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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:* C' J$ X3 `" N

2 {, w. R/ E% U- y. { public Object buildActions () {* S2 f$ f/ U' \' H+ K
    super.buildActions();; ~2 l, Z1 o  D: i9 b% ^  J
   
' [0 L/ n% c5 x' Z    // Create the list of simulation actions. We put these in" I. N: e9 q  k5 B0 ], P
    // an action group, because we want these actions to be
$ Q! O5 v( p0 p8 r4 B& U3 P9 o" _    // executed in a specific order, but these steps should0 j) f& C, G5 ?; e0 h# y# o
    // take no (simulated) time. The M(foo) means "The message) P3 Z0 E" j* u+ l* A+ {0 I
    // called <foo>". You can send a message To a particular9 [8 Q5 c+ Y6 _  q7 P4 D( V* j
    // object, or ForEach object in a collection.
/ A  p" }  ^4 y2 ^1 A2 P        ( u" L+ S/ s7 C. o
    // Note we update the heatspace in two phases: first run
& V) f0 P$ s9 g    // diffusion, then run "updateWorld" to actually enact the' B, H/ U  o( Q7 `* P$ q- f
    // changes the heatbugs have made. The ordering here is$ J8 {. z  W! H* t0 X
    // significant!; ^$ @. h+ Y7 m- |& {
        & F# J$ `; i: o4 u
    // Note also, that with the additional
& E6 ?& x8 m0 m0 }9 u    // `randomizeHeatbugUpdateOrder' Boolean flag we can
" Q2 L' T4 ~6 L$ C* b3 s    // randomize the order in which the bugs actually run
+ g# i- i+ D  c' ?6 V" ?    // their step rule.  This has the effect of removing any! Z9 w- I# Q3 b+ C
    // systematic bias in the iteration throught the heatbug% L) @4 Z$ R, {" Q) E
    // list from timestep to timestep
  W( _( z' z- f: v% B4 E# [6 a% x        
4 ?1 Z, q; [/ x) }! X- r    // By default, all `createActionForEach' modelActions have: g$ |( w! M$ w$ w- C5 i2 l9 |
    // a default order of `Sequential', which means that the# h% J* C, o- V: h4 C
    // order of iteration through the `heatbugList' will be8 O$ s! `! f  P. ?
    // identical (assuming the list order is not changed! b- l1 j+ P- B% u
    // indirectly by some other process).5 t% k1 h5 W( ^9 }( H5 F
      [, o3 W, h. r. s& @
    modelActions = new ActionGroupImpl (getZone ());" D9 d8 _- @5 S+ U! s: x  r, L& C
! l/ M* K- l5 q) l1 D$ u2 W+ ]
    try {
- l0 f6 h. J% |" r      modelActions.createActionTo$message  a8 V) X) u& u& C
        (heat, new Selector (heat.getClass (), "stepRule", false));3 Z& j) F/ u$ i% q
    } catch (Exception e) {7 L- P% H$ g# K. B! U  O: I
      System.err.println ("Exception stepRule: " + e.getMessage ());8 G5 @+ a) ?$ O+ z8 Y5 V( F+ W
    }
( \2 U6 l9 w( L% E
, B0 k& Y. s* g7 y! Y: L    try {. n3 P1 ?, i5 T! f  k; E
      Heatbug proto = (Heatbug) heatbugList.get (0);
  H% T: G7 h+ {2 J      Selector sel = 6 Y+ t# j: z8 C, U8 g
        new Selector (proto.getClass (), "heatbugStep", false);8 \+ p$ Q0 c9 f
      actionForEach =
! L% L( Q. X; q1 H/ L6 N% Q) k) x        modelActions.createFActionForEachHomogeneous$call$ @4 z* k1 u9 A* ^
        (heatbugList,
8 K' m2 ~, T' p. G4 Z9 _         new FCallImpl (this, proto, sel,
7 g) h& F! h, i. U5 v                        new FArgumentsImpl (this, sel)));* c9 B* y$ y; v$ a, z7 R
    } catch (Exception e) {
7 Q. R) \  B- j: E- @9 w+ M; t, {      e.printStackTrace (System.err);
6 {" o' R1 L5 e9 V4 I  A! _9 G3 o    }! Z7 T' a# y; _3 _5 e* w7 p7 C
    ) q( v; H8 ~. v! I9 p
    syncUpdateOrder ();
; E' Y' [) J0 x+ L  A# c7 u1 n- D8 H7 |4 j- t; ?. \" x
    try {
% a: @/ w: _# Y; R      modelActions.createActionTo$message , {8 P0 ^9 R+ s+ o9 Z2 F  \
        (heat, new Selector (heat.getClass (), "updateLattice", false));4 a0 X; a) W; Q* O
    } catch (Exception e) {
% q1 @  V  m4 ^4 c, t      System.err.println("Exception updateLattice: " + e.getMessage ());
) F, S) s1 ~" Z7 u2 ]7 J    }
: F8 N8 I0 R5 [3 [        % `. e( c9 {7 i2 C% a
    // Then we create a schedule that executes the
$ u  p$ e# {; i% ~, f" b    // modelActions. modelActions is an ActionGroup, by itself it5 M$ X" N, w2 b- F1 v% G
    // has no notion of time. In order to have it executed in
# `" y/ m1 B3 f5 Z. J) U" Y+ X    // time, we create a Schedule that says to use the1 e$ `7 e, S  w9 S! H
    // modelActions ActionGroup at particular times.  This
4 b8 w9 _& u+ }) r: S6 n- F& t    // schedule has a repeat interval of 1, it will loop every1 y$ X6 r& ?$ r& M% U
    // time step.  The action is executed at time 0 relative to
; V, t( S1 t1 Q0 B  y0 `% y    // the beginning of the loop.! D, W+ m% _6 O8 I+ M' p* I
1 {/ ]8 {2 ^  U  w
    // This is a simple schedule, with only one action that is
( w4 r0 G4 P4 R8 l/ E1 S    // just repeated every time. See jmousetrap for more
6 Y+ L4 o! @+ p) }6 j    // complicated schedules.' R; g$ ?! `5 k3 }2 G; B
  
* }. A1 i( F* v1 Z0 L8 z    modelSchedule = new ScheduleImpl (getZone (), 1);  A) Y- _9 j$ e1 m1 G' N. K
    modelSchedule.at$createAction (0, modelActions);; u# D4 v8 q5 l; i) s- M
        * E7 `1 G2 s+ Y8 l0 Q
    return this;
4 l  P$ Q  r$ I0 N  }
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