设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 12562|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
- f) ^) Y  J* O- B! `% g
' j7 r" Y4 k7 H+ A$ J' n- { public Object buildActions () {" D8 s6 r& v$ p0 y$ H+ R
    super.buildActions();# u0 b! b2 ^/ K4 J; O* ]. u- C
   
( W8 P6 b+ j1 [6 `3 R% l/ |    // Create the list of simulation actions. We put these in
4 n3 C" c  q' Z    // an action group, because we want these actions to be
2 ?# E* k! O1 k9 F    // executed in a specific order, but these steps should
6 G8 j9 S* u* w* |6 _: i    // take no (simulated) time. The M(foo) means "The message
7 D0 G8 x* g5 Y" \    // called <foo>". You can send a message To a particular
; O. {( p  X7 D+ k- r# J    // object, or ForEach object in a collection.1 e2 `9 A8 V6 ?4 n, v. p4 ]
        " V" @* B, W; j" D! k  ?
    // Note we update the heatspace in two phases: first run
0 D6 ^; S% m& m9 s) D5 J+ e    // diffusion, then run "updateWorld" to actually enact the5 g+ O; X/ m7 H7 _2 g% k+ ]1 a  s
    // changes the heatbugs have made. The ordering here is
7 s6 A! `& O  y# x' C, X    // significant!
& M" F: ]6 Z8 `& L        . ~: f% u$ l0 l5 ~* w6 z; R
    // Note also, that with the additional
) G* V1 P1 A7 @7 z+ k5 A! G    // `randomizeHeatbugUpdateOrder' Boolean flag we can
  K1 _6 y& [: `) p4 V7 p* m    // randomize the order in which the bugs actually run
' m7 Y. N+ y7 _2 z  J    // their step rule.  This has the effect of removing any
/ k5 Z. J% J" f    // systematic bias in the iteration throught the heatbug
# k9 M* H. u+ M$ d0 G    // list from timestep to timestep& z+ o* b) m- n" |
        
5 F/ p4 W, H3 z$ j5 ]5 r    // By default, all `createActionForEach' modelActions have
0 J! W2 k9 ~) W. w* [    // a default order of `Sequential', which means that the
5 P, ~# T/ f  \    // order of iteration through the `heatbugList' will be1 Z( X* e( W2 B! D
    // identical (assuming the list order is not changed7 i6 b2 U2 h2 {1 s, t# W9 M' d( ]
    // indirectly by some other process).
7 V6 ?2 k8 ~; @4 m  t: T4 T. V( H$ r   
: Q$ B2 y7 t. \  v! x    modelActions = new ActionGroupImpl (getZone ());
# q% M0 U6 ?! U. k( W% ^% a  ]
, r0 D- v* i* G. U1 R' k3 S    try {
) x' c1 I! k8 X7 r* V3 e4 n" ^# r3 T      modelActions.createActionTo$message
+ d1 R, k' z- m* P4 K6 h' |        (heat, new Selector (heat.getClass (), "stepRule", false));
/ L' ?& U' _- c9 Y    } catch (Exception e) {3 p) Z8 ], }5 S& y; R& P% `
      System.err.println ("Exception stepRule: " + e.getMessage ());- ~" p; [; L' V: n
    }4 t- m8 D4 u0 m; s6 X  \
$ \$ {8 N* z* t
    try {
, B; h1 d- L6 U  ?- @# m, M      Heatbug proto = (Heatbug) heatbugList.get (0);; R! ^. L% u/ h
      Selector sel = 2 Y+ N" Z/ K" O/ P
        new Selector (proto.getClass (), "heatbugStep", false);
! d/ J+ x  a( T( L0 \  R      actionForEach =
. d2 A- \1 m: l% t# M" ^        modelActions.createFActionForEachHomogeneous$call1 b* F3 f, E6 P* v% v
        (heatbugList,
7 k, c1 ^. }2 i0 P         new FCallImpl (this, proto, sel,
9 [: o8 V. n, V( G: J( R                        new FArgumentsImpl (this, sel)));7 D5 s+ ^( J7 [4 J
    } catch (Exception e) {
) D5 V1 f/ K) O0 A      e.printStackTrace (System.err);. Y0 W) t& v- i/ F5 R- x
    }
2 ?3 P% y7 c; ~4 T    ! R# S; V9 l: j
    syncUpdateOrder ();
6 w2 Q7 `5 T0 M! Q! W3 M
  `# ?- N% Z+ j    try {
* {6 F* e* L0 M; J1 ^! L      modelActions.createActionTo$message 0 G; T; ~  P8 P$ n1 `+ A. t
        (heat, new Selector (heat.getClass (), "updateLattice", false));% h0 `" {) F5 a$ a
    } catch (Exception e) {: t5 b' [+ c  d3 q6 p4 K$ w1 K1 h, D
      System.err.println("Exception updateLattice: " + e.getMessage ());
% F) [. q4 B5 U& A    }$ }7 H$ ]: S/ X
        
! `: S5 b- E- z5 D1 O9 x* ]* D4 f6 d    // Then we create a schedule that executes the
# k4 T# a7 h/ ]4 O" D' s; V1 i$ p    // modelActions. modelActions is an ActionGroup, by itself it
8 r; B( u+ t$ \9 V3 P    // has no notion of time. In order to have it executed in
6 h% k( i$ y  ?$ ]    // time, we create a Schedule that says to use the
7 `0 M& v# I' W  h* K: o1 t- n5 ^    // modelActions ActionGroup at particular times.  This. V7 _% m  @  d2 R5 u' J: {
    // schedule has a repeat interval of 1, it will loop every
! ^3 w/ u: t; _0 y# f7 u5 C* a    // time step.  The action is executed at time 0 relative to
5 e" e1 o  s+ U# ~. g    // the beginning of the loop.1 H5 Z. X, N& ~9 P, A, o. y

3 B! U& i. Y1 A3 C4 S; G/ g    // This is a simple schedule, with only one action that is
* a& j- h2 A" j5 m1 e; t6 z    // just repeated every time. See jmousetrap for more0 R2 u6 _  b) Q8 P  {
    // complicated schedules.0 N& q& ]% M  v
  
/ \% k( M2 R- c2 s+ f    modelSchedule = new ScheduleImpl (getZone (), 1);
" N9 [# u' [/ P6 T! q1 @7 C5 @$ f    modelSchedule.at$createAction (0, modelActions);
$ y. X9 C5 R" j5 |        
9 U8 [, o& p, c    return this;
! @5 }- b: K* A/ U* O7 V  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2026-9-8 17:07 , Processed in 0.015695 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表