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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：, s7 X i2 r+ ^0 H2 t+ G: j
begin P_in arriving
+ Q/ c/ s! p' T' E# C- p# S9 y move into Q_in" l5 d: y2 V" y. {9 z
use oper for 2 min
$ l- N5 k' k8 L' L send to oneof(0.95:P_in1,0.05:die)
5 b' K2 p$ ?% l: R( u aend& N. V: R$ [, u! ^ P e
begin P_in1 arriving
6 D; G0 U8 p% Q7 @& k4 Z if load type = load1 then! S1 @: i8 W3 T) K. C h" U" z
begin* \; Q. o- b( `$ [1 {
move into Q_m1
- _6 l* Q) N- k9 r8 ~ use M1 for u 5,1 min8 _: E8 w8 [+ t4 [- m' C% f9 g
move into Q_out12 ~) [8 I. _' Z2 O- d+ r9 I5 I
wait to be ordered on orderlist OL_1
3 u" {7 q1 o3 O1 K/ r0 Y, b* i- x end" z E" b* a( W# n5 C4 p$ g
if load type = load2 then
. h2 D7 v4 U/ F7 s0 P begin0 k- h- F! ]9 ?+ Q- _5 R) |
move into Q_m24 U z# a3 z [ b1 v, j9 y% l
use M2 for n 8,1 min/ S1 I! I8 C, |. @& l2 m( m/ m% n
move into Q_out2
. P9 H7 C b. { wait to be ordered on orderlist OL_2
0 t3 d! a" b3 W5 R( ^ end; j) p+ S$ K) v" Z" ]; l
end
' u0 a3 Z7 O" L, E9 pbegin P_dunmy arriving
2 B! q+ i) A: g1 t7 E set i = 1
+ \+ J: k G0 a5 ^" U while i > 0 do
: g/ D \$ J1 O) W% B( O begin 2 m9 U y% z4 W& M1 h8 m+ G9 ^" K7 p
order 1 loads from OL_1 to die
5 h1 P# B% {' R+ T: Z- o5 E3 L in case order not filled backorder on OL_1
! C4 F0 I* B$ L$ Q order 1 loads from OL_2 to continue; J5 s9 A. Z2 v
in case order not filled backorder on OL_2' ^# t) y y6 }7 L
move into Q_1
' w7 b) y/ m" d3 g$ P use Massm for n 5,1 min3 p. [+ [7 t0 ~' `9 D
send to die0 k6 k# H: l8 z) Q7 a& ^8 \, P
end. |3 |: m% h; i+ H% C0 v/ o
end% V$ X* t1 {+ W b4 j6 ~4 g+ p% L
这是我的报告. D) ]. F2 c; X! H! N5 k
*** AutoMod 11.1 ***
V3 o1 m: ~# Z4 `6 YModel q
- Q# \( b9 O+ r' m' }- KStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.008 k5 t" s( z+ _; K$ s
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
& z. W. L- ?; w; Y/ X0 pStatistics for Process System "q"- Y% j4 c; r2 S' O9 i4 g
Process Statistics
& G$ n" f4 w" J7 i6 {" \Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait( C+ J0 x5 d! u4 y+ Q- T1 w; A4 T2 c/ Q
========================================================================================- o/ ` J5 I8 I3 R
P_in 222 1 0.32 -- 2 0 -- 126.04 --
6 v: x/ w5 m9 m4 r0 k1 xP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
. ^1 K4 b: H1 H7 ~3 H% yP_in3 0 0 0.00 -- 0 0 -- 0.00 --
& c! s$ f+ G ]4 b( xP_in4 0 0 0.00 -- 0 0 -- 0.00 --
2 X( J4 x/ \- q% O! g/ V$ lP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
0 B* m1 d6 x! W, I0 j LProcess Traffic Limit Statistics& |/ p% V- L3 G% N
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait+ }4 y K# k) N6 \% N- ?, ~
========================================================================================
6 P* n5 a5 G7 | r+ [% f- T( _: @P_in 222 1 0.32 Infinite 2 0 -- 126.04 --9 P* @. p& ~5 w! I
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --. J6 C% S! q& B6 T4 @/ k! h
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
: T; F- x/ X$ aP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
! S# e/ G w+ W4 ?6 {P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
% L- T$ Y1 L- c, BQueue Statistics- i& T5 i7 d: `, `$ e
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait: x3 V$ c( B0 O- ^; s9 m3 O
========================================================================================
3 z7 z0 N7 j8 q, GSpace 223 0 0.00 Infinite 1 0 -- 0.00 --( b) d" ^9 Z2 ~/ l3 y: B
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
- l# n! w5 B. g+ ?+ cQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --# n" ~/ }! z1 { j+ h5 G- k
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
# j- \5 r& Y3 l8 jQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --# e* [6 e# X8 b
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
6 W1 B; I$ G! m5 f3 g. l1 K I& m6 kQ_1 1 0 0.00 1 1 0 0.003 277.31 0.001 d# {8 K w* i0 t6 n
Order List Statistics3 ^% b, V4 a3 P( z
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered. m' D& g$ ^& C1 N1 }
================================================================================# r. x- r7 O2 X2 ^+ D8 @
OL_1 139 139 67.23 139 0 41789.43 12 N. M( C' a2 ?, i6 O
OL_2 71 71 34.26 71 0 41693.20 1
4 D& }4 |7 C& `2 _% C& V+ v& ^Resource Statistics" q2 E& g3 |7 a0 K
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
/ A/ J! o) z( X" B. O3 E====================================================================================================
7 G* X+ |/ ?6 U QM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- - u7 a1 p: z. y- H
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
6 f/ P4 K: T6 I' N! h: @Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
. k+ x" B1 A5 F5 Z" A3 l/ Coper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- # o! X, I2 W, d: A) P) D/ p
Random Number Streams
* I# u6 h/ v6 M! r3 oName Total
0 _0 K3 Z: |) G6 o* @$ b+ _* G============================4 z$ I8 j; k0 t
stream0 455
& w0 M$ s6 S, K- ]( ]+ U) S" Z# Hstream_M1_1 0" N; ~; f+ e) D. c& z3 ?: Y( M
stream_M2_1 0
( |" B2 h1 \, V" H! l8 H' J- rstream_Massm_1 0$ E* a9 O- I9 A' V
stream_oper_1 0
. B) E+ T: c, S/ V9 } z% O, pstream_load1_1 184
- d' I4 |& W7 P8 S' y" Mstream_load2_1 76/ a2 w; S! E4 C/ j/ T: M
stream_dummy_1 0
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8 c0 c0 N! ]" a/ M) O请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
