ^; N1 K/ }" `* t* l, g: p1 A! t
        ) k  w3 n2 w* P/ b2 m" _/ y) R
    // Note we update the heatspace in two phases: first run
2 }8 U' R' D- [: i3 s* Y5 s% \$ J    // diffusion, then run "updateWorld" to actually enact the8 u% y, ^5 h* l
    // changes the heatbugs have made. The ordering here is
1 k) V! y% t( u, z: @. `% M  O    // significant!
  N4 F6 J# V8 T5 j& _        ! B/ v* G, @% A8 f, J6 Y
    // Note also, that with the additional
( ^, ~8 h$ ~) ]/ M% e$ p$ w$ q- i    // `randomizeHeatbugUpdateOrder' Boolean flag we can
" [( Q/ U  k" X. t0 _  L    // randomize the order in which the bugs actually run: Z: [0 T5 }, S9 @! t; f/ N
    // their step rule.  This has the effect of removing any
0 z. M& y0 p% @' t! O    // systematic bias in the iteration throught the heatbug! `- _4 A/ U* H, A0 b  T1 O5 M
    // list from timestep to timestep
+ B7 i+ v9 {4 G# X7 c5 Z# V, A        7 E  P  ]! T6 X% E
    // By default, all `createActionForEach' modelActions have. f5 l& o) V/ G
    // a default order of `Sequential', which means that the7 ~$ p, d* h. I9 f8 [- V/ d- U: t
    // order of iteration through the `heatbugList' will be5 I+ D4 M  ~% G
    // identical (assuming the list order is not changed
7 q- _0 X5 e+ R9 c. X6 S+ k    // indirectly by some other process).
6 [0 }. q, g/ Y  n: z+ \2 X   
% k; M& A# @" Z$ q/ O: q1 c* }    modelActions = new ActionGroupImpl (getZone ());
4 ]! A7 Y" ?/ k7 b1 P. O9 S4 M* \7 n' U, j. p: _
    try {
8 L" b3 i7 a2 d9 k      modelActions.createActionTo$message  `  ]! D" B) v/ y5 V) a8 Z; q
        (heat, new Selector (heat.getClass (), "stepRule", false));
0 }: R$ r4 L2 ]4 t    } catch (Exception e) {
2 M9 J  Q  V! K      System.err.println ("Exception stepRule: " + e.getMessage ());
2 L, p7 T4 r' L7 ]2 {    }
9 b! D5 q* G; T( C; v! Y8 g, s- r, m% E3 Y! P
    try {
2 H& t* ]) y! F$ N$ ~$ T      Heatbug proto = (Heatbug) heatbugList.get (0);5 N/ a" h! @+ W. l" B( T2 B
      Selector sel = / r5 I2 W' U/ s* J. g, T& ^+ F
        new Selector (proto.getClass (), "heatbugStep", false);
% _0 ^1 A1 l1 X* d/ V6 C" V      actionForEach =
1 Y. b- ^: p! x. [- |# _        modelActions.createFActionForEachHomogeneous$call
8 R0 ]5 C" y3 M6 B4 W        (heatbugList,
- F3 {0 c* s8 B         new FCallImpl (this, proto, sel,
0 D9 q: t$ ~# ]9 k                        new FArgumentsImpl (this, sel)));6 o# M/ o4 d8 I
    } catch (Exception e) {& H8 `' x! k+ J4 d% z/ R
      e.printStackTrace (System.err);/ T6 Y/ u4 p* k' ]6 y0 F
    }
0 Q) w8 w6 h# W8 C/ s. z   
: I0 p( ]# _3 l: C' X    syncUpdateOrder ();) w- J; ?; ~" j" n' d0 \7 z2 T

* k2 C/ l. l0 Z1 ]    try {3 k2 j  I; B' W! [9 i* G( |
      modelActions.createActionTo$message # b: x5 l# ~' `, K7 S2 T
        (heat, new Selector (heat.getClass (), "updateLattice", false));
  [8 N0 z# Z5 n+ n5 D3 w    } catch (Exception e) {
5 X* S2 a! L% K4 }: Q7 B      System.err.println("Exception updateLattice: " + e.getMessage ());
2 |) u3 q; j  }    }
/ ]* L8 J9 s; f        
' H+ G. x0 z; {1 g$ A    // Then we create a schedule that executes the2 A$ g+ ?4 M: M2 w* |
    // modelActions. modelActions is an ActionGroup, by itself it
) m3 N/ g" R9 f  g/ k9 m    // has no notion of time. In order to have it executed in
) e7 R! a' {, \% D. v; N1 k5 w* D    // time, we create a Schedule that says to use the
2 M4 d+ x& V8 A4 n    // modelActions ActionGroup at particular times.  This3 W+ \3 R6 W/ Z3 A& n( g
    // schedule has a repeat interval of 1, it will loop every
: u. ^. _6 ?! @! L/ G5 y- r& E    // time step.  The action is executed at time 0 relative to
# q. F! j# l4 Y    // the beginning of the loop.% X" t* @1 x, s5 \

+ n( P7 w3 Z" k    // This is a simple schedule, with only one action that is- G4 J% B5 g; H, X4 \" ~
    // just repeated every time. See jmousetrap for more' e6 M- w8 [* ]* C  d) N
    // complicated schedules.3 Q( @# N9 f( x8 P- \  i; S# |
  ; H' _% _7 b: T- k, U- v
    modelSchedule = new ScheduleImpl (getZone (), 1);) Y. z: s+ \- t7 _/ o/ |9 R* w
    modelSchedule.at$createAction (0, modelActions);' O# [- d( e# u; f5 I( F
        % q" @) D# p/ ^# h
    return this;( ^5 T! m+ Y* @0 B5 g& F3 F1 P: P5 ~
  }
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