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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
! T+ f: N0 e" ?4 d- M! ?/ b- g* }
public Object buildActions () {
. [) H  a8 f; w; `+ L7 V& t    super.buildActions();
' t+ A8 m( b: e2 i& N5 h   
4 n# Q5 p' r8 J$ K- U8 B5 S. {    // Create the list of simulation actions. We put these in: p; N$ g0 Y  o  s% a3 N
    // an action group, because we want these actions to be
* [1 N) ?1 X& R; w    // executed in a specific order, but these steps should, C, V- s/ l0 V# c) r3 K
    // take no (simulated) time. The M(foo) means "The message
3 q4 b" |' `' n- P    // called <foo>". You can send a message To a particular7 v1 e$ j5 F9 K  E
    // object, or ForEach object in a collection.5 K+ s4 \/ S) ]7 [
        
0 e% S+ L& I) P$ m- p    // Note we update the heatspace in two phases: first run
6 G5 L! e/ u) }) i* |% D! j    // diffusion, then run "updateWorld" to actually enact the
8 u) Y7 _6 G: T  a1 L) K    // changes the heatbugs have made. The ordering here is
  v0 Q7 v5 N- n; o4 r: v) f6 r    // significant!0 C5 m9 w1 a4 @# q
        / n; y& u0 r+ N4 s5 W% F4 ~/ @
    // Note also, that with the additional# P8 T0 _4 ]- z+ Q9 p( h
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
3 ]" U! K$ ~/ N1 p3 D# w; z    // randomize the order in which the bugs actually run- \5 Z: g" e; S( E0 Y
    // their step rule.  This has the effect of removing any
: w4 }9 x, ~! r" E! z3 O7 X    // systematic bias in the iteration throught the heatbug
: m; }2 {4 J$ K3 D. ]0 G    // list from timestep to timestep
9 a- h0 i+ j( J5 u1 \. m" V        
: o0 ~! v( ~" B3 J+ B    // By default, all `createActionForEach' modelActions have. i9 w# o! ]) V( v6 X0 i
    // a default order of `Sequential', which means that the' z8 C7 D% \/ C5 Y6 w0 ?! i6 o( {! o
    // order of iteration through the `heatbugList' will be
' V) g) q$ L1 ?/ H    // identical (assuming the list order is not changed5 @! g+ ?. Q" q1 d8 E+ f* Q
    // indirectly by some other process).9 @3 S. \9 O% X" T$ _+ q
    3 p* H2 e  ?3 r
    modelActions = new ActionGroupImpl (getZone ());
- V- j" w3 k, N; f' D/ i( M, S% Q/ g, D6 q" H
    try {
4 H( ]: H8 J) R4 y' ^* Q, r8 L      modelActions.createActionTo$message
6 ?" i2 N  M5 C' o        (heat, new Selector (heat.getClass (), "stepRule", false));9 H3 I- O4 K, D/ {4 I
    } catch (Exception e) {. c5 \. G' N' ?6 Z: j
      System.err.println ("Exception stepRule: " + e.getMessage ());, B; D& W' ]& ~% l: u! D4 g
    }7 K  U$ O- b. I$ |

8 }0 |0 X- }8 X# q# E5 k    try {* k! X. k/ t0 _/ o
      Heatbug proto = (Heatbug) heatbugList.get (0);
( m: H$ k1 {! _, L6 @' v8 O      Selector sel = ) o; |. k6 P, g; W" P7 R! e) c
        new Selector (proto.getClass (), "heatbugStep", false);  j$ l: e3 v# R3 z
      actionForEach =
9 g" E! O6 L4 W0 T6 X1 o5 F' z8 f        modelActions.createFActionForEachHomogeneous$call
4 Q) Y5 q5 z% Q) O& v/ h        (heatbugList,
1 k1 |; h9 h* l) G8 i$ h4 S         new FCallImpl (this, proto, sel,$ M( ^0 D( V% Y2 a% f3 S
                        new FArgumentsImpl (this, sel)));2 L1 ]7 N  o. R$ [  {  g
    } catch (Exception e) {
" Z8 _% j+ J7 E3 I      e.printStackTrace (System.err);
) L, o) d3 Q4 S$ ~- |1 {    }% U; j: D, H& _0 t
   
; I/ S' q! ]! N8 `8 `# g4 w$ H    syncUpdateOrder ();' H* M" R0 |! l* ?/ S

5 y: t6 f% m0 e/ w; ~7 ~    try {
7 b  K) T4 O/ C6 }      modelActions.createActionTo$message
, v3 o. L# u  m7 ^4 j2 u9 C        (heat, new Selector (heat.getClass (), "updateLattice", false));7 P) F, X* ?: ~/ A8 D
    } catch (Exception e) {% p" h, |- E* t2 R
      System.err.println("Exception updateLattice: " + e.getMessage ());$ [) J* V$ u& E; C0 l4 S& L+ r
    }0 c) T. a3 W7 K
        
! o6 ~1 k6 _* D' O1 _. q* D    // Then we create a schedule that executes the
1 s7 K: ]8 R, U5 L; K& R7 v- }) [    // modelActions. modelActions is an ActionGroup, by itself it
9 n6 A  z3 I6 W2 Z0 d0 l& \    // has no notion of time. In order to have it executed in
  e1 {# a0 F( X! s; ], @# s- L! @9 i0 x    // time, we create a Schedule that says to use the  C' b3 p' W! k1 x$ }3 R
    // modelActions ActionGroup at particular times.  This( r  o. k7 O( y9 l% u9 @
    // schedule has a repeat interval of 1, it will loop every# I% j; _; [! E* N  m0 a
    // time step.  The action is executed at time 0 relative to; A0 c$ |$ I& u) Z  j; b/ p7 r' S) G
    // the beginning of the loop.5 {; y& f" Y' Y

" f6 _7 Y" d) W# S    // This is a simple schedule, with only one action that is1 s$ Z6 G2 y% H" Q( U, B
    // just repeated every time. See jmousetrap for more& y2 f( }+ R6 ^$ w. V
    // complicated schedules.
8 T. Y6 U2 X- U* s  
4 Z. K# y6 O" E( B1 a/ m1 [    modelSchedule = new ScheduleImpl (getZone (), 1);
/ \2 K# G) B& |& i0 B& h% @: ~/ a; d    modelSchedule.at$createAction (0, modelActions);
; S) i* L- \% c. F* j. W        , L- `4 r7 Y" e7 ~3 c" u$ T
    return this;, Y" z- x! Q" m0 v! M
  }
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