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发表于 2010-5-11 13:19:52
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用list吧) ~5 G b, u7 R2 ~; Y' z
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []
% _3 o. i# `9 c0 v: P5 b6 _% @ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
) I }/ R$ I b) F* Q, z( h let mylist2 []+ t$ V3 [8 j; a5 a' j P# e% l
set mylist2 n-values count patches [? + 1]+ i1 j& f+ B c/ v* @
* s2 k* E$ \8 g9 } ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]- \2 Z8 D0 ]# D `) {* e$ e
show [rank] of ?1
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let mylist3 []8 v; h$ o2 ]9 ~$ V+ q, J& S
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
) s1 ~/ ?1 {7 n! \0 F show count patches; K( H, m( T' Y) x# r
show mylist1 3 B) W3 l9 I' G+ i' ^! Y7 Q4 s
show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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