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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:7 x  k4 t- W9 j1 y

" n* ^0 N0 a2 }& r. i* Q9 | public Object buildActions () {
/ z, J( v7 a6 w) ^    super.buildActions();
& d( h0 f; y! T. R   
+ R8 m+ w- ^. I, D    // Create the list of simulation actions. We put these in4 @6 F6 L1 u; [1 w- {
    // an action group, because we want these actions to be( C2 k$ }$ o5 |3 Y/ J
    // executed in a specific order, but these steps should6 d/ V' g5 H  s3 l# @
    // take no (simulated) time. The M(foo) means "The message& ?" n& }* y9 K( K7 O, m
    // called <foo>". You can send a message To a particular
2 N2 B3 H; `% G  w1 F    // object, or ForEach object in a collection.
" w- l) E( V: m/ o/ T# O; e        
3 }& @, I1 Z! h* k) _. }- D0 Y    // Note we update the heatspace in two phases: first run% L  z" S& Y* s) @8 j: v: p5 m  }( v
    // diffusion, then run "updateWorld" to actually enact the
) g% F! t/ y/ H2 t, C    // changes the heatbugs have made. The ordering here is9 k5 n1 u$ g+ R
    // significant!
) `: A& S9 J2 k+ b% R0 ^' N        
4 l) B: |  X' J    // Note also, that with the additional; G8 l( @2 \/ ]6 e6 \
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
0 K# [6 y6 d1 k' ~$ ]9 v& g    // randomize the order in which the bugs actually run! o! R' @1 b5 l" y: e/ B
    // their step rule.  This has the effect of removing any
1 T1 k( C) |: v    // systematic bias in the iteration throught the heatbug6 b6 h% W  Y* U4 Z; u! X9 A
    // list from timestep to timestep$ y, Z" s) T& u! T/ n$ f
        ' |8 n7 x% F) ^# R# e
    // By default, all `createActionForEach' modelActions have
$ S( v5 E8 X. s) g6 D$ f    // a default order of `Sequential', which means that the! m% ^: q* s# p
    // order of iteration through the `heatbugList' will be
. I3 F' d/ b( }) Z6 y    // identical (assuming the list order is not changed+ a, n4 |6 r$ z
    // indirectly by some other process).
9 l9 y: g; v" K   
2 j& t3 ^9 o! a+ r+ Q0 j& O    modelActions = new ActionGroupImpl (getZone ());
  t/ q2 l% F" V: `' _! e  g& E  v6 q% I8 _
    try {
4 l. s/ p( W! z; N& `) a+ H% S      modelActions.createActionTo$message
, h4 ~) X- l& c        (heat, new Selector (heat.getClass (), "stepRule", false));+ k, y1 v- ^) {' y- w7 _* H
    } catch (Exception e) {
# E- M. |+ a( k7 |      System.err.println ("Exception stepRule: " + e.getMessage ());; a4 h, w* D# H" H
    }
+ ]: h3 x% p  V( v0 J1 H
: c- m/ C4 j3 s8 `$ C    try {+ n+ w% t9 d, z+ ]2 z
      Heatbug proto = (Heatbug) heatbugList.get (0);
# s: ~9 [5 q. m9 n      Selector sel =
! }/ p" c) R" l/ p$ W        new Selector (proto.getClass (), "heatbugStep", false);7 F% |8 A- Z/ @0 |
      actionForEach =1 y. v' q  H& D3 n
        modelActions.createFActionForEachHomogeneous$call
0 J% I" r# e$ F. |        (heatbugList,
, H- A, Y! L) z& k# w6 P# Y         new FCallImpl (this, proto, sel,. Z  X5 e+ `  y  l
                        new FArgumentsImpl (this, sel)));
  ]: [9 U. E1 Y! u4 |6 A$ b! T    } catch (Exception e) {% J0 K- N) W) X( ?% m- G8 ]- a# f- O
      e.printStackTrace (System.err);) u& I+ g) A0 m
    }8 Q. J  \8 a; f; t
   
/ @4 ~& k7 x% o) _, u- d: [    syncUpdateOrder ();
" g) Q, i- x3 ?. P/ m
; P; D$ B0 S" R    try {' a3 V1 f6 G! y. e# l4 p* {" ]
      modelActions.createActionTo$message
. x3 e/ d' G  K        (heat, new Selector (heat.getClass (), "updateLattice", false));
* ~* u/ a9 T+ `, t0 E7 A, D    } catch (Exception e) {* z$ F8 E- [" |& i  }
      System.err.println("Exception updateLattice: " + e.getMessage ());
1 ~  K  \- p/ ]    }
* K. X/ P  |* X' W5 O2 m0 c        ' ?6 y+ e. \3 a2 Y
    // Then we create a schedule that executes the- \: @8 h4 Q9 C3 s
    // modelActions. modelActions is an ActionGroup, by itself it2 R4 s' ^: L, {
    // has no notion of time. In order to have it executed in
3 E8 L1 X: ^* t! P2 {* B8 d    // time, we create a Schedule that says to use the
/ n0 U+ [4 t/ v# X  o    // modelActions ActionGroup at particular times.  This
# E. i5 p* @2 y# J* _$ O( c3 P$ E    // schedule has a repeat interval of 1, it will loop every
$ l' |9 ~6 [$ i+ D7 n+ X: r9 v    // time step.  The action is executed at time 0 relative to2 d/ e( \  l9 L5 d" ~  r. h6 T
    // the beginning of the loop.4 d8 L6 a5 N& X) [& F* n7 N9 Z

/ a  U2 _. v/ @! x+ j( f    // This is a simple schedule, with only one action that is9 F# v6 A* Z( \2 W. l
    // just repeated every time. See jmousetrap for more
8 D7 p7 q5 ]' o7 F1 P- {: N; M    // complicated schedules.! @- N- j+ Y! }+ p" F/ h- Q& H2 i* w* x
  5 G" j/ y2 Z$ p* e$ s1 e6 C/ r
    modelSchedule = new ScheduleImpl (getZone (), 1);
% g4 c/ J# M# o1 o. N2 P+ t5 K    modelSchedule.at$createAction (0, modelActions);
0 X+ D% V, [' N( n        , J( Z. z; s* w. k9 t
    return this;: j) ^) P) B4 c; G4 ~
  }
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