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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
- B4 R! |, |/ S; r! F1 p8 g1 \& R6 w+ ~) F
public Object buildActions () {/ f$ ~2 N: l* r: L% K
    super.buildActions();, r2 U/ I' i% w4 S7 z/ I' Y
    ' M$ P* T# E$ w4 v
    // Create the list of simulation actions. We put these in
! H8 d6 s! w6 s# F    // an action group, because we want these actions to be
$ x0 d. v1 ~( @: \; k2 j    // executed in a specific order, but these steps should  q4 w6 F% v* ~, c5 A
    // take no (simulated) time. The M(foo) means "The message
7 p$ P6 d0 _8 q/ ?4 [. V    // called <foo>". You can send a message To a particular
/ l8 A* m! x  i  ^3 L, s    // object, or ForEach object in a collection.
: ~1 S* d  o& A' e        
8 F# U+ w; b* p" r1 r; Q2 R    // Note we update the heatspace in two phases: first run
9 F- v( i$ n" H4 W7 Z3 ~& H& Y2 ?    // diffusion, then run "updateWorld" to actually enact the4 j2 j+ F8 T8 u2 [+ n7 U. ?
    // changes the heatbugs have made. The ordering here is
7 w* i, F$ Z3 I% `2 W  o    // significant!
. L3 b+ q) C- t9 u( l        3 w* a  c" H) D# `2 ?# ^4 r: ~. a
    // Note also, that with the additional; @8 q  @' h) v) v0 D, u
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
4 K, k" g( P$ c0 {$ A& H7 H9 c    // randomize the order in which the bugs actually run% g2 x$ ?* [1 Z* r9 V
    // their step rule.  This has the effect of removing any
, N- H1 M5 G6 j% G5 N  o. ~+ I    // systematic bias in the iteration throught the heatbug9 ]# E# ?' b3 ~1 ?* h3 w
    // list from timestep to timestep% J* J. m, a& t# g% F
        
2 P/ G, }& Q4 b7 c    // By default, all `createActionForEach' modelActions have  J4 K4 A* C. ?8 c
    // a default order of `Sequential', which means that the
* Z' Z/ V4 m/ D( J    // order of iteration through the `heatbugList' will be
- o( @) C( {$ |0 U3 e* a9 d    // identical (assuming the list order is not changed" _) I% M: O" r4 N6 F
    // indirectly by some other process).
7 b! ?( b; ~: E   
5 a6 i4 x& i+ y7 E4 h    modelActions = new ActionGroupImpl (getZone ());1 }+ X. v$ c# u) y% P$ B& q1 S5 o+ _
7 _# |$ E* }$ n% m
    try {
" b- B& y( Q  L0 |/ L      modelActions.createActionTo$message
6 o9 a3 w" G& K) I5 J6 G        (heat, new Selector (heat.getClass (), "stepRule", false));
' Z; n+ ]& @/ H( k7 q6 i    } catch (Exception e) {
& [2 m8 a5 {; h: [* a! |0 [  d$ I      System.err.println ("Exception stepRule: " + e.getMessage ());
: q0 X. b9 z/ c    }
9 Y) Q, f' |2 m6 ?8 H
" s6 g$ E% o- }% u/ A    try {, V1 g3 P" s/ e8 a/ V# K
      Heatbug proto = (Heatbug) heatbugList.get (0);
! W; R" F' _* e9 }2 `      Selector sel =
) w/ V& G$ x  f9 M, g        new Selector (proto.getClass (), "heatbugStep", false);
& v0 X* A# F5 [  H! Q      actionForEach =7 |& F' |3 T5 V( u6 u
        modelActions.createFActionForEachHomogeneous$call
6 S# k! M2 Z# q3 m5 u        (heatbugList,
" [6 V& ?- m6 I8 K9 O8 @* l$ s( I9 G         new FCallImpl (this, proto, sel,
6 n( j* t- E* K" Q5 ~" u5 j  _4 e                        new FArgumentsImpl (this, sel)));" K4 Y$ i& _7 j
    } catch (Exception e) {
3 \7 k$ M  P; h( V; E6 n9 z5 q; [      e.printStackTrace (System.err);
- g9 K$ Y9 `9 s  x- Z6 ?& ^    }
0 @) o' i8 t+ a- D, S+ l' V    5 a2 k! x/ ?8 \! o+ E5 w" a# h, D
    syncUpdateOrder ();2 v9 [2 o* |1 n5 s7 N( U- l# s
7 s" s. K. x( E7 {- Q" n
    try {
5 f$ K7 @( Y: q' c6 K( ~      modelActions.createActionTo$message ! R. B  _* z5 j/ W
        (heat, new Selector (heat.getClass (), "updateLattice", false));
+ Y3 v  T" T, N5 F    } catch (Exception e) {1 d6 t9 ~) K$ G
      System.err.println("Exception updateLattice: " + e.getMessage ());- t, w9 L5 u- g- g; e. j: M+ j' J7 h
    }- x" z0 }& Y6 f* Q- ~1 q+ m& C. _
        ! x2 v, C+ M; ^! z: t' o
    // Then we create a schedule that executes the
# w) V7 a0 y, u, Y8 q2 F( J. j    // modelActions. modelActions is an ActionGroup, by itself it: k  E3 S1 f: ?/ }
    // has no notion of time. In order to have it executed in
1 {) x% l7 P& V/ V! {& T5 A    // time, we create a Schedule that says to use the  V" ~6 b2 U3 R% B$ J. a
    // modelActions ActionGroup at particular times.  This
' M+ W5 d. f5 f. u  }    // schedule has a repeat interval of 1, it will loop every7 H! ?" ?1 `5 C2 ~2 p
    // time step.  The action is executed at time 0 relative to
& S- s7 U: h* Y! `! L# y: R: X. O    // the beginning of the loop.
, P. h' h: o$ e5 R) A! J4 h: b% O( |) y5 O! a9 F1 y" ?
    // This is a simple schedule, with only one action that is
/ w: m( R4 v- I3 s7 T/ }    // just repeated every time. See jmousetrap for more
$ x( p, w. ~( Y& u6 l    // complicated schedules.
+ D" ^( p2 y! U3 |4 p& k. J  
$ d# V% U; b, Y7 v    modelSchedule = new ScheduleImpl (getZone (), 1);
* B1 p; W% S  {- D% u    modelSchedule.at$createAction (0, modelActions);
3 Y9 j( C% _3 ?7 _! D- {        
" L5 [! v; h2 h2 \; ]6 Z    return this;
0 E4 u8 S; `, y+ y, I' e, x  }
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