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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 6 I9 [8 R D/ \! M; l( n% L/ a1 R
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：! q v' @9 p2 U
begin P_in arriving/ ^: A5 L3 Z6 V# l5 \' A4 |
move into Q_in
4 N+ M" [, h5 E% E! g5 _, @ use oper for 2 min- H! a/ f* G& B) i" d7 l
send to oneof(0.95:P_in1,0.05:die): J! _3 @' q' C- f
end
# j0 ?. l6 I4 J8 s# z Pbegin P_in1 arriving
6 U1 Q; q/ ^4 G% \" I if load type = load1 then, t0 Z$ x, z0 F1 E$ I
begin
* H, E7 k K" [ move into Q_m1- K$ X. {! D2 {
use M1 for u 5,1 min: K1 K! M' g* P/ m5 |! v+ E" M+ t
move into Q_out1
* q) {$ O8 S) V F wait to be ordered on orderlist OL_1
! R4 f4 E2 M& D4 ]: {1 \9 M end
! x9 t) C# k1 ^2 B if load type = load2 then
7 l+ l2 d+ @3 e) Q# d begin; \1 n+ J- ?: z L6 G1 h/ N* ~
move into Q_m2
% {; H+ F; A% N6 k) a use M2 for n 8,1 min
* ^: s$ }/ d# Q: @ move into Q_out2
, l6 K$ Q7 Q) m/ K3 Y! X" ? wait to be ordered on orderlist OL_2" x- M0 v! @' j0 U8 n" e4 I
end; ~! ?+ |) \3 f. f2 ]* w
end% r: S; T- O7 R% L* s# ?' D H
begin P_dunmy arriving
, s) ]+ F0 Q7 t8 k# Y+ n$ A6 M set i = 1
& C8 U. y0 j6 L! t$ P, g while i > 0 do
* g& t" a$ J9 X- c0 D begin
& r9 t3 n/ j% R4 `5 M( r order 1 loads from OL_1 to die5 [) x' `& ~$ v3 A1 J3 j' y. Z# v
in case order not filled backorder on OL_1
7 t$ H) O% V4 m$ | order 1 loads from OL_2 to continue
, I2 p/ w# \6 P0 }+ s in case order not filled backorder on OL_2- z; q& W) [3 J8 ^' `( |5 ], v
move into Q_1$ j5 e0 N" g' n/ A7 P* f% N7 M
use Massm for n 5,1 min
9 H B8 ?" ^1 o; \5 S, G7 j send to die
! R. K" Z4 h$ \4 N9 `$ W9 H end
+ X5 D3 b+ s" y7 v; rend! s9 _6 Z9 `0 P! `2 y5 e) B! U
这是我的报告. t3 M$ S$ [8 ?3 J7 j' T3 J7 j
*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.006 S' u2 z- f a& `
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
+ y$ {) l6 A/ }: E. c5 lStatistics for Process System "q"* J- s% \. I Y5 M: D* W0 C" j! N; i5 M
Process Statistics
- T, N1 ]; t5 O0 h; t" |8 NName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
% f$ j; s8 h, f, Q========================================================================================
* S: \5 M& a% t. ?1 h* h1 i* wP_in 222 1 0.32 -- 2 0 -- 126.04 --
g# K [* X9 y0 D/ ^+ JP_in1 212 210 102.38 -- 210 0 -- 41725.92 --$ Y) g+ r! A: W( B! S" f
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
+ w" w l& p( A7 o; C/ sP_in4 0 0 0.00 -- 0 0 -- 0.00 --
; K* f* o7 ]+ q! Z0 }- N. w- nP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
6 i, Z2 c( M: E. K7 c, w& `Process Traffic Limit Statistics+ c! ^. S q4 R; @- {, Q
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait& |) p9 O9 R3 K5 q3 f; {7 m3 @
========================================================================================! q6 @; L @$ B S
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
: W& ]% E9 y w! ?P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --$ U0 }& _0 }6 `3 G# L. n9 `
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --& J! [0 ?( ~, e6 B5 ]0 d
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --2 W1 v" I# d. B6 s( p8 O; e
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
9 p7 w2 w: z, WQueue Statistics0 @2 g( i8 S& y% b4 f5 s) R
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
8 g' J L6 j6 n8 i8 Y========================================================================================
/ s. b1 y7 j3 ]3 y7 a" Z; QSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
" |: O+ ?- i4 `Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --7 m1 H' J8 a4 U+ K/ K" R
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 -- H6 S% F& F8 e3 E* b/ d
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
2 C& b4 i# m; [$ z3 NQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
; F O) N8 T' a+ |Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
/ \4 Q( |8 } ^7 D8 n; aQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00. m' E' X' T$ T8 U
Order List Statistics
4 \- b& O. I; g Z3 P @$ LName Total Cur Average Max Min Av_Time Tot_Back_Ordered) k# G! r' y5 m1 L
================================================================================) M' b g+ x+ g+ J$ D7 N' D7 x) |
OL_1 139 139 67.23 139 0 41789.43 1* s! g3 Z* ]; P; q
OL_2 71 71 34.26 71 0 41693.20 1
- n7 D' J/ g! v& a2 r( [Resource Statistics
' P8 c) [. T% o+ ^- MName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State : ~9 I' ^. j$ O+ p
====================================================================================================
8 f! x2 x/ _) i' eM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 9 V, Q$ h/ I8 i# n
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- , d- d6 Y3 v) c3 q
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 4 o+ q$ e: C9 y( z* P" @
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 0 b9 ^& N2 Y9 k% S: [* g( }
Random Number Streams* p% c* o7 L# {1 l7 q: m
Name Total
- h* ^8 w" g7 j/ ]8 e" W/ a============================
* [0 k1 v$ a2 l/ C% D! Xstream0 455( y# p- Q$ t2 p( `# l
stream_M1_1 0
& q; x' E# _( b" `0 W; xstream_M2_1 0
$ ~$ a! ^- f. }stream_Massm_1 05 e6 V$ p1 s/ c, S7 h
stream_oper_1 03 \" y, k* H0 `9 E
stream_load1_1 184* h% }: g& g9 |; C4 s3 Y* _
stream_load2_1 76
" _: U7 w6 S7 @8 y5 _$ F" s* N6 `/ F( Lstream_dummy_1 0 C0 Z- o" y* l# V3 Z9 p9 ?
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
