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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:7 C  X4 F  f! E) f' q

$ j: s  ^' i/ \9 o% X public Object buildActions () {
  e% j" s2 d7 \) P    super.buildActions();
" T' J' c7 Y* x9 j   
) P- d0 ?- Z0 B- X    // Create the list of simulation actions. We put these in. Y& F. j  E; r' |6 U4 l6 S" @
    // an action group, because we want these actions to be
% K8 Y" k$ `3 z  w! t) X/ `    // executed in a specific order, but these steps should  l/ X+ J" Y) i' c& U; H7 V$ ^
    // take no (simulated) time. The M(foo) means "The message
1 c, F: W6 n* W* x; e) q. v2 J    // called <foo>". You can send a message To a particular2 O, A. ~% m1 K
    // object, or ForEach object in a collection.' b% F: X( [" m
        
5 K& w# E. m9 y+ ^- H3 a* a* }    // Note we update the heatspace in two phases: first run
6 \) M3 ^. C" F2 \, z    // diffusion, then run "updateWorld" to actually enact the
8 X- ]- d! B8 V0 n( X* ^& Z    // changes the heatbugs have made. The ordering here is
' T! {& S/ F  N2 P# w% p    // significant!
. \: u# a# P, n( U+ `        
( F/ f4 |' k, e6 B6 m    // Note also, that with the additional
& i5 q4 p( ], [8 c: @( c    // `randomizeHeatbugUpdateOrder' Boolean flag we can
# c) y6 @, S% s# z/ V$ S8 G    // randomize the order in which the bugs actually run
  O7 ^1 ^! L: P) E* _- r    // their step rule.  This has the effect of removing any
( ^; z8 n5 [) _1 ?    // systematic bias in the iteration throught the heatbug
1 C6 A  Z) b6 C  Y! b/ `8 D    // list from timestep to timestep
% k/ y% c' k) y4 s! j        ( z6 s5 `+ b" Q( i/ \! B
    // By default, all `createActionForEach' modelActions have+ O- h/ O: Y& V. j; W3 D0 N
    // a default order of `Sequential', which means that the% X: f- ~1 z. M
    // order of iteration through the `heatbugList' will be
- [0 a7 i% J8 r# u    // identical (assuming the list order is not changed8 r! ^, S7 T7 U( n: G5 M5 I
    // indirectly by some other process).3 t. ^& S" q( D; z
   
! h9 V4 D2 \- K$ h' @& Y/ b" _. S    modelActions = new ActionGroupImpl (getZone ());
4 j# l3 E1 S% _+ d7 U4 h
, Z# @0 `; X6 i. M7 P    try {  o! F' n0 z8 a# i# H# h
      modelActions.createActionTo$message
1 p2 j4 N% @4 x/ D4 a6 P        (heat, new Selector (heat.getClass (), "stepRule", false));
" X" Y0 X" R3 Z( t( |    } catch (Exception e) {4 k$ b6 j$ u$ f( d" R" Z! u
      System.err.println ("Exception stepRule: " + e.getMessage ());, ^( z2 X7 o% H; a1 c
    }; O8 k: P7 R8 i4 j( E4 C% K" }
" y1 t- r$ {9 q1 x& i) O2 H! U
    try {/ l; l  Q. e" T
      Heatbug proto = (Heatbug) heatbugList.get (0);; I9 [& w" C, J4 g' J; g/ K% g
      Selector sel = * t; s. x" }; z8 S: l
        new Selector (proto.getClass (), "heatbugStep", false);
/ O2 l: ?9 a6 M: |/ Y      actionForEach =
" b' V: }- W6 x# W        modelActions.createFActionForEachHomogeneous$call7 c) r6 l; Y8 R5 l
        (heatbugList,
* |: m  N6 U1 I9 I  p. J# m         new FCallImpl (this, proto, sel,
: p- A/ c7 l! l4 @& m7 `                        new FArgumentsImpl (this, sel)));
9 A( k$ o; d/ D- K- a    } catch (Exception e) {* g% z" R! r) k
      e.printStackTrace (System.err);
7 l' I* A( \( A* p, l    }( S9 W7 V  A7 d/ v, I
    , @. R+ M4 a, x* N) K  L- E- F
    syncUpdateOrder ();
- e  ~0 e6 Q0 @: `5 h7 \, ~1 j# d& I
    try {  o/ ?' p/ Q4 t
      modelActions.createActionTo$message
$ m+ x6 o5 g* a6 ?7 N        (heat, new Selector (heat.getClass (), "updateLattice", false));6 v- V- X& E% ^2 q
    } catch (Exception e) {, [7 v2 j2 G0 W5 q, p) {5 `
      System.err.println("Exception updateLattice: " + e.getMessage ());9 G9 z9 s$ W8 ~! w5 w
    }
; u2 b* V. }( G- b6 e: c' X* Q        
& V5 k4 k# x/ y! S/ C: R* w    // Then we create a schedule that executes the8 h% B2 f6 m, o  S" x* i
    // modelActions. modelActions is an ActionGroup, by itself it
. e& E9 Q1 G5 X0 d0 F' m, Y6 r    // has no notion of time. In order to have it executed in
; b) i/ ?( ^: z. Y: W, B    // time, we create a Schedule that says to use the# ]: k' e, S6 Y" @* j4 u2 G
    // modelActions ActionGroup at particular times.  This" X! @/ F* c+ H# J" [! J; E8 }9 e! \
    // schedule has a repeat interval of 1, it will loop every/ N8 j' k8 g- C+ i; b8 C* `
    // time step.  The action is executed at time 0 relative to
& i! u& O/ |; v9 S+ C6 R    // the beginning of the loop.
! T4 q5 z% \# D; r/ x% u( p: J! ~- F3 p4 Y
    // This is a simple schedule, with only one action that is
5 [, u0 Q  W( ^1 H    // just repeated every time. See jmousetrap for more# O# f2 u* y2 @5 R" O0 d: U% r
    // complicated schedules.
. b3 ~% s1 |- `- n. G  1 F. @! L, r+ g  x
    modelSchedule = new ScheduleImpl (getZone (), 1);
8 T. Y3 s! e! i! B2 o, v    modelSchedule.at$createAction (0, modelActions);
' p0 U5 j: I0 |% [$ M8 A0 }        
( j; f4 |. x3 Q* z+ ]    return this;
$ O' W9 z/ C! e. k% X9 Q  }
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