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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:. a' b4 _9 k! E1 o" \7 D

) B- q: K" c* s! y) s- R& L public Object buildActions () {5 J* w- v) D; P! N4 ?" y! }
    super.buildActions();. g/ L5 q/ s% |
    ( W5 d, E: x4 F* Y8 B
    // Create the list of simulation actions. We put these in
4 }1 O& E( V: s; K, u" n$ g1 b# g    // an action group, because we want these actions to be' g' M- K" E) ^- T) x
    // executed in a specific order, but these steps should
- u& [$ S' p. Y: A6 a9 ~2 [    // take no (simulated) time. The M(foo) means "The message
4 g7 O7 c7 U" P7 m$ i    // called <foo>". You can send a message To a particular
' l: k7 Z. O' p) p9 }    // object, or ForEach object in a collection.% d+ L; E% G' M6 g
        
" X+ }: R' Y) Q: e2 m+ x4 h) A    // Note we update the heatspace in two phases: first run. D" Q+ W9 ]7 V$ k# X3 a7 p
    // diffusion, then run "updateWorld" to actually enact the
! l; I$ p0 d2 `; L6 a4 Y    // changes the heatbugs have made. The ordering here is
& V2 N, Q% t5 h0 U. x    // significant!
- E  W$ S7 }1 V5 [' p0 _        
! N; X' u! s, C% [    // Note also, that with the additional8 E  V! C$ i: N
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
5 }  ?. s% u; }2 n, `% ~/ s0 v    // randomize the order in which the bugs actually run
- U7 k& }9 _. i! i6 B( L! f    // their step rule.  This has the effect of removing any
- l5 s+ a/ ?7 i; ~: U, v) m    // systematic bias in the iteration throught the heatbug6 R5 O3 l/ i. m4 ^$ d& }
    // list from timestep to timestep
) h& x" p; C) y# e: `! o        
. G$ m$ @: D# q. p! D: }( x    // By default, all `createActionForEach' modelActions have: Y* q3 e  z6 l' e0 X% I8 S
    // a default order of `Sequential', which means that the) z8 r9 B; k+ N8 E6 R4 H% ]! I6 B
    // order of iteration through the `heatbugList' will be6 |- l  }  _6 q0 A, W  f
    // identical (assuming the list order is not changed' B1 j* m* R/ r- }5 f
    // indirectly by some other process).
$ J  c# V2 U' ~" d, \    6 n* h$ ]: U6 A6 A3 M9 P
    modelActions = new ActionGroupImpl (getZone ());
! S& C9 C: p5 r- B9 A' R. H, K
0 B9 y9 W% M- a1 m$ m    try {7 J! Z% k8 V% {5 @# P
      modelActions.createActionTo$message
0 v* }# S* l0 X+ v6 i2 I        (heat, new Selector (heat.getClass (), "stepRule", false));
- C4 v' |$ m$ M, F1 z% P/ r    } catch (Exception e) {- W) @+ `3 y5 j4 J
      System.err.println ("Exception stepRule: " + e.getMessage ());
; a3 D) E( d) x7 A2 d& G$ Y    }
$ `1 O" j7 d8 K- h3 r
' @* a6 Y9 U' f6 O7 Q, Q* x6 @    try {
& U0 }- \: r7 W! R      Heatbug proto = (Heatbug) heatbugList.get (0);
; S  e. X/ [4 t& H      Selector sel =
- D2 F9 f$ s" E0 e8 P        new Selector (proto.getClass (), "heatbugStep", false);1 Z1 q' l7 h* g* H) v+ ^; D
      actionForEach =! a8 D) ]4 P, }9 q  ^, Y
        modelActions.createFActionForEachHomogeneous$call6 }/ r: [9 f0 \9 [" t4 C
        (heatbugList," V* x+ I7 G/ M8 M
         new FCallImpl (this, proto, sel,
7 K4 r6 P) P! E. N$ g1 S                        new FArgumentsImpl (this, sel)));
! z- N$ ^- g$ @& d. b, r    } catch (Exception e) {
. q" x$ i! u, }$ K+ F" v: O1 x2 I. e      e.printStackTrace (System.err);- M4 }- e1 k- J3 v- @6 u" e8 m! Q
    }
8 @& a% M- i% [! [: h    ( A& V1 ^$ s. A! h
    syncUpdateOrder ();
- x6 A* x1 n  }5 I! B- C* j; S# J& S; H$ t4 L& R* w/ g
    try {
+ s# k9 \! e) N; ^      modelActions.createActionTo$message ! z0 E; z( k2 g$ P
        (heat, new Selector (heat.getClass (), "updateLattice", false));% G8 T& k, q" w3 e
    } catch (Exception e) {
, b. e' \6 W' v      System.err.println("Exception updateLattice: " + e.getMessage ());
( m$ a8 I5 A4 I    }" l( e/ _0 N$ L2 z. h: @3 g# a
        . b4 l( \0 r- m, Y6 a" w) s8 N
    // Then we create a schedule that executes the
  e4 S# U6 D& K5 J6 {/ m3 U    // modelActions. modelActions is an ActionGroup, by itself it
% y! R5 Z# {5 r    // has no notion of time. In order to have it executed in# p. q# Q4 K$ n# O; o
    // time, we create a Schedule that says to use the
4 f3 R  v& D6 I! Q- q) m' B    // modelActions ActionGroup at particular times.  This
: E6 ~+ ?$ ^) l) ^$ m    // schedule has a repeat interval of 1, it will loop every. }1 O* c, L: k$ X. q# m) u$ p+ C
    // time step.  The action is executed at time 0 relative to
9 G1 @; a. l1 \+ [    // the beginning of the loop.2 B% p% p+ ~4 y- q, @# G7 J
9 ]) A# I' Y6 Z) p: R
    // This is a simple schedule, with only one action that is
" {) v7 G3 t. [    // just repeated every time. See jmousetrap for more
0 d% h6 z, S4 g    // complicated schedules.
) l4 `; U1 i; y! K. L  6 W- T- K7 x/ ~( m
    modelSchedule = new ScheduleImpl (getZone (), 1);
( J+ g. U2 o' A; @1 G    modelSchedule.at$createAction (0, modelActions);# S4 [$ e$ m7 t1 C
        
- i5 v  M- v3 {, `4 J; J    return this;
+ _- k5 {# S3 B% t0 T) ~# _  }
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