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本帖最后由 soso001 于 2014-12-17 14:53 编辑 3 A. o/ j, i4 d$ w3 z) J) e# @
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不好意思,打错了个字母,呵呵呵!3 C: @1 G' b. O
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示& `$ U& i) H5 y( f1 n$ V) l( {- G
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!5 |! g1 J+ u, l/ X7 ~
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j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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9 U* n6 {* s6 [: `$ M( h) k8 f initorders;' P3 p! L. ?0 x: h' t X. f
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scheduledorders.delete;
+ V+ i1 i+ L7 u) e: t6 b- s seletTab.create;- n6 f9 z' a& W: |$ s5 ^: {
5 b. K" o9 m( S# w& g- h orders.initialize({2,1}..{2,*},0);; t0 ~. Q/ R! n, l
orders.initialize({4,1}..{4,*},0);4 Y, l" y9 n) t* X/ L8 f
for j:=1 to numorders loop8 Y. X# q$ r- W' T6 A" L0 O
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);) B* v4 J% l% s7 I0 a
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--XUNHUAN6 E, H1 F/ O" H- a) |9 U5 f2 i
for scheduledsteps:=1 to numsteps loop --
/ k7 j' { z/ h selectab.delete;
6 {: q4 ^; W6 V+ K) l k:=1;
# a5 O8 J6 B! s3 c9 J' P/ ? for j:=1 to numorders loop# P( g0 |" `; H! k$ G, [6 C
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nstep:=orders[2,j]+1;6 g4 Q) K. w8 S" o4 C
if nstep<=orders[3,j] then2 E$ S. B3 A: b D; J, z
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
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next; c% y; h$ j9 _) x& k2 E
mincomptime:=selecttab.min({3,1}..{3,*});% [" K! L* I; O! e. r% y
3 ^$ @ u; U" r* c from j:=1 until j>selectab.ydim loop
) [7 H+ Z6 Q1 |" {
' P) `! D6 E0 q5 h/ K; K% T if selectab[2,j]<mincomptime then
; t8 X+ r0 M# E! V j:=j+1;
$ D, n. m; m5 v else
% X0 c; e" |: _; W selecttab.cutrow(j);
# L7 {2 y) {3 |. N: X end;4 y4 O0 ` M% ]( p6 ~7 x) k7 ?
end;
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$ ?" o) Z# `0 Y: C& Z5 v/ @2 m2 |1 l+ u j:=selectionrule(selecttab);
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1 n% C$ N- h5 C) t4 M* j* U nstep;+orders[2.j]+1;
# J. H6 Y+ Y) I- c+ b orders[2,j]:=nstep;" Y7 o3 M1 `$ A
m:=orders[1,j][1,nstep];
* v* q# h( @2 L* j1 o4 O. e4 _ c:=orders[5,j]
/ o. y* G e1 B/ ^' o occres[1,m]:=c;
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* o" ?( f$ ^3 c+ m* K --jieguo:start,end,res,job,step3 m3 b1 z: c! n* H- E
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
7 X8 X& I1 f# _" L \6 n- ]6 ?4 H E for k:=1 to numorders loop0 c( \4 I" V& `6 V! P$ m9 a
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then4 e; E6 @' W1 ?5 \. i8 ~
orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
( k" {) P" f Z' M2 G --
$ t b$ Y& i% s+ {& h7 b end;
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nstep:=orders[2,j]+1:( U% |' p* d" r z e! C) @0 ]" ~
if nstep<=orders[3,j]; n5 t- B0 }0 f& [
9 H1 [6 S5 U1 P5 z then
) t- v# O/ t. u orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);+ R, ]# U6 Z2 N, K9 a
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
" B1 `: d) Z% l: h end;
R, v3 v9 b$ a$ }" Y6 a next;
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4 p: q3 K7 W/ [1 n3 k: O6 l print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
; M, m! h! G3 X: }/ g mygantt;
2 M; H, X0 d0 g3 y* z ens;
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