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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：: e6 ~2 H8 P9 q; l, W' V
begin P_in arriving/ ?% u' _' h2 \# G+ c' S% f1 j' W5 n. k
move into Q_in
) f$ g0 V! G' A" o& L% D. L2 V use oper for 2 min
7 R& o- {1 q9 b$ D3 r send to oneof(0.95:P_in1,0.05:die)
7 [- W j9 R8 s/ lend5 u( k8 h; z% e) M, p8 |" B7 ?2 b
begin P_in1 arriving: F7 t7 F! c! i, N: n A
if load type = load1 then
3 V& g: g# ]6 `0 O begin
2 ?$ m5 X. h1 f ^! k move into Q_m1
, [2 \5 [0 H: u0 u5 W use M1 for u 5,1 min& [8 T+ w1 y1 `5 s- T- N6 B! l4 a+ q8 Q
move into Q_out1
0 j; i' W7 [2 A- f wait to be ordered on orderlist OL_1
; s) |0 D" @! j8 P end& g: Y/ V/ i' b" p
if load type = load2 then: M* F1 }" d8 s
begin6 j3 s5 Z- {- z' k+ }
move into Q_m2
. v" x( i/ ~ T, Z& ^/ r) L use M2 for n 8,1 min: w; |/ g* V; Q \+ Y
move into Q_out21 z! U2 h& h( X2 g7 N
wait to be ordered on orderlist OL_2
0 y6 |& C- U' E: e! M' B/ V end
6 F X9 g0 q/ h nend
; ~$ Q3 u& J/ p' M! S; j r0 kbegin P_dunmy arriving
* X) u! A6 s& T2 | i8 r set i = 18 k5 E" ?+ }9 U7 j
while i > 0 do* k: i% y' [! z6 ^. Q* ?; N5 u
begin
7 F( U4 ^' w1 s4 d5 a" X8 P5 | order 1 loads from OL_1 to die; |* V2 F( m/ @4 v
in case order not filled backorder on OL_18 X/ ]% s1 l$ l. p/ F$ C+ p, V0 G( L
order 1 loads from OL_2 to continue+ c% L' q$ g. s5 S$ j8 q
in case order not filled backorder on OL_2) I8 |( x( Y5 ?# k4 V( X# f
move into Q_1
9 ]. q4 A9 ^$ ]$ h2 _ use Massm for n 5,1 min! o) D' z1 H. x% @1 Q, i
send to die2 L% Y* S7 E) D9 G
end
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$ |( H: h8 x1 \这是我的报告5 b9 P* J1 E% k; _2 {0 m& ?
*** AutoMod 11.1 ***" ~# K4 ^6 k4 o' o# P1 b4 c* C, V
Model q
/ T2 G; L( G. f: D/ oStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
* R, b! f. [8 q. U5 E C, PCPU time: Absolute: 42.859 sec, Relative: 42.859 sec( e! V+ z- D, Y, | U
Statistics for Process System "q"
+ ]9 I3 C, [: F" RProcess Statistics
8 o* g5 b/ U. C" SName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
' U: x8 k6 A8 i: e========================================================================================
0 O: O! y" n, g; ?9 e6 C- F7 RP_in 222 1 0.32 -- 2 0 -- 126.04 --
; m* g8 L/ j0 v+ H9 m7 gP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
" e( U/ x% ?0 E6 P3 MP_in3 0 0 0.00 -- 0 0 -- 0.00 --3 W& {, x" a* k- [! g' I# K& o
P_in4 0 0 0.00 -- 0 0 -- 0.00 --( Q# A; D1 p1 Y6 x' ~5 u
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
/ J/ a/ j0 n! J1 kProcess Traffic Limit Statistics; h+ o* N. R5 I: i. B) Y
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
$ P9 a6 f: ^8 x9 C========================================================================================( o+ a! @4 x* B$ Q/ w6 f
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
2 {% P9 u/ O6 O( R+ hP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --0 l- b) Y+ _5 Y0 {0 O) _- T$ j
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
& P) S9 ~ l; U+ O0 w$ f) TP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --* |! i) L' |3 }! x+ v b- X3 @3 {
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --0 L- Y' {3 J, E5 t2 k
Queue Statistics; N) L/ g. s! o$ F4 @% W4 ]
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait# f* \- ^+ r, Y; b! X
========================================================================================
8 ]% x/ v1 k. Q2 @Space 223 0 0.00 Infinite 1 0 -- 0.00 --
' e& o1 M1 ]" s' {Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
5 U- M4 W& Q% NQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --5 k* m1 U- j: C+ r7 V
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
0 B2 l9 X$ D* Q4 e) Z) gQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --6 {( Q5 T( Q" t+ D$ R& ^
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --) u/ c) d+ S( [' n4 I
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
# z3 k7 q- F7 aOrder List Statistics
/ i' i; |! S& O6 s7 h4 sName Total Cur Average Max Min Av_Time Tot_Back_Ordered
- D0 I7 J* _9 z; u================================================================================
T a9 F& c: T2 V! u+ eOL_1 139 139 67.23 139 0 41789.43 17 N* T6 l: M* @) o
OL_2 71 71 34.26 71 0 41693.20 1. k8 y/ W# X! p' e. z
Resource Statistics
4 |/ |- j3 r" [- g; G2 ?7 A9 U0 |Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
, G. W2 y% m; u0 r r7 @====================================================================================================2 E$ v4 t C+ @7 y
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- * [5 l% [) c& w+ N, G+ u* w
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
o9 ^4 r/ a( G. ZMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- " f- c, q$ U0 C( A7 @
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
- |/ K8 H, L8 m5 u; r) _7 z# q5 dRandom Number Streams6 z; v! N% [4 f' k% f' R
Name Total
# `* E a3 ?! o5 b; p============================9 ?, S4 M6 V9 U2 {6 b! k* |
stream0 455
0 y$ S9 M+ O1 W# [. H3 ystream_M1_1 0
4 R. v/ m: `! H7 Y8 Ustream_M2_1 0, e5 N9 e- S2 Y3 a9 y
stream_Massm_1 0
# \! `: {: Z e) tstream_oper_1 0' e1 K+ f) v0 W
stream_load1_1 184 Y/ B! o0 O% {0 Z$ J# g+ W) O
stream_load2_1 76' {. x2 Z( C4 V9 K m- F4 q
stream_dummy_1 0; v/ ]8 Q! `2 C
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
