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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
- K5 M8 {9 D; k8 }7 L, }5 G
8 j  P- ~6 Y2 ?, z5 X4 m# b public Object buildActions () {
3 H2 h3 t& X' x& Y4 G    super.buildActions();* G( `. x$ T, o% ?, N- M
   
8 c8 b$ f) F. D% c    // Create the list of simulation actions. We put these in0 [8 q/ e6 X6 I9 w6 `' I% y
    // an action group, because we want these actions to be+ j& `% T+ U8 K8 ?4 Y7 ~
    // executed in a specific order, but these steps should, S6 c1 q7 [9 r- Q( W
    // take no (simulated) time. The M(foo) means "The message2 g) h+ X" t7 [9 x
    // called <foo>". You can send a message To a particular
2 C* O/ O; D& l8 G  z; K! V    // object, or ForEach object in a collection.
; N# K- p4 }! f) Q        
! n! E" z. d4 `6 B9 f) n    // Note we update the heatspace in two phases: first run
* ]# e! D5 U" \: `    // diffusion, then run "updateWorld" to actually enact the& {) c9 I, j7 B& k3 T/ r8 y: w
    // changes the heatbugs have made. The ordering here is7 a5 J6 O1 l# Y( c) X* ^' r. q
    // significant!4 B2 L& q2 c5 m; J+ T
        0 |$ t- |  y1 r& s/ o4 D
    // Note also, that with the additional
" D  N; D, u, l7 e  Z# L  D    // `randomizeHeatbugUpdateOrder' Boolean flag we can
% t* K/ G- W7 S# y1 S6 b    // randomize the order in which the bugs actually run0 j# X: `3 D3 C* V% D
    // their step rule.  This has the effect of removing any) q5 W% g3 v3 u, ]1 I! c
    // systematic bias in the iteration throught the heatbug
& F( M, b- X# H# X6 J    // list from timestep to timestep
# S; o3 }0 P5 ^8 c' w% n% O2 Y        
) J* a# Q; |/ }! U6 Y+ X1 }4 a" G    // By default, all `createActionForEach' modelActions have3 \! \7 G' ~# z1 r9 F* |
    // a default order of `Sequential', which means that the- w3 t9 c" {3 ^$ Y
    // order of iteration through the `heatbugList' will be, z4 X6 e% F. W/ w
    // identical (assuming the list order is not changed
9 P; r+ ~. s. w    // indirectly by some other process).  P* N( E6 [9 g2 |: `+ o! U- Q( G
    8 E0 \% J1 j9 `
    modelActions = new ActionGroupImpl (getZone ());
; t, i. q6 U% {( A8 M0 T2 l% U% l# r$ `
$ g! a2 a. l9 s    try {! b" F$ Q+ `" r' Y
      modelActions.createActionTo$message
* \1 E0 K7 \- ]' S        (heat, new Selector (heat.getClass (), "stepRule", false));
4 t" ], C% D: y( }: B    } catch (Exception e) {
$ ^2 i; @/ _% \3 I9 K      System.err.println ("Exception stepRule: " + e.getMessage ());: ?- a: ]5 }) r# l( t( d% e
    }
; O" C3 ^" V# ?* S& S6 j; l
6 G* F8 M7 @% {7 |, @$ ]# P    try {
  D  D- A: d1 n" {3 c9 }      Heatbug proto = (Heatbug) heatbugList.get (0);
2 s! s# i' w! o9 R! ^* _* C      Selector sel = * l# v) X/ d. q. s* h
        new Selector (proto.getClass (), "heatbugStep", false);
; R. C4 _' E: V2 `      actionForEach =' B$ j- O' B  I$ o  l1 V2 \
        modelActions.createFActionForEachHomogeneous$call
3 X& T, r# K) ?- [) [5 J( e        (heatbugList,+ i1 k6 Q2 m8 {* z* a7 d6 I/ x8 \
         new FCallImpl (this, proto, sel,0 ~% a8 U0 \/ q+ G) u4 u
                        new FArgumentsImpl (this, sel)));
$ E8 f+ r3 D( r* f' ^/ F    } catch (Exception e) {
0 K' f8 _4 f; U( n      e.printStackTrace (System.err);
0 n$ ~+ N: U) n$ B    }
/ ~' x4 [; A* `( }9 D9 `4 o   
* y8 ?  j/ G0 W1 W/ r4 ]# V    syncUpdateOrder ();
2 ?6 Q- A( ~* M3 r: L) Y/ ~; F. U3 ~9 k7 n9 A3 E
    try {- Q+ w& D; k( m9 r: I
      modelActions.createActionTo$message # Q8 j2 Z! Q' ^/ ?/ i! h4 |
        (heat, new Selector (heat.getClass (), "updateLattice", false));5 v: l  O; W# R( X, V$ U  E
    } catch (Exception e) {
& d# X- j& M! `9 u! @      System.err.println("Exception updateLattice: " + e.getMessage ());& L+ D) z! ?, @: i7 d
    }  b3 K! c; a& h3 \' a- i" V
        
9 }& Z$ Y, v( h$ n  s7 w    // Then we create a schedule that executes the; z- e+ h9 C7 n( s+ F3 _
    // modelActions. modelActions is an ActionGroup, by itself it/ f% g  U  F/ e/ W( f
    // has no notion of time. In order to have it executed in
" m" e- A+ H7 \( ~( U    // time, we create a Schedule that says to use the
4 G2 j9 ]% Z7 ~8 T    // modelActions ActionGroup at particular times.  This
1 P, m$ {- |# i* i% X    // schedule has a repeat interval of 1, it will loop every
# E0 r4 }, P$ I    // time step.  The action is executed at time 0 relative to5 R( q0 E  N0 h% p
    // the beginning of the loop.
+ q2 X8 E, h$ n  f9 R9 L) {: J  ?" q- Q
    // This is a simple schedule, with only one action that is
  |# W1 a5 {. S9 M    // just repeated every time. See jmousetrap for more
0 z1 y! T" U0 d$ d/ Z    // complicated schedules.1 b7 n# K3 k' A
  
" ?9 S* |! _9 a- ^4 F6 Y    modelSchedule = new ScheduleImpl (getZone (), 1);
& v( S+ ]: Q! B  \  l2 z6 \    modelSchedule.at$createAction (0, modelActions);3 o7 I( }4 V; f  z( s
        
) ^, C! O7 ?! S. _, q7 B1 t& A    return this;
3 A# b6 p" d( g4 K9 Z, a1 \  v  }
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