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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
`( t3 a- y% c$ fbegin P_in arriving
+ j! J9 ]0 g( { move into Q_in/ @8 e2 d7 b5 \( |
use oper for 2 min
- \2 ]/ Z$ a$ p9 c6 D/ w send to oneof(0.95:P_in1,0.05:die): D4 N( f! d7 j
end
: K: D% T! ^' T8 O* N F Q, ?begin P_in1 arriving* _7 g1 g! p; l. `
if load type = load1 then2 }* z& t. D" Y3 W' L
begin' q4 m- i( E0 H2 z
move into Q_m14 ^* |& b8 X7 x! X5 _# y4 _# a" z* d. w
use M1 for u 5,1 min
/ B4 N$ Z5 ]" Z9 q2 r move into Q_out19 M0 W( e; _1 S5 n3 s! t& G
wait to be ordered on orderlist OL_1 f' q [0 e# v3 u; a n
end
; H% @3 u/ C9 K% _' p% n if load type = load2 then# D' B% j: ^: i
begin
& y. s* ~# c# }, A/ u6 f) Y) d move into Q_m2
# l; _, d0 c& A use M2 for n 8,1 min+ Y8 b- T6 ~, w9 B4 M- Y. m3 G8 }
move into Q_out2
6 x$ v+ _+ ^3 T( B wait to be ordered on orderlist OL_2
2 d- V# h; ^3 Z: \% _* S, Y end
9 [, N% D2 N% {: Tend$ y- g3 E& W& J6 Z! F: H
begin P_dunmy arriving
7 @3 h; r* t7 n& Y set i = 1! s- a/ k* E- s, {; T7 M
while i > 0 do
) O% O& `4 M- h begin 5 I/ a6 c* R* x O3 S! M
order 1 loads from OL_1 to die
, s" Y' y! ]% t/ b, H! Z in case order not filled backorder on OL_1
( t8 l+ |- E% g8 y. E6 y order 1 loads from OL_2 to continue1 F8 O" C5 x( U. ]; V# M& V% Y
in case order not filled backorder on OL_28 R- p, h+ W8 P# l
move into Q_1
/ A# `# C* B# `; u8 [7 K use Massm for n 5,1 min
* E3 a: S# u0 t m- ~6 G send to die
( P% A, |6 v# I end
1 p/ T9 y) T4 L: A6 K0 {end9 r1 A6 i! e4 O4 K+ [8 G3 J8 S
这是我的报告
2 t, C* i& L. w*** AutoMod 11.1 ***. h( U) q& k( [$ ?/ f: W
Model q
5 E4 d+ I% Y& L. W0 c# q" YStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.003 I0 V4 {5 m7 g
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
& _0 ^2 s/ O" \3 ?# [8 @Statistics for Process System "q"
" m7 \. s; G; ~1 m9 d rProcess Statistics
% }$ _6 p! k0 w. X3 |Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
# T5 g0 `# n; j4 c========================================================================================3 g& G- r+ }& r* c6 L" G5 Y
P_in 222 1 0.32 -- 2 0 -- 126.04 --
- W' E3 U) j7 o) r! Z7 Z( ]+ v8 dP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
. \2 U7 Z9 i0 {. J# r( X HP_in3 0 0 0.00 -- 0 0 -- 0.00 --4 Q+ v' p8 O) T2 g" ]: n* O
P_in4 0 0 0.00 -- 0 0 -- 0.00 --/ e( b' }; i0 |9 t. i+ V
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
0 _: | a- D+ i W7 _! JProcess Traffic Limit Statistics' T/ g5 ? b6 W2 A- e0 z: H. w( a
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait& q" g4 `; w8 \/ m
========================================================================================2 d3 a" Z- ^/ X% B# R
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
% y p/ I8 A4 `, E. YP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
0 M- I8 A- F" S" uP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --: ~' |2 T8 [9 }. \& B: u! q
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --6 ~9 H1 ~, j& l/ w- Q
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --3 K* _4 J( t- s3 ?2 G: x7 ?
Queue Statistics6 g! l2 e: p# Z: T3 V
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
7 ]: v6 i' z2 J. m, b( N========================================================================================
7 Z) j+ d7 E+ S6 F* V4 A% PSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
: b5 G& d+ W/ Z" tQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
- k! d' L; y) r4 B2 V KQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --* Y+ [# c3 e) O* c
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --0 ?9 F+ A! y1 y
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
* z. _3 J" a6 S8 l# R% _9 BQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --9 o5 D' P9 V8 q" g# A
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
# y* F# q G9 H4 ^Order List Statistics# K1 B N; E& R5 F( [$ S
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
+ z; o0 a9 E! T( {7 ^: d/ k================================================================================ H: F4 K v7 R4 I0 |4 c+ _
OL_1 139 139 67.23 139 0 41789.43 19 d) I( T3 E/ Y/ I! w3 L. J6 a
OL_2 71 71 34.26 71 0 41693.20 1
: t, Z& ]) `* z+ g! ]: uResource Statistics4 i1 x S; C0 i8 M/ P2 E0 [' S( i
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
, E" a! d4 } T/ o2 P====================================================================================================
1 Z* E3 i, P! w3 o. V, lM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
! X( R4 a) J k+ r EM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 5 b) O# V5 |! ~2 t. g
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
# A, M$ Y: e- ~" f! y' Ioper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
1 F) | b; n. v8 I+ z8 _9 tRandom Number Streams+ g$ _6 q5 v: Y& w& q( D. y5 k
Name Total
- ]" d9 {3 c- v* ^5 D; U) O============================
! k; m+ r5 n# R( I( Y& ~" A: j+ lstream0 455) X0 p3 Z6 Q3 c' S1 p
stream_M1_1 0
8 W# Z+ ]3 y6 W2 F3 \: xstream_M2_1 0
3 n1 `, M+ Q; {% Estream_Massm_1 0
4 x8 N" ]% C: f( q% o; y0 }stream_oper_1 0) ~9 m2 S& r+ n$ T$ Q5 Q+ `! g4 }
stream_load1_1 1845 T% R0 Y6 L! h, q# s0 D
stream_load2_1 76! Q* |9 \( d& J T+ O& y" u
stream_dummy_1 0
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
