HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下: X9 o' Z$ P; ]$ `; h! Y' W+ _) S
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public Object buildActions () {- T" @3 b* x: y/ ?
super.buildActions();
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// Create the list of simulation actions. We put these in; S# Q. r0 ~5 i1 A4 X. h! V+ g
// an action group, because we want these actions to be" |; Y4 b! H4 S& `" E
// executed in a specific order, but these steps should2 r4 X2 ^7 ^1 r
// take no (simulated) time. The M(foo) means "The message. M( i b4 ]4 h- U( P
// called <foo>". You can send a message To a particular+ C T. `3 }8 A! p8 f
// object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run/ \; h3 p0 A$ @! Q) S
// diffusion, then run "updateWorld" to actually enact the e4 D) i! S+ O# ?& r# g z
// changes the heatbugs have made. The ordering here is
* J( ]7 Q4 o) [+ _% K // significant!, x% R. s) O" t
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// Note also, that with the additional" r J( k& y$ r1 c$ L6 i9 R' w
// `randomizeHeatbugUpdateOrder' Boolean flag we can
/ l" z* B4 _* l+ z$ K. N+ ?& I // randomize the order in which the bugs actually run9 X, h6 d b# i! Q
// their step rule. This has the effect of removing any' v0 b! C4 @( {; D: p6 O, h
// systematic bias in the iteration throught the heatbug
, Q* S; L6 X4 V' P // list from timestep to timestep9 n1 B; m2 [2 k1 N
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// By default, all `createActionForEach' modelActions have. ?! p, t4 h* s0 m" H# N- v
// a default order of `Sequential', which means that the& U* ~7 D% x1 w) d- x
// order of iteration through the `heatbugList' will be9 H/ \0 z* T+ W1 x5 z+ o
// identical (assuming the list order is not changed
3 C+ [# N* e. L' U# K- ]. S1 l // indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ());0 }; W4 J- f) t% M
9 W. z7 P {4 V: @+ n; N2 H try {
5 g8 Y. f) J" \8 s modelActions.createActionTo$message
5 g, K1 t* N) t! ]- k( P (heat, new Selector (heat.getClass (), "stepRule", false));; A M% Y8 @3 W4 }8 D+ B! O
} catch (Exception e) {
8 ?; b5 ^( m7 Y" Q System.err.println ("Exception stepRule: " + e.getMessage ());& b/ }. z. j' o# Z! Q5 i( v
}
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try {, {/ E6 l/ \7 }
Heatbug proto = (Heatbug) heatbugList.get (0);5 l' W7 M3 s' @
Selector sel =
' n4 W* t \+ {/ @! K2 G" P new Selector (proto.getClass (), "heatbugStep", false);
" Y. x! e, G! `/ v: ]% R) Q/ [ actionForEach =
" {* {# F4 H0 t. h2 K" ]. B modelActions.createFActionForEachHomogeneous$call
/ s4 j. _( x' R+ o( J8 B$ h% v (heatbugList,, T; w# a, O9 N. s
new FCallImpl (this, proto, sel,
/ l w3 T1 y8 j! i new FArgumentsImpl (this, sel)));& ?* h, `0 P6 w5 M
} catch (Exception e) {( N' D6 s: y0 i; C/ C7 r
e.printStackTrace (System.err);
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- P6 i, B1 _! f4 m, I syncUpdateOrder ();
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modelActions.createActionTo$message
) C5 D6 T: e* U2 I! U) ]+ \$ P8 w/ Q (heat, new Selector (heat.getClass (), "updateLattice", false));
2 [( M. g% ?2 G1 t8 c, x! m$ I } catch (Exception e) {1 _1 O) {, {" `% l! B( k+ m
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the
5 P6 W0 r$ O1 |# J // modelActions. modelActions is an ActionGroup, by itself it& E- \6 Q( ? Z' S/ E
// has no notion of time. In order to have it executed in
' N6 U# ^4 X% C$ _9 ^- }0 L$ T F$ S // time, we create a Schedule that says to use the
# ?5 y, ]0 z7 U- ~" E0 A // modelActions ActionGroup at particular times. This
# p4 A% L8 H; |6 Q( t // schedule has a repeat interval of 1, it will loop every
8 N5 l( n l. O9 j" W- v5 i3 Z // time step. The action is executed at time 0 relative to
9 b ~1 ], I% y' a // the beginning of the loop.* N& m! [/ I9 Z2 J7 j
( P2 l. W4 P' L; B& @ // This is a simple schedule, with only one action that is6 m) f z" ?, V, {
// just repeated every time. See jmousetrap for more
3 R. z K4 l, }1 k3 x+ Y, O // complicated schedules.
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! m: [) G$ Q/ p: `. \* J. Z1 @4 \: P modelSchedule = new ScheduleImpl (getZone (), 1);: u# n! W- m0 b* T9 S! x
modelSchedule.at$createAction (0, modelActions);
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3 p, \/ d2 N/ K5 y& y return this;
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