HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:. k4 r3 T$ d& }) ?' O% k5 B# c
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public Object buildActions () {3 q) }* K, l `! f M# i
super.buildActions();
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+ m7 S1 o! b( h) i- L7 [. \3 E // Create the list of simulation actions. We put these in% N% i8 ?) J Y9 r1 q+ R! n
// an action group, because we want these actions to be4 |( ~& J( s$ T
// executed in a specific order, but these steps should3 Q* \* K r/ m& a& H
// take no (simulated) time. The M(foo) means "The message
8 B' E/ O) h# s8 M, z( ] // called <foo>". You can send a message To a particular
" p2 j+ l) D1 T4 F2 U: G( N- U // object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run
4 s/ I( l% P6 r/ }# L // diffusion, then run "updateWorld" to actually enact the( }1 ~( E2 ` B' R
// changes the heatbugs have made. The ordering here is
$ f4 [8 b" }- W/ r // significant!* N" k; T t+ ~" n' |$ x. G
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// Note also, that with the additional
}$ U2 Y# _; L6 H w // `randomizeHeatbugUpdateOrder' Boolean flag we can! [) H5 c# C1 s2 R- |7 f
// randomize the order in which the bugs actually run
! W; ^+ Q( C# h; `0 Q2 a" K) p // their step rule. This has the effect of removing any
! ]5 ?. i- t1 i0 B0 k( S3 j // systematic bias in the iteration throught the heatbug) t% R) B4 C5 K4 E3 `
// list from timestep to timestep
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// By default, all `createActionForEach' modelActions have
- y+ U+ m6 @& x0 \/ u" H // a default order of `Sequential', which means that the. {+ m' Y$ B& |2 [( J' t
// order of iteration through the `heatbugList' will be
, A3 d/ n- j) _" R, I. L) L // identical (assuming the list order is not changed
- y ]1 D7 o$ ^. T // indirectly by some other process)., Z/ V N0 P/ V6 x
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modelActions = new ActionGroupImpl (getZone ());
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, {# o2 D; h6 S1 { try {
* c+ g& |* {7 \0 |8 b9 V modelActions.createActionTo$message
. B/ Q& h- S4 N: G# s (heat, new Selector (heat.getClass (), "stepRule", false));
9 y# Z- Y2 j7 D2 v. J z1 @ } catch (Exception e) {8 e- c# f. D- h; x. y/ p K
System.err.println ("Exception stepRule: " + e.getMessage ());
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try {
0 y6 |( y6 f& u% ] Heatbug proto = (Heatbug) heatbugList.get (0);3 v& O2 ^$ K. J0 l# r
Selector sel = " ^1 s2 J7 O# q z- K0 w( p
new Selector (proto.getClass (), "heatbugStep", false);8 g a- v7 v; L* i& o: H# A
actionForEach =3 n: W& M' u% l- Y$ R
modelActions.createFActionForEachHomogeneous$call- U! c/ b0 t. J8 E; E
(heatbugList,1 S4 V4 g/ U+ B
new FCallImpl (this, proto, sel,
2 S/ q7 g/ O+ d2 g. w9 Y9 ^ new FArgumentsImpl (this, sel)));
) k/ {2 L7 J, { } catch (Exception e) {
$ P6 m% r2 j% D' X& @% X, D$ f& { e.printStackTrace (System.err);
( L3 S6 h& h) Y* g) L }
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syncUpdateOrder ();) P9 g/ N( w! v" Q+ \
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try {0 P. J2 W; U @0 f
modelActions.createActionTo$message 2 C* t! c; w9 u
(heat, new Selector (heat.getClass (), "updateLattice", false));
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System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the5 _4 D0 w6 r% M
// modelActions. modelActions is an ActionGroup, by itself it6 ]( ^0 X9 t6 {
// has no notion of time. In order to have it executed in |: L6 N5 x4 H! P8 i$ I6 |
// time, we create a Schedule that says to use the
7 u( Q9 ^! a5 K! F0 B // modelActions ActionGroup at particular times. This
% e: o5 \, ^! C$ w9 S // schedule has a repeat interval of 1, it will loop every% Z; x8 g5 e( c8 W
// time step. The action is executed at time 0 relative to# |3 D1 ?: X) g' N9 `) c3 F/ }
// the beginning of the loop.
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// This is a simple schedule, with only one action that is
- ?7 o+ a" B6 o2 b% j // just repeated every time. See jmousetrap for more3 g. x! M7 T3 V" T
// complicated schedules.1 {; D" ^; c ~+ |- @5 a' L% ^
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modelSchedule = new ScheduleImpl (getZone (), 1);8 P# G7 g1 o. P. I1 V
modelSchedule.at$createAction (0, modelActions);
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& X( i9 h* D( o6 B! g5 l: f9 [4 N* q0 M return this;
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