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发表于 2010-5-11 13:19:52
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用list吧9 q6 C1 m% n+ L; v) n
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []
- }. m( M7 P: l- p& t5 Y# B set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches! |* L6 i% e, ~& n! r5 ?3 X
let mylist2 []# s$ p. A! M; b1 [4 e
set mylist2 n-values count patches [? + 1]
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: l8 @; {$ m0 l ( foreach mylist1 mylist2- s6 [/ p2 B! N9 i: v( B
[
/ X- v0 F. s, u2 @ ask ?1[ set rank ?2]
4 T' _5 L) [) d. a# b# W' B1 i; T show [rank] of ?1
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+ [( K1 }& `( |! ?3 Y/ } ]
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let mylist3 []8 y+ J+ N/ e( L, o
n$ F7 F2 d' o' t# E8 h: d set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
; F4 n! W0 e+ ?% q; ~3 x0 ~ show count patches2 _7 t5 s$ |3 e" I- y
show mylist1 3 h. k$ B; z ^
show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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