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发表于 2010-5-11 13:19:52
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用list吧2 ~$ V: B9 w$ ~% l' M& r5 M
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []
9 T: ? k! H/ T9 o' ]! L# U set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches/ K P( ^$ ?. d* q8 p. t
let mylist2 []9 i/ w5 _6 w7 [1 \+ s. o9 x; J
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2, q+ ?+ g, n$ z: {
[
2 B8 M, ?1 o4 z: w* H8 b$ J! x0 z ask ?1[ set rank ?2]
' R; A/ F( s4 i' w# ]' }3 y' O- M show [rank] of ?1
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)
1 ~0 C* m( s g let mylist3 []
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: a9 T" |1 B1 I- F p; e# s set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
, ?1 f- D9 t( k: {" B0 g show count patches9 a; H2 @4 I" A0 }6 D( i4 K
show mylist1
& O; D. T( o. _. \% F5 M; c show mylist3 O; k0 u% F2 `8 a9 W& b
end
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这时的mylist1 和mylist3 应该是一样的 |
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