HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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, c; T5 K5 q* d2 Q W- _) t1 C, i# E public Object buildActions () {
( d+ m5 b1 n' U7 W: T8 ?5 v super.buildActions();# P s" l+ O$ K* I j2 V
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// Create the list of simulation actions. We put these in
/ u/ } k w( k( ] // an action group, because we want these actions to be
' k9 M3 y2 @) p$ D9 g( h( e // executed in a specific order, but these steps should
9 S( ?* O: s/ j5 {4 | // take no (simulated) time. The M(foo) means "The message
7 S/ R: y6 r) |+ {% {8 u // called <foo>". You can send a message To a particular
8 J2 s+ j7 h2 t // object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run1 {( y q* L* s+ @& b+ y \& b0 S
// diffusion, then run "updateWorld" to actually enact the+ F0 e$ h. R) w
// changes the heatbugs have made. The ordering here is
4 D4 K' w$ e* {/ u // significant!4 G) s2 \/ O& r
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// Note also, that with the additional8 b! m# R: f3 e: m) \' E& t. P# }
// `randomizeHeatbugUpdateOrder' Boolean flag we can O4 S9 H- _; ~2 v: t
// randomize the order in which the bugs actually run n- K7 j; d7 h$ z6 c
// their step rule. This has the effect of removing any
- O6 d& w9 x! Z! p! A2 [/ t9 R" D // systematic bias in the iteration throught the heatbug0 I$ [! Z+ K2 _% z
// list from timestep to timestep
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// By default, all `createActionForEach' modelActions have
1 i: J6 o! Z: {" T2 H# j // a default order of `Sequential', which means that the
0 y6 L; q* j% T' W* `, H // order of iteration through the `heatbugList' will be$ k; E5 n! ^. G7 n
// identical (assuming the list order is not changed
; Q$ M7 n& k, U) L // indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ());4 _9 E. k+ X! J' T) U0 @% b4 ~
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try { E9 d9 P: M h) C
modelActions.createActionTo$message( B5 ^. P3 n6 `- q* T% B
(heat, new Selector (heat.getClass (), "stepRule", false));1 R' m- Z; s' j
} catch (Exception e) {
% Q; [# P/ T0 V) j) ~ System.err.println ("Exception stepRule: " + e.getMessage ());: z& n6 @* x# {$ c4 v
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; q( A7 F1 {+ A$ q+ V try {
0 S; _* I: u8 Z/ @8 u2 c Heatbug proto = (Heatbug) heatbugList.get (0);# B9 c8 O- d1 b8 z) g' i! M2 p
Selector sel =
' i5 H; @" Y6 Q new Selector (proto.getClass (), "heatbugStep", false);; K8 D# E2 m+ p3 v; i
actionForEach = c# S3 ~$ }" m/ V8 O; m3 i" o; @
modelActions.createFActionForEachHomogeneous$call. b7 j5 l' d6 [
(heatbugList,
9 ^( `' H- c( u9 F. h- p/ | new FCallImpl (this, proto, sel,
, X$ x S' J2 w" p new FArgumentsImpl (this, sel)));% G/ {: v# b! k- T
} catch (Exception e) {
9 \, O, H1 i5 K. o: Q2 U [+ j e.printStackTrace (System.err);
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syncUpdateOrder ();
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modelActions.createActionTo$message
4 S* F+ X3 y& M I1 ^ (heat, new Selector (heat.getClass (), "updateLattice", false));
: D L; v& `( W0 {/ s" Z } catch (Exception e) {5 j$ |9 ~5 T. v8 ~
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the
; ~6 K6 u% O) [$ r; O: A // modelActions. modelActions is an ActionGroup, by itself it0 I: Y4 X1 M8 A! v* r4 r: _
// has no notion of time. In order to have it executed in0 j+ N: L5 @* O5 k
// time, we create a Schedule that says to use the5 c+ M0 y( g, f& D9 x
// modelActions ActionGroup at particular times. This" ^' g8 {5 x0 F R7 u
// schedule has a repeat interval of 1, it will loop every+ J1 L! Z9 j1 C0 N9 P
// time step. The action is executed at time 0 relative to
' D- X0 Y, w6 y6 _/ x9 q // the beginning of the loop.! F- r$ ~/ u1 r7 K
2 D# [' _% {* d2 q4 s& f+ t // This is a simple schedule, with only one action that is
& k8 s6 J1 z1 H% v) _5 t# M // just repeated every time. See jmousetrap for more
4 n f! M( I) T) o; V // complicated schedules.
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modelSchedule = new ScheduleImpl (getZone (), 1);
6 W; V8 u3 o2 I- U modelSchedule.at$createAction (0, modelActions);9 `- ]% N4 K6 r. B
: C0 A6 O$ \" I) a4 G! l( J return this;3 s6 E" Q& R3 V% U% U2 W0 n
} |