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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:" a, l- c' D9 u( ?' r. L3 e/ S
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public Object buildActions () {0 s7 y. ]2 i7 y6 e8 O
    super.buildActions();3 \3 l1 t: J, ~8 F( F4 b  u; g) _
    5 S4 `' `8 u( Y0 u' L! t- f
    // Create the list of simulation actions. We put these in) O0 b3 n& z& \" k- a9 `5 p
    // an action group, because we want these actions to be
. K- k& T' E  J    // executed in a specific order, but these steps should
7 J, c- h* K" s: Y* U5 K* ?3 b    // take no (simulated) time. The M(foo) means "The message- s+ d" S$ I) A. n4 w  z
    // called <foo>". You can send a message To a particular0 C" m' K  \7 k" e' O3 ^
    // object, or ForEach object in a collection.0 J+ y# k/ s% m* j$ Z; a: V" x. d3 ?
        9 o3 O* F8 K5 j0 B. b
    // Note we update the heatspace in two phases: first run
7 j9 B/ R9 r5 k: r2 H3 R6 h2 |  C    // diffusion, then run "updateWorld" to actually enact the9 L) z" ?$ ?( Y2 D
    // changes the heatbugs have made. The ordering here is
, @  l, c" G, ?* }6 D, S9 `    // significant!" y6 P6 w3 x5 B% X
        ( _6 k! K& a$ T, ~8 P
    // Note also, that with the additional
9 K: g* Z3 j5 q1 J3 H0 Y' Q! b    // `randomizeHeatbugUpdateOrder' Boolean flag we can" X# j( c( R; _8 ~- W2 V9 E
    // randomize the order in which the bugs actually run
; w. ^, ~  x/ C$ e; `    // their step rule.  This has the effect of removing any
: ?( E. D* I* S, l    // systematic bias in the iteration throught the heatbug
' a8 c# B, E) \3 X    // list from timestep to timestep2 y, u! T+ L1 C( B0 Z) U
        
' }- b0 L! [5 s) Y9 I    // By default, all `createActionForEach' modelActions have
2 N- t4 s, I7 _3 s4 p# q5 F- w+ {    // a default order of `Sequential', which means that the: G" C7 J6 a2 Y- m: O) \
    // order of iteration through the `heatbugList' will be& o5 x  G/ _4 Z- Q/ U# G0 S0 Y
    // identical (assuming the list order is not changed
, u! D) U6 h" e& v$ W    // indirectly by some other process).
& B2 u4 f$ ]6 X/ @   
. |. U: h! k7 p* i7 [    modelActions = new ActionGroupImpl (getZone ());) O- I; ?- F# w& v  L  y6 w

/ E% J# t3 V; T, a; O, X    try {
! ~  l' X7 c0 ~% L; Q! {, ?      modelActions.createActionTo$message3 t* @1 Z/ T5 N$ _; u/ d
        (heat, new Selector (heat.getClass (), "stepRule", false));
/ X! j/ W; T' V, J' k# y    } catch (Exception e) {
. i1 e! b( ]" v0 P% J2 C& m      System.err.println ("Exception stepRule: " + e.getMessage ());
  m: N0 ^& W5 G    }9 Z4 P* H$ z6 H1 z2 b3 {! G4 ^
( y7 _" `9 d! }! a
    try {
4 G1 @6 D3 {6 w+ L9 b      Heatbug proto = (Heatbug) heatbugList.get (0);: @7 X3 S+ @0 E" R
      Selector sel =
% F- D% s2 r: U+ C( d+ u% Y; a        new Selector (proto.getClass (), "heatbugStep", false);4 q6 h3 f# ?+ S/ ]6 t3 [3 W. L
      actionForEach =. t$ }$ Q, n& N! X2 C1 x2 n, \
        modelActions.createFActionForEachHomogeneous$call
3 i, \/ ^  h& V        (heatbugList," P+ V% h+ g6 m, P4 `
         new FCallImpl (this, proto, sel,
+ v/ V3 U# i% q. a( M. t                        new FArgumentsImpl (this, sel)));, t6 r6 L) Y" p1 C$ q+ K1 y
    } catch (Exception e) {  V# Z% X+ p& N, d* f
      e.printStackTrace (System.err);
5 e/ s) r" ~( K( ~* b% H- r    }
* _' a# K9 q5 F# S0 E% w    * Q& V2 Y2 ]) h5 |% ^( p4 {; I2 F
    syncUpdateOrder ();
0 M3 e$ f6 F, F9 V2 |1 X, M9 F
# M1 i, [8 w+ X! N9 V    try {# F, i. G5 U7 Z' K3 k
      modelActions.createActionTo$message
' m1 f( K6 `3 E, Y        (heat, new Selector (heat.getClass (), "updateLattice", false));
" R! Y  B2 X4 q! c  T) L( Q    } catch (Exception e) {
' S2 M( O2 d5 |- n2 H  n      System.err.println("Exception updateLattice: " + e.getMessage ());) O" o2 d2 `  C, D1 N* }
    }# \2 |/ x3 l/ U7 n1 H) N
        4 K' v  S1 \* F3 N) i
    // Then we create a schedule that executes the
) z  s- }7 a( y6 `0 y    // modelActions. modelActions is an ActionGroup, by itself it
4 F8 V/ f7 d$ v6 @0 [9 A8 O# U    // has no notion of time. In order to have it executed in- V7 [2 v9 p, {4 M  M$ S; k+ F
    // time, we create a Schedule that says to use the* l2 Z: y- w/ m
    // modelActions ActionGroup at particular times.  This
, D1 W/ ?" _" o: g! p) a( V; B9 K5 H    // schedule has a repeat interval of 1, it will loop every
6 i! ?8 x  S: @$ V" m    // time step.  The action is executed at time 0 relative to
1 f7 L+ m! Q# w    // the beginning of the loop.* q0 n9 |  ~2 [

7 ?/ K: X8 R" q* D    // This is a simple schedule, with only one action that is% ?, o9 ?- `4 Z5 `
    // just repeated every time. See jmousetrap for more& P! ~  a$ @' {0 W
    // complicated schedules.
$ n8 N0 V% c# b3 E2 a. Y2 c" x; k  . Z( Q4 Y4 D9 H  W4 l
    modelSchedule = new ScheduleImpl (getZone (), 1);1 V5 V8 t+ q  ?" t4 \, e! b! e
    modelSchedule.at$createAction (0, modelActions);, t0 s6 ^8 e3 y4 R
        
/ P' ~7 J7 F& V0 ]& w- n) W9 y( `$ o    return this;4 {, n7 z4 O" e7 P
  }
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