|
|
本帖最后由 soso001 于 2014-12-17 14:53 编辑 ; H8 Y& t- L; v$ K$ n1 F
: {* a( M, m: m不好意思,打错了个字母,呵呵呵!
; ?3 z+ v8 L- N* R A大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示7 F9 ^, ?: Z8 ?6 p. X( ^
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
, ]$ e! G3 A& g( G- Lis
6 E$ ]5 v V& n8 Y" b j,k,nstep,c, scheduleteps,mincomptime:integer;
& H: X: w. m9 { M:string;
8 z6 C3 |" V, e selecTab:table[integer,integer,integer,string];
& ?, c: ]/ B. ~1 y6 G0 B7 Ado
' |+ l( h6 F2 z' S initorders;! P a+ ^2 Y$ s% v- ^8 N
) H4 {3 I# G, f7 z$ h& j
scheduledorders.delete;( ~' _ W, ~6 u5 j
seletTab.create;
) `' z+ B+ w6 B$ {% s0 [9 `8 d! `8 H# a - ^% [6 j) S% V3 g% U" w8 L( }
orders.initialize({2,1}..{2,*},0);
4 ]; I- I! Q- M5 K, \( l orders.initialize({4,1}..{4,*},0);; Q# @# Z7 Y; E7 [4 k) r% u
for j:=1 to numorders loop
6 V# _' W, O0 ^ orders[5,j]:=orders[1,j][2,1];- p; F( k' `6 Q9 Z
next;+ k8 b& s8 d' R
occres.initialize({1,1}..{1,*},0);! A0 {0 v9 C. [8 G
/ \- F, {5 O, Z4 q --XUNHUAN
+ m; z& r1 E) b6 \: P: T for scheduledsteps:=1 to numsteps loop --6 ] k5 h6 ^$ ~+ z
selectab.delete;3 i( A3 t0 z; _8 ~
k:=1;
* L7 o5 J. g2 c: P1 o' e for j:=1 to numorders loop
: Z! z8 _! @/ q2 g# @* ^% u
$ C2 b) p1 M* W' t nstep:=orders[2,j]+1;
8 R* w9 h3 |9 G1 V' S8 A if nstep<=orders[3,j] then* b* }: Y& I, N8 {/ a
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
6 q% ^ z, U |& f1 \$ Y k:=k+1;
# b- @4 ?% T% _/ N2 n
# ?$ [; t7 b/ A. u( z, N% p0 K end;
6 B/ l+ @0 v3 F& d4 }7 y2 k next;( S, Z( U$ V4 ]. B# g9 l J0 |
mincomptime:=selecttab.min({3,1}..{3,*});- h4 u0 N7 t% _3 G+ W
% K! \2 S% _% F2 [, ` from j:=1 until j>selectab.ydim loop( U$ T" w- v5 l6 `
, U3 a1 C$ C+ k( u if selectab[2,j]<mincomptime then
5 E$ V) w2 _/ L# g j:=j+1;
0 g5 r" i& v$ k! `" P' v4 _ else+ Q+ C8 B: P) S9 ^& ^, w4 N1 A) r
selecttab.cutrow(j);
) n8 a9 G0 v; {+ N2 v end;
4 Q, t# Q/ A; b% q! X end;
' m F! l. r: p& s
. D5 P6 m6 \8 E. D8 D+ u j:=selectionrule(selecttab);5 `3 Z H& l3 N$ h- x- @/ O3 A
( m* y) [# k+ } T6 p
nstep;+orders[2.j]+1;' W% }1 y& W( K
orders[2,j]:=nstep;
' h' _* T. b7 t# k) G m:=orders[1,j][1,nstep];
5 H3 Q- u/ T/ K& f% l c:=orders[5,j]' g4 P; G2 b; t9 I* A5 i. Z# e
occres[1,m]:=c;- t5 g9 K! E, A: Q) b
* J0 A* A/ t- @ b" F
--jieguo:start,end,res,job,step
3 n. X5 i: u- k4 o& k scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);! x; n# O& }) O0 g
for k:=1 to numorders loop! c7 c' e2 ~7 S( e" B
nstep:=orders[2,k]+1;7 y2 W9 A+ f; G/ ]. I
2 e% B1 Q: w1 Z# n if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
, C- X) |( H) M+ Q/ B/ N9 w) ?$ O --
! M1 h2 l. D, |" [4 p) t" e then
( T7 Y" B* Y8 X7 a% U* ^) n3 t orders[4,k]:=max(c,orders[4,k]);
9 M/ h- K a2 H --( _7 x% ?+ D" E; g! W3 [& ^
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
2 h2 R8 F5 e z5 H2 u4 T9 ] --6 \$ }6 \& b ^: b; A4 E
end;
3 H: \" @3 l* h; p next; q0 o5 K( \! s8 o. s
nstep:=orders[2,j]+1:& r! O: K0 H$ z7 ~& e, K! {# O
if nstep<=orders[3,j]9 O' w" P- E# g8 U9 ?1 @, c
! ?& j, ~" U3 y' ^& W/ v
then) H+ q. j$ Z: G& T* C/ B
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);% ]9 s( }3 d' T# H$ m0 F
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
0 R1 E# S& h# v X2 p0 B; n end;
$ s; @# D! x0 K9 v0 l next;5 X7 Q6 t8 |0 J8 O3 t
( G% B! i x. i; R" k- M" B
print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});( z# }. a) h" M1 S Z U# y
mygantt;
B! k, D9 A1 O2 v) p ens;
1 l9 t5 W* R9 B4 V. r8 ^/ M |
|