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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!) ^' W/ e& v2 x/ G2 t, q, H8 V
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
9 t' G" ]% X; a* Q, w$ {9 F- p8 f“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!. Q& v4 y) ~" ^8 g5 ]
is
9 B% H0 Q, _( U j,k,nstep,c, scheduleteps,mincomptime:integer;
- B" Y+ N9 B8 F2 ^2 g M:string;- {; T$ g* Y+ ?% y
selecTab:table[integer,integer,integer,string];
6 ?( \. M$ T& r& X5 K6 i" ydo
9 ?9 D: H5 h: x/ m0 s! O initorders;' V" ~$ x- p. b0 d" Q! l/ }. a
9 D% d$ p2 \1 U8 b1 r scheduledorders.delete;# H. n( U: `9 V5 O% E) z3 H/ @9 \+ {
seletTab.create;2 |/ u$ u) n# m8 ]2 e# O/ @
e1 c$ _. \: c
orders.initialize({2,1}..{2,*},0);) A- r# X/ F/ J$ P# W
orders.initialize({4,1}..{4,*},0);
+ A: X9 B; {9 F4 Z. h for j:=1 to numorders loop
$ d3 [1 A4 e+ m h' h1 D4 K' G orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);: y3 G% I U5 c; j3 W/ \
) z0 R7 C" y0 m) c: c! E --XUNHUAN2 g! c" p& j9 _2 x
for scheduledsteps:=1 to numsteps loop --# L1 A5 m* u5 y$ D0 l4 R. y7 g1 j
selectab.delete;
! G" g6 k* `' R3 Y9 u k:=1;
3 P7 S; d' L+ B for j:=1 to numorders loop
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nstep:=orders[2,j]+1;! u) I6 j( ~- X$ ?) w* p5 ^
if nstep<=orders[3,j] then
5 K* F& R2 \: o& ?* ^ p4 a selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
: T5 _" \1 K7 L k:=k+1;
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0 `/ Q; G6 ]6 p. E end;
; |* l; ~) I/ e6 o( b2 |0 J next;
2 Z; |4 K' L* k5 V mincomptime:=selecttab.min({3,1}..{3,*});* r! v+ n- V2 g. V0 M5 z
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from j:=1 until j>selectab.ydim loop. u4 Z, ?: B- V& O: ]4 y
) L; _5 Z8 ~; X4 ^% u3 R+ { if selectab[2,j]<mincomptime then
" {+ {! ?. @" _2 u2 l j:=j+1;
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selecttab.cutrow(j);$ M7 o+ t* D$ z
end;
/ f7 I1 k% }3 \' S2 B end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
3 ]; P/ G/ o# i+ I) f, f' h/ y orders[2,j]:=nstep;
2 C0 j- i3 m) `2 A. a+ |0 L0 o m:=orders[1,j][1,nstep];
+ p- v+ H- S4 ^6 v c:=orders[5,j]
. K/ b& O* c y3 U- A% S occres[1,m]:=c;3 [- N3 Q& v! i6 ~0 N
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--jieguo:start,end,res,job,step
- E6 C! C+ ?9 j2 A3 J scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);4 _! q- g! e: }3 Z' z8 u( [/ }
for k:=1 to numorders loop
' l ?1 t% M6 G6 B8 t nstep:=orders[2,k]+1;
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( U- s- }: _+ Y$ f. U if nstep<=orders[3,k] and orders[1,k][1,nstep]=m+ a( n) ^$ k1 _; O; b
--2 f* v U6 X8 [2 ^+ y
then2 g5 h- N# M6 K! t4 ^7 j
orders[4,k]:=max(c,orders[4,k]);
# p. n% S% @+ |' @2 m: A- a! F --
0 K! j+ r: y/ z5 R orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];& |; e" P2 }- b& P
--1 E6 B( [8 L( n
end;
0 J* y: U/ _& {2 |1 \% | next;
# r( _( ]* O( z& t) R, E nstep:=orders[2,j]+1:
: l$ l: W4 A9 Q: e6 P* \/ g) J8 q if nstep<=orders[3,j]
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then7 ~6 x6 V. X) P! B
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);% c! T( ]3 o6 A& [
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];- T+ [" {# V% i n. F) D' X( F
end;; y8 W' u1 {2 [6 h8 [
next;0 W/ `( M3 t, L: k2 y% S; P# p& U- X
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});, g3 ^8 e; X* N7 [
mygantt;
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