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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!' `3 j) k% {5 p @
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
s# D8 @. p5 Q1 W" t“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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8 a+ ~: A( x3 d' R" C j,k,nstep,c, scheduleteps,mincomptime:integer;6 l" r0 R, f9 P
M:string;
$ d3 Q0 h* w8 j U selecTab:table[integer,integer,integer,string];
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initorders;
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4 ^' M/ k9 o7 Y* j1 ~3 u! A scheduledorders.delete;
9 N R* s- Y6 \6 d M" T/ E seletTab.create;
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orders.initialize({2,1}..{2,*},0);* ?9 l2 Z K' ~( M4 p4 ^' d- d, }
orders.initialize({4,1}..{4,*},0);' _& I O+ q- q
for j:=1 to numorders loop
9 n' L3 k1 E; }) r4 M8 @ orders[5,j]:=orders[1,j][2,1];8 t$ `( T; m8 H/ X# C8 C8 d0 B! B
next;
1 W# |" B( i. a1 s! j. W! _ occres.initialize({1,1}..{1,*},0);
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--XUNHUAN2 Z& s( V. Q* m5 N4 s- l5 P
for scheduledsteps:=1 to numsteps loop --. o: R6 I3 Q# f4 t8 W9 B+ Z$ V
selectab.delete;
$ S: {1 J8 c- R1 G$ a+ ]3 k7 y k:=1;
1 o! h) I( G4 u6 r& W for j:=1 to numorders loop
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2 m; _& p# w7 n* K% Z nstep:=orders[2,j]+1;
8 s s. Q+ K0 U) n) K1 l if nstep<=orders[3,j] then6 E+ ~/ T& ?4 W+ q
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];. l9 w1 \* @1 P
k:=k+1;2 G% }# T) Y- G; A& P6 ?6 P
& R, s5 S& H$ i& y+ N end;+ c) l( j, J C+ w1 ~
next;
6 ]# G: G5 k2 i7 H. v* w, T mincomptime:=selecttab.min({3,1}..{3,*});* a2 ~5 A0 D! {4 Q
: E% B u- t, H3 }, | from j:=1 until j>selectab.ydim loop
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4 q$ u% X) j$ a if selectab[2,j]<mincomptime then
1 G9 r! X/ l2 ]5 A0 h, O2 S j:=j+1;$ n' R2 b9 D: V) h! c9 p9 u7 e' P
else, v( o# z6 |6 r) ]
selecttab.cutrow(j);
2 o; c1 S1 `1 c( F end;
2 h. {6 i9 {4 z# b end;
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7 z& q1 V- j/ ~2 ` I2 R# `( d, k j:=selectionrule(selecttab);
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$ @9 V9 Z" w7 d! n& y nstep;+orders[2.j]+1;. z+ u3 H( B5 m. E
orders[2,j]:=nstep;
4 D2 @) I0 O# E, w+ V% o m:=orders[1,j][1,nstep];9 B$ B1 f. J! G) C
c:=orders[5,j]
8 i8 v# K! W, z, r occres[1,m]:=c;% T' _* A, p% |; I2 |2 v" m
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--jieguo:start,end,res,job,step: G0 ~: c- K" z4 |+ e1 V( e, f
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);0 `9 J1 A0 p; G5 M( e S$ X
for k:=1 to numorders loop9 {6 C5 \2 e; Z5 r1 s
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m% g$ d7 }% t5 j, i
--
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orders[4,k]:=max(c,orders[4,k]);
; h6 K: n6 z4 O+ u; W' S! K --
4 V/ {0 d0 E: X- U* w orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
0 Y9 c$ g$ Y7 T, @7 B --
' A! S& z8 x3 A end;
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nstep:=orders[2,j]+1:$ ^ \8 b' R1 y
if nstep<=orders[3,j]
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) F8 }; L4 s7 p1 l7 [: J then
D' ?* r. }0 H4 k6 `# F3 J3 ~ orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);! b& o, E2 `: L: B
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
& ^) O! x- Y, @2 X end;
) G9 F+ L8 e6 C- x next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});& B/ L" Z. L1 c- x
mygantt;' [( c* c) m/ E) n5 `3 E3 s+ D
ens;# \, q o6 j" _
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