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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!; x5 c* ~9 S4 \! ~5 C
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示 O; t1 l! H! z8 H3 a6 [' G v
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!0 n$ V4 B7 o9 B( q. N
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j,k,nstep,c, scheduleteps,mincomptime:integer;' j( P% e8 N9 B( g M k
M:string;3 ?+ E- ]: G6 }6 R
selecTab:table[integer,integer,integer,string];
C' B# \# H& ~% J# ?2 C. ddo
6 ?5 T0 ]( Z7 f; M6 E* k O+ \ initorders;) T6 n, A, b: p& c. L
8 ^/ d3 H+ t: [, p scheduledorders.delete;' I" b7 A5 r, O5 A! L% _/ x! }
seletTab.create;
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orders.initialize({2,1}..{2,*},0);9 W6 I" o- q* P x- [& `( H
orders.initialize({4,1}..{4,*},0);
. _2 _, }/ F7 R, k V( ? for j:=1 to numorders loop/ F' ]+ K6 Z4 g. J% F$ E; s
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);6 W. n4 H* ]. f! \9 `
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--XUNHUAN9 t4 {+ `/ S% F3 e0 a
for scheduledsteps:=1 to numsteps loop --
- I7 X9 S5 c' N, H/ L5 l. t selectab.delete;
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for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
( x5 J' T7 Z$ P/ ` z if nstep<=orders[3,j] then
2 C* G" l9 V4 c selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];4 H6 p0 N/ w# M
k:=k+1;
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next; @9 M. W9 W% b: K9 W) q- X
mincomptime:=selecttab.min({3,1}..{3,*});& U" [2 U( q- o/ V( Q, N
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from j:=1 until j>selectab.ydim loop; G5 |/ e2 t8 S6 n
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if selectab[2,j]<mincomptime then' N5 a0 x3 ?1 `- M3 w
j:=j+1;' N( r5 w% w8 \' B" R
else
; [" z7 G. `' u4 `5 U+ Q selecttab.cutrow(j);9 g2 H; e/ K7 P9 g0 K
end;
1 Y; M& c B8 T/ c end;0 K& s4 @/ _' n
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
1 i& ?! z( o- Q( L( v- v orders[2,j]:=nstep;
6 L$ U, C. F: `7 `5 W+ u1 S m:=orders[1,j][1,nstep];
@5 H: o0 U6 S9 p c:=orders[5,j]
% J, T0 K m: \- x occres[1,m]:=c;4 e. t5 Z& m/ E A2 M& a5 G2 j
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--jieguo:start,end,res,job,step
4 L2 V8 v/ F: q7 a% n scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
' }2 l+ _( {7 J" a% }, ]3 _ for k:=1 to numorders loop
: p9 y+ N5 l2 A+ Z1 A3 W nstep:=orders[2,k]+1;( j( @' d# |8 O' r
8 l* Y5 q& ~! k( u6 X5 c if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
% N- h7 C8 S0 T4 y7 d --
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orders[4,k]:=max(c,orders[4,k]);( f0 ?; Q$ ?6 G
--
( v2 S5 B7 g; n! [ orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;( z& m! @5 B3 R" @0 \
next;8 g6 O! n& s0 i! P1 f A9 G
nstep:=orders[2,j]+1:
8 x6 } }& r& r6 a' u+ j1 o9 a: Q if nstep<=orders[3,j]
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4 e. h$ k- G7 N; v% \# M8 m then
1 w% Z! x3 r2 q orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
! S* `5 P. u6 @* D+ z7 t orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];8 |' U* U7 u% S+ C) |# G& u
end;
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) z' {4 g: I# ?# U' M8 X, N7 m/ k print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
% W1 \; d8 [( e. ]. g% _; v mygantt;. J; }$ `' l; D( m: u
ens;
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