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发表于 2010-5-11 13:19:52
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用list吧
) C3 U' J. R0 b, e' f8 |patches-own [wealth rank]1 n8 j# Y! G9 r$ G
to setup: C. K% H. g5 ]0 Y# j! g
ca; z# u$ T. ?( W, c5 G! c& u
ask patches [set wealth random 100 set pcolor green ]
! }5 |* k3 i# B/ E- \end
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to go! Q8 D. V0 B7 ]0 f! g% ?/ e8 C
let mylist1 []
# u7 N7 J# u5 { set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
- c3 q! m$ [# q8 U) C% C% V let mylist2 []
/ {5 W% Q3 ~; |5 M set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
# z2 A$ r! E; r7 A8 w6 r; `4 i [
& R( n7 U c/ e' G# @ ask ?1[ set rank ?2]
% ~: X( O: P+ ?9 g/ w- o4 Q q show [rank] of ?1
- A: }5 P/ N- x 4 T' ?* l3 a/ J& L2 s4 `6 Z/ ]
]
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let mylist3 []3 n$ Z1 `9 e9 [* N5 {' Z7 \2 L
0 ^! Y4 j6 g8 ~7 Y" M* r set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
+ p4 m3 {/ d2 |* }9 y. P show count patches4 F" V, M# \7 E: h! S
show mylist1
2 Y1 g6 a% Y3 x) V show mylist3
J9 S7 l8 m1 i# N3 aend
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$ \& o7 C# c' f R这时的mylist1 和mylist3 应该是一样的 |
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