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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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' g3 y& B% l" n& D9 h: Q' \不好意思,打错了个字母,呵呵呵!
7 c, z" v! G0 t! X# q大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
/ ]/ [: j5 k' l m( n6 H“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!4 e) G3 c2 o& d+ o( p4 `& ]& R
is
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M:string;
, N# ?5 N$ Q3 U4 \" a selecTab:table[integer,integer,integer,string];4 t1 ~( d7 s- h% A( R7 Q
do& O3 p; T7 s0 h3 y0 e' H
initorders;
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. _2 A! |* B$ X7 U; S scheduledorders.delete;
) S0 S A% i( E5 J* _$ t seletTab.create;
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. W9 q5 C4 l2 A orders.initialize({2,1}..{2,*},0);, Y. h4 Y: R" |
orders.initialize({4,1}..{4,*},0);4 g! r7 m2 ]% [0 c% X P$ X: c% ]
for j:=1 to numorders loop; S9 v: k4 { n7 C
orders[5,j]:=orders[1,j][2,1];
2 [" ^8 L/ r' _, N next;
4 h/ Y8 X. e% k O- w1 ?% ^1 s occres.initialize({1,1}..{1,*},0);
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1 i) V( q' u# Z, `5 m5 j/ z --XUNHUAN9 q& _: v7 T3 C$ L9 k7 q( g- {1 N: ?
for scheduledsteps:=1 to numsteps loop --. o, ?3 [- z" P, W. j! _$ v
selectab.delete;
' f, f8 g/ o4 C* K' g% v0 q1 `0 t k:=1;; L; K7 w/ N9 x& J6 K
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
$ V' U$ O5 S1 B2 R if nstep<=orders[3,j] then
0 D; A. K: \4 Y/ h! k Q selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
. h# R8 z; S3 V: m! W. S k:=k+1;
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) a I6 R* \( G end;( |% y- \1 X- N* e1 g
next;( t3 M1 K+ e0 c9 H4 r& C
mincomptime:=selecttab.min({3,1}..{3,*});+ V. p. _/ W7 m- j8 P! S
+ s! ?) z2 ^' V% l from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then) z' C- `% d# c: U) w; f
j:=j+1;; U2 g4 `+ H2 a+ d3 S7 q' ?
else6 h: `% [$ @$ _5 q) l, a( V' Q
selecttab.cutrow(j);# G6 m8 B7 |) ?: T& Q( u
end;
`; N4 Z ]2 Q+ I end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;" {" q" N! E& I: T
orders[2,j]:=nstep;
# N7 u0 Q! t9 y! E# V$ u0 x+ Z* t m:=orders[1,j][1,nstep];
+ o% i8 A# H3 H r* |3 k' P c:=orders[5,j]% f* {$ n7 B) u
occres[1,m]:=c;
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6 H" h& I6 k$ n( R+ q( m7 t --jieguo:start,end,res,job,step0 f' S, e- L& t& p3 a: C
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);1 p& C7 f; d* y& V
for k:=1 to numorders loop9 W( l0 D' S. j' o9 L& |% y" d
nstep:=orders[2,k]+1;
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. \, U; E1 A' K6 F0 O/ G. [ if nstep<=orders[3,k] and orders[1,k][1,nstep]=m+ l) Q- H4 b6 d) J" J3 M7 O
--
6 `1 f4 J" l, K- @5 d/ `3 g then
- w* _$ O% U6 {, g0 Z orders[4,k]:=max(c,orders[4,k]);# [, u. @ a- F
--3 o4 _( D3 P( V# W& _5 d4 D) J! D1 W
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];7 m8 C6 N+ ^1 r9 j: U4 ]! p f
--& `- P9 T3 C1 }" c6 y2 p
end;: F' `7 Z3 t7 X5 D. h
next;
$ K! ~7 j- I+ P" l! g6 S7 w nstep:=orders[2,j]+1:- W- P7 ?- o& J& Y
if nstep<=orders[3,j]; p+ V1 |% G2 t. f3 v/ s
9 g7 I7 K& h# U" y& W then
5 W+ |. s! F2 @% }& ~4 K# P orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
6 m1 l- S; T V- K orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];& Y3 @; M2 x% h' A6 l/ X9 W
end;! `1 R- ]4 r' k/ u. I* m
next;
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& H$ o! ^- f) G3 C6 x print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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