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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!, k5 F3 @5 w% S1 a4 `
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示5 F5 Q7 _# V9 E* [
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!' e' [3 r- e( c
is
. ]5 ^9 l+ Q7 M4 F j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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, T, D: |6 u- z( U6 { initorders;
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+ \' [8 S# `! @ scheduledorders.delete;
; @" B2 E5 \: ]. X& e( f* | seletTab.create;
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orders.initialize({2,1}..{2,*},0);
2 ~1 y9 c% _9 g- P# l6 Q2 ~ orders.initialize({4,1}..{4,*},0);) V& U; I; H. L' S! d: d
for j:=1 to numorders loop
g7 q3 Y( `4 D% U, L8 F# l! t orders[5,j]:=orders[1,j][2,1];
- ^* Z$ L% _" P6 j0 T next;
9 T+ L: i# s( Z" q8 X8 V( e occres.initialize({1,1}..{1,*},0);
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; s9 G* b$ N6 b8 [+ l( T, | --XUNHUAN
9 k7 x% x& {& C" v1 t9 {: M* C for scheduledsteps:=1 to numsteps loop --2 k6 v3 o4 l9 ?
selectab.delete;
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for j:=1 to numorders loop
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nstep:=orders[2,j]+1;! a: U% D: ^. c& f& Q0 x7 G+ x
if nstep<=orders[3,j] then& ~ y' ?" F2 C* |) N" a" |
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];' R' ?. @+ `( o. e
k:=k+1;
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end;3 I9 X k/ g1 T4 E! Y+ {
next;
, i& n4 @9 g5 m" N3 K" T mincomptime:=selecttab.min({3,1}..{3,*});7 T5 Z( ~! x# g, w L
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from j:=1 until j>selectab.ydim loop! M% p8 w" K- E# L- ] h' t- s
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if selectab[2,j]<mincomptime then; R5 r0 k$ K6 D% H8 s$ f# S( B
j:=j+1;2 K" W+ i _# G
else
4 w' b$ k+ z0 K1 ~1 `, r; n4 A selecttab.cutrow(j);: R& p/ Q& |8 n! `; ]
end;
( c) c6 K1 @) @9 O- W: ] end;
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/ { @/ U% Z5 i% Q j:=selectionrule(selecttab);8 h' c: h) y1 b
1 _: L% f% W2 A nstep;+orders[2.j]+1;
9 T: Q% T. p; t+ R1 p# S! q orders[2,j]:=nstep;; n7 ?. u; S& X0 ~1 Z1 G
m:=orders[1,j][1,nstep];
7 h* Y/ q }' w4 ^ c:=orders[5,j]
* P; w6 M9 `0 a5 F occres[1,m]:=c;
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--jieguo:start,end,res,job,step. @0 ~8 ]: {2 S
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
4 o1 p! _: u% j! z for k:=1 to numorders loop. I Z/ l; F. @% c1 a% ?. k8 ?
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
$ _9 h# _& T9 D Q0 ~ --
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orders[4,k]:=max(c,orders[4,k]);
9 w, b. Z+ B" c2 s! n --
2 ?% i1 w" v; N7 R5 U$ ^$ c) B orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
: k+ o3 Q" r3 y8 t --
, ~# g7 y# N9 ^' y/ m+ E, O% ~5 ?9 f end;
9 {3 |9 P, b3 Q2 V; h next;) n- n, a; e+ U# y v; s$ R
nstep:=orders[2,j]+1: E+ p7 I0 A7 s* m$ w; f
if nstep<=orders[3,j]. ^8 T' ]9 F* S
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then
' R9 T( r# A1 a8 {$ X: O orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
+ l! l: \0 A: z2 K$ q# D* f orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];+ G" O( {1 n4 G5 M4 ]) S. g
end;1 D7 S1 H1 B0 C* A" [
next;$ K) b1 r. t- p$ F7 F, w4 p7 M, v
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});# K. g$ ^: l9 J! \. O, g* y
mygantt;
; N% h$ k+ _2 r0 { ens;
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