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本帖最后由 soso001 于 2014-12-17 14:53 编辑 * Q) r- |6 p# W" k% }. t3 S( N
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不好意思,打错了个字母,呵呵呵! t* L. X2 r+ C* H
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示' J6 x, n& ~4 Q* e3 l
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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. y8 [6 q- Z4 D6 l N j,k,nstep,c, scheduleteps,mincomptime:integer;# a% E6 J V1 _9 w3 I# P. Q
M:string;
# z+ u1 L% c6 S/ M2 {8 M selecTab:table[integer,integer,integer,string];. A" N- R8 y- k
do
# s/ F! ?. h+ t7 e initorders;
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scheduledorders.delete;
; V, _. V" U7 W3 _- H. L) U1 ` seletTab.create;2 p, _# W! w' ] H
; C' i$ K5 |4 x& Q* n: i$ D- A orders.initialize({2,1}..{2,*},0);
9 r* U2 x- m, i! V; n orders.initialize({4,1}..{4,*},0);* J' N' l6 Y% k s) M
for j:=1 to numorders loop+ [7 [' z* `; p% f; ^) C' k
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);% u8 R/ g7 r! k$ L: G9 ?3 q
1 x! t- f, q. v9 F --XUNHUAN% R" c* l, s6 k/ e1 `# i
for scheduledsteps:=1 to numsteps loop --! a: j; B% H0 P6 V9 m
selectab.delete;
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: b9 r2 N+ F- Y, o$ P) V for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
' `$ z: M1 o+ q7 d" H if nstep<=orders[3,j] then
' P$ {4 p k: |& ~ selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];2 Z5 S9 \" O$ }8 N
k:=k+1;# p1 |7 }% z6 [% d' l
* L- e7 y, D2 _: S" t end;$ S" W, }" n4 {$ }4 p
next;
& x* X6 ?$ r! n! W mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop N1 u4 f+ ]# W+ `
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if selectab[2,j]<mincomptime then
( z* B8 F* Q$ t0 `. j% i5 O0 ]8 v j:=j+1;5 ^0 p" G- b) `; S0 h$ R3 T
else
& v$ K! R. s5 {2 m8 H% g+ r selecttab.cutrow(j);
7 x! o5 W/ n0 x2 n0 h' n, Q end;
4 M# j% f3 I2 `& t/ S# W end;
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& u" k" q8 M/ w j:=selectionrule(selecttab);
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1 p: D$ |5 I2 N* K# }* J nstep;+orders[2.j]+1;
x# T' W5 a3 H; t orders[2,j]:=nstep;
; Z' J' B. J5 V m:=orders[1,j][1,nstep];" I# l; ^! n! ]/ R: b
c:=orders[5,j]+ u6 I- O, X( }$ \
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
4 V. R5 f" _# ?4 ~) u) H/ a/ c scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep); h5 C1 K, i* R& {6 ]# _# @
for k:=1 to numorders loop
3 I9 j- S0 }2 U Y) [7 W9 g& y nstep:=orders[2,k]+1;
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( z6 T# ?% i% p9 i3 Q1 j. V if nstep<=orders[3,k] and orders[1,k][1,nstep]=m7 }. x0 i# k' B4 G$ E5 `
--
, y! M& z/ @# {8 d+ E then
% C e# {1 w2 S" x! C orders[4,k]:=max(c,orders[4,k]);
3 S q, Q1 o! @1 { --
7 c8 X' z2 w* |5 _ orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
. O7 k6 [3 B* H. B --
$ w$ r) f3 O' P. H6 U end;8 m- l& d9 O! E8 i- E2 @
next;
# f7 u8 D. W" f( a) F; J nstep:=orders[2,j]+1:, q0 j, G5 l. l' o5 P& O* n
if nstep<=orders[3,j]7 N$ p( W0 j O) e! z2 {0 v5 w- `7 D( w
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then
1 l# T9 h/ O. h% v+ E orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
* _- T5 A0 c9 ] g orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
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next;; X8 O( `9 s. E3 E8 m: x: B3 ~4 R
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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