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本帖最后由 soso001 于 2014-12-17 14:53 编辑 7 w' W$ j, N# K- s3 f4 c
' Y% Q s& B1 W& }6 w; F# n不好意思,打错了个字母,呵呵呵!% M: z4 L$ l' B, T) ?# T& m$ ~6 l9 g4 u
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示% |8 H4 {! ?4 g9 n
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!9 A" V" L4 l1 G( U6 B3 G# r1 l; E( Q2 \6 k
is
6 e' R8 u6 F( V C j,k,nstep,c, scheduleteps,mincomptime:integer;2 V. \) E- W+ ~ b& [4 g( _
M:string;
" `$ r. s& ~! g0 j$ N( G selecTab:table[integer,integer,integer,string];
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initorders;
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7 R* |7 |: T- p- E$ F3 o scheduledorders.delete;, S9 G$ I0 b# L2 O4 K! H" ]" o
seletTab.create;% Y3 `! y" c3 L, T1 v0 z5 D
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orders.initialize({2,1}..{2,*},0);
" k5 j* y Q; B* a$ X orders.initialize({4,1}..{4,*},0);. a0 V& u" m. B* {% l/ f- q) K
for j:=1 to numorders loop b0 K& ~& I9 @" M5 k% P" }6 Z
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);$ A, S$ p! |! Q* p' Z+ T& p
- @% C* W# M6 X --XUNHUAN. J0 x) V) S+ p* g! m* p% q
for scheduledsteps:=1 to numsteps loop --8 Y" w* v" x8 H; J
selectab.delete;
; K8 Q( Y0 X' d+ N1 b9 b* J; g k:=1;
+ O0 `! ^8 M% z- g- t- Q4 _ for j:=1 to numorders loop* [5 a8 i! a5 M' e3 p; \
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nstep:=orders[2,j]+1;
; R V) L0 V4 l5 Z if nstep<=orders[3,j] then
/ X9 i8 o" @' D1 H5 z0 x' W+ u. k selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];4 W$ [4 G1 k( N& K; R* Y) } S2 Q
k:=k+1;# l/ r' O4 v. F0 K2 x8 o( x2 K
% O2 j8 V! W/ K9 U9 q end;
: q3 S* [5 Y& \9 r2 K( r$ f next;' T* K. m5 \& e; f5 @5 w4 a
mincomptime:=selecttab.min({3,1}..{3,*});; T! y U$ @+ v4 A% x6 |/ m; G9 z4 x
: \, L3 Y! D: _* t$ m( B, E from j:=1 until j>selectab.ydim loop \2 X. s" g) Z' h: r- d
4 c3 I) f6 v" I! s if selectab[2,j]<mincomptime then
2 i: {, M6 Q' O& b j:=j+1;
: Z+ U0 A! L* q4 T) c else
4 _7 V; Z2 `. Y3 A; X selecttab.cutrow(j);
( R. j# g1 a4 [4 F0 S; |5 { end; F1 ^/ g/ a: ]
end;3 J* X2 {# u+ K: G
0 q7 s) L- e8 ]1 p) C4 X( l j:=selectionrule(selecttab);, c" R8 W6 c2 h6 e8 W' h
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nstep;+orders[2.j]+1;
7 K+ H0 n/ `1 R9 ~ orders[2,j]:=nstep;
o9 {* U! B9 d3 z# e m:=orders[1,j][1,nstep];. i; ^2 B/ A. E Z. {9 l- y
c:=orders[5,j]
% {% E, k) y. L4 n. [% h! S occres[1,m]:=c;
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0 k) W! Q1 O' X- q2 n3 z. c8 w3 g --jieguo:start,end,res,job,step( i( i6 b# L/ q" O) |
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
% Q! t) j' A* M S+ [ for k:=1 to numorders loop
; z6 x5 f+ R6 U6 T. K nstep:=orders[2,k]+1;0 F3 W4 y- X* k) n3 m* Z- G
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m- _$ c8 f7 ]6 g& n6 U
--
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7 t+ R& D$ q) j. E, d, y orders[4,k]:=max(c,orders[4,k]);. v5 d2 V6 q- k" Q9 M, o
--+ _& S8 H0 H! m$ m
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;% N; m# r; t0 F$ ~7 C1 T
next;( y I6 O# \6 q8 D: |5 w0 g
nstep:=orders[2,j]+1:
. H8 A# u7 Z1 @/ w if nstep<=orders[3,j]
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then
/ P7 s7 H6 b | orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);$ o& f$ f/ k) H4 r5 p
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
$ o. s( z* P2 o. Z0 K end;' B) U! f0 c1 c, q! X
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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