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本帖最后由 soso001 于 2014-12-17 14:53 编辑 9 g: q: s5 C0 g8 ], M9 K
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不好意思,打错了个字母,呵呵呵!
% M% f" b* n+ E. O) D( n大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示1 E7 W3 u9 h: N" l, r; {
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助! s6 x: x }2 d! ]* W, a
is
/ Q" k3 Z+ T( V1 f4 x j,k,nstep,c, scheduleteps,mincomptime:integer;
& [) \6 n# O- L( o0 O# r+ f) D M:string;
. W% a* ^$ |& t6 C- M; B selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
! s( S8 f+ B1 o2 N seletTab.create;
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, A' r2 A3 s+ y- b5 O' l4 i% C orders.initialize({2,1}..{2,*},0);4 C% e9 o4 c& d5 X' G
orders.initialize({4,1}..{4,*},0);: x* E& W1 p; M% d' U7 Q' ?
for j:=1 to numorders loop
' r$ U# l, j* c- S" U j e orders[5,j]:=orders[1,j][2,1];6 C5 a3 w; n. k
next;
0 Q5 }8 z& ^9 j9 P occres.initialize({1,1}..{1,*},0);* ~7 {" V. c- D% @, K
$ A. u+ b9 d% K" j2 _ --XUNHUAN
7 J4 y) G4 i7 a5 D& q# }: C) U4 B for scheduledsteps:=1 to numsteps loop --
4 l. ?+ l) [4 S selectab.delete;
* a4 a- J4 w! t1 \ k:=1;
1 O. d% Q2 \5 i! l9 G for j:=1 to numorders loop8 Q& p% E& {+ t& o% M: {% L
1 C; t1 a: R& s& Q0 a nstep:=orders[2,j]+1;
5 J1 u' _7 r7 C, @ if nstep<=orders[3,j] then- N6 U2 \ P1 w0 P' V8 |7 A- @, v
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
4 L3 I7 K& a {& S) O) A k:=k+1;
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2 H6 y) @8 @: y! N1 o end;# p6 d7 z) ^( \9 B, E! ?
next;
7 i0 C1 B0 e2 ~! q/ C* T( P mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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8 }. a1 N! v$ |) E/ Z" R. t# V if selectab[2,j]<mincomptime then
; B. P8 {& k6 t0 x( c+ {2 B j:=j+1;7 u Q. M- P8 ]- ^( Z9 f
else4 C$ t1 B. o% Q1 Y9 w* C# G+ o
selecttab.cutrow(j);% K5 q' d; S: B! {. K" b/ _
end;' Z/ F8 [; r8 H& E* i/ x. R) b
end;1 A8 }6 d0 c5 _; r$ R' P* l
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j:=selectionrule(selecttab);5 R( O* B# v. I* D9 L- l$ g; ]; j
$ S/ f8 J5 I6 p1 _ nstep;+orders[2.j]+1;
/ W7 `3 F$ X0 R orders[2,j]:=nstep;- { D' Z+ u3 d: p4 e6 c8 X* u
m:=orders[1,j][1,nstep];7 |9 m) y8 t' h N; o& i5 q
c:=orders[5,j]
. B' c7 j( z# a1 K( S. j/ g occres[1,m]:=c;
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) d& n% K/ y5 |7 s --jieguo:start,end,res,job,step
- o& G4 g$ {! u5 A4 j scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep); F* d1 u3 D0 O' C
for k:=1 to numorders loop
# S; ^* w+ |. k0 O6 F7 D5 l nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m* L+ N6 a" }: ~2 `& J2 E
--
* s2 }0 h$ y! ], j/ J then
" N' l7 q/ a. u( H, Q orders[4,k]:=max(c,orders[4,k]);. E" P: ]* S; |. l
--
0 Z7 G5 u3 Q [* t orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
1 e9 C; H: s: }3 J k --. E( \: w$ s( }8 h7 X
end;+ Z8 |% q2 Z+ O( m
next;
7 s2 x+ }# a" q ] Q9 Z. ^ nstep:=orders[2,j]+1:) g! i- n7 a: f) A/ H0 m+ V% g0 O
if nstep<=orders[3,j]
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then% [. ~/ ?9 S g! Y7 ~+ C
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);0 y) s' J( K2 Y! r: Q
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
5 v) t8 o9 l1 M9 A end;
1 U3 a: u+ b5 J3 Y/ _1 t/ w next;. `. p0 X' \* D
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
! E* w- k; c- m! s4 d2 S mygantt;
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