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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
' p- J5 L9 a0 w7 vbegin P_in arriving0 h. I9 x. B" R/ F5 Z; G% D* \
move into Q_in3 [* S ^) B# l- z" _6 V
use oper for 2 min' A7 s% b2 t- E6 w% r/ p, n
send to oneof(0.95:P_in1,0.05:die)7 Q1 v- @4 G3 b( b9 S+ i
end6 |7 Y7 n- |5 b
begin P_in1 arriving* [7 [! X5 v8 w$ F4 l1 @
if load type = load1 then
' [! I4 G" q) z+ U begin$ A/ F8 L. ` T2 h0 c: @7 d9 a) T/ q
move into Q_m1" |( ]- [ t0 X3 ~& c% w* x) \
use M1 for u 5,1 min X- A/ [" x# w% Z* S9 ^
move into Q_out1
) t, t1 i8 a: D( e8 ] wait to be ordered on orderlist OL_16 Q" N! J: _. S7 \4 Q8 I
end
" P5 F2 y/ L* c if load type = load2 then
, o' I% a- {7 x m6 g begin
. ^" Q Q' m$ m move into Q_m20 _1 F4 w) F* C5 t) n+ a& k
use M2 for n 8,1 min
4 [9 @5 M: T# I% q move into Q_out2, z$ j+ W, U$ B B
wait to be ordered on orderlist OL_2' ?6 e; o* h2 g
end. F% H. E$ B* [) _
end
8 `- j# |) I) x/ u( Lbegin P_dunmy arriving
/ V" n) K+ j' Y0 n2 r set i = 13 P+ e: O1 E8 L
while i > 0 do
3 {6 x- I: Y0 G9 b7 O0 w+ Y begin $ \! n7 D! k: r7 Z
order 1 loads from OL_1 to die
% z% E8 l. q1 }- L- N5 g in case order not filled backorder on OL_1' `/ A7 D1 M) U7 @. x
order 1 loads from OL_2 to continue
) W$ ?1 b% l* P* Y* p( q% l( q in case order not filled backorder on OL_2
, V8 O' D' _. e% R( b move into Q_1. i& r* {# d) m' j& e3 q5 E
use Massm for n 5,1 min
6 p) t! q# d4 N, _4 l) |$ q send to die
1 b9 D2 ?$ R1 Z+ Z# S4 F1 X* r2 i end! R2 c& t+ u$ m v' B
end- l0 ?$ G; W Z$ I7 }( R. h
这是我的报告
k# [" \2 P; L: W1 |/ b6 l1 t9 A7 W' r*** AutoMod 11.1 ***% M1 H- S4 k6 n' n, |& L m8 H- Y5 i
Model q
3 ^8 Y& }* V/ }" wStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
& @2 U/ H; \, m- `; B: x3 z9 XCPU time: Absolute: 42.859 sec, Relative: 42.859 sec2 |( b3 F; ^) z1 b' ?! v% ?
Statistics for Process System "q"
3 a0 }. W5 J9 B2 }0 rProcess Statistics U% K- Y4 } E% @4 _: l
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* Z. [6 ?6 W+ M7 a# f========================================================================================
; G% j( T' R) @" Q. L+ hP_in 222 1 0.32 -- 2 0 -- 126.04 --
; C" h7 y* g+ o/ U! SP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
4 v P. y1 J# @# X; @$ r4 gP_in3 0 0 0.00 -- 0 0 -- 0.00 --
3 D$ i. H9 l5 b, g; R, I. ]P_in4 0 0 0.00 -- 0 0 -- 0.00 --* _! \9 i5 E, b6 a
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --0 }4 i3 @) H9 o- L' e# g2 O9 y7 m
Process Traffic Limit Statistics
# Q; _" h/ F' V4 [: K* L: z2 q4 BName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 A! N" O5 e' e* y d========================================================================================! g8 A0 B5 v" z# W! _" N* f R
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
, `, Q9 K$ b& q& wP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
3 ^* S8 R) p" H& m9 \5 h( G( jP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
. n# p- P. v1 NP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --9 Q! w2 i0 W: e8 b- ?4 E
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
! ^2 n7 x3 w! e) C1 |$ Q DQueue Statistics# h/ _0 D* w. t& b9 H
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait. K" c$ _0 S" k0 e
========================================================================================
v0 z4 \' M( J+ G. h2 W+ eSpace 223 0 0.00 Infinite 1 0 -- 0.00 --# B! ?# u& R" X
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
; h( V2 d$ T0 e3 b5 \. T% `8 y+ eQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
" d; N ] J) d% Z4 O. bQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
" a% e5 l# q I6 u& fQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
$ G& e4 S$ {1 {. ^Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
! j' O2 h7 w7 W# oQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
- `0 i% u; K5 |4 _Order List Statistics
9 ?. d, r% Q1 }1 m, JName Total Cur Average Max Min Av_Time Tot_Back_Ordered9 z. l( h5 D0 w
================================================================================
7 O9 V0 V, ?* j" fOL_1 139 139 67.23 139 0 41789.43 1" Y4 n, J- v* n7 z9 E$ g
OL_2 71 71 34.26 71 0 41693.20 1# C- d8 G0 A1 Q& \1 r( O+ |# \
Resource Statistics4 v, }( H- q& v6 l G. ?6 G
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 8 c* {4 C) [2 ? T' l
====================================================================================================
$ Q6 h: M' ?( g; _* b6 Q5 i9 `M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
$ Z; |' `" h: D0 x( F. SM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- " N7 D: [5 z# \3 a
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
$ q8 _5 v# Q3 L4 hoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
$ e% y( U' ^% G/ GRandom Number Streams" k' P1 v' {- ]
Name Total - M s# q! X& ~# w! v; m" a
============================
' H( [( O/ M# n& m# j' h. x6 Zstream0 4559 f" d8 D) d7 \: N5 u
stream_M1_1 0
$ g/ p, r# e2 s5 y. H0 l Rstream_M2_1 0
( j; s3 A) O7 s, k" T; ?stream_Massm_1 08 E; v( r$ Z0 |* S
stream_oper_1 0) m- @9 g6 v$ ?
stream_load1_1 184
% h7 s7 p- m; X- m' wstream_load2_1 765 k$ q: n) Q, v0 Z2 _5 c: l
stream_dummy_1 0" c1 L5 U! M, [7 z# w0 [
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请问我的错误在那里?我用的版本是11.1的学生版 |
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