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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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& h5 m: x, w( |7 A1 l# \6 g7 i6 V不好意思,打错了个字母,呵呵呵!
% `, R7 ~$ u, E% j8 b大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示- ?6 c* W3 D& m) z% Y
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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- w. j- w: b4 u+ x! I j,k,nstep,c, scheduleteps,mincomptime:integer;6 I2 D" j3 q8 A9 N( {
M:string;
: Q, m5 P3 s" @ s, L3 E/ | selecTab:table[integer,integer,integer,string];
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initorders;) o. O2 r- [# g* j# W r
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scheduledorders.delete;8 s5 S6 f" u. i& W2 G9 z" B% T. |
seletTab.create;! J0 `$ E* r- d F. x% R6 E
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orders.initialize({2,1}..{2,*},0);
- N8 i9 Y8 X8 N- x9 G orders.initialize({4,1}..{4,*},0);
: _8 q: m. z# [$ U for j:=1 to numorders loop; x. F3 T3 R& N+ _( K
orders[5,j]:=orders[1,j][2,1];
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3 Y2 @6 q0 Z/ ^! B! P' ` occres.initialize({1,1}..{1,*},0);
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4 V2 M \/ W( N3 q) E: q2 z: M3 [ --XUNHUAN
5 z6 i. w9 n+ h: @: ]* Z for scheduledsteps:=1 to numsteps loop --
; }$ w$ Y/ E2 M1 E' j6 x selectab.delete;, ~* a0 P9 J! U1 Y2 Z6 {: W
k:=1;! u/ }6 _! r; v# j( r
for j:=1 to numorders loop" g1 `1 e& E! l7 y8 U& M! g
5 X5 F- O* p( x0 U nstep:=orders[2,j]+1;
1 k0 n% `9 ~ ~) h* t0 g x8 t6 W if nstep<=orders[3,j] then5 @5 D. t+ B% H9 X' T4 g4 ^& C1 @
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
8 s3 e+ M9 w& _ k:=k+1;
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end;; C4 j! C% h* ?$ g* Z* l
next;
: r' [- s" I m mincomptime:=selecttab.min({3,1}..{3,*});) ~2 X: j5 i. {/ U
6 B3 h* U1 ]2 a& m; |9 R from j:=1 until j>selectab.ydim loop
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+ w% f3 L# U5 E6 P! ~ if selectab[2,j]<mincomptime then9 Z4 C' ]& G; z
j:=j+1;( A; h; ^1 L0 u6 L8 k# Z3 [( n
else
8 _6 K: {% Z0 j% Y: h selecttab.cutrow(j);* h/ M0 C& |: o) c: o
end;% F+ q6 D+ R( j1 k
end;
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j:=selectionrule(selecttab);
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: f9 `0 n ?5 \4 a4 s& ?8 Z nstep;+orders[2.j]+1;$ E0 K4 U) G- g+ F. q
orders[2,j]:=nstep;
5 g6 m1 S" r1 a( f3 c q# m/ |( J m:=orders[1,j][1,nstep];* u6 M0 j9 H% q0 F- e! S% F
c:=orders[5,j]
S& J! o* w0 h1 j' o. b) r- K occres[1,m]:=c;
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--jieguo:start,end,res,job,step* }% o9 c) L, O3 R0 ~
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
. X; B h& N9 }" R% o! C3 |& ~ for k:=1 to numorders loop+ c$ N4 p& b c
nstep:=orders[2,k]+1;
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% [3 G' [- N7 @& y' _1 w if nstep<=orders[3,k] and orders[1,k][1,nstep]=m( q. w5 [+ j8 a6 Q2 l2 f$ y$ V4 c4 T
--
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$ w* L0 P7 }* I% t+ p/ c9 @ orders[4,k]:=max(c,orders[4,k]);2 s' `7 j$ t* |; x& Y
--
8 W7 Z( t( b% z1 h# o4 A orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];" p* _4 ` n5 o& ^: T! B
--7 e# t5 N2 h6 f; J8 M
end;
4 U1 Q/ D$ y. |# H7 ` next;" e n/ r% V U# U0 U. |6 O
nstep:=orders[2,j]+1:
) b! o4 t. p* P& _ if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
: f. {3 z$ E% S$ @, u orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];" R& g. r8 j& \1 m2 o
end;7 @( q2 e0 I ?: T% Y/ m
next;4 v: I2 e( g$ l0 j) Z1 J
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*}); Z8 ~+ H [: g6 e* a, n; Z6 N
mygantt;
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