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发表于 2010-5-11 13:19:52
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用list吧6 `& K) }8 t& i. y
patches-own [wealth rank]
, K. E3 _+ O8 W9 T; {to setup! D5 I+ M: `2 S" ^6 w
ca: o! [& [/ c# \, }. J& d
ask patches [set wealth random 100 set pcolor green ]
& a5 f0 B: [ G- r @; P6 C. v; c/ uend
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1 {4 ^: C# g+ S0 J0 Cto go
1 y8 t! a7 C7 P8 e6 d let mylist1 []
8 P- g1 s1 X2 ] set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches( f {! w8 q2 [' C- n
let mylist2 []
( N( c, o! K7 V4 H8 Z: L5 U set mylist2 n-values count patches [? + 1]
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- v" ~7 J6 z7 O( U$ [4 G$ e: ?" _ ( foreach mylist1 mylist21 s. N; t, c7 d' A ]
[$ x& }5 q; y' `7 U3 A
ask ?1[ set rank ?2]% `, d, \, m8 b' J$ K: _
show [rank] of ?10 b7 {2 T1 F5 P+ X& f
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]
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let mylist3 []- v% ~1 V8 W) [( j, r0 A# ~' S
& X+ S1 b- {) @6 X
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
( u( D7 n0 T8 J2 H show count patches# t% |, O0 f3 f0 H7 T
show mylist1
' U% v M& V) o show mylist39 S& X# Z2 B3 O* f3 m: w Y2 k
end- B) ~, [ w/ r# _( v5 ^3 y
7 |, z& G. i! D这时的mylist1 和mylist3 应该是一样的 |
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