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本帖最后由 soso001 于 2014-12-17 14:53 编辑 * C9 {/ H! n' a0 ^4 h% @
" D- A5 x' d8 R不好意思,打错了个字母,呵呵呵!2 \# s: T$ E( G6 p
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
1 v; x4 B: g! w7 P“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;' t0 c9 s* S" `& n9 j6 y( Q
M:string;( i4 t: v# h! ^) K9 B" l6 J
selecTab:table[integer,integer,integer,string];
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initorders;# e; |' s- ]2 ^! O# H+ y g: n& i
# U' a% G( g+ d; O5 T scheduledorders.delete;
% f$ `7 `# l1 K) w* y5 L" Y seletTab.create;4 T# f, P/ n5 [) A
& I1 s; o: S8 v' r2 | orders.initialize({2,1}..{2,*},0);
6 @" X ?8 S+ u% W orders.initialize({4,1}..{4,*},0);# U7 y* ~$ g" b8 `& g/ x, \. W
for j:=1 to numorders loop9 A' x! D, S# ?; Z- f6 b
orders[5,j]:=orders[1,j][2,1];
+ W7 g3 T0 [: x+ ` next;% D; [6 D1 h# U2 Z, D0 D
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN+ R) u+ x% p8 w7 A
for scheduledsteps:=1 to numsteps loop --/ O6 L" t4 y6 @+ _+ A. ^# J. k
selectab.delete;
+ I) @2 L) G3 e* ~) D1 O! k) ` k:=1;
: A4 f/ g; E2 O) k for j:=1 to numorders loop: K/ _5 r* k. ]& c" `8 [/ v. M
% m: X0 `7 }+ `1 t; O8 x nstep:=orders[2,j]+1;8 i$ [8 b* M6 H8 D# p# [+ A K
if nstep<=orders[3,j] then
3 F/ _* t2 }# W selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];2 \& q- {1 I, w: U, E) M8 f
k:=k+1;
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end;9 F; S$ q- U+ u, x* Y: s2 [1 K
next;* p5 {) ]2 T( Y$ l7 Z
mincomptime:=selecttab.min({3,1}..{3,*});2 K& N3 U C5 t
% K- l8 E G7 { from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
; ], ~8 `. w, D1 h2 v8 e6 w j:=j+1;
+ R4 O0 y0 Z! j0 F0 \ else/ v- c4 E" s3 E" v2 X7 G
selecttab.cutrow(j);5 k9 _, E0 J' Z8 S
end;1 B2 B' J" X4 ^8 g8 v
end;9 Z, K3 r& ~4 a1 h8 x, Y/ u- g
/ c1 f2 @; v V( S j:=selectionrule(selecttab);: Z5 @; B( e% \% A, G
$ ^, \0 o# u* O6 [" }) y nstep;+orders[2.j]+1;) |& E/ O& S' d1 F8 ^9 ]& ]" S
orders[2,j]:=nstep;
- P2 C: Q1 `$ T( z. P$ q m:=orders[1,j][1,nstep];
j/ e$ ^2 @" |& [4 t$ \' g c:=orders[5,j]) i7 n0 q& v: v5 V5 T1 P& X( _! z ^
occres[1,m]:=c;
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/ K' W# v6 c# \, J --jieguo:start,end,res,job,step8 L! o+ B9 L; P
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);. ~+ l0 A6 G6 k- Y( `
for k:=1 to numorders loop- [. K/ v7 L5 y( h' c3 ]" p0 ^
nstep:=orders[2,k]+1;
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; [7 s' k- i0 |8 b4 e" i if nstep<=orders[3,k] and orders[1,k][1,nstep]=m( b& q' k5 L* S) h9 r
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then; u- _$ |! m+ ?, X
orders[4,k]:=max(c,orders[4,k]);
) B* d R# U, f! i2 P --
* }5 O+ k& ]: a' M% i; E orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
7 x7 q( P8 P8 A$ ]8 X4 L2 X9 Z next;
) }/ A' g: W+ [8 q1 ~0 n nstep:=orders[2,j]+1:+ K' n6 [4 J4 P Y) q
if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);, w r4 e6 C: V' o5 Q5 u( N# L
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];: `! X$ Q7 R4 D# p$ q) b/ y! }3 r' Y
end;1 H! {8 Y) Y$ ]; K1 P9 i
next;
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9 W& c8 M6 {+ r2 A% j. S: i8 ? print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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