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发表于 2010-5-11 13:19:52
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用list吧
& ~% ~1 h" ?& }$ a2 C! ?4 ipatches-own [wealth rank]
9 g$ a/ _) G( y7 g) p" x, xto setup
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* G% \- I& M# p6 v5 ~& Z( p ask patches [set wealth random 100 set pcolor green ]: i# S" _7 k% Q* B! T' q
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to go
0 ~# l9 Q& g) m! \ let mylist1 []& E. a: m' Q8 y7 ?0 O7 S
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
0 ~( C; o; M* Q! x6 l! a let mylist2 []
! \" R2 x& U6 u. r2 ~ set mylist2 n-values count patches [? + 1]8 r* c# b: [ c c$ K/ |1 x
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( foreach mylist1 mylist29 H6 K; _+ j4 h' P1 Z) d2 x% z
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ask ?1[ set rank ?2]
3 r: T8 J, |, R& h' r" x show [rank] of ?1! z" z+ S* W+ [. b& i
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let mylist3 []/ {1 D2 ]# ?/ T, S \& A
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches$ U7 p, I; H2 M \% M" F
show count patches. l; ]! P9 R! A4 ~+ i
show mylist1
8 o; `8 T8 a% {* ?9 T3 G show mylist3+ x$ F! @+ J0 v5 k
end: Z5 T7 e M( E8 ^8 j% L
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这时的mylist1 和mylist3 应该是一样的 |
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