设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 9576|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
: C. a& @. Z7 Z: M$ n' ?
- D7 K$ _' x2 B public Object buildActions () {, k6 O- |! L( l) N# P
    super.buildActions();5 g0 L& ~* {0 A" O
   
5 h# W3 b4 E9 ^7 o8 Z& a8 V    // Create the list of simulation actions. We put these in
9 T* @* M% ?$ V. B9 g    // an action group, because we want these actions to be
* c$ B* K+ o+ _, I+ _% k    // executed in a specific order, but these steps should; H0 q" W- l% ]9 F1 u! d/ Q  v% [
    // take no (simulated) time. The M(foo) means "The message
4 W3 H3 u8 {9 h) f& b& I    // called <foo>". You can send a message To a particular  a) c/ z, F+ }: F+ F* x% r
    // object, or ForEach object in a collection.  F/ n6 }) z. s6 ?0 A
        
9 Y$ I1 |9 w  S4 }5 f1 f    // Note we update the heatspace in two phases: first run
4 o; l+ H0 s0 m& C    // diffusion, then run "updateWorld" to actually enact the
; G- L: N3 x+ G7 l2 j1 E    // changes the heatbugs have made. The ordering here is
. E, L/ h- X3 s    // significant!
& R' U7 C6 o* u) h) I; w: c: F        6 h( y- w2 i# E
    // Note also, that with the additional0 f0 l8 N( E3 {7 E3 ]3 z" \, ~& T5 ~
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
; \! k& D1 k% U; N3 _    // randomize the order in which the bugs actually run
2 p' R9 J, t) g! n$ N8 K) g  R1 m    // their step rule.  This has the effect of removing any* ^9 ~6 ~$ p5 q2 \6 N3 i
    // systematic bias in the iteration throught the heatbug
$ Y  i9 N% b& {2 y    // list from timestep to timestep9 M$ c* @2 O. x) w* C
        " C8 l( w3 _* g% v
    // By default, all `createActionForEach' modelActions have
0 U# Q% C+ ]/ a/ o4 g: U$ ^    // a default order of `Sequential', which means that the% o4 h' t" J& P( B; j
    // order of iteration through the `heatbugList' will be; u4 U" i1 Q& v2 S3 N
    // identical (assuming the list order is not changed8 k/ S& c9 t( l2 n0 ]6 U- |
    // indirectly by some other process).# b7 j; g, M% c9 P+ L* v- w
   
& e9 V# Z  j% q- ?    modelActions = new ActionGroupImpl (getZone ());
7 c, e' V/ V/ R; q: \  J7 \" n( O: p% |6 w  _8 L
    try {
/ d  a( g, \9 N5 l      modelActions.createActionTo$message
* S, H/ K; P5 n, k/ q2 l, q        (heat, new Selector (heat.getClass (), "stepRule", false));
& C+ A( X1 J8 B+ Y& p; ]$ M$ p6 R    } catch (Exception e) {
! F. M% [% T% N      System.err.println ("Exception stepRule: " + e.getMessage ());
. S" l: {* x" s0 {  H# |( }1 @    }
; T" U( ~' e( }. p! i( ^
2 }8 o* V: n3 D5 Y& @7 x: ?    try {6 h# ?7 x9 e+ A' c( S
      Heatbug proto = (Heatbug) heatbugList.get (0);0 s8 @* D- f  _, z
      Selector sel = : [  ^; b9 E1 ?! Y  `
        new Selector (proto.getClass (), "heatbugStep", false);) L  M, `: o0 e
      actionForEach =2 R. l; m% H. @
        modelActions.createFActionForEachHomogeneous$call2 Q) v- V5 b! e5 Z2 ^  c- g( }
        (heatbugList,% n  l  J& P* E, N
         new FCallImpl (this, proto, sel,
, `! D' v; d, b# y2 u( V/ a, b                        new FArgumentsImpl (this, sel)));
5 b5 ~* }' n: P% n8 q; Z    } catch (Exception e) {" x$ q3 z. d5 a* z% f$ N# d
      e.printStackTrace (System.err);. ?; y2 r0 N- {& ]1 M" s) D2 x
    }% z$ B) S0 x( |1 Z7 c8 N: @
   
# V, x' G8 M& C4 x6 W  Y( [    syncUpdateOrder ();: G- @" g4 _$ Z& D$ j- `
0 M0 t: Y# o2 V4 D7 T+ P
    try {: T0 @7 _, f6 \' |; ?
      modelActions.createActionTo$message
$ ^" T" {6 i7 Z  K        (heat, new Selector (heat.getClass (), "updateLattice", false));1 a7 c/ q1 [0 U
    } catch (Exception e) {
* z0 ^9 H* ~: J' N      System.err.println("Exception updateLattice: " + e.getMessage ());- t) H1 d, p7 [( S
    }8 ]* K' u: D2 ]; d7 J# P
        & x, }( E- B/ u+ i7 Y. j6 q3 ~4 ^
    // Then we create a schedule that executes the
2 b, _+ H: {3 B5 p" u/ J9 k    // modelActions. modelActions is an ActionGroup, by itself it
# e, L5 s' J" t* m7 u( G    // has no notion of time. In order to have it executed in
8 b6 U" T; w3 I: ]! u- ~    // time, we create a Schedule that says to use the# z# i9 W' Y- P3 z/ h$ Q
    // modelActions ActionGroup at particular times.  This
* S- L- E3 v( A    // schedule has a repeat interval of 1, it will loop every
5 Q1 o+ S, b' l8 n9 _    // time step.  The action is executed at time 0 relative to
) r7 j% d9 S( [0 s+ B! {2 ~    // the beginning of the loop.
4 i2 H; e# ?* O  |
: {) g6 `, M5 d) x* T    // This is a simple schedule, with only one action that is
1 }) c( N5 y/ F3 i0 Y* U4 B, U2 r    // just repeated every time. See jmousetrap for more
8 i" {# y+ D! L5 V    // complicated schedules.% q- d/ ^: P3 _- u( k! ^4 V6 q
  
  }' O! n. i% j    modelSchedule = new ScheduleImpl (getZone (), 1);6 R" m# P: m! t% q/ `; V
    modelSchedule.at$createAction (0, modelActions);) P3 M8 f, S, K! x1 a
        
6 \; O; m7 B; l1 o9 D    return this;! ^6 I2 Z& T( r- q# t8 O) c0 t, z
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-3-11 13:45 , Processed in 0.013340 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表