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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
- m4 l' H" L- H  E
% B9 Y; L3 s" J public Object buildActions () {
5 K0 Y7 V6 C+ X1 w2 f5 T# }8 j    super.buildActions();
* O9 F1 K2 v. \/ ]4 _/ y3 B    ) n# M* \9 ~* J" K
    // Create the list of simulation actions. We put these in
' ?0 {2 x, D3 \) w5 ~, `    // an action group, because we want these actions to be: U! J6 y7 n5 t6 N& t; c, ~
    // executed in a specific order, but these steps should! n" O: X- A7 s# G
    // take no (simulated) time. The M(foo) means "The message
/ V' m. k4 n3 [! U    // called <foo>". You can send a message To a particular
2 A% I) w4 _. @  e    // object, or ForEach object in a collection.
0 z5 ~! j4 {& K! C8 f        3 o, Z1 D6 V" U( k2 T
    // Note we update the heatspace in two phases: first run6 l4 w, I8 o7 q& }
    // diffusion, then run "updateWorld" to actually enact the" d2 e  E- y. ], R8 l
    // changes the heatbugs have made. The ordering here is
- _9 ^$ F: c0 i$ y$ _5 k$ S: ~    // significant!
6 h. y* e2 t# W' b4 w        * t" F5 G. {4 m, G- G8 a2 j. a% U% o
    // Note also, that with the additional% g! V* }# B: j/ I8 P3 r# w
    // `randomizeHeatbugUpdateOrder' Boolean flag we can" [; j6 z; _5 h% n$ e& Y$ ]+ S& p" {9 K
    // randomize the order in which the bugs actually run
1 B4 t* [- C, H3 D    // their step rule.  This has the effect of removing any3 n5 |. X, b7 s8 [3 H+ l4 ^
    // systematic bias in the iteration throught the heatbug
# ~) T. C) t) W' _    // list from timestep to timestep
% G" D2 D$ P  E* A+ ^        
% ^6 U3 t# s7 m* }    // By default, all `createActionForEach' modelActions have
) V9 b8 ~  d: `1 D    // a default order of `Sequential', which means that the8 Z$ X1 c1 D) @, A+ o7 w
    // order of iteration through the `heatbugList' will be
+ y/ a; Q- a  u/ x6 o, d7 U    // identical (assuming the list order is not changed+ \! E$ M+ c. n  k/ Y
    // indirectly by some other process).
0 l3 N/ G* i& S- N9 y' v; g! I   
6 Y+ n1 @! ?  X) {    modelActions = new ActionGroupImpl (getZone ());# j9 h" r' w+ t. u5 w

! O7 S6 i4 V/ ~0 P7 x    try {- _. m6 j" X6 G, A& C( r- i
      modelActions.createActionTo$message
" [% F8 }( N$ ^2 [. l        (heat, new Selector (heat.getClass (), "stepRule", false));& X% O4 e, M9 O4 B& n' u) B
    } catch (Exception e) {
- `6 m- D3 f. b9 v7 \& C      System.err.println ("Exception stepRule: " + e.getMessage ());! o& b$ p5 U6 H7 b# j7 c/ Y4 h5 X
    }
* z* o7 p3 z5 m$ B& u2 s
+ V! V8 }& c" K    try {
' g! E$ N2 @; s5 w      Heatbug proto = (Heatbug) heatbugList.get (0);! D2 B: Z2 r0 @! C! t3 s
      Selector sel =
) ]/ M5 }' R, p, Q" C( z2 v        new Selector (proto.getClass (), "heatbugStep", false);
7 U; @  ~1 q! `( W: M: Z      actionForEach =8 Q9 Z6 p5 _- l, |. @! }. w0 m
        modelActions.createFActionForEachHomogeneous$call& ]3 N1 ]) Y2 X( ]: x9 f
        (heatbugList," _8 V+ i& a4 H* y8 I
         new FCallImpl (this, proto, sel,  e* }0 E2 F( l# n4 O) J5 i: ^. A
                        new FArgumentsImpl (this, sel)));
& X- }* A: t3 T& A4 Y    } catch (Exception e) {
, I/ P/ g/ G, f      e.printStackTrace (System.err);
$ z+ b' X7 v9 c+ o, V    }
, K+ A0 C. O' R   
* U( o$ T5 I4 h3 A( H    syncUpdateOrder ();
: q" l- v8 L$ @1 J
& l4 d  X2 {& q  a4 d* r  r    try {
( w/ V: T5 B" U- p( Z      modelActions.createActionTo$message
, m, s4 `2 O/ D+ c( f. \        (heat, new Selector (heat.getClass (), "updateLattice", false));
) W1 V, ^9 `; e( M; k    } catch (Exception e) {9 ^! a- b4 k. U* S, Q! L3 ?
      System.err.println("Exception updateLattice: " + e.getMessage ());
7 g" i& u  n& k2 I" K    }
" Q% `/ g5 [7 L* l        
, w) y/ t/ R% q  ~3 S9 ^4 K7 m    // Then we create a schedule that executes the( [4 R$ k( p4 O& r
    // modelActions. modelActions is an ActionGroup, by itself it
+ I7 z( K6 O8 H" W! p2 a4 N6 M% @- m    // has no notion of time. In order to have it executed in& Y& }* H# s; G% [+ f
    // time, we create a Schedule that says to use the  Y" i% k4 z/ Q" ]
    // modelActions ActionGroup at particular times.  This, [( ^9 Y2 m/ a% Q
    // schedule has a repeat interval of 1, it will loop every: ^7 F/ p, k+ s
    // time step.  The action is executed at time 0 relative to
) ^0 `( y# `0 M& f9 n! n    // the beginning of the loop.
6 M' U5 K3 M0 s: e, Z# m$ P2 r, z
    // This is a simple schedule, with only one action that is
- h" `; M1 A4 O2 p% P2 C9 i( Q2 g    // just repeated every time. See jmousetrap for more! u7 @7 Z* P: F- f- S# @
    // complicated schedules.& z4 O* R3 a7 _5 o
  
+ R1 m% @+ p5 ~, X) R    modelSchedule = new ScheduleImpl (getZone (), 1);
& V; e3 ]) e; {    modelSchedule.at$createAction (0, modelActions);4 o- ~- t* ?4 h" w# B# ?
        9 y" M$ G9 p( i/ X
    return this;" J$ z6 n% R' e7 h
  }
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