HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:9 y5 B4 c, f$ t1 {. Y
5 D) c/ `' b4 m6 |% N public Object buildActions () {9 U. l5 M4 ^) q
super.buildActions();* G1 `& x' A5 {% p* U. R
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// Create the list of simulation actions. We put these in# Q8 H' r' ?7 Z/ N, ]/ Z
// an action group, because we want these actions to be
2 d. ~; Q$ t$ x- r$ {6 s // executed in a specific order, but these steps should) N. u2 c$ E3 z* L
// take no (simulated) time. The M(foo) means "The message
, Z0 J% _$ s3 J6 q W% t, @* H$ I/ ?$ P // called <foo>". You can send a message To a particular
( p7 D7 h. t: I // object, or ForEach object in a collection.
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& v8 P. Q$ M: m$ q9 P5 O // Note we update the heatspace in two phases: first run
! E0 x4 M% F; G: S1 ? // diffusion, then run "updateWorld" to actually enact the2 }7 d) I4 f U
// changes the heatbugs have made. The ordering here is
$ N1 [, _1 D2 E! l // significant!
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- l w! ]7 @( E8 d$ W8 p // Note also, that with the additional
8 m9 K2 a: J! G# j: Q% L# Q // `randomizeHeatbugUpdateOrder' Boolean flag we can
2 y6 }( e- B$ E a' P8 H // randomize the order in which the bugs actually run% g7 v& l0 a4 I( f' w6 K! {% M
// their step rule. This has the effect of removing any+ k4 v; o! P4 ^1 F1 X6 P5 t
// systematic bias in the iteration throught the heatbug
T& i+ c8 J* P // list from timestep to timestep
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// By default, all `createActionForEach' modelActions have: W# }0 T! O" k, n% J: n3 U( [
// a default order of `Sequential', which means that the3 u+ g: x1 N$ D3 n( ]1 {
// order of iteration through the `heatbugList' will be# o. J8 _7 h3 [" k
// identical (assuming the list order is not changed
2 o0 e1 p! L, n7 Y // indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ());
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try {
5 P C/ T2 ]7 ?9 [' V modelActions.createActionTo$message- f7 H) [- O1 N' ?; |4 c
(heat, new Selector (heat.getClass (), "stepRule", false));- M) ]8 w( x/ Y0 {$ W& w9 z
} catch (Exception e) {
1 _! e) H) T' { `3 o8 D System.err.println ("Exception stepRule: " + e.getMessage ());
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try {& f" I0 [3 C _7 v
Heatbug proto = (Heatbug) heatbugList.get (0);
9 h( [, K! k- v$ w- k Selector sel = * u: g& @8 @: K2 J* u) d
new Selector (proto.getClass (), "heatbugStep", false);- @( u5 C1 r2 `: x8 |& |6 j) K
actionForEach =
7 [9 C! c2 o% U& K: G/ Q3 \ modelActions.createFActionForEachHomogeneous$call9 L4 |2 @( X: K' A) I7 F
(heatbugList,
6 k! k7 J0 j! [9 \ new FCallImpl (this, proto, sel,
& u1 p: o; z, }" ~+ y- j$ k new FArgumentsImpl (this, sel)));
( H! Q( ` y _5 t } catch (Exception e) {3 U R) j. B' r3 J8 Y3 Y
e.printStackTrace (System.err);/ B! o7 @1 q* {3 y
}
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5 p, _7 e Y! a. e& y* d0 {# t syncUpdateOrder (); @+ y" X" T, M
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modelActions.createActionTo$message 7 k5 k; A) i/ z+ g. h j
(heat, new Selector (heat.getClass (), "updateLattice", false));
5 A/ M: l/ S4 k! K% F4 o } catch (Exception e) {
, d6 [. R4 `0 [+ r: K/ y' J System.err.println("Exception updateLattice: " + e.getMessage ());+ Y' U4 X$ m! B
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// Then we create a schedule that executes the
9 D( `8 y; \0 F. W // modelActions. modelActions is an ActionGroup, by itself it# b0 P0 L5 W# U0 _% {0 Z( A
// has no notion of time. In order to have it executed in/ D+ j7 ~3 G$ \ B. C1 h
// time, we create a Schedule that says to use the
3 m: V9 {" N; B, f3 t0 D! n // modelActions ActionGroup at particular times. This6 C# T5 x j) ~" ]; f8 C
// schedule has a repeat interval of 1, it will loop every
D# W) P/ `; o1 d. J // time step. The action is executed at time 0 relative to7 g) N* B8 F# Q' S
// the beginning of the loop. q6 g. t' {3 x9 r a9 h/ l6 X
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// This is a simple schedule, with only one action that is" X8 n% t8 ?5 ]4 q
// just repeated every time. See jmousetrap for more# Z( a2 c7 a* ]# A5 C, i
// complicated schedules.
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$ D# C' g) y- Z: E( c modelSchedule = new ScheduleImpl (getZone (), 1);
/ U6 o" f. r8 N5 J8 w modelSchedule.at$createAction (0, modelActions);
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" W2 f0 x) Y' k# J9 X return this;7 T: {0 s/ L7 U* B$ `
} |