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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
6 i( B3 L* F. `) `5 ~7 B* ~
0 @/ m" s& R+ C6 z( B+ k( r public Object buildActions () {) p% G9 `# n/ p5 \( Z1 H
    super.buildActions();$ [- {% ~8 }, ^& `  L
    9 z9 @4 z& e3 @' o' Q
    // Create the list of simulation actions. We put these in
/ R  ]% T5 M# m$ _( g5 |. I    // an action group, because we want these actions to be
7 G* Y8 Z8 J5 L- ]' ~9 t1 u  w    // executed in a specific order, but these steps should! }& a/ P+ M4 A6 O; t
    // take no (simulated) time. The M(foo) means "The message
  a! l# X) s8 |$ E% m    // called <foo>". You can send a message To a particular
5 P1 N: U6 l  m    // object, or ForEach object in a collection.
  \/ v% [5 V+ {+ Z% G' x        9 Y, f/ x1 e% o& L3 x
    // Note we update the heatspace in two phases: first run4 S- z8 m8 \) L& F, N) q% z
    // diffusion, then run "updateWorld" to actually enact the
" `; t/ y9 i% ?8 E9 F4 B7 L    // changes the heatbugs have made. The ordering here is" e5 [% f( W: W8 E# P! B: x( N. m( @
    // significant!7 i( K3 T8 J9 O/ T* }, P) y
        + h2 l. J$ j  q% H5 U
    // Note also, that with the additional
7 R3 Z/ g/ |$ L( O" p( ?    // `randomizeHeatbugUpdateOrder' Boolean flag we can" j. U  F' o: q% @, Y
    // randomize the order in which the bugs actually run
, {- X% X; a! A3 Y3 r, q1 i    // their step rule.  This has the effect of removing any
. D% L8 }2 B4 y+ l9 F    // systematic bias in the iteration throught the heatbug: g9 d, g  D4 `) [2 k! I
    // list from timestep to timestep
6 ~! c% W3 w# H* G$ g- M% E' A        ; l* h1 u4 \5 `" f9 \$ t0 Q
    // By default, all `createActionForEach' modelActions have
" W  w" m# w2 \6 r: p    // a default order of `Sequential', which means that the
# q, d0 z8 h. p) ]# A3 i, r    // order of iteration through the `heatbugList' will be& g) _- i( Y8 Z* W& R! N
    // identical (assuming the list order is not changed) o/ @- F$ [8 O) s
    // indirectly by some other process).2 r* W% D) L6 S/ v
   
( p9 q  V4 p; {7 R5 m    modelActions = new ActionGroupImpl (getZone ());# A' C4 I' ?, I6 z# z( S
1 C: e& F, X6 g" `9 t
    try {
: q& W$ d8 T! f8 l      modelActions.createActionTo$message3 w% H/ U! ~( _) `( ~  |+ F, c
        (heat, new Selector (heat.getClass (), "stepRule", false));% j, h/ B! d6 ~7 L
    } catch (Exception e) {1 z: S5 Q% Y! r' Q
      System.err.println ("Exception stepRule: " + e.getMessage ());! m" k1 D: c! B6 f
    }
& B( G0 r" a  M0 x" N% T4 z
  ]2 Z* k( i$ C0 W4 a    try {$ W9 ^+ P0 O% ^/ A$ b8 L( l
      Heatbug proto = (Heatbug) heatbugList.get (0);
/ |5 p" _+ A3 j* J9 R* X3 _      Selector sel =
9 O' b* l' f) w: V' e- h4 x3 \6 ~        new Selector (proto.getClass (), "heatbugStep", false);. H3 L2 r# A) v  `1 d
      actionForEach =& L0 o6 E9 w( _6 D& h- b0 x& b" t
        modelActions.createFActionForEachHomogeneous$call
. |  ]2 a9 \7 }* z        (heatbugList,; y# X' y+ \6 f9 M8 {9 N1 C3 a0 d
         new FCallImpl (this, proto, sel,
9 N! y5 j% K5 k                        new FArgumentsImpl (this, sel)));) A1 e" J1 X  p4 J# f, S6 D
    } catch (Exception e) {+ U; v& t9 [2 p0 a
      e.printStackTrace (System.err);  e# Y/ @) E4 U! j) q1 j7 G2 R- L0 I
    }9 e4 D, T) y9 V- `! K
   
( O1 b& i& p. K( \# q9 \# k    syncUpdateOrder ();
; X6 d$ G! E( h% _
0 F' C/ Q8 K& Q    try {( H' W8 S% w% q, h
      modelActions.createActionTo$message 8 a& ?0 X7 j9 u+ z! X. J& R
        (heat, new Selector (heat.getClass (), "updateLattice", false));+ ^5 N/ T( u) V6 X
    } catch (Exception e) {
/ x( w+ V5 n( ~" c* K      System.err.println("Exception updateLattice: " + e.getMessage ());2 s) @0 R; H7 L6 w
    }
' k- ]) `  T! T        4 l" O8 y+ w" X* Y# s
    // Then we create a schedule that executes the
; t& D1 K& t% t4 u# C/ h    // modelActions. modelActions is an ActionGroup, by itself it" a1 _# ?' N$ ~' z* j. L+ e3 @' \; J7 M
    // has no notion of time. In order to have it executed in
( q+ j7 b9 N6 I- q    // time, we create a Schedule that says to use the
0 K* W" @3 J$ ~7 Q  B2 {    // modelActions ActionGroup at particular times.  This& @" Q. @( t" f& G+ S
    // schedule has a repeat interval of 1, it will loop every
' B& `5 R4 ]. q/ Q! j- M* Z) b    // time step.  The action is executed at time 0 relative to2 X* o: Y1 }, \% `
    // the beginning of the loop.5 b% F& c6 y. a; a/ l; U

+ |! G8 N# O+ u- P: n4 B    // This is a simple schedule, with only one action that is& I5 ]) p- _% p' k
    // just repeated every time. See jmousetrap for more  y) u7 a: L( z. h7 T5 h- }
    // complicated schedules.. C9 V2 U9 l- `
  / b) T5 _8 R( @/ V4 A6 M# Q% A
    modelSchedule = new ScheduleImpl (getZone (), 1);: w% S; u4 _' g, |/ p0 ~2 J4 b
    modelSchedule.at$createAction (0, modelActions);
( m$ w" f- g$ {/ L, [- h# r3 W        ( Y) C" _1 ^" I+ n
    return this;
% [4 w. M+ W; `; F, S  }
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