设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 11345|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:( F$ W, ^. E8 [+ J+ R- h
; O1 t# J3 Q  B' h# x  X
public Object buildActions () {" }9 J0 k+ ^& X: Y" o* z1 \
    super.buildActions();8 m' U$ y7 `$ I7 x  V$ k) N, u
    4 b+ X" q  G2 G7 G1 V) `
    // Create the list of simulation actions. We put these in- S. O0 }( S" ?+ L1 i
    // an action group, because we want these actions to be
9 [+ y4 a1 J8 j) M# f, H    // executed in a specific order, but these steps should/ ^2 j1 k9 u8 O1 P' R; E
    // take no (simulated) time. The M(foo) means "The message
8 F( e7 o1 ^) @6 t" @, R    // called <foo>". You can send a message To a particular
" O& l* w* `& m4 b0 [    // object, or ForEach object in a collection.
2 J* S) i0 n1 i4 U. |" c; G: N) C        
9 W* W7 Y, E2 A- u    // Note we update the heatspace in two phases: first run
7 n, u- E7 Q) `  `' p( l    // diffusion, then run "updateWorld" to actually enact the
7 R/ T8 [- d! f! g    // changes the heatbugs have made. The ordering here is+ }( X# N2 D2 C' f5 A/ g6 _
    // significant!: L# x$ d8 N  R
        
5 X- a! v! X5 q% }% ]* F    // Note also, that with the additional9 I  e5 Z9 A; B# g' N' C* a
    // `randomizeHeatbugUpdateOrder' Boolean flag we can% y) w: {% D$ `% r' ^5 C: H
    // randomize the order in which the bugs actually run
: X1 S; f5 ^/ E4 |    // their step rule.  This has the effect of removing any$ f4 N# s0 k' W6 {" P$ {
    // systematic bias in the iteration throught the heatbug5 x: Y6 X. ]( H4 q* q. U# M
    // list from timestep to timestep# g* H# y! j. _  o  Y) `4 m' K
        
& j9 N* r0 a4 X( C    // By default, all `createActionForEach' modelActions have: ?. |3 ^$ s7 }, [6 I5 m3 W9 j; Z" \  o
    // a default order of `Sequential', which means that the' V0 x0 O1 s+ F' g  k3 y
    // order of iteration through the `heatbugList' will be
# r% \* J8 C! T/ E- r% T    // identical (assuming the list order is not changed
* R3 \0 r, d  c( u: O3 Y    // indirectly by some other process).
, d! q% ?' x. P( `   
: J0 s) T) ^' S    modelActions = new ActionGroupImpl (getZone ());
$ A1 D( _( Q. Q+ y
2 w% o+ u' n" E& ]. H6 L5 Y    try {; \! y; N& P% G/ `7 Z) Y) n
      modelActions.createActionTo$message
0 H( Z& g7 D# B1 }9 O) v        (heat, new Selector (heat.getClass (), "stepRule", false));: ^+ X$ o; l' m
    } catch (Exception e) {
. L% e& j) N5 K/ C/ e& |% q$ J      System.err.println ("Exception stepRule: " + e.getMessage ());3 K' Q2 H; C- A+ M3 Y
    }
% D4 ?# N7 [) E( j4 `* z4 h. ~$ F$ V, F# W% ^4 S
    try {
# p* V$ j5 ?* X      Heatbug proto = (Heatbug) heatbugList.get (0);! O; L/ R6 y3 m; a6 V
      Selector sel = * p+ O1 f4 F$ X( x" G" Q0 f
        new Selector (proto.getClass (), "heatbugStep", false);  |) w4 ]' u0 p2 N
      actionForEach =+ K" q) |6 h. Y% w
        modelActions.createFActionForEachHomogeneous$call& x" V/ }- R- c+ J
        (heatbugList,- ?% Z; k- B: F' i" v- e3 a! F* }' l
         new FCallImpl (this, proto, sel,
/ ?1 \- n  g% z3 Z$ b                        new FArgumentsImpl (this, sel)));
8 u, A# u6 k3 O% |4 ~0 B    } catch (Exception e) {( B: ?1 L* T( U
      e.printStackTrace (System.err);, G( a' s$ k' i8 ?# K' C
    }% M& C9 g( N6 A7 K
   
$ u/ I7 u- V& m6 K0 ]# @6 @4 @    syncUpdateOrder ();6 ?% j* u* @8 o7 Q3 ^9 c

+ n2 ^; W9 N6 m    try {: d* N0 z: E6 b
      modelActions.createActionTo$message 4 p+ r8 O7 p( w, r9 w1 L
        (heat, new Selector (heat.getClass (), "updateLattice", false));8 j. X+ Q/ n% r1 `  \9 I
    } catch (Exception e) {( V2 o/ k2 I4 V# G; z
      System.err.println("Exception updateLattice: " + e.getMessage ());
: d  U( j8 ]0 |0 t, K" O; j    }
* M0 x+ }7 ?! R6 P# M8 \' ^        
% R$ n( m( j5 i( _$ ^; U6 d    // Then we create a schedule that executes the
, n' P0 f, r% V5 j    // modelActions. modelActions is an ActionGroup, by itself it1 w) |! ~9 S. ?: b9 |- S# w
    // has no notion of time. In order to have it executed in
$ t8 j- Z6 O1 {/ k  o    // time, we create a Schedule that says to use the+ _5 Y$ T# z; U( |9 s
    // modelActions ActionGroup at particular times.  This
. Z% ^  O2 K0 c/ _    // schedule has a repeat interval of 1, it will loop every
1 F1 a$ S/ H: r$ Q( o( c    // time step.  The action is executed at time 0 relative to( G, H" Q" e# K8 [: ?% L
    // the beginning of the loop.
. x  r1 D: x0 M/ M" f: F. S
6 M! v' E/ b6 b$ W% a& L0 R    // This is a simple schedule, with only one action that is2 R& m4 ~4 v- G# H. U1 f
    // just repeated every time. See jmousetrap for more, z9 k5 V' C8 P$ Q9 h. N, R1 L# ^
    // complicated schedules./ S! ^2 B+ X6 t1 v+ w$ N: m+ T- H/ }
  + K8 y# L+ i; n& J
    modelSchedule = new ScheduleImpl (getZone (), 1);6 q! _% k" s! g9 \5 }0 i
    modelSchedule.at$createAction (0, modelActions);
) ~5 {1 _1 A3 \4 x3 \& D$ n4 ?        
3 V0 T6 p2 M9 I; c, b2 N    return this;1 P( k+ n; s" W& X* C
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-6-28 07:02 , Processed in 2.358370 second(s), 12 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表