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发表于 2010-5-11 13:19:52
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用list吧
9 u$ z6 f# t v: fpatches-own [wealth rank]
; |7 |5 x4 [$ p8 y( Tto setup
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ask patches [set wealth random 100 set pcolor green ]1 X' ` m% S. D4 \$ G# N% D
end% y4 A, `5 _0 W; w: P0 X2 T9 O3 [
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to go
, d3 b+ \7 f' h+ I9 x4 { let mylist1 []- V9 V9 d, h1 P V
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches( g5 L0 h! ~* i1 {& C) F0 A
let mylist2 []* o" B: X, I ]# L
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2: D I1 G. |# z0 o
[
3 Z' a1 g5 w( j: |4 \# b ask ?1[ set rank ?2]
0 @9 F6 M7 f% l& e show [rank] of ?1
1 q. S# y7 Z& e5 j" [
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)
. T+ v6 h! M! i, b& @ let mylist3 []
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+ E5 `; L) d* Z1 x& k5 @$ n set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
7 ~" e( L+ x0 b$ L& ]% H4 V show count patches
) q' s C% u3 H' w+ u2 z, n show mylist1 " l( K: a& I- i/ d/ A' z4 T
show mylist3# ~6 V: v: q) f e5 B
end
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3 u0 p d; d; T( m0 h$ M4 u2 p4 }这时的mylist1 和mylist3 应该是一样的 |
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