设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 8551|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
: k4 @4 Z! [! _% D3 ?. k2 j( K: d
( C  S# d! n5 w. B/ h6 } public Object buildActions () {, p1 T$ x$ P! r: C% g" W$ W( }1 p  b+ N
    super.buildActions();
  P/ |6 m+ q' k+ J    * b0 j9 y& S: Y' L3 g9 F. k0 q6 e
    // Create the list of simulation actions. We put these in
3 e0 L5 J% v: }6 y; y7 y9 a$ }    // an action group, because we want these actions to be3 {; D# w/ }# g" l  Y1 L
    // executed in a specific order, but these steps should
, ^) u/ z* e# |    // take no (simulated) time. The M(foo) means "The message/ z& }7 |' V% ]# v
    // called <foo>". You can send a message To a particular/ L# h" X, a% E: m
    // object, or ForEach object in a collection.
. }3 G  M% Q! A- Y9 g        
' {& H. q% t9 p4 d    // Note we update the heatspace in two phases: first run9 L' y! k. S' i2 u2 s
    // diffusion, then run "updateWorld" to actually enact the
9 a- b+ P* d/ o$ _: q    // changes the heatbugs have made. The ordering here is
3 k2 Q+ i4 ]$ ?    // significant!
9 [. C) F+ Z; f, w/ v5 C) K, W0 k        
4 ~3 K8 s: {' B) b) y    // Note also, that with the additional% J, n- {1 e# H. J+ D5 G9 j  q9 x
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
+ a  v7 A  X! s2 V    // randomize the order in which the bugs actually run- H: {* _: d! G
    // their step rule.  This has the effect of removing any
8 y- t# G7 v/ @3 b    // systematic bias in the iteration throught the heatbug7 O; u7 ~5 S- v/ U  M: c! g
    // list from timestep to timestep
# a. b  E* V9 ], r        
4 Y3 H' ^# W  x1 I% s    // By default, all `createActionForEach' modelActions have
6 C% ~9 d5 `- \; j- f    // a default order of `Sequential', which means that the
, ?- y- a" _0 b, J7 [- p) @% {    // order of iteration through the `heatbugList' will be( ], M5 g4 o& u; ], k7 l
    // identical (assuming the list order is not changed
% X: Z3 B, A: u    // indirectly by some other process).
) p( y! V3 M) \  N* n    0 `6 ?' k7 l* w
    modelActions = new ActionGroupImpl (getZone ());
- l: h* ^$ X/ `# S1 n
  V! q6 \8 ?( P- G5 ~; \$ h    try {+ O+ }* e& h- ~" o1 S! }$ \
      modelActions.createActionTo$message1 I, Z# ?1 |8 U2 m% H- W3 n
        (heat, new Selector (heat.getClass (), "stepRule", false));  i  z: K& {9 }+ Z% g$ w
    } catch (Exception e) {
- R/ i9 p; y1 g7 V: |" }, I; J6 @) q      System.err.println ("Exception stepRule: " + e.getMessage ());
3 U8 p4 t9 {6 S, u7 ~3 c    }9 c8 |7 X: F2 B) g
3 E0 n& R8 c  o. A' D1 H
    try {
1 H8 T' l( b; M      Heatbug proto = (Heatbug) heatbugList.get (0);1 ^) `* x+ a. D' Q0 u+ x  W3 B
      Selector sel =
4 P, n' J; |* e1 Y        new Selector (proto.getClass (), "heatbugStep", false);. H% @+ p/ E& G! T
      actionForEach =. ^1 b  c5 q6 I& X/ I. V
        modelActions.createFActionForEachHomogeneous$call( Y/ r7 X6 u" J4 |  q0 _) L: R* i9 w
        (heatbugList,, p; ]% q+ Q" K# k
         new FCallImpl (this, proto, sel,
/ h2 Y7 N2 r" m- ^                        new FArgumentsImpl (this, sel)));, T$ u( n2 x) z8 ?
    } catch (Exception e) {5 D' V$ j0 d. T3 |
      e.printStackTrace (System.err);
$ j5 }7 L) s8 h3 q, s    }
& R; [/ u/ b1 R; ~9 D% ^   
* a* j3 I) ]& u4 m# T" X4 t4 Q    syncUpdateOrder ();: G8 X' H" s6 O8 {: @3 T  `

' Y  {+ T- R" A+ V! M    try {% J7 s% w5 j! u# i  _2 O$ N7 x
      modelActions.createActionTo$message
" I" D* \4 t3 \/ H! C6 p1 W. U        (heat, new Selector (heat.getClass (), "updateLattice", false));# z7 f2 l, `1 _+ Q- Y
    } catch (Exception e) {
1 D* K) j  H) E: V      System.err.println("Exception updateLattice: " + e.getMessage ());0 w2 c, s! a- l
    }$ V$ f3 Y6 q4 {! e/ X
        / s$ e& t: I* b, k6 F, f& u
    // Then we create a schedule that executes the$ \' O7 S4 I, [  \
    // modelActions. modelActions is an ActionGroup, by itself it8 X" G4 k( Y1 H- v. _% I3 S
    // has no notion of time. In order to have it executed in- U* c9 l& N: q* A% V; s4 T& A
    // time, we create a Schedule that says to use the: r4 f2 ]: R0 O9 I2 p% K! x' G
    // modelActions ActionGroup at particular times.  This; q, N% w9 s0 a- X9 k2 P, D
    // schedule has a repeat interval of 1, it will loop every
& B  ~* `: K! H3 v& x5 G0 Y    // time step.  The action is executed at time 0 relative to0 o( f1 R( C7 D7 U4 w7 l9 m
    // the beginning of the loop." g: a* m- a1 B8 ?$ X
$ Q( w( I9 k: F, U" P! X
    // This is a simple schedule, with only one action that is+ F* o) C/ \% W; j
    // just repeated every time. See jmousetrap for more$ Y- s  j2 M5 i# G9 t: g4 }
    // complicated schedules.7 v5 U" G5 ]8 f9 B  b3 `
  
3 F( V7 j1 m/ k$ f    modelSchedule = new ScheduleImpl (getZone (), 1);% X# B$ R0 F9 f
    modelSchedule.at$createAction (0, modelActions);
* d" g8 D9 X7 o* w- S; ?        2 ]9 J3 l5 `" g
    return this;0 ]4 B  r/ G/ O, ~/ I/ ~4 ~: D
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-1-13 17:29 , Processed in 1.493594 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表