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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:; t) X, g  Q8 k/ A9 d. a7 m

) \" ]% |( S, ]& p6 H3 k( \ public Object buildActions () {
0 Q. G0 r( Z; w$ k5 l    super.buildActions();
) u- t9 s1 b( V% |( q5 E: ?    , G2 }: \3 P" i9 {
    // Create the list of simulation actions. We put these in: U1 X6 F4 L7 Z/ q9 Y2 r
    // an action group, because we want these actions to be
, G0 A; _$ ]; U2 y& B$ Z  j  K( e1 t1 X    // executed in a specific order, but these steps should) X6 S/ K& G' Y) U1 U9 T
    // take no (simulated) time. The M(foo) means "The message
6 L# f5 j/ W( }5 a, ?! G6 u8 a    // called <foo>". You can send a message To a particular
' v: e- q+ c  ?7 G2 A3 g    // object, or ForEach object in a collection.
/ s" A( L- G0 U  |" A9 a        ' j5 y3 z- J' P4 Z, {$ I" Q8 J6 J
    // Note we update the heatspace in two phases: first run
$ W4 n# j8 k* V- {- f" s    // diffusion, then run "updateWorld" to actually enact the
4 i  `6 h. f2 m+ r& b& I6 e    // changes the heatbugs have made. The ordering here is
2 W- p/ s0 h: ^; Y% \6 C1 K    // significant!
. u7 o" i! K  c- l3 c; D5 Z        
  Z) G! y6 K* u2 t5 M( {8 w5 I    // Note also, that with the additional
  N5 P# |3 a# N) R1 Z% P& C    // `randomizeHeatbugUpdateOrder' Boolean flag we can9 X" ?; a: ~. x6 ~$ _9 r0 }4 s5 ?
    // randomize the order in which the bugs actually run
* I+ r# R- o9 q, \" |/ [/ ^; m    // their step rule.  This has the effect of removing any
7 Z( q3 n! E# [9 o! R2 E0 @* R0 U    // systematic bias in the iteration throught the heatbug% t8 I$ w, ^9 T2 h8 V+ b9 U
    // list from timestep to timestep
6 _3 C0 [; w8 L, `" P; b        
1 V5 [* z4 Z$ w    // By default, all `createActionForEach' modelActions have# M( b* R  N6 ^& S5 w  H" P8 e
    // a default order of `Sequential', which means that the6 T$ r4 N8 G+ n
    // order of iteration through the `heatbugList' will be
1 ~$ w) m/ W( C; P) `    // identical (assuming the list order is not changed" J: I3 s8 r2 s8 K1 F: ^& c8 Y: ^
    // indirectly by some other process).
, M7 e5 w; H! o" K+ n) {   
* f9 o- o* H6 c2 r1 V' o    modelActions = new ActionGroupImpl (getZone ());
$ ~2 l0 }: l5 P1 s5 L7 }# `" G3 O  `9 u
    try {
" u( ~0 B; y3 E      modelActions.createActionTo$message
# O* V7 F, V7 Y        (heat, new Selector (heat.getClass (), "stepRule", false));
( {% Y+ V6 \" U9 G& Q  D    } catch (Exception e) {
1 X5 \5 U% C. e+ n  F' C1 S1 I* w( Z4 x      System.err.println ("Exception stepRule: " + e.getMessage ());
9 N& J$ }4 C. |; p    }1 V+ q& o* @" z9 [" O
- l2 ?: L1 Z' r6 u5 m, q
    try {2 M$ B. g' a. }
      Heatbug proto = (Heatbug) heatbugList.get (0);) o# B% q7 R( x' J) y- v
      Selector sel =
; c( \& T" \( u7 I        new Selector (proto.getClass (), "heatbugStep", false);
5 M8 w4 h) u/ ~9 i      actionForEach =& W0 R8 v* W6 \) |" |) b
        modelActions.createFActionForEachHomogeneous$call
$ a! r7 S) r$ J& G, c        (heatbugList,
0 ?3 t/ E1 D% P: M1 e4 v( E8 d+ D         new FCallImpl (this, proto, sel,4 z7 B' ]; m# C  ]$ c
                        new FArgumentsImpl (this, sel)));, M! w9 w! Y" p! _/ Y) m
    } catch (Exception e) {( p7 l4 b0 n& o: t1 ]. @0 U/ h
      e.printStackTrace (System.err);: v4 W3 t+ Z6 \0 ?* {
    }! A, g2 }# `1 {( U5 J
    ' b9 P' A% {) R+ P2 V
    syncUpdateOrder ();
7 q; h/ A2 K5 m" l2 l5 i! o6 M* p% _
    try {
. s/ Y" Y- d% Y) P2 |      modelActions.createActionTo$message
+ _4 d4 `* J6 e5 @" {' }1 z; Y        (heat, new Selector (heat.getClass (), "updateLattice", false));
4 \, F4 D/ z. q% C    } catch (Exception e) {
9 u1 h. Q# A: G2 S' N      System.err.println("Exception updateLattice: " + e.getMessage ());
1 ~: a6 }) w$ c* g% \1 `1 ?8 _7 ?    }
2 Q# u: B  U3 M. U) E) E' d        % J# Q$ H4 B. N: l% s: @3 I; \
    // Then we create a schedule that executes the) L5 T, v% J* t- |7 \+ d6 B
    // modelActions. modelActions is an ActionGroup, by itself it  L: D. E; b9 ~+ l5 l
    // has no notion of time. In order to have it executed in/ Y4 W6 D) T2 Y( F! Y
    // time, we create a Schedule that says to use the
- A0 _$ `# G1 D- ^, l) U    // modelActions ActionGroup at particular times.  This
: h( Z" p3 n/ S3 y) T7 d) c    // schedule has a repeat interval of 1, it will loop every7 {6 ]& \; ]1 n1 y
    // time step.  The action is executed at time 0 relative to
7 F' }6 f6 B7 k& a  ?; p# e' Q    // the beginning of the loop.
  f$ A! F# e5 e9 k  U# o0 e# p0 J. ]8 z; q4 H' w; E
    // This is a simple schedule, with only one action that is/ t' F/ N: Z( H1 ~& s
    // just repeated every time. See jmousetrap for more, S( o" B$ q. b* g( \& P, ^
    // complicated schedules.
0 q, \! c2 z6 n4 C/ Z1 V  : ^* g/ `4 n. e
    modelSchedule = new ScheduleImpl (getZone (), 1);
8 @( A+ p' u- k  e7 V    modelSchedule.at$createAction (0, modelActions);9 g& y  _: d4 ]% C3 r4 J0 J8 q! a" L
        0 h3 \- c; L0 |" ?! c: s3 d' ~( F
    return this;
$ |% p" S1 N4 L1 ~" S  }
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