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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:( \1 M2 O; J. H" T5 |+ y
& c' Y) P8 e+ ^  g
public Object buildActions () {
' Z! p9 |$ |8 P& V) {; Z0 m& J    super.buildActions();, |1 o6 H) `& D: B8 }5 Z/ b, D( Q
    $ f# B# _1 R, z5 ~. T
    // Create the list of simulation actions. We put these in# p6 |& T8 Q" U$ N: o
    // an action group, because we want these actions to be
" C' \. q/ U$ s2 z) ?2 }    // executed in a specific order, but these steps should" z) w6 e$ N1 D$ F& D6 f7 P, X
    // take no (simulated) time. The M(foo) means "The message
! E. z9 x9 i7 Q6 S    // called <foo>". You can send a message To a particular
% G" A4 J& k  @& N1 W* F  \    // object, or ForEach object in a collection.
4 J9 f8 C, |/ {3 z7 e/ P2 P        5 U: w/ K) B- y% Z( ^9 v
    // Note we update the heatspace in two phases: first run7 D# u, _2 U4 X% D& @
    // diffusion, then run "updateWorld" to actually enact the( U! C# t* Z3 M6 @. e
    // changes the heatbugs have made. The ordering here is
& b9 Y/ L" O) F# C9 v    // significant!
( u5 V0 u% L0 Y2 p! j* z        
! |6 q3 d. H* B, h    // Note also, that with the additional; P. v! m$ k+ K( r
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
# E7 }1 W+ j* e# N5 x    // randomize the order in which the bugs actually run
4 f4 M5 W$ t0 Y9 u+ r" {2 ~4 n    // their step rule.  This has the effect of removing any; c- `# T' n9 @) ?
    // systematic bias in the iteration throught the heatbug% T5 Z0 c$ C8 `5 I* ]
    // list from timestep to timestep$ M; i5 m7 [: {8 t5 o1 l8 S
        
+ p, h- I: c7 z! g; a4 {+ o    // By default, all `createActionForEach' modelActions have; k# Q2 t$ |  C% {/ D
    // a default order of `Sequential', which means that the1 I! f- V" d8 E: q+ s$ }; q2 v0 M
    // order of iteration through the `heatbugList' will be9 }$ }* L( Q3 q  Y8 a
    // identical (assuming the list order is not changed
. f  }* `+ M5 ~    // indirectly by some other process).$ Z3 f- S8 K% p: E9 s
    . p, e9 s  L  R& I& n8 f5 z
    modelActions = new ActionGroupImpl (getZone ());
# o- {3 V# G# @: o- V
8 b! r" ~2 F) x8 q    try {
: o4 Z6 Y1 q( ?% c7 G/ k% p- Z      modelActions.createActionTo$message
" ?& N3 X9 s# l# l5 h' H        (heat, new Selector (heat.getClass (), "stepRule", false));
8 Y5 W$ b1 {9 M$ g& e2 T3 e    } catch (Exception e) {
& I7 B+ _! V7 d% j3 ?: i      System.err.println ("Exception stepRule: " + e.getMessage ());; |, ?4 ?6 x7 ?
    }, U3 v1 v7 s9 z+ y6 k
4 _. l' O: K. t  a' h$ U
    try {% Z# b' h) a0 o2 x
      Heatbug proto = (Heatbug) heatbugList.get (0);
: ?* m8 u! s3 M* _4 t# v      Selector sel = # M- Y3 ?8 y/ C9 q
        new Selector (proto.getClass (), "heatbugStep", false);
* f* B5 y: Q, g7 R      actionForEach =
( k1 h# [8 `( A, w8 u6 y. F        modelActions.createFActionForEachHomogeneous$call% c' b- O4 o3 M3 H) i+ N+ V
        (heatbugList," u6 p" f3 E! o0 x
         new FCallImpl (this, proto, sel,$ D) r9 a# O/ f- M* S- m; _' w/ s" w
                        new FArgumentsImpl (this, sel)));
0 K- A" @+ Z! |; V# J; {    } catch (Exception e) {: b, k+ Q) V. O8 c& j  L
      e.printStackTrace (System.err);8 O0 y* v8 C5 ]# ^
    }& `4 n5 M2 L' L+ ^2 ^
   
7 L4 u2 k; k* n2 p    syncUpdateOrder ();, q+ }% p2 _3 Z4 W( _7 G* T7 u! w  F
) l+ Y& I+ O/ ]8 o' q. O
    try {
) [4 e% V9 r' H      modelActions.createActionTo$message ) ^( k. J; M1 ?5 o! n
        (heat, new Selector (heat.getClass (), "updateLattice", false));
0 X+ N) g) Q: n* ]- H    } catch (Exception e) {
: I& _% I+ k1 V0 z4 K2 k# m. @: `& \" h      System.err.println("Exception updateLattice: " + e.getMessage ());
0 n! i  Y; P& |7 v% ~/ [8 g0 o    }6 X  K7 D8 i3 A+ X6 l1 h* {/ s
        3 ]& r0 B, \$ z+ K  Y. Y3 |' P1 W2 q
    // Then we create a schedule that executes the
8 L  i0 j/ \$ _8 j( G    // modelActions. modelActions is an ActionGroup, by itself it) Y- L5 s, b& B8 p9 w4 Z+ W9 j
    // has no notion of time. In order to have it executed in* g- s- `, h0 B
    // time, we create a Schedule that says to use the3 v6 r& O1 {! D7 |/ K9 u2 z
    // modelActions ActionGroup at particular times.  This4 ?' `& e& B6 H) W  q3 B
    // schedule has a repeat interval of 1, it will loop every$ G8 E6 ~0 J& R6 e& K
    // time step.  The action is executed at time 0 relative to. s' q4 O9 @) N4 V
    // the beginning of the loop.  i8 Z# C0 M: R$ h4 W
, U% a! _2 R5 J$ h2 r% n1 x
    // This is a simple schedule, with only one action that is& A, G1 A7 L! x7 J& N
    // just repeated every time. See jmousetrap for more1 w7 w# e, G. T$ G! T  x, Z$ D8 X, u
    // complicated schedules.
0 B) g4 p! U: Y  
. y% Q: K; I7 Z; T    modelSchedule = new ScheduleImpl (getZone (), 1);
) j5 E2 U$ C; l+ i+ j5 |    modelSchedule.at$createAction (0, modelActions);1 b& m6 p9 ]  B+ r0 |7 ]  w
        
1 K7 ?) K; M( p8 J2 m    return this;
$ D  h7 t  E6 P) q  }
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