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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!9 M& Z3 a0 J! j9 _1 u6 ?% b
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示* k! O# p9 Y' G; v0 n; F
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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* s! z( U6 f) ~" I9 c! w' o j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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- B7 |3 B2 C) _. c, M initorders;
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$ T; k; b0 U! M2 w: l) P+ T6 U5 c6 C scheduledorders.delete;3 C" S3 F" y3 u7 F: H# ~ s( k8 _
seletTab.create;
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/ b1 j' L! E8 a3 J c E orders.initialize({2,1}..{2,*},0);
8 |3 {0 F, ]% j% ?2 A; z" A$ n orders.initialize({4,1}..{4,*},0);
: }" ~/ ]# ~/ i |0 g: ]) X- @ for j:=1 to numorders loop' D6 g. _( `( d% M6 ?; {
orders[5,j]:=orders[1,j][2,1];
% [0 J4 p, k/ @5 S; A+ | next;
2 I* L2 O2 |5 r7 n; i3 |7 u occres.initialize({1,1}..{1,*},0);
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--XUNHUAN, W( e4 `$ Q) x# s$ ?5 a; D7 g
for scheduledsteps:=1 to numsteps loop --
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k:=1;. ^( X7 K9 E t
for j:=1 to numorders loop0 \5 r8 l5 `% |) ^5 V3 v* E F
( F. ?1 I1 z, R nstep:=orders[2,j]+1;/ E& E: L( o0 _' Q
if nstep<=orders[3,j] then, g, P( x5 a' h& x, y2 i
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
/ ]( r' q% L6 C$ t% L/ ~' b* {0 L) R k:=k+1;
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5 f3 v3 } R, h end;% V0 Q0 R& O. M+ M X* }: D# H
next;
0 ~* C" r* o9 ^; e2 O mincomptime:=selecttab.min({3,1}..{3,*});: `' U; X2 S1 v. r, H! z
/ p7 L' ~% O! r3 y1 r from j:=1 until j>selectab.ydim loop4 b, f* g: @2 f4 C: |
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if selectab[2,j]<mincomptime then2 r7 r# P1 ]/ E. |6 Q
j:=j+1;8 D" i# J2 ]2 K% ], D
else
6 H* }# X1 Z9 u1 {- a+ b2 T selecttab.cutrow(j);
$ }6 P+ _2 ~( A' h end;
8 s; E) l( A# C0 l4 T6 L7 O end;
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4 a4 B1 B1 \) ] j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
2 h7 ]4 {2 D+ d9 @( ]. E6 Z orders[2,j]:=nstep;& K/ z4 F9 o4 n9 ^6 q
m:=orders[1,j][1,nstep];0 Y& f: c v3 ?+ H( G# }
c:=orders[5,j], d) Z3 m7 o. C$ s% {' ]
occres[1,m]:=c;
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! [ o7 x6 e" e --jieguo:start,end,res,job,step
) g# T0 L2 |9 ^ scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);2 @8 w6 C8 Z% ?8 t! d
for k:=1 to numorders loop
5 I$ A1 Q Y6 i& P5 p$ b nstep:=orders[2,k]+1;
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8 l% q Z5 U! I7 P+ F8 W if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
% X3 d* q; |8 g" b3 K3 @ --
8 V: J4 a2 {8 m4 H$ B then
& S& V7 g3 K- [& s+ o orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
; |! } r3 a9 H1 W* A, S6 r8 |; h! w2 z next;" ?$ ?" L1 s) j2 W: c
nstep:=orders[2,j]+1:; T. s! N5 l1 U
if nstep<=orders[3,j]5 T# O! q" [: \: `) m
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then. {* r6 C6 K- R) ^. Y1 r( V5 X* F
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);# Y# A7 y$ W. W" }. {# ]
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];2 N! I4 G4 _/ f* K
end;
! w6 C' M `- {5 y next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});5 O, R0 K. Z' x& ^7 V- Y
mygantt;
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