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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:0 Q- j* Z3 V2 a* @4 n  M  Q. `
( e7 n1 {  Y% e
public Object buildActions () {
; h& @2 A0 w. q+ F5 A    super.buildActions();
3 `7 W& R" ]( B+ v% I  {    * ?6 `9 n5 r& e3 Y; F
    // Create the list of simulation actions. We put these in
5 k' p# M7 v; [    // an action group, because we want these actions to be
- l3 b; [. [# V8 L, v) K    // executed in a specific order, but these steps should) Q. S' u% a: |6 d9 ~% u; A' d
    // take no (simulated) time. The M(foo) means "The message
( l* V% ?2 r7 F( T    // called <foo>". You can send a message To a particular
" `7 A7 G4 i5 a% L4 o: a( o    // object, or ForEach object in a collection.6 W4 Y+ e: M1 A+ Q1 W
        & C& u, Q, \8 K& i
    // Note we update the heatspace in two phases: first run
# N  |6 @7 Z; o4 p8 B    // diffusion, then run "updateWorld" to actually enact the. v* Z* w% c# q; }4 e- q
    // changes the heatbugs have made. The ordering here is
5 w% i1 O' C; E    // significant!
8 d3 |9 y! v& L6 r        
4 S6 K1 e. s2 I* g9 T' ]    // Note also, that with the additional
: E+ B* y( X1 d" ?    // `randomizeHeatbugUpdateOrder' Boolean flag we can
& ]2 |4 l+ g8 x% ?    // randomize the order in which the bugs actually run
8 K; T1 a4 c3 E9 s    // their step rule.  This has the effect of removing any
( a% I# j. p3 G) w5 W    // systematic bias in the iteration throught the heatbug
0 J# r; F( p# B    // list from timestep to timestep
# t& s+ }' i1 R3 Q) z( K        - b* J4 S; E% U, E
    // By default, all `createActionForEach' modelActions have
( i8 H8 \+ T& _6 Q- N    // a default order of `Sequential', which means that the1 f7 h* O/ A' b- D
    // order of iteration through the `heatbugList' will be3 o7 n- }$ l$ r  `' n
    // identical (assuming the list order is not changed; c  v8 x. {7 j
    // indirectly by some other process).0 n2 s! T2 o# V' Q
   
; t' v* P) p2 D6 W. j* H    modelActions = new ActionGroupImpl (getZone ());2 L" m1 ~' \, e$ I+ ?! V

/ r5 L; n. v& x$ e    try {
2 M) m! e9 N$ U4 f      modelActions.createActionTo$message
9 f) p" l: h$ R$ p        (heat, new Selector (heat.getClass (), "stepRule", false));
' i' D- c' h$ s; p+ ?    } catch (Exception e) {4 x1 h; `5 B/ x7 n5 u: z
      System.err.println ("Exception stepRule: " + e.getMessage ());$ ?, S6 H, y' n! k) _3 C! T: i$ o
    }8 d$ g0 E( o5 _( Y) `! W

+ ?0 R/ Z" k# R1 I: r    try {
6 L( _8 k5 `$ C8 q; `      Heatbug proto = (Heatbug) heatbugList.get (0);
8 g# {; j8 {/ m      Selector sel = ( R) N) h) }  _$ Z* L1 X# w8 J
        new Selector (proto.getClass (), "heatbugStep", false);  s* B$ n- j$ k# ]3 R
      actionForEach =
9 _, C$ O' @6 b) B  \) r+ u        modelActions.createFActionForEachHomogeneous$call
$ @2 F: K- B7 i$ k        (heatbugList,/ v) I9 Y6 c* ^& n- k7 D" m7 w
         new FCallImpl (this, proto, sel,
# M" |% e- i6 Q) f4 u0 K! o3 v5 r                        new FArgumentsImpl (this, sel)));
! y) O) X! }( j1 K: x3 I    } catch (Exception e) {& D9 i9 n. M/ X
      e.printStackTrace (System.err);# K" B& g4 z5 x' ?8 c  Y1 G* V# B4 J
    }8 |; p5 P2 G& s
   
$ b+ p# C, ?$ ?4 K0 L  k. a    syncUpdateOrder ();7 x3 s; G) L5 Y
0 w; E7 S/ R' J/ g/ S) K
    try {
; M; ^* K7 p6 o9 }' P      modelActions.createActionTo$message
1 m, z5 r. Q8 }* A- v$ ?3 ]        (heat, new Selector (heat.getClass (), "updateLattice", false));
, o; `5 |; R9 h) r! C$ A    } catch (Exception e) {9 I" z5 P) P! U5 [: F
      System.err.println("Exception updateLattice: " + e.getMessage ());
; N& A" C# R6 e, e    }, s! d$ m) }: q( `) H
        
3 w% I% B; s3 l. n: ]* Y' R( M* n1 ]    // Then we create a schedule that executes the
# z* q  E: n  ?% N$ N, t4 g" a    // modelActions. modelActions is an ActionGroup, by itself it1 z9 ^/ K" E* B+ v  e) R
    // has no notion of time. In order to have it executed in$ u4 c- h! W9 ^5 u
    // time, we create a Schedule that says to use the
8 L8 a( a+ `8 n4 {% |5 r    // modelActions ActionGroup at particular times.  This( \; J6 k( Z( h
    // schedule has a repeat interval of 1, it will loop every
1 L! [. [, {1 H6 v    // time step.  The action is executed at time 0 relative to' @8 }7 ]5 z2 k$ d' ]7 {0 h
    // the beginning of the loop.
9 V% X  q6 W5 A- l8 s9 A3 k5 z! i6 U, s
- V6 P" N4 G' |% n- }; A    // This is a simple schedule, with only one action that is1 B3 x6 A3 _  }4 P2 q/ P
    // just repeated every time. See jmousetrap for more
  }. m) f' y& O6 K  g- ?4 f    // complicated schedules.
! |  H  S$ a+ z6 |; L* r! d  G. L  
- V6 j6 a. W) O, c  b/ t    modelSchedule = new ScheduleImpl (getZone (), 1);
- D: K8 _$ y  @; w. o" Q8 x9 B" I2 }9 b# \3 y    modelSchedule.at$createAction (0, modelActions);
" S0 S! S. Y* C4 c( O, \/ A        
3 f* F7 R2 u# G" q0 \    return this;
, J& N: B+ Q8 W  I. b  }
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