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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:; T0 i' a+ ^1 Y$ C# {
- `0 J) s( h/ d8 W
public Object buildActions () {
' X! t/ m( n! k8 a    super.buildActions();1 T1 v# ^3 O+ f+ g& }
   
! m1 o5 x$ q* y# X' S, J: }% q    // Create the list of simulation actions. We put these in, w3 w  w' e" c" O. @* J+ |5 M
    // an action group, because we want these actions to be
5 P# |- O! S, D0 i4 o" y    // executed in a specific order, but these steps should
2 M; |! _: k% n- r    // take no (simulated) time. The M(foo) means "The message
! l3 C" x# u. j' g, w# a  K$ ^& m& G    // called <foo>". You can send a message To a particular
& Q) M& k9 g4 \    // object, or ForEach object in a collection.% N5 B2 {7 a# y# m, ?
        
) z" D, c: h+ ^+ j( f( n0 R    // Note we update the heatspace in two phases: first run! V) c2 ~$ |8 Q/ V) B
    // diffusion, then run "updateWorld" to actually enact the
) m8 k4 E/ F! ~( G3 ]- @: K) D    // changes the heatbugs have made. The ordering here is& w1 |7 f+ K0 L3 R5 j1 q1 Q4 h. \
    // significant!
4 t2 w" a1 y* H, ?/ N  X        
! ]2 u1 W, S; \5 F    // Note also, that with the additional
2 i& \4 s. E3 @* i    // `randomizeHeatbugUpdateOrder' Boolean flag we can) z+ q3 d/ Z4 [/ u  E8 ~
    // randomize the order in which the bugs actually run2 T/ P# t$ e* B1 I( \1 A
    // their step rule.  This has the effect of removing any2 E. b9 s+ R1 H
    // systematic bias in the iteration throught the heatbug
) J0 k. b( ^% F$ z' B    // list from timestep to timestep
+ d2 h# T- l- X. G+ T+ p4 A7 S        2 Q+ \9 X0 P8 L
    // By default, all `createActionForEach' modelActions have5 S* ~" @! \0 L' P
    // a default order of `Sequential', which means that the
+ h2 A9 L1 F% H' i. U- e    // order of iteration through the `heatbugList' will be% U! N2 A' o: \+ W( {
    // identical (assuming the list order is not changed  Y# w2 n# f' O/ m
    // indirectly by some other process).! _( Z+ Z/ v, M' j, S
   
+ n4 `$ N  N5 n9 g0 q2 ]    modelActions = new ActionGroupImpl (getZone ());
2 N4 l2 z6 {$ ]; y3 R( n: H0 O
. _) Q, m" H1 ~( f1 Q0 H# ~1 O0 ?, r3 t    try {
- @5 i1 h' C% t4 W- b1 E5 ^      modelActions.createActionTo$message
' s! s, n! G; H% z& Y: {* q        (heat, new Selector (heat.getClass (), "stepRule", false));# r  F5 F- _) c. N
    } catch (Exception e) {
9 r: e+ z7 b/ I$ }3 ^9 K( g      System.err.println ("Exception stepRule: " + e.getMessage ());
/ n9 k" |  [  O/ `) g    }
* r9 K8 J* ?* Q/ f3 W. M
( O# |) B# }% n3 X+ W3 e) P& G    try {
, m" ~, n: ~/ Y. u* w( u6 X- ?8 `      Heatbug proto = (Heatbug) heatbugList.get (0);
$ R, q0 R( q3 r8 d6 W2 i+ c      Selector sel =
- C# P+ j. D. F6 w$ K        new Selector (proto.getClass (), "heatbugStep", false);
: A6 l( X& Z9 m! E$ W      actionForEach =/ H# P6 Y" B2 R3 e9 W. M" e
        modelActions.createFActionForEachHomogeneous$call
0 }; e; H4 \" a5 L5 P# B        (heatbugList,4 S( A4 q7 w3 G) e4 r1 n4 p
         new FCallImpl (this, proto, sel,
; P3 G5 J: K$ A4 ?) n9 z. a                        new FArgumentsImpl (this, sel)));
" l% a5 |/ \. K) p% x) F% k. M" G    } catch (Exception e) {
  T) T& ]$ t1 f( ~" \; U      e.printStackTrace (System.err);5 w% p/ J' t5 y" O4 k% m* s1 e
    }
5 v* J$ l2 m/ {) a2 Q7 \4 Q! m    ; X/ W" f* K5 s9 N5 f& C
    syncUpdateOrder ();
3 v8 i1 y3 C# [" R2 g$ j' y
8 ]$ o9 J+ q) q$ U    try {
, X2 v: O& D8 h" o( Y) h; |! D      modelActions.createActionTo$message ! ~7 n9 i. z9 m+ S$ M( ]3 C
        (heat, new Selector (heat.getClass (), "updateLattice", false));8 B" Q7 r/ ?& g' m5 N8 y
    } catch (Exception e) {! j! }+ `% y4 e& [8 n1 j
      System.err.println("Exception updateLattice: " + e.getMessage ());1 [* D% L5 v; \' P: u9 t! @
    }+ a! o. I! y& B8 o6 R9 O1 n
        6 X& w9 m. C8 ^- i
    // Then we create a schedule that executes the2 _/ c, l3 B$ v2 P* z. w
    // modelActions. modelActions is an ActionGroup, by itself it' E. N. a( t4 _1 K- B/ T
    // has no notion of time. In order to have it executed in3 P7 |4 {6 n( j1 b+ K' E
    // time, we create a Schedule that says to use the' G+ K9 n$ M, }/ r9 g9 Y5 S
    // modelActions ActionGroup at particular times.  This0 H' M9 ~/ b4 ?, Q7 F
    // schedule has a repeat interval of 1, it will loop every5 ]* `) K: R( X, _
    // time step.  The action is executed at time 0 relative to
7 ?; b. K% Q) ~! |' d! J; M    // the beginning of the loop.  k" n! H. y9 T+ H( U  v

* q6 }0 N# ^* |) ?6 z( i    // This is a simple schedule, with only one action that is! Z4 \  K" S8 ^( q, W
    // just repeated every time. See jmousetrap for more
  b3 o. m3 J9 Q  _' s% q    // complicated schedules.
3 O0 x8 i# t& ~+ y  $ @- w( b6 M8 y. R0 y
    modelSchedule = new ScheduleImpl (getZone (), 1);
/ u. Z/ L( l; n- N& w    modelSchedule.at$createAction (0, modelActions);( g7 z+ \, `9 \8 F+ {9 K' w
        7 G8 g0 G. m. V% E- V
    return this;. O: l: h% f! u4 M, I8 s' `9 t
  }
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