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发表于 2010-5-11 13:19:52
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用list吧
' s6 C" T" q# D1 m, O( upatches-own [wealth rank]. t- V- O3 }# X+ R, W
to setup2 w( b8 |; s) {' w
ca
( u- c& s6 e4 z" A5 |6 ]* g3 J0 w ask patches [set wealth random 100 set pcolor green ]
7 p& f0 f( ~8 e) Q( S) Yend
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9 j# b2 a% W, B$ E8 _2 |" Hto go6 I, v, \) o; h/ o3 w4 v
let mylist1 []
, ]* o! L1 p5 B7 ^$ K$ \ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
; q7 c4 U J$ }/ y+ r* E let mylist2 []. H1 A. @2 B& c! E& D' \: f" Z
set mylist2 n-values count patches [? + 1]
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: h% N) F! @5 J ( foreach mylist1 mylist2
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" X( t# y; r& I2 { ask ?1[ set rank ?2]
$ C% `# e' |; K show [rank] of ?1* p5 Q' a" ` w3 Q7 [+ [0 Q5 a
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]
0 j7 Q3 Q' R! B8 D )
- Y1 r, C/ Z" ~, [' I. Z let mylist3 []5 V. l+ G' h- h. g, W q1 X; q
5 k7 n# L+ \" A3 ?. {9 @: y set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches3 K9 @! K6 V5 I; |
show count patches
: U6 u- G4 j ]- w show mylist1 . _0 w" B( ], C S* q
show mylist3 z! V. b9 T9 e% M+ J, _6 Z
end/ Y) Z& e( y% b' J( N
3 K5 Y$ V7 l6 X, a! h# Y: ^8 y
这时的mylist1 和mylist3 应该是一样的 |
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