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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
% T/ @. Q& }+ d2 I
+ r" {9 V3 q- ^# k# [2 D. e) d public Object buildActions () {  q; R, P) Z3 S7 }( F
    super.buildActions();$ y7 N) X2 s6 x( g, N
   
( ?  F" x6 s" m$ C    // Create the list of simulation actions. We put these in, _2 E: w+ V9 q1 ]/ m* e9 G
    // an action group, because we want these actions to be
2 ], e/ L  o1 o4 i+ U2 [0 U    // executed in a specific order, but these steps should+ R7 ~; @" R6 Z# U8 q& i1 a
    // take no (simulated) time. The M(foo) means "The message# Z% W9 F" Y6 i/ I9 ?  Y" l: j
    // called <foo>". You can send a message To a particular! X% Z  \/ F( i/ J. v  L, |& _- P
    // object, or ForEach object in a collection.* Q4 C! o1 ^: v! j' n: p
        
. e0 ]* l: U3 _) \    // Note we update the heatspace in two phases: first run
3 M; B% A5 v) V+ c    // diffusion, then run "updateWorld" to actually enact the/ {7 q8 T' Y' Q) H" m- Q
    // changes the heatbugs have made. The ordering here is$ {7 I4 `3 i6 U8 J9 K
    // significant!. U1 v8 s, C" E' Q$ ^
        , A7 N. {6 S/ h0 \9 \
    // Note also, that with the additional
' _( k' W3 r( d' U8 b9 }' d    // `randomizeHeatbugUpdateOrder' Boolean flag we can
2 c# o7 w  o- ~    // randomize the order in which the bugs actually run4 h7 [/ y, f$ c# Q6 Y! H- E5 q
    // their step rule.  This has the effect of removing any
& @+ ~  g0 m: u7 q    // systematic bias in the iteration throught the heatbug
) ~+ F! C  G: I    // list from timestep to timestep
# R  W: z) P1 u7 @        
: W# T/ d; D- {; l    // By default, all `createActionForEach' modelActions have; p3 V( e7 k& S$ x' ]8 P8 e9 X. \  D
    // a default order of `Sequential', which means that the
; D' N7 Z) o( ?& x+ g    // order of iteration through the `heatbugList' will be3 H/ ^1 g+ y" @* m) P* x
    // identical (assuming the list order is not changed7 r  L- Q- t2 o& Q8 V' h2 H1 R
    // indirectly by some other process).
0 @- h& N* Z, E- N9 @5 ?/ z1 O   
0 f0 Q) X, X& d3 b% S    modelActions = new ActionGroupImpl (getZone ());
4 x; M/ U8 [1 C% H
; g! ~4 d7 s' R6 {( x. d    try {! O# A3 n7 f: }" K
      modelActions.createActionTo$message8 k% Z6 o! u& L9 Z$ X
        (heat, new Selector (heat.getClass (), "stepRule", false));! O, G, ~# f* D/ a/ a
    } catch (Exception e) {
- g2 R! M; U1 E( s1 ~( }% Q" }      System.err.println ("Exception stepRule: " + e.getMessage ());
- j& `0 ]% \" m" I    }
3 R9 B& Y; ]; z' o; s7 s3 d: A" L$ x
    try {
' G* V% N# I- J! ^  y; Q8 ^      Heatbug proto = (Heatbug) heatbugList.get (0);8 g- j4 P$ p, k
      Selector sel = 9 S7 {& g- T5 E, r* t
        new Selector (proto.getClass (), "heatbugStep", false);
; Q: T$ Y/ V) y; W; N8 z- y; p$ D      actionForEach =5 t7 ^+ f& }% j" T# u# g# l5 L
        modelActions.createFActionForEachHomogeneous$call- G4 m# b9 Y0 Y% {1 k8 Q0 d! g
        (heatbugList,
8 M- Q$ V. w2 o         new FCallImpl (this, proto, sel,
1 j- d+ L; z4 |) ]+ q                        new FArgumentsImpl (this, sel)));
$ Z: `) e% U4 r7 I. H    } catch (Exception e) {0 G9 ?7 k+ `" i
      e.printStackTrace (System.err);3 t; M2 }) U; D2 L
    }! i6 m/ ~: x6 E7 }$ Z
   
+ N% }2 \1 @, W    syncUpdateOrder ();
& Y) P3 B+ [& q2 P3 E& K' ]% A: Y
% ~3 c% m; f; j  K    try {! S6 U: B; A% N  P+ Y) c  x! w
      modelActions.createActionTo$message . P. R& n5 d+ {4 b5 u* O
        (heat, new Selector (heat.getClass (), "updateLattice", false));  _. m& _# b+ r& H6 ^+ R- _
    } catch (Exception e) {9 _1 h/ y7 U9 p1 g2 y
      System.err.println("Exception updateLattice: " + e.getMessage ());
# l: F4 H; o; M9 o8 R$ e! M2 ~    }
7 Y9 X/ @; W# k$ W) W) J        % u; z" t8 ~# i9 T
    // Then we create a schedule that executes the  K0 n: i+ J1 W. |6 e& |
    // modelActions. modelActions is an ActionGroup, by itself it; X; V6 R. i) N) a8 E
    // has no notion of time. In order to have it executed in
& {7 T& o6 B0 O    // time, we create a Schedule that says to use the
  p0 ]- }" o( t% K7 o/ t! H8 [; K0 r* ?    // modelActions ActionGroup at particular times.  This
8 c* s5 j0 d4 T5 z    // schedule has a repeat interval of 1, it will loop every! P6 Z  C& D* P  R
    // time step.  The action is executed at time 0 relative to% M  w/ j1 j2 P' h
    // the beginning of the loop.' X, l( a" G  A' P$ |4 V; r8 \! I: y: u, C
2 }( j! O/ N, ]" r' V
    // This is a simple schedule, with only one action that is) a* c: P- r( {! ?/ [" K
    // just repeated every time. See jmousetrap for more
$ p7 G$ V. c; ^. t4 x    // complicated schedules." \$ e: V! C4 L* b/ o# a; u
  7 |% G$ h. Y. C. v3 N- N5 @
    modelSchedule = new ScheduleImpl (getZone (), 1);1 ?0 B, L9 Q) ^3 E
    modelSchedule.at$createAction (0, modelActions);3 p3 _1 C; I7 `
        
9 C* ~1 _9 S6 J1 W0 k. N    return this;- W# B/ B0 w" A/ n: P- d
  }
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