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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:7 J1 V9 e& k# l
begin P_in arriving" \0 Q( @7 I5 U5 U
move into Q_in# [4 Z. [: R- h* l6 {; D8 r
use oper for 2 min
& G- g; E! [7 V F( I" z* c) {2 ^ send to oneof(0.95:P_in1,0.05:die)# P5 h7 @+ `( T' t3 V7 ^1 f* W8 r% N
end) d+ ?8 U$ m$ s) _# P0 r5 I
begin P_in1 arriving
' c; ^* A7 u% c8 k! w: l- I if load type = load1 then
0 w) w2 q2 ~8 f) { begin/ q9 O. d" R7 p) p" w( |# x. M
move into Q_m1
# P6 ]5 D! r" I+ q2 I/ z use M1 for u 5,1 min
9 v* z4 `- s- r" y! w* K move into Q_out1 Y# w) b/ X' v, e
wait to be ordered on orderlist OL_1
- F4 B8 f2 q" N end
6 h6 S' {. z/ W' ]) z. U if load type = load2 then
! U7 D7 T$ v8 \ h: f7 z# i; X begin; C( t8 ?" ?) S+ L8 {7 H) N$ k
move into Q_m2' @8 s# ^, a! i' W) t( v0 c) }2 ~
use M2 for n 8,1 min
+ D& p- t2 @! Z" k, W move into Q_out2
/ P- F! F! Y1 I: @* N/ z8 A9 w0 z5 h wait to be ordered on orderlist OL_2
; V" V1 \4 ^- f: u. p3 q end
; m0 V/ R+ K3 Q7 S6 dend' C5 ]4 c' t, C( Y
begin P_dunmy arriving
; `4 t* ^4 f5 c" y; }( h set i = 10 F8 V$ w1 p' z! g4 @$ c" o( H
while i > 0 do
/ H; A, {+ I1 j. U" [5 r' G$ h begin
# I3 N* H1 z* V6 m# Y- P order 1 loads from OL_1 to die
$ R1 E' e2 @) f: _2 A# _! p6 } in case order not filled backorder on OL_1+ ?* b- m8 b. _; j5 ^
order 1 loads from OL_2 to continue
( Z3 B: w; ? H- u K* z( S+ ?. |" u in case order not filled backorder on OL_2
2 ~* P1 Q: [' E! @/ U+ R% L move into Q_1
, ~8 u& r5 v( [& ^, d use Massm for n 5,1 min, c$ k; r# h$ G |
send to die( e% g N: V" s; p: }% ^$ G) Z! @
end4 _. }0 u% A* o+ O/ K: Y
end s- B6 Y2 G; _# U- c
这是我的报告7 c* G2 {5 C% D8 U. L, G
*** AutoMod 11.1 ***
; L" k/ ?$ {% E6 _4 Q& ~6 OModel q
$ z# r- q" H0 J7 N5 z4 I) T: sStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
3 S3 o( E4 P3 ~1 o1 zCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
+ Z% R7 l) x6 M) D c% n, ~0 Q: R/ tStatistics for Process System "q"
* d0 H1 }8 u0 s0 \Process Statistics
1 \* {6 {# r+ l4 M& z- T) cName Total Cur Average Capacity Max Min Util Av_Time Av_Wait; l3 l" k9 x5 S
========================================================================================
$ a1 H, b6 ?/ r5 V1 n* ?% L- pP_in 222 1 0.32 -- 2 0 -- 126.04 --" ?6 I& v! z3 L' ^8 f2 K
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
! ]7 t9 r/ U+ U4 O! i0 C vP_in3 0 0 0.00 -- 0 0 -- 0.00 --
; t- @3 v2 K4 R+ {3 X; l3 KP_in4 0 0 0.00 -- 0 0 -- 0.00 --( B d N* g" V* w% K7 M
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --, D( X* K6 x0 `
Process Traffic Limit Statistics& h$ C" k: I! k! q1 q8 [
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
2 R% v j1 }* j========================================================================================
% E( Q: |6 u. RP_in 222 1 0.32 Infinite 2 0 -- 126.04 --7 ]3 c, c+ X$ p, [2 E% M
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --- G( e: ^1 ~# D1 d
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
) b% L9 E6 S0 ~: ^9 f) d8 E4 [P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
% @! @" Q: g5 m. kP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --8 A% }1 k- u% c( _+ t
Queue Statistics
3 A) b4 e H/ l, r( TName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
: {4 F& q- A2 d" k* c========================================================================================' \, Q1 @9 @; p# h: C! p6 k
Space 223 0 0.00 Infinite 1 0 -- 0.00 --2 \/ q1 d, h4 _8 O* I! m
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --5 W. C/ N: b* `6 Z2 U0 t
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
( \2 g! V( I% i3 QQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --6 |% m* _! Y& W; M$ N
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
1 c5 S' q8 e1 K( _) xQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
3 K- Q F ~' Q7 QQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
1 w7 r* R* X' t( }- sOrder List Statistics
* N& z9 A* p2 GName Total Cur Average Max Min Av_Time Tot_Back_Ordered
: o* [( R- A" z5 U# _8 x================================================================================4 Z$ P( \" X5 E1 a6 T
OL_1 139 139 67.23 139 0 41789.43 11 g. z2 a% f, B' p. ]
OL_2 71 71 34.26 71 0 41693.20 1
+ Q4 E3 G; W$ V: w: @6 u1 oResource Statistics
* n/ g7 n5 B; e: _9 V" R% w& RName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
' Q$ U7 d! ]+ L S2 q4 v====================================================================================================
# V+ _: Y' R! t# q u zM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 3 A% g* A& J% x9 }/ e' C* T4 y
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- - C' ?6 r3 n# j# x+ h# G( E
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
' F' @) Z4 b) P# |4 Z+ Yoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 4 K# G4 m. l" c0 D' [- V
Random Number Streams( q$ \: G* n& @) F5 r
Name Total
/ [. j9 t ^- R- J% a============================5 S5 J7 g+ l9 U
stream0 4555 J( H! k1 t, w. S4 W, T" ^
stream_M1_1 0
( L( v# f* P& p( F9 g: k$ d, Istream_M2_1 0! X& s/ T' @; `/ C* B- G6 a9 `
stream_Massm_1 0/ L1 t B3 H4 E
stream_oper_1 0
4 y0 F5 ]2 @) G* b1 ^: lstream_load1_1 184
1 @% r! c! Z9 a4 w$ k# N4 sstream_load2_1 766 G. D" t6 _/ B" w1 N
stream_dummy_1 03 \& _4 H) [/ E5 |6 P) Y0 [
& Z7 d' j7 q' _请问我的错误在那里?我用的版本是11.1的学生版 |
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