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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：$ e8 Y$ V$ {% v2 W5 g
begin P_in arriving1 |3 K$ D4 Z# H$ g- O6 S; R/ b
move into Q_in- k% z0 w7 ` I( E
use oper for 2 min, u3 z ~' O) d3 o( h" ~
send to oneof(0.95:P_in1,0.05:die)
9 p5 `- v$ u7 w# y9 [% wend- {; C# K( T* t a, S; N& c! v; k
begin P_in1 arriving
7 r, ]/ O& [+ Y2 U8 m8 r8 I/ p7 U+ C if load type = load1 then8 Q) Q, J8 r6 o3 S) R
begin1 Q' ^1 [+ F; e# v- b
move into Q_m15 b% J* _; W8 E, n" g
use M1 for u 5,1 min1 x) k! g' G7 \7 J
move into Q_out1 A: a' k% |* y$ B+ ?
wait to be ordered on orderlist OL_1
3 G: o5 u$ o8 Z7 Y" M end3 ]% H8 i# s$ w
if load type = load2 then
0 w0 t2 J* z- t8 n) I9 ? begin
" _- T6 _ P: H9 c move into Q_m2
$ t/ O1 v: t7 u) V% W& R2 M use M2 for n 8,1 min! S+ i1 D) G4 \6 ^' J
move into Q_out2
$ y: S, n3 K, z wait to be ordered on orderlist OL_2
3 m; C) c8 Z* c6 H" q end% h1 ?; b# H/ |& _) x
end% J5 R% l/ K. |7 W3 @
begin P_dunmy arriving5 O( D, P/ ?3 @5 r5 W. n$ t% m
set i = 1
0 O5 {7 x( g0 d while i > 0 do. j/ S( Z0 E1 H. R/ H6 D& U, K
begin 4 S; p1 v: r- y# Z$ D
order 1 loads from OL_1 to die
5 h- x# ?* H! R+ H+ T in case order not filled backorder on OL_1
/ A3 s# D' X. V" W4 V3 m N% H order 1 loads from OL_2 to continue& J9 N) w( c* d' C- K
in case order not filled backorder on OL_2
0 E. P/ Z4 l- w3 [: I move into Q_1
( q6 r' y5 D) Z8 e8 v8 O use Massm for n 5,1 min- H1 j2 A5 J% V- B
send to die' i3 Q& A$ B( C' h1 e
end) j: b4 P, _+ b- R1 k
end7 S3 _* n6 T5 f# X# g6 X; g5 \
这是我的报告
$ ^: H8 L) {, S. H& O- [5 q*** AutoMod 11.1 ***
3 `5 S' o( |, A c6 c4 {' ?$ X# h6 TModel q
& v& J3 o/ `( i; L- U8 h& {Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00' s* i) {) I1 H$ @0 P2 Q" k0 T% r
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
( G' w: D) S' y! h. |$ B! YStatistics for Process System "q"
! d7 T$ i! k: c8 J, @4 n" f1 `Process Statistics
3 B$ H/ a2 p9 ~0 i! B* B4 ]7 A6 ]7 BName Total Cur Average Capacity Max Min Util Av_Time Av_Wait# r) m- f% N- h: R2 c( P% {
========================================================================================3 ~' k) h6 I8 x" H& _
P_in 222 1 0.32 -- 2 0 -- 126.04 --: g' j5 A+ R! j6 ?( E9 [2 V9 `3 T
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
5 q ]3 E. h! ]P_in3 0 0 0.00 -- 0 0 -- 0.00 --
- b( G- S5 s* Z" q) G, v7 iP_in4 0 0 0.00 -- 0 0 -- 0.00 --# q( [1 `8 K1 p4 H/ T
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --* W6 Z& k N% ~# s' h. k) ]
Process Traffic Limit Statistics
+ z1 U. @ f( C) K1 @Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait) ?+ T( U! v8 G ~
========================================================================================; u% z0 h0 \7 {- M0 y6 x) }
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --% R8 _/ L, C- @! V- H5 w- Y
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --: D8 j1 a: e& \4 ], C4 r
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
$ {9 ^. M' h, X% {. Z0 }1 p8 s6 s9 hP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
- m5 j. n/ Q! b2 h1 U9 |# LP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
6 x) K, s F/ A* FQueue Statistics' F$ x# q+ |9 M: `$ H
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait+ c4 N& z! E* g
========================================================================================
: I! D, k) F; t5 ~9 G0 T0 F5 kSpace 223 0 0.00 Infinite 1 0 -- 0.00 --% B% _+ M4 J3 v" M4 t' C% g- W
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --7 a8 V7 \8 I4 a. u8 b/ `, F
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
" M! K: e' n% M+ |# M1 MQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
0 m9 Y" N4 T" L [+ OQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
% P& d) q. e3 m* fQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
( p4 K! O" g3 `: zQ_1 1 0 0.00 1 1 0 0.003 277.31 0.006 Z- _, u8 k0 O# u# E
Order List Statistics
2 O N% u7 d1 p2 t% M, v7 FName Total Cur Average Max Min Av_Time Tot_Back_Ordered
, Y0 U$ b: w6 F0 S+ s================================================================================
( u7 @5 P+ }) h! H0 YOL_1 139 139 67.23 139 0 41789.43 1+ I, r6 f C% |+ U
OL_2 71 71 34.26 71 0 41693.20 1% |! q3 p8 X% f
Resource Statistics6 U8 f7 g, V4 N5 ^0 Y/ ]3 m3 G" U, N
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ! x3 D% j3 N; g6 T: p p5 M& {# ^
====================================================================================================
+ ]6 Y7 a* X- ^M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 1 f$ k' [' h! |3 e5 e
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
% x, O: c' p2 qMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- # X" R& b( w2 y5 _: Z
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
) I5 G' s% X" }# @" ^Random Number Streams
1 \$ s* Q3 ^. D' h: a; gName Total 3 k. [, c" f! U# Q; U& m
============================
9 o2 G$ c7 S, m6 u9 k; ^9 d# N6 {stream0 455
, {2 I5 W$ q- [6 Astream_M1_1 0' m1 I9 k$ f! \$ m+ [8 o
stream_M2_1 0
' ], O$ V+ v3 A- Pstream_Massm_1 0
! f5 N, ]" l9 T7 H& |stream_oper_1 0
8 {7 v( Z2 E- d' \0 c: Dstream_load1_1 184' v5 o u6 s/ _( \
stream_load2_1 76
# q+ y$ _& S: N& V" Qstream_dummy_1 0
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' Q+ D. n7 v+ V- H请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
