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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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public Object buildActions () {
0 `- {& f; T, F3 w1 R* h    super.buildActions();
' c( O+ k9 R, T" J   
5 n0 w0 o1 {: o' s# \5 ~    // Create the list of simulation actions. We put these in# U) {4 ?& b, D9 [0 T6 r" j
    // an action group, because we want these actions to be* _" ?, w) P; l3 E% [# |4 F
    // executed in a specific order, but these steps should+ w0 I$ D# i) r% y! o: z
    // take no (simulated) time. The M(foo) means "The message
* A0 j3 z+ H3 l1 W* v    // called <foo>". You can send a message To a particular" h8 n, u; B9 p# R* H3 z
    // object, or ForEach object in a collection.. w* c. m) e2 m  l( B! m& `$ d' S
        ' X8 j0 _& I: v2 i) r! {
    // Note we update the heatspace in two phases: first run$ i# G1 `: X- B! X& A; N& |! I
    // diffusion, then run "updateWorld" to actually enact the
) a$ a6 g5 z5 S' C  c    // changes the heatbugs have made. The ordering here is' c0 E( f7 O  _
    // significant!
; h1 u* N& `- e5 B& Y; X9 O; y- Z        . n* f* w$ {8 z$ h9 S2 Z9 M
    // Note also, that with the additional# C0 b  ~. O  {+ x- p1 z4 N
    // `randomizeHeatbugUpdateOrder' Boolean flag we can2 K4 _( X# x# n' I
    // randomize the order in which the bugs actually run
, ~: X  u) G" u8 t6 G    // their step rule.  This has the effect of removing any
# t1 {# s7 p7 R) V' f# d7 U, B    // systematic bias in the iteration throught the heatbug
% J( k" y; h, l9 x: w$ X    // list from timestep to timestep  e( [* h3 _% O4 {  m
        0 J' b' }; U. k
    // By default, all `createActionForEach' modelActions have, N$ g4 k" _( x  d
    // a default order of `Sequential', which means that the
0 \$ [5 A5 i: H( c9 z& C    // order of iteration through the `heatbugList' will be- ]0 V  u' @$ G1 K4 p/ P0 m# e6 r3 \
    // identical (assuming the list order is not changed
0 A. |8 [4 ~  Q, {8 C9 |    // indirectly by some other process).+ \7 T- V3 U4 Q* _
   
8 z# H* Y3 k3 Q    modelActions = new ActionGroupImpl (getZone ());
$ z& y* A! [4 B# L! k3 x
1 `4 P" P( `2 Q1 K' M# W# t& n    try {
$ l' P  b& e# s      modelActions.createActionTo$message, }5 ~3 f) w* x+ y" z- s$ }
        (heat, new Selector (heat.getClass (), "stepRule", false));; T; ?9 d* W, d. X7 f
    } catch (Exception e) {
; q( z. h* Z6 A" d& i+ Z      System.err.println ("Exception stepRule: " + e.getMessage ());
- ~8 ~% r4 o6 F4 M3 k    }) c2 O# p+ z# x: @4 R* |" {( _

) Y8 D1 g5 I( w' [2 c3 g    try {
) g7 h4 C/ l$ y6 v9 H2 K! w) k      Heatbug proto = (Heatbug) heatbugList.get (0);
# P' Z$ H( U$ {/ n; D% j/ d  L. F) w3 k      Selector sel = 4 V3 n( Q% x/ S2 R, u. t. H
        new Selector (proto.getClass (), "heatbugStep", false);4 Y1 S7 k+ C: F( t! Q) F4 c: B
      actionForEach =
2 P. [8 s' H, F0 P4 ?! n" [/ q        modelActions.createFActionForEachHomogeneous$call
$ Y) \& B$ F8 z3 k2 N        (heatbugList,
- Y: z2 X. z7 t8 z- v         new FCallImpl (this, proto, sel,
1 c6 ]6 Q/ H6 o/ d; x                        new FArgumentsImpl (this, sel)));
1 ~1 T* F8 a7 k! L* t, W8 `8 S5 {    } catch (Exception e) {
9 T  `  ]* r* {" F6 L      e.printStackTrace (System.err);
& ^' |! O5 v  q% S    }3 }! s  p  R: g0 r, F- s" f% r& i2 ], Y
   
) z7 t* i! D6 x    syncUpdateOrder ();
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7 X0 W, I; i& D- E# P& D: T    try {. n/ d- f0 y4 K+ ~# J' ?% ]
      modelActions.createActionTo$message % w* a3 d5 Y1 B( e! H6 c; n8 {: `
        (heat, new Selector (heat.getClass (), "updateLattice", false));2 R! E) D5 n" t
    } catch (Exception e) {5 N- H7 f6 R. c" Q& y: N( B; J
      System.err.println("Exception updateLattice: " + e.getMessage ());# P8 _0 d, A+ X9 U7 J, O& n) m2 G
    }0 R, O* f  u& e, ]
        
! S/ W. T1 B8 w( e    // Then we create a schedule that executes the% o* o: J6 ]* I' ]
    // modelActions. modelActions is an ActionGroup, by itself it3 R- B; Y5 j- F" W, x
    // has no notion of time. In order to have it executed in. i- \& n" ~  y* t4 |2 ?
    // time, we create a Schedule that says to use the
: u$ y  E6 [& j1 j5 Z, Q( }2 u4 o    // modelActions ActionGroup at particular times.  This3 b8 {( U7 @6 L" F
    // schedule has a repeat interval of 1, it will loop every6 x: P* Z& S0 x: ]7 A
    // time step.  The action is executed at time 0 relative to! ?* ?, ~2 c  c" @
    // the beginning of the loop.
0 c# \$ }4 n( F' f( }9 u2 e2 K8 L6 a/ O6 w
    // This is a simple schedule, with only one action that is0 c. H2 M0 A( Q* k7 d
    // just repeated every time. See jmousetrap for more
( s6 P& F- B* _( T    // complicated schedules.
/ y, ^  H4 K% J! F  
4 h, ~' M$ |8 }% R( K! B, L4 A    modelSchedule = new ScheduleImpl (getZone (), 1);
) i; |. _. ]9 a- `+ f    modelSchedule.at$createAction (0, modelActions);
4 q  p8 n7 ]  F0 ^2 C3 d        
6 l( f8 ~9 K7 |" y    return this;
! p8 f# i6 n: ?5 _* r  }
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