编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
  if count wolves-here >  0           
  [let otherwolf one-of other wolves-here                     
5 g* L! T8 b2 E* }9 ^2 `; i3 Y    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
   ]
9 @0 ]1 E6 a% }5 u& K, s3 V   [ set  [k1] of self [k1] of self + [k1] of otherwolf
   ]
     end
& g" P6 q9 q0 {8 H4 I4 a* {显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧