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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:, w& `1 a; Q% y

- K, y7 \5 E5 X; t) s3 j public Object buildActions () {0 s6 S" V* j/ E1 c
    super.buildActions();
$ [! W% x7 ^# U& I) x    3 U' u; B; |- |4 W
    // Create the list of simulation actions. We put these in
6 E! I% @* f3 O6 v0 s    // an action group, because we want these actions to be$ l: v- p/ s) C) Z! {
    // executed in a specific order, but these steps should* m* c6 @# ]) r- L) Q( u: `3 y; H
    // take no (simulated) time. The M(foo) means "The message
7 M4 i# B2 D0 |& i" O6 v! i    // called <foo>". You can send a message To a particular5 C0 i: ^' [( Z2 p5 U- I
    // object, or ForEach object in a collection.
- f5 |- m- V  {' f4 z' ]  I        
3 P) l$ o; X0 D! D$ c    // Note we update the heatspace in two phases: first run
' ]* g1 e- `* d- `- M    // diffusion, then run "updateWorld" to actually enact the4 O9 E/ D) v; V! U
    // changes the heatbugs have made. The ordering here is# A2 j! [( b9 a9 j
    // significant!
6 o6 B9 i3 @! L# y0 a        
/ A0 G6 F1 s( s# s/ H8 t2 j2 _    // Note also, that with the additional9 A/ U( s: h# ?) s) D# n& r
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
0 b% H) C9 X6 X    // randomize the order in which the bugs actually run7 J9 U8 t. d& ]- c8 s; Y4 M0 Y
    // their step rule.  This has the effect of removing any7 y* s& H  t! N/ k% W) D
    // systematic bias in the iteration throught the heatbug" J8 E$ v; Z5 C
    // list from timestep to timestep
/ T/ |5 _6 n& Q1 i! @$ p8 i        0 f) |( Z; j% e# {' v
    // By default, all `createActionForEach' modelActions have) q9 H3 l9 R/ N$ H* F
    // a default order of `Sequential', which means that the3 A# @# z- G; q& P, B
    // order of iteration through the `heatbugList' will be
4 _+ R! x" |1 ^$ |. G    // identical (assuming the list order is not changed
: w; a9 {8 d, w' d: a4 @3 s    // indirectly by some other process).
% v. v/ n& j5 Z; v: D1 P    % E+ E; _6 |! C( z
    modelActions = new ActionGroupImpl (getZone ());& `+ X6 W& n2 G  |5 v
  M+ L9 [( ?6 y3 b. Z  ^) W
    try {
8 b- T1 e5 y$ g, j7 x      modelActions.createActionTo$message
: t$ K! U7 U4 W; T$ v: l. X        (heat, new Selector (heat.getClass (), "stepRule", false));
# F% A1 ~! C9 E& ]( L    } catch (Exception e) {0 u% F. T$ x3 `  j
      System.err.println ("Exception stepRule: " + e.getMessage ());
2 S  [( @- H( N; I. _* S    }
% V6 v: ~, x& e. v( x: v0 s  x1 L4 N# ]4 R; k- I$ ]9 u6 Z5 b. L
    try {
# {; H; f, k9 L8 h, ]2 l2 {8 h      Heatbug proto = (Heatbug) heatbugList.get (0);
/ T4 \, m0 l2 n- T# g( \+ s      Selector sel = $ O' Q5 ^$ H/ ~; k: E
        new Selector (proto.getClass (), "heatbugStep", false);& @; q2 a# g# Z1 S* D6 Q" M
      actionForEach =
$ H* y+ Y! O) C+ L" l) I- a4 X        modelActions.createFActionForEachHomogeneous$call
6 ?7 U  m5 |8 p' `  x        (heatbugList,
4 d2 e9 e% K( \) ?         new FCallImpl (this, proto, sel,( U: `, W+ A1 [
                        new FArgumentsImpl (this, sel)));) J, v0 {$ h8 N
    } catch (Exception e) {- W* A- s1 A5 f% |6 E0 F' c
      e.printStackTrace (System.err);
2 ~& w1 ^2 _! y    }5 G3 g. T, v) B+ }  R
    1 ]' f, U2 U# G" Q. \7 m
    syncUpdateOrder ();6 @; Y0 q1 `# X& x  N' x
, d3 G& U1 f) C4 I' Y+ n
    try {6 ?* Z! r( x7 `5 V+ F' l# D
      modelActions.createActionTo$message % Y7 Y4 V0 C, b. r, I( A* {# A
        (heat, new Selector (heat.getClass (), "updateLattice", false));
0 m6 K( N" l$ X0 l5 H    } catch (Exception e) {/ p, a9 {8 w# x8 q/ h6 ^7 g
      System.err.println("Exception updateLattice: " + e.getMessage ());
, ^* D8 @& `) o3 x8 V% J    }3 @" u  q& N5 j( s! E% x
        
1 ~2 X$ i  J# {    // Then we create a schedule that executes the/ P' i; T, B; Y& |* X8 U+ a
    // modelActions. modelActions is an ActionGroup, by itself it
4 ~- |( W" m5 z    // has no notion of time. In order to have it executed in" z/ Z4 i9 z& k6 b5 h& n2 H, z
    // time, we create a Schedule that says to use the
1 G# U0 W- u8 Z7 o. F    // modelActions ActionGroup at particular times.  This
9 k+ y) x0 C" z  n% S8 K$ U    // schedule has a repeat interval of 1, it will loop every
1 H2 t- ?9 A2 ]0 V5 ]7 U8 S    // time step.  The action is executed at time 0 relative to. p+ b  k" C0 k2 i% r
    // the beginning of the loop.
: ?- p2 v& b0 c* F1 H
7 T; s" f. A) g% R7 l, U! n    // This is a simple schedule, with only one action that is5 `' x7 \6 f: c( v6 X1 ?1 X. R4 p' I
    // just repeated every time. See jmousetrap for more
2 f9 L, e' X) A3 a; K4 Z3 \    // complicated schedules.2 q( a# G# O3 ?7 V. x, @
  
0 I. b* N  |  x* I' N' h$ O, s    modelSchedule = new ScheduleImpl (getZone (), 1);
' [& X3 ]) B, K* F" ?    modelSchedule.at$createAction (0, modelActions);
! d4 Z$ v# f1 k* C! F8 K        8 g! P( Q# E  P- b0 o6 k7 M
    return this;+ g' {+ o" O  D& m) m1 P, w, P
  }
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