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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:. _; H% B' \1 B. U9 G. T
. O' W0 J6 M, Y8 q+ V, `
public Object buildActions () {- @- D2 U: r) Z, L. z
    super.buildActions();
4 ~# W+ g0 g' Z. P5 V5 M* \' w   
& w- ]- A  I, B. a    // Create the list of simulation actions. We put these in
, l3 L! x0 `0 k' L+ O4 N- v3 N    // an action group, because we want these actions to be* z% m8 F  G; b- K
    // executed in a specific order, but these steps should
$ N9 T6 j# y# c0 F; I( Q    // take no (simulated) time. The M(foo) means "The message
, f- J+ r6 }0 M6 w7 B; N    // called <foo>". You can send a message To a particular
: {) o' {2 V( z5 {    // object, or ForEach object in a collection.  b) i! n8 c/ S) }# l
        
, m! h1 T3 W* S    // Note we update the heatspace in two phases: first run
! g7 }8 N/ P8 {( E* N    // diffusion, then run "updateWorld" to actually enact the' v  e" G& S$ z% ]
    // changes the heatbugs have made. The ordering here is8 o) M( B  b% z3 N6 P) X, V) Z  }
    // significant!
" T* v) O; M" a0 U& N. u! D0 F        
$ W6 @* c' T: X5 }( n3 Z. \    // Note also, that with the additional& z2 E7 c1 |0 E! J+ J. j; E
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
6 o, e) [& p$ B    // randomize the order in which the bugs actually run- |4 c( p2 G$ Q7 M4 `
    // their step rule.  This has the effect of removing any
% B8 B; d0 T: ~/ a5 M    // systematic bias in the iteration throught the heatbug
8 k% P$ I9 h& F" S4 R5 m    // list from timestep to timestep7 l* f) Q( S6 b1 [) @: A( G
        7 m$ K+ d& x5 E# d* D- v) e3 H" g
    // By default, all `createActionForEach' modelActions have
& z$ f3 c4 c+ T( q( I2 d) s$ w) P    // a default order of `Sequential', which means that the9 r8 y( s# b- [* I; k7 g# ]
    // order of iteration through the `heatbugList' will be  F6 z" j: e, \" a) t8 z
    // identical (assuming the list order is not changed9 P' p0 c6 i  G- I
    // indirectly by some other process).
: b% u4 R0 v& Q* e  R    7 I2 M1 R5 S: z; S2 u* V6 Q; w
    modelActions = new ActionGroupImpl (getZone ());
" o1 D/ ~0 N- }4 J+ }6 b: L
, y" y3 `; R3 p% Q    try {
$ E) c9 z1 _( _5 P2 a8 n      modelActions.createActionTo$message
; t* Q0 k* ~# k        (heat, new Selector (heat.getClass (), "stepRule", false));& b6 e. v* U' Q, q, o1 c- H8 }( ~
    } catch (Exception e) {1 J! X+ U1 `4 {; N
      System.err.println ("Exception stepRule: " + e.getMessage ());
$ a2 _, f/ e4 I. k$ \, Y$ i    }: A! {& c0 p3 N: g8 g/ H+ \
$ t; Z9 j$ F% z5 _! u6 I7 v
    try {
1 i$ E: i0 n3 \      Heatbug proto = (Heatbug) heatbugList.get (0);
/ z+ G$ _9 D' y4 M, ]$ R  v5 Z      Selector sel = - f2 q4 J2 X$ E% C. O) V2 m5 K
        new Selector (proto.getClass (), "heatbugStep", false);& {$ s! N) t0 M4 n! [% o
      actionForEach =
! H8 p. `- g$ }- C        modelActions.createFActionForEachHomogeneous$call$ a2 X8 z3 r1 I) V
        (heatbugList,
" n  R- d& r  d% U         new FCallImpl (this, proto, sel,
) Q7 T( c8 ~5 K8 c                        new FArgumentsImpl (this, sel)));+ Q6 F/ ]+ y; j' m# j, A% ~
    } catch (Exception e) {
$ m: p- J) U) b, P      e.printStackTrace (System.err);' |/ A$ H7 l' w$ [2 q
    }, y' ?5 X+ ]+ z8 l2 @9 h/ z
    6 o3 B7 n* J# \8 i) {! ^4 @
    syncUpdateOrder ();4 O6 F3 [9 Q) E
, l0 A  @. A8 c( s' t6 B
    try {
% y% X& l- P. O      modelActions.createActionTo$message ) B: W1 c& c7 `8 u* p
        (heat, new Selector (heat.getClass (), "updateLattice", false));
" }3 S3 f9 k$ T; L    } catch (Exception e) {7 L  Y' U) M4 ~& f! g
      System.err.println("Exception updateLattice: " + e.getMessage ());* \- w7 O7 k) q! |* Q. Y9 h0 e) s
    }
+ ^# I; Z& R" S; @; p+ v, [, b        
& V- X# n! x5 {; V    // Then we create a schedule that executes the
0 {$ ~. |+ |- z7 r    // modelActions. modelActions is an ActionGroup, by itself it
% \6 B. [, c% _$ J7 i7 V2 A/ g2 \    // has no notion of time. In order to have it executed in
8 A* J) i$ M0 A% p( ]    // time, we create a Schedule that says to use the1 k: [2 M  ]& R- l- q1 A& e
    // modelActions ActionGroup at particular times.  This
- B) q8 U1 `2 {    // schedule has a repeat interval of 1, it will loop every' W: i7 k5 C: I# x2 X. }
    // time step.  The action is executed at time 0 relative to: p2 I+ E$ i+ H- O% w* R
    // the beginning of the loop.
: J! d, L( D& j; o2 l
' U2 z& q0 T0 I6 a& e% x8 p2 T    // This is a simple schedule, with only one action that is0 r- ^% j- [$ P% b( y8 c$ j  U" V% r) H
    // just repeated every time. See jmousetrap for more$ `$ t$ |+ R' w% ~# t- B
    // complicated schedules.; q8 q8 o7 A, Q: x! v9 ^0 `
  
+ |8 U! o" o5 p( W" b) u# d4 W# R    modelSchedule = new ScheduleImpl (getZone (), 1);$ [3 H- o7 }. D9 \/ B1 o/ @
    modelSchedule.at$createAction (0, modelActions);$ ]9 k+ Z: c0 v' G2 z% z, G+ K! Q
        
0 @: N& {& Q2 b! w5 G; j    return this;4 a3 {6 N/ \! e4 H
  }
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