1 ? K9 e2 r. D/**************************传递数据给extend**************************************/ , C' x3 I g0 z* B+ c pokeVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *3);6 q' |4 i8 S; f5 k0 E+ x1 l- L6 k+ Z
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valueStr = SysAllocString((WCHAR *) L"1232");9 j0 _! e$ b H6 U3 D/ }- l9 A; S
VariantInit(&pokeVariant[0]); ! Q, C6 F) ?7 d/ w- y
pokeVariant[0].vt = VT_BSTR;, `0 V$ @( }. M. @% `1 r8 ~3 J1 a6 `
pokeVariant[0].bstrVal = valueStr;2 J. U, ?# m& q
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itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0");2 m2 k+ n: U% B0 t7 H' h- u1 Z
VariantInit(&pokeVariant[1]); " a' a$ ~; _& W* g, r pokeVariant[1].vt = VT_BSTR;6 F1 R" D( Z3 e+ \7 V- j$ v
pokeVariant[1].bstrVal = itemStr; 2 u& [4 I' {( W& z+ U8 o: j: N t; ^2 s; [9 _# p& Z" C' q+ R% c
topicStr = SysAllocString((WCHAR *) L"system");- l+ l* E4 V: {3 D3 P
VariantInit(&pokeVariant[2]); 4 M& |' b5 Q$ F$ u% }" `( J pokeVariant[2].vt = VT_BSTR;0 x1 ^8 c* k. O* Z. d; r- N; P
pokeVariant[2].bstrVal = topicStr;8 h, D# A" X1 K
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// Set the DISPPARAMS structure that holds the variant.6 J! C& h- S: g2 `, ?: \
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dp.rgvarg = pokeVariant; 2 C4 }' V. g1 V& s+ P. m( P, Y' G& W dp.cArgs = 3; ( R8 G1 u3 M! u- h5 k dp.rgdispidNamedArgs = NULL; 0 |1 p8 @% v1 i. M6 D- ~ dp.cNamedArgs = 0; 3 R2 T z5 _- y2 K : c' u( x5 j7 C' y0 v8 d// Call IDispatch::Invoke() " C: G, O7 x0 Z9 ] 1 G3 A% `# `" Z' F/ n$ | hr = m_pDisp->Invoke(# s* K3 T! y; O4 x& Y. {2 Y
pokeID, : x) B X2 r+ b# l0 D4 G; M. ~ IID_NULL,- X% S" I H( c8 K. A8 I
LOCALE_SYSTEM_DEFAULT, 2 g9 Q8 w# ] d: O7 \2 a* n9 S DISPATCH_METHOD,: H/ x \+ T: T- y; |
&dp, ' G6 e( T3 Z- R NULL, " _7 k$ s/ b: s. @& Z &ei, - B2 E- _7 p' | O. Y &uiErr); # F9 g5 ~& ]3 z6 ^1 @ , G+ z9 p2 e, \' \: h& y SysFreeString(topicStr);5 }2 |2 L: H5 ~2 a2 F
SysFreeString(itemStr);2 g+ t2 ]6 _ v2 n- M' ?* _. `
SysFreeString(valueStr); ' A$ Y5 {4 V; o8 X$ D+ r f9 X! Q3 M. z0 d5 X- _$ n
现在这个程序可以实现将1232这个数据发送到extend,extend有一个对话框弹出并出现1232这个数据,不知道这个对话框为什么会弹出并显示这个数据???% `4 Z$ Y+ w L1 m: L$ R9 `/ x
此外我希望将这个数据赋给extend程序里面的一个变量,请问如何实现????4 k% Q5 |( M7 E/ j" @: ]. I, r
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2.这是request的程序- } z/ S" C" v" a% y/ `
// Request a value from Extend! _( I9 b) u5 n1 A8 U2 H
// % _7 A$ T4 Y$ s// Initialize the variant that will hold the BSTR. Set the variant's {$ Q% V: h$ t* }8 Q+ b// type flag to indicate the fact that this variant holds a BSTR. Place the 4 C, g: @% y7 ?: Y( V* m// BSTR into the variant structure. ! @9 s+ `9 i5 i0 s. ~( v! j$ u `+ K; y
requestVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *2);& b3 [: S. k9 S8 X
$ p& t1 w8 `1 D7 @ itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0"); . D3 `& L1 X- e VariantInit(&requestVariant[0]); ! D. p m# S/ A5 t( X' K
requestVariant[0].vt = VT_BSTR;7 l( v, |) k H5 u
requestVariant[0].bstrVal = itemStr; 1 [- ]# E" P' ~! K; Y: y% Z: ?; w# s, d/ C' S. O
topicStr = SysAllocString((WCHAR *) L"system"); r# X9 e; ]2 i/ }* T+ ~5 B/ R VariantInit(&requestVariant[1]); # Z1 a$ c. V. V% K; C: X2 w5 v
requestVariant[1].vt = VT_BSTR;7 ^2 q0 [, ?3 _) r+ k0 c
requestVariant[1].bstrVal = topicStr;0 Q) I, X& C8 T6 O7 r" b+ Z
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// Set the DISPPARAMS structure that holds the variant. & ~# O" ~* g, o, |! K8 f8 k( I 2 d3 r `4 I9 ], ^ dp2.rgvarg = requestVariant;3 Q$ @: q8 ]4 m1 M: ?
dp2.cArgs = 2; " N1 F/ i" C# m/ ]: d# u8 R dp2.rgdispidNamedArgs = NULL; $ a. z( N# s0 M& R7 w dp2.cNamedArgs = 0; 4 ?4 n8 j, w$ k / _* n3 e: X3 o; w& M N var.vt = VT_EMPTY;+ h% E! L9 c/ B. j$ `3 Z7 [
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// Call IDispatch::Invoke() ) v7 l1 @7 ?1 O( s7 n5 p* h; e, i# w/ a
hr = m_pDisp->Invoke(( s3 P( J1 L- c/ ]" H$ W
requestID,; y5 G* k/ n: S: u' w6 p4 @: _/ |
IID_NULL, ' L+ T" X. N/ { LOCALE_SYSTEM_DEFAULT,# W7 O! j D: h3 d: B
DISPATCH_METHOD, 9 H9 o F1 H+ H4 X' v6 R$ J &dp2, , F! q1 G3 m( h+ Y& K &var,6 z- R4 D5 W* n- n. U
&ei,& P y2 ]& e% v c* R4 N
&uiErr);2 G+ m. X# `: g/ `8 c7 d
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SysFreeString(topicStr); 1 V+ s8 ~3 v& i8 O SysFreeString(itemStr); # i2 Y6 ~/ ^+ \- K0 v2 W请问该程序是获得extend里面的哪个值? $ {2 r5 _9 Q2 c" O; ^/ y如果我希望获得extend程序里面的某个变量的数值,那个c++程序应该如何实现????