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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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* O+ k' R F, S2 [ y4 k* b. G) e4 i我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
2 y8 i# F; f, [* \; h* ]) \: s4 u4 rbegin P_in arriving3 c) I2 R& B$ r* ^- A
move into Q_in$ |" x- N& o3 r ]6 w# D
use oper for 2 min
( \4 D+ u0 m! Q& I0 d send to oneof(0.95:P_in1,0.05:die)
6 q- n2 ?9 r# D# `! @end- E9 Y6 U' ^7 H. i- u. Z3 t) r% A
begin P_in1 arriving g8 a* e) G N4 K2 x) q
if load type = load1 then
. G( U4 ]1 M$ i4 k; {. D begin; s; o; g+ }/ i2 s$ |: V
move into Q_m1
2 f7 o0 i. K5 A1 e use M1 for u 5,1 min
! |8 v7 Q& \4 e% T4 j move into Q_out1- E' z( l% t$ n3 O; i: d9 ^, O
wait to be ordered on orderlist OL_1# I; s2 b; F( S, D# @8 r8 B8 a
end2 R& b7 K! w5 L1 j$ C$ s
if load type = load2 then0 `2 }8 ] B | C
begin
$ t! C: F: i3 T move into Q_m2
, y1 |3 }, K, s8 _! z g use M2 for n 8,1 min1 L2 ~! a; a/ ]% h
move into Q_out23 P, w7 u" ^3 S
wait to be ordered on orderlist OL_2
' v j# A. Y9 t! ~ end- i f. H6 x2 \& J9 o
end
* A9 i3 z/ f5 Q. Cbegin P_dunmy arriving
/ [! y% P, ^0 V1 ^- T7 Q' c+ o5 O set i = 14 i1 L0 b0 Y" J: Y: o) }2 I
while i > 0 do
4 i- J; }3 U* l7 o begin
5 y$ C. V( h7 H0 m1 K# C order 1 loads from OL_1 to die
; t) p1 S" y+ g5 j2 m8 V2 T in case order not filled backorder on OL_17 k m$ E3 @ Y5 @ o
order 1 loads from OL_2 to continue
7 p* X: b+ T. b# b# O1 z: s5 { in case order not filled backorder on OL_2
9 G9 J- g8 D) T move into Q_15 K, Z8 o- @, w- {; O
use Massm for n 5,1 min! {% ]/ Z6 ~9 Z5 v- H: P
send to die
" i6 B( u" m; r3 S; \ end+ m' r+ B( p( V, }8 ^0 ]/ T
end5 R) C# ~: ^. Y. I2 c6 F
这是我的报告
4 [' q: F4 s2 ?*** AutoMod 11.1 ***
0 v! m( X/ k- Z1 F" b5 ^8 DModel q
8 |5 \" J3 E# I; o8 W* j" ]Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.009 w' N) r* p: I! }
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
- }8 d3 [: A$ e1 m/ HStatistics for Process System "q"
& b8 P" _; l8 D. t. F- }! XProcess Statistics
# ?# r' d. M6 k" E/ M& r0 V; nName Total Cur Average Capacity Max Min Util Av_Time Av_Wait& x& c# m5 H: `
========================================================================================
! f5 p9 ~' O5 L- MP_in 222 1 0.32 -- 2 0 -- 126.04 --1 F7 j& ]! u) q# W- g
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --8 k5 j# f, V5 l& l& V @& E
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
, J$ u/ N) x$ N& uP_in4 0 0 0.00 -- 0 0 -- 0.00 --
0 k. [/ t) D) F# oP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --2 D3 ]: m6 P- s& z% A' p8 `
Process Traffic Limit Statistics# g* y# I. d0 K( Z, D' H& z, N; n
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
) E# }- F- n; X========================================================================================$ S- M: |6 g# E- K5 H
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --' e" P6 l! f0 P6 Y; u; P- s
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
) j' x# J- n9 d4 F/ J' p VP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
- T" Z6 {2 F0 r& o: pP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
7 v! E7 E% A% a. ]. fP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --, E1 e. ]$ q6 }
Queue Statistics
+ F# @ R( p, ?9 IName Total Cur Average Capacity Max Min Util Av_Time Av_Wait' T$ c' B% \& {1 _6 R
========================================================================================
( A5 r# b/ I' F! YSpace 223 0 0.00 Infinite 1 0 -- 0.00 --/ a- \1 n) r& g/ J1 ^; @8 `
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --/ n; I" ^2 z+ N# B8 l% ~9 C
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
2 Z4 W: |1 w1 R6 Z9 Z- CQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --6 ^# G$ V# I* I) d
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
- Y8 \( {2 v2 Z. s7 n9 {) ?" }Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --' [; [* ~4 q( Q$ T( @
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00: S: V1 | A6 p% w) `
Order List Statistics) g$ j$ o1 x" G9 Z
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered+ L4 V! N, X8 O+ M8 x9 X0 I, H
================================================================================
6 h4 t' y+ w5 E/ f7 X9 pOL_1 139 139 67.23 139 0 41789.43 1# a7 D% U; Y8 D* W, Z
OL_2 71 71 34.26 71 0 41693.20 1
* _; M2 ]" y- X. j( t6 D. p$ `Resource Statistics
# z$ v1 ]! N1 r+ V( b/ [Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ! Q5 H( N5 P& C
====================================================================================================" y, w R! b" N9 U; n
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
3 X0 _% M( l2 k4 s: G, D% p$ YM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- . }- ~+ q6 X/ U V' A d8 \) S" I
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
3 L: o' c9 E0 ioper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
; p$ X" r; Q$ Q5 l4 gRandom Number Streams4 b) P0 u$ x! c- z6 I
Name Total 0 K v3 b) ~5 e
============================
3 h% h `2 r( wstream0 4552 x. n* O8 ^8 ?
stream_M1_1 0
8 J+ @. t, d/ |3 _% Mstream_M2_1 0
: ~ E0 R3 U" b. w- \# l$ |stream_Massm_1 0
/ U# l; N/ H3 b1 _% f4 j1 c1 fstream_oper_1 0
- J F3 Z' S( U( \; e% \stream_load1_1 184 ?$ I* I0 O" T, u, w) {9 U3 n: }
stream_load2_1 76
j8 T- J3 Z: a9 Estream_dummy_1 0% o& O; ]3 _. Y- E( j0 X) L/ H
X0 c$ \9 W. K$ @: e: L8 ~! u3 L: B
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
