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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:/ ~2 N+ _& c4 ~

2 D3 g' V' f( _  `, @/ I" B: `8 q public Object buildActions () {
- b1 y9 ~- f+ P" }    super.buildActions();& i2 D$ q, f. I! _" h/ a
    & O; t# P( j- z  P# K# H
    // Create the list of simulation actions. We put these in
" V- Q0 v1 m9 q# u2 U    // an action group, because we want these actions to be
# G( f6 o# G" I1 b8 \+ ]7 Q0 b( S* ~    // executed in a specific order, but these steps should
6 h2 k: B4 C1 i0 |. n( l    // take no (simulated) time. The M(foo) means "The message
, }) A3 B$ f! @5 @) X    // called <foo>". You can send a message To a particular' o; W+ A. g3 u4 e5 S) j! ^
    // object, or ForEach object in a collection.
( w. r- N; w" ]        . P- j. I# ?2 T4 S+ U" M9 @
    // Note we update the heatspace in two phases: first run
, l! d6 f' |- T' k. c    // diffusion, then run "updateWorld" to actually enact the, o5 P: b; Y* S2 ?2 l
    // changes the heatbugs have made. The ordering here is
& Q) V6 |- F1 t4 j: m* p    // significant!' M  W1 Y- U/ B
        - o9 G- a' o# _8 G2 B/ P# {$ V
    // Note also, that with the additional
2 T# Y% V4 y, w! J- {8 h- I  J# k    // `randomizeHeatbugUpdateOrder' Boolean flag we can
6 l. ^, m. g0 i; P4 r    // randomize the order in which the bugs actually run
/ g% U+ d9 n, a# |* o; o    // their step rule.  This has the effect of removing any
5 G: u3 D2 W3 V, ^" ^    // systematic bias in the iteration throught the heatbug1 z; b; {0 {) r  I$ M* B& Y+ ]
    // list from timestep to timestep+ Z* _! x& J$ ~4 X0 n
        / r7 k9 i. J0 F8 M4 w
    // By default, all `createActionForEach' modelActions have' U7 j/ x5 O/ o# E& J- }
    // a default order of `Sequential', which means that the
: \- ?, z% P" {$ u( b    // order of iteration through the `heatbugList' will be
7 D6 C. @+ s$ \: C9 \    // identical (assuming the list order is not changed* a2 |% a- R+ j2 J
    // indirectly by some other process).
' |) D7 g7 n$ l+ B& [3 Z   
& t. g1 X5 z5 s5 i* }1 ^$ [) F    modelActions = new ActionGroupImpl (getZone ());& o* |( J- |2 e3 ]: C

7 e) ]. P! z, T, |, b. b    try {
: n' l* J, }7 }      modelActions.createActionTo$message
! s+ X& |. x+ b( ^        (heat, new Selector (heat.getClass (), "stepRule", false));
' l# U' V  T+ f. r    } catch (Exception e) {
; f( E; s" I( h1 g2 p      System.err.println ("Exception stepRule: " + e.getMessage ());
0 o! U! C: W& T4 w" Q  I, S- f    }9 k* q5 N9 a# q6 b1 _! U# W

  }1 x9 V7 U2 v' s9 _+ P    try {" T& c9 \! u0 k' y$ F: v
      Heatbug proto = (Heatbug) heatbugList.get (0);
0 ?: \: G* P+ i; o5 x/ ]; x1 P      Selector sel = % ?- k$ |, h$ [
        new Selector (proto.getClass (), "heatbugStep", false);
" d2 J2 y" e5 o# w6 f- g1 e6 E/ ~3 o      actionForEach =+ o7 e  _, F: C2 o2 K
        modelActions.createFActionForEachHomogeneous$call
- a' k& N% d% H- `        (heatbugList,; }, v$ [* U6 g9 v4 t# l
         new FCallImpl (this, proto, sel,) E' a1 u% A( x5 M4 I
                        new FArgumentsImpl (this, sel)));
- g2 V5 M" [& G    } catch (Exception e) {2 R+ M- S; u0 r, a0 {
      e.printStackTrace (System.err);& g9 R2 }3 Y$ W4 w/ |# l
    }5 X) @+ `8 O0 d" l  [4 N0 Y3 I% g
    6 F* ~* V2 Q  `' Z2 b
    syncUpdateOrder ();+ @  P* w) F3 p! K$ f) ^
8 o4 ^9 m% ^5 h' T% N2 f  l: ^: R
    try {, p6 z8 x5 Y0 y8 s$ u8 Z3 [6 [$ ?
      modelActions.createActionTo$message
6 y$ C4 {1 C+ l: w: L: N5 t        (heat, new Selector (heat.getClass (), "updateLattice", false));' g8 ^# H* c; g% i3 o- I3 {
    } catch (Exception e) {$ K! H& v- m5 U. \2 s- Q
      System.err.println("Exception updateLattice: " + e.getMessage ());
% f- j; i1 X0 b9 c    }% t. `9 S9 u- N& o. K" ?1 i: }
        * S; |$ e$ r" ?/ q7 h4 h
    // Then we create a schedule that executes the0 C$ [) m9 ^" {& C
    // modelActions. modelActions is an ActionGroup, by itself it1 O. {6 |# ]* ^; e
    // has no notion of time. In order to have it executed in
3 q" L) u3 I" Q0 p% V0 h$ s7 n    // time, we create a Schedule that says to use the; p6 F  v+ O* @3 }8 y" m4 v5 [5 f
    // modelActions ActionGroup at particular times.  This( d1 q5 y4 F" Q( M+ w3 N3 p
    // schedule has a repeat interval of 1, it will loop every) k/ |; V$ W" f" v
    // time step.  The action is executed at time 0 relative to6 Z" v+ }8 v. O9 \
    // the beginning of the loop.- `# ^6 I2 h- e# m
, N2 l4 r) o' \+ K  `# p
    // This is a simple schedule, with only one action that is+ h" W& T4 `% X
    // just repeated every time. See jmousetrap for more/ z/ e' d" k4 d3 a, F
    // complicated schedules.7 N6 }* |' Y0 I8 Y
  
' A9 k0 V1 f$ E0 N2 s    modelSchedule = new ScheduleImpl (getZone (), 1);
3 C, l  Q0 g3 l% X: I% Y" S    modelSchedule.at$createAction (0, modelActions);0 h3 k9 F, I- D' _$ J: f% \
        
" {) b5 M9 I0 U9 u4 Y  t; G    return this;
* U0 w( {: E9 T, v  }
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