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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
+ X6 l0 U' `/ G6 g* d3 J3 y* d3 \+ ]& S5 L8 O
public Object buildActions () {& M* f1 Q  n9 Q, ^+ B
    super.buildActions();5 ?# o/ S% k- L4 ^. M- x
   
* I) R1 V: U6 I: K2 `$ w# e    // Create the list of simulation actions. We put these in
. f- L% s* B5 L% @/ K; y" Y    // an action group, because we want these actions to be
& b& C9 }- T7 t7 y- ~0 z: b/ X% B    // executed in a specific order, but these steps should6 |, Y& C/ d9 |3 k
    // take no (simulated) time. The M(foo) means "The message
, @/ Z4 x8 T  Z5 x# l1 L    // called <foo>". You can send a message To a particular- x$ |5 k; ?3 \- m( V! B2 Q* S
    // object, or ForEach object in a collection.
  i. h+ m) H+ @8 V+ e6 k        * h9 b. R5 J/ Q+ n. {' @
    // Note we update the heatspace in two phases: first run9 g7 g% {' s, ]7 ~$ a+ N2 W
    // diffusion, then run "updateWorld" to actually enact the8 _! V9 N% N8 k  i7 \! E
    // changes the heatbugs have made. The ordering here is7 {1 V. K9 i7 z4 H' k0 Z
    // significant!
/ r3 n- K" s% i, R          j/ ~5 B9 ?4 y0 g% W) R1 D
    // Note also, that with the additional/ u; X# ?! T0 Y2 R4 |
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
+ T1 N+ H' b' g    // randomize the order in which the bugs actually run' \5 B* n) y8 q* i
    // their step rule.  This has the effect of removing any
- l3 ^- w" R0 E5 k# D: O    // systematic bias in the iteration throught the heatbug# Y, X, Y2 L8 |  E0 k
    // list from timestep to timestep( L+ r/ k" q( [2 I1 H: ?
        9 F' G4 S) z. z
    // By default, all `createActionForEach' modelActions have
; J# z# ~2 p/ X! s    // a default order of `Sequential', which means that the
+ x& K: k/ e& V2 X0 C    // order of iteration through the `heatbugList' will be
4 C; Q1 H8 W0 G% |3 a/ v    // identical (assuming the list order is not changed
: U# Q+ [( s! J3 C6 K. @    // indirectly by some other process).
& W- p- }/ ^1 M0 l    % h( h; a7 n. `
    modelActions = new ActionGroupImpl (getZone ());; z( ^% z! k2 N" _+ h
5 e  ]$ z: Y; L
    try {7 O$ u  B2 J2 i
      modelActions.createActionTo$message6 R4 w# p! t. k# T
        (heat, new Selector (heat.getClass (), "stepRule", false));" D  O$ |% w$ t$ ^
    } catch (Exception e) {
3 c' e) q, T; C7 M      System.err.println ("Exception stepRule: " + e.getMessage ());1 j, C# e0 ^" n
    }
3 X, ?! ?- w& [  D. z+ B7 n1 X
, t; Y# V# f2 D6 @    try {
" ?6 z- l7 P5 W/ R0 L      Heatbug proto = (Heatbug) heatbugList.get (0);
9 ~: U# z! }/ ^, _      Selector sel =
0 F9 l; B5 o! u) [/ N        new Selector (proto.getClass (), "heatbugStep", false);
) t* d# ~* I% k+ `) z5 h7 V      actionForEach =
" v* q! d$ _! x2 |        modelActions.createFActionForEachHomogeneous$call4 ~4 U. e: R& a6 a8 k) P
        (heatbugList,7 P% T9 t( }, R4 _' k
         new FCallImpl (this, proto, sel,
. R$ E# `8 G4 W# l# t) i5 v: v                        new FArgumentsImpl (this, sel)));
$ d3 L& n4 i. Y% C    } catch (Exception e) {
: ^7 p. q0 \* ?! D1 _      e.printStackTrace (System.err);
) F  ]9 U1 m; G2 ]& ?2 X( i    }! f8 d4 m  r5 n5 p, A0 ]( [% o
    : E4 ^1 H/ e) z( C
    syncUpdateOrder ();
1 k; X, t3 W; S4 ]9 k1 \4 x' p' p% M
    try {
& n% I( ]) ~  V      modelActions.createActionTo$message
) f, H4 O8 i, |# G        (heat, new Selector (heat.getClass (), "updateLattice", false));. H1 W# k5 w. f9 `! V
    } catch (Exception e) {
: X* K. Y  A& L0 W5 ]; w      System.err.println("Exception updateLattice: " + e.getMessage ());5 s5 Y8 g$ A# Y' `1 m
    }2 V9 B! F, _0 V# B: e$ N- {/ f
        . b8 G4 G- D/ Q* X
    // Then we create a schedule that executes the9 ?& N  L3 A7 M. u; |  g6 z
    // modelActions. modelActions is an ActionGroup, by itself it- Z! N. Z% |* [- U! F" f" I5 ]6 ~
    // has no notion of time. In order to have it executed in
7 k% }/ z9 C2 \  r, j    // time, we create a Schedule that says to use the
  K2 l+ X  m. D1 R# y; p    // modelActions ActionGroup at particular times.  This+ i/ ]. e1 O# Q
    // schedule has a repeat interval of 1, it will loop every
: L# F$ x3 [& E- A) Y    // time step.  The action is executed at time 0 relative to
* s8 ^( a. C1 n) l: T* w# K    // the beginning of the loop.
& P% ?$ v2 X1 z* A) v% u/ a; q7 s4 J
    // This is a simple schedule, with only one action that is
; q+ O' F7 v0 R5 u2 u& k0 C7 u    // just repeated every time. See jmousetrap for more* E0 K1 X' C  D& w8 _
    // complicated schedules., x1 M- @7 _5 `) M- G0 @6 W  r
  : W$ S9 D7 i3 }/ f/ Q3 r
    modelSchedule = new ScheduleImpl (getZone (), 1);
/ A) x, e8 T% Y& _( `2 k& y) R$ H( Z    modelSchedule.at$createAction (0, modelActions);9 h5 @8 H/ a1 @% j, ^
        . M) v! \: U- E$ d$ P/ C
    return this;& F: G, C; E' s, b& n1 g& s4 k
  }
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