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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 9 c9 ]# J/ k" d: ~% B( s' x* }
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
9 i3 U7 N4 o) Y. M' C5 F. Fbegin P_in arriving0 c6 D) w& [) V6 u; P
move into Q_in
! F; z# F1 o( u M5 [7 m use oper for 2 min/ I% Z( z2 Y6 L# I6 O
send to oneof(0.95:P_in1,0.05:die)/ B, ^) }/ y* r! {
end3 @5 {% y; s+ p/ r9 E
begin P_in1 arriving
# @, C w( [% j! Q# {: } if load type = load1 then% O" p X+ S2 R: p" L9 R% m. i
begin
8 T7 C& E8 |$ Q8 h2 K" K8 C move into Q_m1
1 J# \! b; E2 n2 N use M1 for u 5,1 min6 x9 E" J1 F/ _0 P! @/ J" @
move into Q_out1
+ G" c3 B; {! y. v1 W, W4 L wait to be ordered on orderlist OL_1
: ?3 c1 O% I; A; |$ l4 O. J9 j) P end
* P) A7 O* K8 f* E5 d if load type = load2 then n5 Z* }! A9 d+ I" u
begin
( ]" _: d9 d3 O. Y6 O0 W1 B6 G, r! H move into Q_m2/ P7 r3 O3 a1 b4 |7 l. z' d
use M2 for n 8,1 min
6 z! _+ X! P0 R move into Q_out2, L6 X! v o4 |' |8 B0 M6 Q
wait to be ordered on orderlist OL_2
9 I& j) [% f S* e3 k% ^# ] end
f2 Z5 M2 f6 mend8 C* s1 x* t+ l& y
begin P_dunmy arriving
, _1 R' \+ d7 z5 d$ k* B" [- q set i = 1; {% @0 K1 A# A7 B# e, I
while i > 0 do
: z& d5 }/ }9 u: N begin % @! U* ^6 R# u9 M9 W+ Q
order 1 loads from OL_1 to die \, _- T$ Q- x2 W
in case order not filled backorder on OL_1
6 e$ ^9 J6 ]. u8 }1 m. O( j* W! n order 1 loads from OL_2 to continue
) L! e+ i$ {: x in case order not filled backorder on OL_2
* m" d. S6 a+ L8 n* G( `6 I' v move into Q_10 q7 P8 m, U0 N# A( Y- Z) m
use Massm for n 5,1 min
- B5 N o9 B% m" ^$ ]9 s8 z2 d send to die
( H8 [; R- q. G1 `! a0 W end6 c- d: _: S9 C' K( @& |' e5 A
end
2 i8 O" A" {* U5 `6 q6 \) p这是我的报告
: ~1 T0 l6 h& ^0 K' y*** AutoMod 11.1 ***5 s: }+ @7 t) `& J |& r3 v9 g
Model q5 U& }0 s8 f& f. w
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00; d/ {+ Y0 e* Z6 u' u0 S3 ^
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
. f0 V3 |7 {# J* n: gStatistics for Process System "q"0 W* v4 X3 N* B0 _, N
Process Statistics( x$ s" z6 V+ e. r: k0 ]$ _( A
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
, n6 ^/ u8 [ V4 A5 b========================================================================================5 O* o( r2 }$ p) H! O
P_in 222 1 0.32 -- 2 0 -- 126.04 --
1 }2 ^8 N' J7 e( g; B, U2 z1 Z" e! jP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
/ o' i/ j2 Q5 N6 A1 ?P_in3 0 0 0.00 -- 0 0 -- 0.00 --% R9 }7 T' m$ c9 f
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
6 a$ r' m* s2 U- O7 SP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
, \" @ Y2 b# {: Z% g. uProcess Traffic Limit Statistics
, I" T* V. `1 |. K9 MName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* P" H0 p4 ]$ g$ i6 w========================================================================================- N6 C, x1 G5 S4 N
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
" ]: ~) e! n `/ T7 V* fP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --5 X2 u! L7 j) }; w2 W+ e0 X
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
6 P) v0 B5 v I8 ~* H6 Z7 _P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --1 J9 K( s+ E& p/ Q8 K: v5 ?5 X+ K
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
. {/ L, c$ T6 C1 _3 vQueue Statistics
* T1 I! B' R. {2 e* ?0 I, }Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait3 l% z# g" _* j: t
========================================================================================
! _9 r) T7 R: j4 G3 K% X: @/ VSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
) P3 [# y1 w+ M$ y$ b7 eQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --9 d' n- B/ y# w6 H
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --$ `: e7 i7 m# n8 W! E( n
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
1 C" t( |, m, Y7 r! A4 A! kQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
" ~' x3 q# Y9 j: f, T6 @. S5 K/ lQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --) h4 \# S- s- X% a9 q# R$ B
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00# t; b, H' L X# k4 }# J, P
Order List Statistics
5 p4 Y6 {: I. J+ I% }' _) s8 n9 t7 eName Total Cur Average Max Min Av_Time Tot_Back_Ordered, E8 V7 T& A! Y. ^/ D! |5 ?" C
================================================================================* l0 M2 \% Z9 w1 H
OL_1 139 139 67.23 139 0 41789.43 1* c6 w$ Z6 ^3 W* E" A: r
OL_2 71 71 34.26 71 0 41693.20 17 T. O6 P% `8 a
Resource Statistics
1 g1 h: E9 E2 `# ]* KName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
7 |& B; A9 S, |====================================================================================================/ c0 D: r3 @/ c* p7 w$ _
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ; k; @7 \6 y9 D p
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
* t. [6 h- j8 f( ^9 o, T9 zMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
/ a' V' A( Q, Y) r, s% d. goper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
( Y: F1 ^& T7 G0 ZRandom Number Streams* l) F t/ l5 r6 P" D
Name Total
# d r+ U' _1 S e7 V/ a============================
9 w3 ?2 { @2 J3 ~" e. a! W7 v+ qstream0 455; \- X; \& h* Q0 V# z2 g1 G+ `# [
stream_M1_1 0: T, j5 s! ?/ m6 O2 K g
stream_M2_1 0
* m* t- @7 ^+ b# ]! z- Nstream_Massm_1 0* c+ R/ f5 l1 B$ N( x
stream_oper_1 0
8 w" _& b' M$ Y5 estream_load1_1 184$ [# v+ O- `0 B: _
stream_load2_1 76" g4 ^ T+ X% d9 H' ]
stream_dummy_1 0
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2 }% F' {0 J7 H请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
