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本帖最后由 soso001 于 2014-12-17 14:53 编辑 ' ^' [! K3 `+ t
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不好意思,打错了个字母,呵呵呵!
, f5 E$ R. t5 l) D3 t0 B$ T/ T大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示8 ~; l3 B% H; ^
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!: L1 e# T' z) v- K* P
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j,k,nstep,c, scheduleteps,mincomptime:integer;
% T: K+ j5 t% m: Z M:string;. l$ j' W+ h5 S3 G
selecTab:table[integer,integer,integer,string];
# o- @8 d6 U0 Sdo
- t$ U, d- N a$ ?7 m* O initorders;9 |0 _/ P+ s; L
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scheduledorders.delete;( t0 c3 t' B, w) d8 b
seletTab.create;3 }# V6 d/ k! q, d
5 }0 ~! a$ O5 f, S( E orders.initialize({2,1}..{2,*},0);
0 ~1 F& A% a) w0 l: g orders.initialize({4,1}..{4,*},0);
8 M0 i" G: O2 q& i) a for j:=1 to numorders loop/ E7 `. _' i( Y4 l
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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--XUNHUAN, w W# v- O) x5 ?! U2 g
for scheduledsteps:=1 to numsteps loop --5 [& Z3 }' j$ D" F8 T
selectab.delete;
2 A s: p" V% i- t- e/ o k:=1;
: }8 D3 q$ x) g4 H* y. x* D for j:=1 to numorders loop
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* C; ?1 R( l5 k- o {3 [9 u, t nstep:=orders[2,j]+1;
9 z& W7 e7 A2 F" H7 w! Y9 \ if nstep<=orders[3,j] then9 \8 _/ l+ H- q, u: A \ ?4 H
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];6 P; z" F w8 U! P( H
k:=k+1;6 Q2 P) Q8 F, r" T/ W* k
* n7 Y' S3 l9 T! ] end;9 d% _& h( m* E* X1 N1 b
next;: S8 P: i0 a; o$ d' |; T9 x* X
mincomptime:=selecttab.min({3,1}..{3,*});9 r# _% {9 ~) h2 ?: b
& X# r: L8 j _ from j:=1 until j>selectab.ydim loop9 r3 `$ }" |! F' m& K e4 {+ J3 y
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if selectab[2,j]<mincomptime then. h" y+ d2 a0 L* W: I
j:=j+1;: V4 y* ^% v9 M) ]
else! u4 O$ i5 Q$ k _3 y
selecttab.cutrow(j);
5 ?. | \6 \" J) g) `$ D end;
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j:=selectionrule(selecttab);( u$ z+ D+ _5 ~( J
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nstep;+orders[2.j]+1;# K- T$ t4 l+ x p9 _ h+ N- i5 _2 Q
orders[2,j]:=nstep;" x7 Y" G* `1 A( \% l
m:=orders[1,j][1,nstep];) z4 U5 D8 |5 u- S0 o& p) J9 e1 \; i
c:=orders[5,j]8 ^8 {! a3 L# I' @2 J8 j
occres[1,m]:=c;/ y! h& k) \# b* Z" s9 @
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--jieguo:start,end,res,job,step
0 l9 |! L* P- }2 o scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);- B8 w/ d1 ]2 W+ i, R0 r
for k:=1 to numorders loop
- b' q9 B$ M% i1 N- P4 _ nstep:=orders[2,k]+1;' ~0 t" ~" B1 l$ G
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m. ^7 p8 e2 Q/ @; @( ]4 B; f, I, F
--: ~$ r8 f! @" E8 x7 T6 `
then0 Q3 T2 W' j6 P! ^( T& i
orders[4,k]:=max(c,orders[4,k]);( Z" u/ Z1 D* }: G b! v9 P$ w9 u
--8 M9 C2 x1 E* r. y
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
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nstep:=orders[2,j]+1:; O/ K x3 Y' e% |
if nstep<=orders[3,j]; C6 s9 k5 B$ U
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then
9 |( _0 U( |0 x: ^/ ]( T6 c9 S4 q5 Z orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
; M' ?% Q6 Y- b6 i/ h orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];' f$ ~7 U' ^/ G& v, z A# {1 }* {( k
end;% O0 Z# E) i! W, i+ K
next;& W3 N7 _# I6 X
! \+ u& s7 ]! @ print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
1 B, C, V6 ^5 M6 k8 Q mygantt;( I; F3 }2 p# ?+ q8 R/ F# i
ens;
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