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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:+ o) R5 K2 R. {& x+ f8 F/ d. r: w

# Q' v0 T4 m+ {/ J0 ]5 Y* G public Object buildActions () {
$ F$ G# o, m: q, ], r  J    super.buildActions();5 h9 `% P; a. y( |2 R
    , H, A" j) `! D0 d/ z$ d$ n9 {# L
    // Create the list of simulation actions. We put these in
; R  C8 n  q' I6 X8 H    // an action group, because we want these actions to be
( t0 ]. P: g3 E* g3 M    // executed in a specific order, but these steps should
/ w/ g& ^6 E  V/ K- B/ A  A( U    // take no (simulated) time. The M(foo) means "The message+ H& B/ `2 A0 }; Z7 r. c
    // called <foo>". You can send a message To a particular
/ W1 K8 R( t; A2 x$ H- \# X; p    // object, or ForEach object in a collection.
+ ^- n5 ?9 l4 Y. _1 l( ~        2 ^7 [% U9 m$ X! m4 P
    // Note we update the heatspace in two phases: first run7 `2 J$ Q. Z2 n' k9 }8 Y: H( K
    // diffusion, then run "updateWorld" to actually enact the4 k1 |2 q2 ?, h
    // changes the heatbugs have made. The ordering here is* Q# _, t9 R! x0 P+ O. p# D
    // significant!! B! h2 q! t* O
        # x% q" ?* V8 _: V0 @% K% L
    // Note also, that with the additional# D% \. O8 C% u# a. q3 I
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
: z& ^# V$ W5 U8 m    // randomize the order in which the bugs actually run
  G6 U9 s* L& Z, g- k    // their step rule.  This has the effect of removing any2 L, \8 ?' E1 N3 W; T2 g/ ~$ {
    // systematic bias in the iteration throught the heatbug/ X- s, h3 n: p8 L0 f
    // list from timestep to timestep
* B  ~; F3 w) d* N+ I        
" q; X  I( v% j+ J    // By default, all `createActionForEach' modelActions have
0 j$ C2 \$ l; i6 S    // a default order of `Sequential', which means that the
! i7 r) C7 n. B# {+ `5 ]' ^    // order of iteration through the `heatbugList' will be
' N  w' {% h6 x; J7 Y    // identical (assuming the list order is not changed
2 f9 v, x- k0 H) g    // indirectly by some other process).. [' Q. z- H9 F+ ]- I
   
9 b- f  {. |( e$ ^/ y3 k3 L3 U    modelActions = new ActionGroupImpl (getZone ());
! J3 Y: t7 P/ A. i1 Y$ R( F3 z. q% w7 M1 ]% E; P  T% d4 K
    try {8 a! V: ~0 \% ^; c- j0 o
      modelActions.createActionTo$message
. J8 c2 z" P/ ]/ e        (heat, new Selector (heat.getClass (), "stepRule", false));& z* m; d5 k, d3 f8 K: Z) `
    } catch (Exception e) {
0 d2 X, C4 c  Z+ o# m1 i5 g      System.err.println ("Exception stepRule: " + e.getMessage ());
5 G# o# x: M( V$ f    }
* L# Y' N( }. R  l" y1 s, |) r3 H# e
    try {& N& D' N2 W0 I- z
      Heatbug proto = (Heatbug) heatbugList.get (0);
) M% E+ Z5 V4 r0 _$ h, w# G      Selector sel = 0 v9 z% N( G. g$ `; b! U
        new Selector (proto.getClass (), "heatbugStep", false);4 Q) ?" m4 N! D% l, @
      actionForEach =3 q2 ]. m7 [6 M  G- ?6 `/ [" P
        modelActions.createFActionForEachHomogeneous$call
5 l7 L+ n; m# D: `6 z! v        (heatbugList," H- t0 o0 F+ f
         new FCallImpl (this, proto, sel,
, K4 r" U, M! P; i$ I: d                        new FArgumentsImpl (this, sel)));
3 ^, }1 Q1 K4 u' ^3 N4 l8 O    } catch (Exception e) {
( _8 T/ m7 e7 P+ A( x5 x% [      e.printStackTrace (System.err);8 w7 d5 a, ?0 P
    }& ~! V2 `" C6 i+ N9 N/ D
   
, a/ z4 x; Z8 ]6 W5 }    syncUpdateOrder ();! x! P. b# v3 {: X) Q. f

1 v" N) m; D# v' e# A% K    try {
& u3 v, E, E/ G; C0 h      modelActions.createActionTo$message
) s* G  Z" x" b4 \7 Q8 ]        (heat, new Selector (heat.getClass (), "updateLattice", false));1 k  i  Y/ @" u) k% E  Y' O
    } catch (Exception e) {* b+ K( t0 E. z1 I' W$ p/ a
      System.err.println("Exception updateLattice: " + e.getMessage ());
: p/ ~; J8 b0 E7 }% j" z    }6 U5 p* p( k) a& V$ H$ @. T* ^
        * N# t( Z! w" R( Z- d5 I
    // Then we create a schedule that executes the
% j( v! G/ ^1 Z: i    // modelActions. modelActions is an ActionGroup, by itself it: O/ i' m! B2 `
    // has no notion of time. In order to have it executed in1 o; s2 s3 ^  Z2 k
    // time, we create a Schedule that says to use the
6 \+ w2 L! p) Q! J- K, u8 Z    // modelActions ActionGroup at particular times.  This  Q4 V' S. c9 ^& d3 a# ^
    // schedule has a repeat interval of 1, it will loop every
0 m! ?1 C! |  S6 n4 R    // time step.  The action is executed at time 0 relative to5 r% ?$ f2 M+ p$ z7 |1 Z: y3 u+ G
    // the beginning of the loop.
1 w1 M$ {, j# T& X0 o$ |- L6 b5 X# v/ {' G
    // This is a simple schedule, with only one action that is9 I9 i5 t) {' ^4 G# v
    // just repeated every time. See jmousetrap for more, c: W% u: M& v  Y
    // complicated schedules.
7 ]" S/ A9 A7 c' U  0 \" b2 ^0 O: f# s. a8 ]
    modelSchedule = new ScheduleImpl (getZone (), 1);0 e" Z" A% `7 `: W, M9 z7 N
    modelSchedule.at$createAction (0, modelActions);0 P9 ~& @  a, @+ n* J$ g. g
        
1 F; V8 Z! }7 E3 Z    return this;  M; q# E: O: s! k
  }
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