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本帖最后由 soso001 于 2014-12-17 14:53 编辑 ' a6 @: J' [% I; t
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不好意思,打错了个字母,呵呵呵!
/ q8 q# F8 N/ W1 t8 @大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示5 u" G$ ]8 m. W- D0 M1 X' @
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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5 q3 I; x5 W# s! ^* m j,k,nstep,c, scheduleteps,mincomptime:integer;0 J" O# w# Z0 U) e u* f
M:string;
" f! J0 B5 ?- G. M6 N0 U* d selecTab:table[integer,integer,integer,string];5 o# M; {! Q2 Y g$ \7 p) B
do
* ]+ ^+ A8 J7 r) a5 v9 v initorders;
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scheduledorders.delete;
% `) G2 U4 H) p. J% R seletTab.create;
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orders.initialize({2,1}..{2,*},0);
! H9 p1 L$ e6 ]9 D' Z3 M orders.initialize({4,1}..{4,*},0);) a. x" E e+ Q' }( L: e) P
for j:=1 to numorders loop
8 W" w+ }$ l q6 J orders[5,j]:=orders[1,j][2,1];
# Y2 y3 c" ~' q% _; a2 k. N next;0 p2 C& T' k/ {3 Q' C y
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN
& N2 C. J' d7 ~* V) i for scheduledsteps:=1 to numsteps loop --5 }3 C: }! N6 k% l
selectab.delete;
7 w+ [4 v& z& w, G; W' e# |0 {' E k:=1;
! A0 |9 i& W+ S [ g, H0 }0 C3 m for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
3 s0 u% }+ S3 P) U$ Y: h if nstep<=orders[3,j] then) p5 M% |: c# D
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
! Z4 Z6 q, e. E N5 [1 ` k:=k+1;3 x# _; N' w- y
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end;
! J1 y2 p; S. T next;
) G# M; ?5 M, G mincomptime:=selecttab.min({3,1}..{3,*});
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8 K9 V' Y' _* v from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
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else
$ h+ k5 H! \/ H# Y% r1 [9 J selecttab.cutrow(j);" R) B1 s6 g# E8 J) q9 ^
end;+ l5 W7 r6 s1 u
end;( |5 d8 C* n/ E1 C
7 X$ v/ K: d6 | E% V0 P& b @ j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;0 h6 Y/ r( V1 \
orders[2,j]:=nstep;
, ~6 V: f. r) G. |3 { m:=orders[1,j][1,nstep];8 ` D- M. v; Y7 {
c:=orders[5,j]
9 ?; g$ p$ d" w3 }, S- @; n occres[1,m]:=c;" c! Z6 d2 m4 r# P
# W/ f5 J7 V1 b( j+ ? --jieguo:start,end,res,job,step
/ R3 ?3 ]# F# I. }$ |3 N8 O3 A scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
" Z0 V+ Y% E/ n0 l: a% [ for k:=1 to numorders loop
- e: M7 ~& R' ]9 M3 Y! ]* h nstep:=orders[2,k]+1;2 M; n1 ]8 |; z0 ]0 F% T
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m: U" j/ R1 c. Y
--
+ ^8 R9 J/ |+ }( J then
2 i# z# ?8 ~! v& q5 w# g) A orders[4,k]:=max(c,orders[4,k]);
4 r, s( X$ m3 G4 ^, S: h6 ]+ S8 @$ R3 I --
* L Q- w5 y! `) P3 B3 M orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];+ }. T( H. v+ V! J1 e
--
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next;
3 {. A$ f2 X7 w. V) B nstep:=orders[2,j]+1:2 [8 {2 v: B9 d; W( W' u5 y
if nstep<=orders[3,j]+ c! v; g' ]4 U$ a3 r( B5 o
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);0 S, e) s/ g0 G. V* X
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];, H0 p9 d0 I# l4 n0 X
end;# m' |' e+ Y q" z3 S0 J' I
next;* r# g- B3 N( B; f, i2 Z
8 g. d# S) k- w/ u }; t S" A print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});% T7 f' z6 [3 \# _( d5 b
mygantt;' q9 j' p d% N4 T8 V; }9 R
ens;' ?# {7 |( ]; ~
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